Answer:
Mass.
Explanation:
I took the quiz and got the answer right
The Earth's history is shaped by different geological processes over a wide range of space and time.
For example, in the late 1900s, a crater was discovered near the town of Wetumpka, Alabama. Scientists found shocked quartz in the core samples collected from the crater. Shocked quartz occurs as a result of intense metamorphism (change in the structure of rocks).
Which of the following geological processes is most likely responsible for the formation of the crater?
A. erosion by water
B. tectonic plate movement
C. volcanic eruption
D. meteor impact
meteor impact this ecological processes is most likely responsible for the formation of the crater. Hence option D is correct.
What is meteor impact ?A collision between celestial objects that has quantifiable effects is called an impact event. The most frequent impact events involve asteroids, comets, or meteoroids and have little impact. However, impact events have been shown to occur often in planetary systems and have physical repercussions. However, many surface impacts are reduced by atmospheres through atmospheric entry when massive objects strike terrestrial planets like the Earth. Nonetheless, there may be major physical and biospheric effects. The majority of the solid objects in the Solar System are covered with impact craters and structures, which provide the best empirical evidence for their frequency and size. Since the birth of the Solar System, impact events appear to have had a substantial impact on how the Solar System has changed. Significant impact events have impacted Earth's history and have been linked
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Definition law of moments
When an object is balanced (in equilibrium) the sum of the clockwise moments is equal to the sum of the anticlockwise moments.
Vector approach in solving forces in 3d
Answer:
[tex] \red{ \rule{1pt}{500000pt}}[/tex] [tex] \red{ \rule{1pt}{500000pt}}[/tex]
Explanation:
A constant force of 10N is applied to a 2−kg crate on a rough surface that is sitting on it. The crate undergoes a frictional force against the force that moves it over the surface. (a) Assuming the coefficient of friction is \mu_k=0.24μ k =0.24, find the magnitude of the friction force opposes the motion?(b) What is the net force on the
WITH EXPLANATION PLEASE.
Answer:
Explanation:
The kinetic friction between crate and the surface can be calculated as follows: [tex]f_{k}=\mu_{k}N=\mu_{k}mg=(0.24)(2)(10)=4.8 N[/tex]
Assume that the direction of the 10 N constant force is on the right, the kinetic friction will go the left, then:
[tex]\sum F=F_{net}=F-f_{k}=10-4.8=5.2 N[/tex]
A constant force of 10 N is applied to a crate of mass 2 kg on a rough surface, then the net force on the crate is 5.2 N
What is friction?Friction is the resistance to a thing sliding or rolling over another solid object. Although frictional forces can be helpful, such as the traction required to walk without sliding, they also provide a significant level of resistance to motion.
The forces of attraction, also called as adhesion, between both the contact zones of the surfaces, that are always microscopically uneven, seem to be the main contributor to friction among metals.
These "welded" joints are sheared, and friction is created by the irregularities of a harder surface scuffing down against the softer surface.
From the given data in the question,
Firstly, calculate the friction between the crate and the surface,
[tex]f_k\\[/tex] = [tex]\mu_k[/tex]mg
= (0.24)(2)(10)
= 4.8 N
Now, let's calculate the net force,
ΣF = F(N) = F - [tex]f_k[/tex]
= 10 - 7.8
= 5.2 N
Therefore, the net force will be equal to 5.2 N.
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Which has more momentum, a 5000 kg truck moving at 20 km per hour or a 1000 kg truck moving at 50 km per hour?
Answer:
First truck has greater momnetum
Explanation:
momentum = m * v
truck a 5000 * 20 = 10 0000
truck b 1000 * 50 = 5 0000
Which two generalizations can be made based on what you know about cycles of matter in a closed system?
New matter is added, and old matter is destroyed.
Matter changes its physical form, allowing it to return to its original state.
The amount of matter within the system remains the same.
Matter and energy can cross the boundaries of the system.
0 The cycle has a well-defined starting and stopping point.
Answer: It's 2 and 3
Explanation:
By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
Kinetic is calculated using ___
Answer:
Ek= 1/2*m*v^2
Explanation:
kinetic energy= 1/2* mass * square velocity
if a copper coin with a volume of exactly 50 cubic cm is dropped into the volume of water 4cubic cm,how much water will be overflown (water is half way of the can)
Answer:
50 cubic cm
Explanation:
As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.
1. Zahra oscillates a swing and makes 100 complete cycles in 20 seconds. Find: a. Period (
Answer:
Explanation:
Period is : [tex]T=\frac{t}{n}=\frac{20}{100}=0.2[/tex] s
What is the difference between magnitude of displacement and magnitude of velocity
The power in an electrical current is given by the equation
Answer:
P = VI
Explanation:
the power is equal to the current × voltage
Answer:
P = V • I
Explanation:
Power = Voltage • Current
Two pendula are shown in the figure. Each consists of a solid ball with uniform density and has a mass M. They are each suspended from the ceiling with massless rod as shown in the figure. The ball on the left pendulum is very small. The ball of the right pendulum has radius 1/2 L.
Find the period T of the right pendulum for small displacements in s.
The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.
How to calculate the period (T).Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where:
L is the length.g is the acceleration due to gravity.Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.
1/2L = L/2
L/2 = 1.1/2
L/2 = 0.55 meter.
Substituting the parameters into the formula, we have;
[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]
T = 1.49 seconds.
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8. A turtle crawls along a straight line, which we will call the x-axis with the positive direction to the right. The equation for the turtle's position as a function of time is x(t) = 5.0 cm + (4.00 cm/s) - (0.625 cm/s2)t2. (a) Find the turtle's initial velocity, initial position, and initial acceleration. (b) At what time is the velocity of the turtle zero? (c) How long after starting does it take the turtle to return to its starting point? (d) At what times t is the turtle a distance of 30.00 cm from its starting point? What is the velocity at each of these times?
(a) The turtle's initial velocity is 4 m/s, initial position of the turtle is 5 cm, and initial acceleration is -1.25 m/s².
(b) The time when the velocity of the turtle is zero is 3.2 s.
(c) The time taken for the turtle to return to its starting point is 6.4 s.
(d) The time taken for the turtle to travel 30 cm is 0.08 s.
Initial velocity of the turtleThe initial velocity of the turtle is calculated as follows;
[tex]v = \frac{dx}{dt} \\\\x = 5 + 4t -0.625t^2\\\\v(t) = 4 - 1.25t\\\\v(0) = 4-0\\\\v(0) = 4 \ m/s[/tex]
Initial acceleration of the turtleThe initial acceleration of the turtle is calculated as follows;
[tex]a = \frac{dv}{dt} \\\\v(t) = 4 - 1.25t\\\\a = -1.25\ m/s^2[/tex]
Initial position of the turtlex(t) = 5 + 4t - 0.625t²
x(0) = 5 cm
Time when the velocity becomes zerov(t) = 4 - 1.25t
0 = 4 - 1.25t
1.25t = 4
t = 4/1.25
t = 3.2 s
Time taken to return to starting pointThe total distance traveled is calculated as follows
v² = u² + 2ad
0 = (4)² + 2(-1.25)d
0 = 16 - 2.5d
2.5d = 16
d = 16/2.5
d = 6.4 m
Time to travel the given distance;
d = ut + ¹/₂at²
6.4 = (4)t + ¹/₂(-1.25)t²
6.4 = 4t - 0.625t²
0.625t² - 4t + 6.4 = 0
solve the quadratic equation using formula method;
t = 3.2 s
The time travel the distance two times, = 2 x 3.2 s = 6.4 s
Time taken for the turtle to travel 30 cmd = ut + ¹/₂at²
0.3 = (4)t + ¹/₂(-1.25)t²
0.3 = 4t - 0.625t²
0.625t² - 4t + 0.3 = 0
solve the quadratic equation using formula method;
t = 0.08 s
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A Cadillac Escalade has a mass of 2,569.6 kg, if it accelerates at 4.65 m/s^2 what is the net force of the car?
Answer:
11948.64 Newtons
Explanation:
I will give brainlisted for the correct answer!
A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average force of 70 North, calculate the instantaneous velocity of the stone when released
Explanation:
solution: mass m = 5g = 0.005kg; extension e = 7cm = 0.07m; force f = 70 N; velocity = ?; using: work done in elastic material w = 1/2 fe = 1/2 ke2 = 1/2 mv2 - the kinetic energy of the moving stone. 1/2 fe =...
A kitten sits in a lightweight basket near the edge
Answer:
So where's the problem now?
A kitten is just sitting
Calculate the speed of sound in a string that has a tension of 100 N and a linear mass density of 0.0001 kg/m
A baseball is thrown a distance of 60 meters. What is it’s speed if it takes 1.5 seconds to cover the distance
Answer:
V = S / d = 60 m / 1.5 sec = 40 m/s
Note 40 m/s = 40 * 3.28 = 131 ft/sec
131 ft/sec = 131 ft/sec / (88 ft/sec / 60 mph) = 89 mi/hr
__________________ 1. Adobe Photoshop is the current market leader for commercial bitmap and image. __________________ 2. The image is the space provided for your picture. __________________ 3. The drawing tools allow you to modify the image with different tools and achieve the desired effect of your image. __________________ 4. In Photoshop, images are pixel-based. __________________ 5. Create a new layer by clicking on the Create New Layer icon. A new layer will be created below the active layer.
Answer:
Cheswick and apples cheessticks
an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship. at what horizontal distance from the ship should the crew of the airplane drop a pump into the water next to the ship
For an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship, the horizontal distance is mathematically given as
x=606m
What horizontal distance from the ship should the crew of the airplane drop a pump into the water next to the ship?Generally, the equation for the y axis distance is mathematically given as
y=vt+0.5gt^2
Therefore
500=0t+1.2(9.8)t^2
t=10.1s
In conclusion, the horizontal distance
x=vt
x=60*10.1
x=606m
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List three methods of energy transport in nature and explain how the energy is being transferred in each of those methods. Which two are means by which energy is transported inside the Sun?
This question is for my college astronomy class!
First normal transportation is the light energy of sun is transmitted to our earth .
Next for transportation inside sun they are
Fusion and fissionFusion means when two hydrogen atoms reacts to form helium nucleus .
Fission means when one nucleus is broken into two or more nucleus
Explanation:
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An aircraft starts at rest and is accelerated for 9.2 seconds, at which time the aircraft launches. If the distance traveled from the starting point to the launch point was 428.8 m, what was the launch velocity of the aircraft in m/s? Assume the acceleration is constant. (Hint: multi-step problem).
Explanation:
Since the acceleration is constant, we use the big four equations.
[tex]x = x _{i} + vt[/tex]
[tex]x = \frac{1}{2} a {t}^{2} + v _{i}t + x _{i}[/tex]
[tex]v {}^{2} = (v _{i}) {}^{2} + 2a(x - x _{i})[/tex]
[tex] \frac{1}{2} (v + v _{i})t = x - x _{i}[/tex]
Next. identity the variables.
We know
t=9.2
change in position or (x- x_i) is 428.8
Initial Velocity is 0.
We need to solve for the final velocity, so we use the fourth equation.
[tex] \frac{1}{2} (v - v _{i})t = x - x _{i}[/tex]
Subsitue
[tex] \frac{1}{2} (v - 0)(9.2) = 428.8[/tex]
[tex] \frac{1}{2} (v)9.2 = 428.8[/tex]
[tex]v = 93.22 \frac{m}{s} [/tex]
A 0.5 kg turntable with a radius of 15 cm is rotating 78 times per minute.
A. What is the angular momentum of the turntable?
B. A 100 gram bar which is as long as the diameter of the turntable is dropped on the
turntable such that the bar is rotating about its center. What is the new angular velocity of the turntable-bar system?
C. In order to stop the turntable and bar in just one rotation, how much force must be applied to the edge of the turntable (assuming the force is applied perpendicular to the radius)?
Answer:
c
Explanation:
What should you do with electrical cells and batteries that no longer work
Answer:
Yes, single-use batteries are now made of common metals deemed non-hazardous by the federal government and can be disposed of in your regular trash in all states except California, where it is illegal to throw away all types of batteries.
What do radio waves, microwaves, light, and X-rays have in common
Answer:
They are all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other
The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were tripled
(with no change in its resistance), then its new current would
be milliAmps.
Answer:
180 m amp
Explanation:
V = IR
v/r = i mutiply both sides by
3
3v / r = 3 i so the current will triple to 180 mAmp
A Rich has been hooked and is puilling on the line as shown in the figure below.
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If the pole makes an angle of 25° with the horizontal, the distance between the point where the line is attached to the pole and the anglers hand is L. 2.45 m, and the fish
pulls on the line such that the tension in the line is T-166 Nat an angle 35.0 below the horizontal, determine the magnitude (in N.m) of the torque exerted by the fish
about an axis perpendicular to the page and passing through the angler's hand.
Nm
For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as
Z = 360.33Nm
What is the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand?
Generally, the equation for the Torque is mathematically given as
Z = force x perpendicular distance
Z = Tcos30° x L
Z = 166(0.886) x 2.45
Z = 360.33Nm
In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand
Z = 360.33Nm
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what are the two most important traits between a whale and a shark?
Answer:
Both are aquatic animals and are hunters
Explanation:
