The ratio as a unit rate is 0.8 meters per second.
What is a Ratio?A ratio is a comparison between two amounts that is calculated by dividing one amount by the other. The quotient a/b is referred to as the ratio between a and b if a and b are two values of the same kind and with the same units, such that b is not equal to 0. Ratios are represented by the colon symbol (:). As a result, the ratio a/b has no units and is represented by the notation a: b.
Given:
The given statement is "8 meters in 10 seconds".
It can be written as:
= 8/10 meters per second
= 0.8 meters per second
Thus, the ratio as a unit rate is 0.8 meters per second.
learn more about ratio here:
brainly.com/question/13419413
#SPJ2
The Question attached here seems to be incomplete, the complete Question is
Write the ratio as a unit rate. 8 meters in 10 seconds.
A. 0.8 meters per second
B. 1.125 meters per second
C. 2 meters per second
D. 80 meters per second
v2 = u2 + 2as
u = 12
a = -3
s = 18
work out v
[tex] {v}^{2} = {u}^{2} + 2as \\ {v}^{2} = 144 - 108 \\ {v}^{2} = 36 \\ v = 6 , -6 \: [/tex]
Solve for x. Round to the nearest tenth, if necessary
Answer:
20.4
Step-by-step explanation:
cos(74) = x/74
x = 74×cos(74)
x = 20.4
Answered by GAUTHMATH
please help me in this questions....
Part (i)
I'm going to use the notation T(n) instead of [tex]T_n[/tex]
To find the first term, we plug in n = 1
T(n) = 2 - 3n
T(1) = 2 - 3(1)
T(1) = -1
The first term is -1
Repeat for n = 2 to find the second term
T(n) = 2 - 3n
T(2) = 2 - 3(2)
T(2) = -4
The second term is -4
Answers: -1, -4==============================================
Part (ii)
Plug in T(n) = -61 and solve for n
T(n) = 2 - 3n
-61 = 2 - 3n
-61-2 = -3n
-63 = -3n
-3n = -63
n = -63/(-3)
n = 21
Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).
Answer: 21st term===============================================
Part (iii)
We're given that T(n) = 2 - 3n
Let's compute T(2n). We do so by replacing every copy of n with 2n like so
T(n) = 2 - 3n
T(2n) = 2 - 3(2n)
T(2n) = 2 - 6n
Now subtract T(2n) from T(n)
T(n) - T(2n) = (2-3n) - (2-6n)
T(n) - T(2n) = 2-3n - 2+6n
T(n) - T(2n) = 3n
Then set this equal to 24 and solve for n
T(n) - T(2n) = 24
3n = 24
n = 24/3
n = 8
This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.
Answer: 8Cual es el resultado de la siguiente división (– 1/3 a^2 b^5 – 1/2 a^5 b^4 + 2/5 a^3 b – 5a^2 b^7) / ( – 5a^2 b^2)
Answer:
dont understand clearly
Step-by-step explanation:
Find the length of BW
A.132.59
B.134.24
C.21.26
D.3.33
Answer:
BW = 132.59
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan 9 = 21 / BW
BW tan 9 = 21
BW = 21/ tan 9
BW = 132.5887818
BW = 132.59
Answer:
Step-by-step explanation:
Side BW is the height, aka as the side adjacent to the reference angle of 9 degrees. We have the side opposite the reference angle (21) and we are looking for the side adjacent to the reference angle. The trig ratio that we use for this, the one that relates the sides opposite and adjacent, is the tangent ratio, namely:
[tex]tan(9)=\frac{21}{BW}[/tex] and solving for BW:
[tex]BW=\frac{21}{tan(9)}[/tex] so
BW = 132.59
Find the measure of the indicated arc.
A water bottling company has purchased the rights to bottle 960 liters of spring water a month from the local spring.
How many 4-liter bottles can they produce a month?
Answer:
becouse 4×960 will give you
3840
Two cards are drawn from a deck of 52 playing cards. The first card is NOT replaced into the deck before the 2nd card is drawn What is the probability of drawing a King and then another King?
Answer:
probability that 2 cards drawn from a deck of 52 cards are both kings.
is probability that first card is a king times probability that second card is a king
with replacement 4/52*4/52 =0.592%
without replacement 4/52*3/51=0.452%
Step-by-step explanation:
factor and solve the problems in the photo ……….. pleaseeeee help i haven’t done algebra in 2 years
Answer:
30. 2x²-x-1=0
or, 2x²-2x+x-1=0
or, 2x(x-1)+1(x-1)=0
or, (x-1)(2x+1)=0
so, x-1 = 0 or, x = 1
and 2x+1 = 0 or, 2x = -1 or, x = -1/2
so, x = 1 and 1/2
31. 3x²-14x=5
or, 3x²-14x-5=0
or, 3x²-15x+x-5=0
or, 3x(x-5)+1(x-5)=0
or, (x-5)(3x+1)=0
so, x-5=0 or, x=5
and 3x+1=0 or, 3x=-1 or, x=-1/3
so, x = 5 and -1/3
Answered by GAUTHMATH
In the picture below, which lines are lines of symmetry for the figure?
A. 1 and 3
B. 2 and 4
C. 1, 2, and 3
D. none
Answer:
None
Step-by-step explanation:
No lines can be folded over to match up with the opposite side
If 12 out of 30 fruits are oranges, how many oranges fruits will there be per 100 fruits total?
Answer:
40 oranges are there in 100 fruites.
4.
A line contains the points R (-5, -6) S (1, 5) and T (x, 10). Solve for x. Be sure to show and explain all work
Answer:
x is 3.[tex]\overline{72}[/tex]
Step-by-step explanation:
The given points on the line are;
R(-5, -6), S(1, 5) and T(x, 10)
The number of points required to find the equation of the line = 2 points
The slope, m, of the line using points R(-5, -6) and S(1, 5) is given as follows;
m = (5 - (-6))/(1 - (-5)) = 11/6
The equation of the line in slope and point form, using point S(1, 5) is therefore;
y - 5 = (11/6)·(x - 1) = 11·x/6 - 11/6
y - 5 = 11·x/6 - 11/6, given that the x-value is required, we have;
x = (y - 5 + 11/6) × 6/11 = 6·y/11 - 19/11
x = 6·y/11 - 19/11
At point T(x, 10), y = 10, therefore, we have;
x = 6×10/11 - 19/11 = 41/11 = 3.[tex]\overline{72}[/tex]
x = 3.[tex]\overline{72}[/tex].
how do you answer this
Answer:
19 units
Step-by-step explanation:
count the squares around the shape for the slanted part treat it like a rectangle and just count the squares from the pointy spot to the other side where it stops
How do I solve this: 12v + 10v + 14 = 80
Answer:
v = 3
General Formulas and Concepts:
Pre-Algebra
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
12v + 10v + 14 = 80
Step 2: Solve for v
Combine like terms: 22v + 14 = 80[Subtraction Property of Equality] Subtract 14 on both sides: 22v = 66[Division Property of Equality] Divide 22 on both sides: v = 3Please see screenshot for question you will get all 60 points plus a crown if you answer correctly
Answer:
12.73
Step-by-step explanation:
Set up ratio.
[tex]\frac{22}{100} =\frac{2.89}{x}[/tex]
Solve for x.
[tex]\frac{100}{22} =\frac{x}{2.8}[/tex]
[tex]\frac{100}{22} (2.8)=x[/tex]
x=12.73
find the radius of a circle if the circumference is 44cm. (take π=22/7)
Answer:
The radius of the circle if the circumference is 44 cm will be 7 cm.
Step-by-step explanation:
➝ Circumference of the circle = 44 cm
➔ Circumference = 2πr [For finding radius]
Finding the radius:-
➜ Let radius be r.
➜ 44 = 2 × 22/7 × r
➜ Multiply 2 × 22/7
➜ 44 = 44/7 × r
➜ Taking 7 to LHS.
➜ 44 × 7 = 44 × r
➜ 308 = 44 × r
➜ Taking 44 to LHS.
➜ 308/44 = r
➜ 308/44 = 7
➜ 7 = r
➜ r = 7
please show the work for it as well thank you
Answer:
2x^4+4x^2+2
Step-by-step explanation:
f(x) = x^2+1
g(x) = 2x^2
g(f(x))=
Replace x in the function g(x) with the function f(x)
=2( x^2+1)^2
= 2( x^2 +2x^2 +1)
= 2x^4+4x^2+2
2( 5 1 m− 5 2 )+ 5 3 2, left parenthesis, start fraction, 1, divided by, 5, end fraction, m, minus, start fraction, 2, divided by, 5, end fraction, right parenthesis, plus, start fraction, 3, divided by, 5, end fraction
Answer:
2/5m - 1/5
Step-by-step explanation:
Given the equation :
2(1/5m - 2/5) + 3/5
First step:
Open the bracket by multiplying values in the bracket by 2
2/5m - 4/5 + 3/5
-4/5 + 3/5 = (-4 + 3) / 5 = - 1 / 5
Hence,
2/5m - 4/5 + 3/5 = 2/5m - 1/5
= 2/5m - 1/5
Dorothy put $470 into a savings account for one year. The rate of interest on the account was 5.5%. Find the interest earned on the amount.
Answer: $25.85 assuming annual compounding.
Step-by-step explanation:
PV=470
I/Y=5.5
N=1
CPT_FV
Determine the 3 digit chopping and rounding approximately of the number 0.9
Answer:
We want to "chop and round" the periodic number 0.9 at 3 digits.
First, remember that we can write our periodic number as:
0.9 = 0.9999...
Such that the nine repeats infinitely.
Now we want to chop it at the third digit, and then round.
To chop at the third digit we just "cut" the number at the third digit after the decimal point, we will get:
0.9 ≈ 0.999
Now we round.
Remember that to round a number, we need to look at the last digit after the decimal point.
If the last digit is 5 or larger, we round up, adding 1 to the previous decimal.
If the last digit is 4 or smaller, we round down, don't adding anything to the previous decimal.
in our number:
0.999
The last digit is a 9, so we round up.
Then we add "1" to the previous decimal
but the previous decimal is a 9, so when we add 1, it will transform into a 10.
So it also adds one to the previous decimal, which also is a 9, so the process repeats, this time adding 1 to the decimal to its left, in this case, that decimal will be the first decimal at the left of the decimal point.
So after rounding, we will get:
0.999 ≈ 1
Then we can conclude that:
he 3 digit chopping and rounding approximately of the number 0.9 is 1"
helpppp please.......
The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).
This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).
[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]
[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]
note1: I use the identity [tex]\tan^2(\theta)+1 = \sec^2(\theta)[/tex] which is derived from the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1[/tex]note2: based on the previous note, we can say [tex]\tan^2(\theta) = \sec^2(\theta)-1[/tex]So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.
Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.
The tangent ration! helpp!!
Answer:
13.5
Step-by-step explanation:
Given
tan34° = [tex]\frac{x}{20}[/tex] ( multiply both sides by 20 )
20 × tan34° = x , then
x ≈ 13.5 ( to the nearest tenth )
I need help to find m =
Answer:
hlo buddy
are u free now.. nhjm....
Quadrilateral A'B'C'D' is a dilation of quadrilateral ABCD about point P Is this dilation a reduction or an enlargement? O reduction enlargement
Answer: reduction
Step-by-step explanation:
ABCD-> 'ABCD
its bc 'ABCD got smaller compared to ABCD
Answer:
It is a reduction.
Step-by-step explanation:
Hope this helped.
How in the world do I set this up?
The formula
c = 75 + 30(n - 5) is used to find the cost, c, of a taxi ride where n represents the number of [tex]\frac{1}{5}[/tex] miles of the ride. Find the cost of a taxi ride of 2/frac{2}{5}
Thanks
Answer:
Step-by-step explanation:
The 2 2/5 is not showing up correctly, but I think it means that you are going 2 miles + 2/5 of a mile. If that is not true, leave me a note and I'll correct it.
So 75 and 30(n - 5) represent cents (I think) per 1/5 of a mile.
1 mile has 5 fifths.
2 miles has 10 fifths
2/5 has 2 fifths.
the total is 17 fifths so n = 17
C = 75 + 30(17 - 5)
C = 75 + 30(12)
C = 75 + 360
C = 435
That means you pay 4 dollars and 35 cents.
What is the slope of a line parallel to line B?
14. Peter needs to buy a package of pencils to write his final exam. The store offers two packages.
Package 1: pack of 6 pencils for $1.68
Package 2: pack of 9 pencils for $2.34
Determine the cost per pencil. Which is the better deal? Round to 2 decimal places. Show all your work for full marks. (3 marks) REPOST
Answer:
Step-by-step explanation:
peter can buy pack of nine pencils
6 divided by 1.68 =3.5
9 divided by 2.34=3.8
package 2 is just 0.3 more
it give 3 more pencils for 0.3
Ive never really understood 8th-9th grade volume, could use some help
The answer is B
Eplanation:
V = pi * r² * (h/3)
Then from here you just make h the subject of the formula:
h = (V * 3)/(pi * r²)
h = (393*3)/[3.14* (10/2)²]
h = 15.01910828 ft
which is rounded to 15 ft...B
:)
Can someone please exlpain how to do this???
Answer:
40. A c=60
41 B z= 40
Step-by-step explanation:
The sum of the angles in a triangle is 180
40. 61+59+c = 180
Combine like terms
120+c = 180
c = 180-120
c =60
41. 90+50+z = 180
140 +z = 180
z = 180-140
z = 40
13. The Cyclone Coaster has 16
cars. Some of them hold 2
passengers and some hold 3
passengers. If there is room for
36 people altogether, how many
cars hold 3 passengers?
Answer:
Four cars that can hold 3 passengers
Step-by-step explanation:
The number of cars on the Cyclone Coaster = 16 cars
The number of passengers some cars hold = 2 passengers
The number of passengers the other cars hold = 3 passengers
The number of people altogether the Cyclone Coaster has room for = 36 people
Let x represent the number of cars that can hold 3 passengers, and let y represent the number of cars that can hold 2 passengers, we have;
3·x + 2·y = 36...(1)
x + y = 16...(2)
The value of x can be found by making y the subject of equation (1) and equation (2) and equating both values of y given in x as follows;
The value of y from equation (1) is, y₁ = (36 - 3·x)/2 = 18 - 3·x/2
∴ y₁ = 18 - 3·x/2
The value of y from equation (2) is, y₂ = 16 - x
Equating both y values, to find the coordinates of the common point to both equations, gives;
At the common point y₁ = y₂
By the substitution property of equality
∴ 18 - 3·x/2 = 16 - x
3·x/2 - x = 18 - 16 = 2
x/2 = 2
∴ x = 4
The number of cars that can hold 3 passengers, x = 4
(From y₂ = 16 - x, we have
y₁ = y₂ = 16 - 4 = 12
y = 1
The number of cars that can hold 2 passengers, y = 12).
