which of the following statements best describes the balls motion ?

Answer:

What should we find state that first.

Answer:

930v

Explanation:

u=i*r

u=310*30=930v

Answer:

29.51m

Explanation:

Suppose you walk 11.2 m straight west and then 27.3 m straight north. How far are you from your starting point

Your distance from the starting point is your displacement

Using the pythagoras theorem

d² = (-11.2)²+(27.3)²

d² = 125.44+745.29

d² = 870.73

d = √870.73

d = 29.51m

Hence your distance from the starting point is 29.51m

Answer:

O inertia

Explanation:

The moon's property that prevents it from being pulled inward by the Earth is called it's inertia.

Every object in the universal space have gravitational force of attraction to one another due to their masses.

An inertia is the reluctant of a body to move or the tendency of it to remain in constant motion.

Inertia entails the property of objects to remain at rest or continue in uniform motion.

As the force of gravity acts between the earth and the moon, inertia keeps a body in constant position.

Answer:

2.5m/s

Explanation:

Using the law of conservation of energy;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values in the formula

2(10)-2(5) = (2+2)v

20-10 = 4v

10 = 4v

v = 10/4

v = 2.5m/s

Hence the velocity of the combined object after collision is 2.5m/s

Answer:

A

Explanation:

Myra is struggling to be a great wife, attentive mother, and an innovative designer all at the same time.

Myra's scenario is most accurately represented by role conflict because she  is struggling to be a great wife, attentive mother, and an innovative designer all at the same time.

When there are expectations put on an individual that are not compatible with one another in relation to their profession or position, this may lead to role conflict. When a someone feels as if they are being tugged in several ways while attempting to react to the multiple statuses they hold, they are experiencing role conflict.

The work-family conflict, also known as the struggle one has when torn between the demands of personal and professional responsibilities, is perhaps the clearest illustration of role conflict.

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Answer:

The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Explanation:

Given;

the position of center of the target, x₀ = 60 m

initial velocity of the bullet, u = 240 m/s

The time the bullet strikes the center of the large target is calculated as;

[tex]t = \frac{x_o}{u} =\frac{60}{240} = 0.25 \ s[/tex]

The distance from the center of the target to the point where the bullet strikes the target is calculated as;

x = vt + ¹/₂gt²

where;

v is the final velocity of the bullet when it strikes the target = 0

x = 0 + ¹/₂(9.8)(0.25²)

x = 0.31 m

Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Answer:

[tex]59000[/tex]

[tex]1.8\times 10^5[/tex]

[tex]4.3\times 10^{-2}[/tex]

[tex]9.0\times 10^{-6}[/tex]

[tex]8.4\times 10^{-6}[/tex]

Explanation:

The given numbers are

[tex]1.8\times 10^5=18000[/tex]

[tex]4.3\times 10^{-2}=0.043[/tex]

[tex]8.4\times 10^{-6}=0.0000084 [/tex]

[tex]9.0\times 10^{-6}=0.000009[/tex]

[tex]59000[/tex]

The arrangement of the numbers from largest to smallest is

[tex]59000[/tex]

[tex]1.8\times 10^5[/tex]

[tex]4.3\times 10^{-2}[/tex]

[tex]9.0\times 10^{-6}[/tex]

[tex]8.4\times 10^{-6}[/tex].

Answer:

Explanation: very far

Answer:

64 J

Explanation:

The potential energy change of the spring ∆U = -W where W = work done by force, F.

Now W = ∫F.dx

So, ∆U = - ∫F.dx = - ∫Fdxcos180 (since the spring force and extension are in opposite directions)

∆U = - ∫-Fdx

=  ∫F.dx

Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U =  ∫₀²F.dx

=  ∫₀²(40x - 6x²).dx

=  ∫₀²(40xdx - 6x²dx)

=  ∫₀²(40x²/2 - 6x³/3)

=  ∫₀²(20x² - 2x³)

= [20x² - 2x³]₀²

= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)

= [(20(4) - 2(8)) - (0 - 0))

= [80 - 16 - 0]

= 64 J

The change in potential energy will be "64 J".

Given:

The potential energy of spring:

→ [tex]P.E = \int_{0}^{x}F.dx[/tex]

          [tex]= \int_{0}^{x}(40x - 6 x^2).dx[/tex]

here,

x = 2m

then,

→ [tex]P.E = 64 \ J[/tex]

Thus the above answer is correct.

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Answer:

Explanation:

Gravity

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

        [tex]v = \lambda * f (1)[/tex]

       [tex]\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)[/tex]

      [tex]\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)[/tex]

Answer:

8.8s

Explanation:

Given parameters:

Acceleration  = 1.6m/s²

Initial velocity  = 36m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time;

      Acceleration  = [tex]\frac{Final velocity - initial velocity }{time taken }[/tex]  

Insert the parameters and solve for time taken;

   1.6  = [tex]\frac{50 - 36}{t}[/tex]  

    1.6t  = 14

         t  = 8.8s

Answer:

Vo = 17.69 [m/s]

Explanation:

To solve this problem we must use two equations of kinematics.

[tex]v_{f}^{2} =v_{o}^{2} +2*g*h\\v_{f}=v_{o}+g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 55 [m]

t = time = 2 [s]

Now we replace the gravity acceleration into the second equation:

[tex]v_{f}=v_{o}+9.81*2\\v_{f}=v_{o}+19.62[/tex]

And then into the first equation:

[tex](v_{o}+19.62)^{2}=v_{o}^{2}+2*9.81*55\\v_{o} ^{2}+2*v_{o}*19.62+384.94=v_{o}^{2} + 1079.1\\39.24*v_{0}=694.16\\v_{o}=17.69[m/s][/tex]

The initial speed at which the ball is thrown upward is 17.7 m/s.

According to the question the initial position of the ball, y = 55 m, and the final position of the ball is y' = 0 m. We have assumed upward direction as positive direction and downward as negative direction.

so the total displacement:

d = y'-y = 0 - 55

d = -55 m

now applying the second equation of motion:

d = ut - (1/2)gt²

where t = 2s ( given ) and g = 9.8 m/s².

-55 = 2u - 0.5×9.8×4

-55 = 2u - 19.6

u = -17.7 m/s

the negative sign indicated that the initial velocity is opposite to the direction of displacement.

This means the initial velocity is upward as it should be.

Therefore, the initial speed of the ball is 17.7m/s

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Answer:

μsmín = 0.1

Explanation:

       [tex]F_{frmax} = \mu_{s} *F_{n} (1)[/tex]

       where  μs is the coefficient of static friction, and Fn is the normal force,

       perpendicular to the wall and aiming to the center of rotation.

       [tex]F_{c} = m* \omega^{2} * r (2)[/tex]

       where ω is the angular velocity of the riders, and r the distance to the

      center of rotation (the  radius of the circle), and m the mass of the

      riders.

      Since Fc is actually Fn, we can replace the right side of (2) in (1), as

      follows:

     [tex]F_{frmax} = m* \mu_{s} * \omega^{2} * r (3)[/tex]

       [tex]m* g = m* \mu_{smin} * \omega^{2} * r (4)[/tex]

       [tex]g = \mu_{smin} * \omega^{2} * r (5)[/tex]

      [tex]60 rev/min * \frac{2*\pi rad}{1 rev} *\frac{1min}{60 sec} =6.28 rad/sec (6)[/tex]

       [tex]\mu_{smin} = \frac{g}{\omega^{2} *r} = \frac{9.8m/s2}{(6.28rad/sec)^{2} *2.5 m} =0.1 (7)[/tex]

Answer:

The population size decreases.

Explanation:

If more of a species are dying than being born, the population size will decrease.

Answer:

Heat transfer processes: Radiation - Natural Convection

Energy balance:

[tex]\dot Q_{rad} -\dot Q_{conv} = \frac{dU_{sys}}{dt}[/tex]

[tex]\epsilon\cdot \sigma\cdot A_{s}\cdot (T_{s}^{4}-T_{a}^{4})-h\cdot A_{s} \cdot (T_{a}-T_{\infty}) = m\cdot c\cdot \frac{dT_{a}}{dt}[/tex]

Explanation:

The asphalt is heated due to the radiation from the sun and cooled by natural convection of the wind. By the First Law of Thermodynamics, we have the following model that represents the system:

[tex]\dot Q_{rad} -\dot Q_{conv} = \frac{dU_{sys}}{dt}[/tex] (1)

Where:

[tex]\dot Q_{rad}[/tex] - Heat transfer by radiation, measured in watts.

[tex]\dot Q_{conv}[/tex] - Heat transfer by natural convection, measured in watts.

[tex]\frac{dU_{sys}}{dt}[/tex] - Rate of change of thermal energy of the asphalt, measured in watts.

By applying the definitions for conduction, radiation and thermal energy, we expand (1) below:

[tex]\epsilon\cdot \sigma\cdot A_{s}\cdot (T_{s}^{4}-T_{a}^{4})-h\cdot A_{s} \cdot (T_{a}-T_{\infty}) = m\cdot c\cdot \frac{dT_{a}}{dt}[/tex] (2)

Where:

[tex]\epsilon[/tex] - Emissivity of the asphalt.

[tex]\sigma[/tex] - Stefan-Boltzmann constant, measured in watts per square meter-quartic Kelvin.

[tex]A_{s}[/tex] - Surface area of the asphalt, measured in square meter.

[tex]T_{s}[/tex] - Temperature of the sun, measured in Kelvin.

[tex]T_{a}[/tex] - Temperature of the asphalt, measured in Kelvin.

[tex]T_{\infty}[/tex] - Temperature of the wind, measured in Kelvin.

[tex]h[/tex] - Natural convection constant, measured in watts per square meter-Kelvin.

[tex]m[/tex] - Mass of the asphalt, measured in kilograms.

[tex]c[/tex] - Specific heat of the asphalt, measured in joules per kilogram-Kelvin.

Answer:

408.33watts

Explanation:

Power is expressed according to the formula

Power = work done/time

Power = force × distance/time

Power = Force× velocity

Find the force

F = mv/t

F = 600×1.75/4.5

F = 1050/4.5

F=233.33N

Get the power

Power = 233.33×1.75

Power = 408.33watts

Hence the average power of the elevator motor during this period is 408.33m/s

Answer:

C. the top line represents a greater velocity

Explanation:

The graph is a distance - time graph.

The distance is on the y-axis and time is on the x - axis.

For this graph, the slope is the velocity.

The lower line is not so steep and its slope is lesser compared to the upper one.

Answer:

I) True,  II) False,  III) False,  IV) True    

Explanation:

In this exercise, it is asked to answer different statements, for this we will use the relationship between angular and linear velocity

           v = w r

let's review the claims

I) True. From the initial equation we see that the linear velocity depends on the radius

II) False. All points rotate with the same angular velocity

III) False. Linear velocity changes with radius

IV) True. The angular velocity of all points is the same

At various radial points on a rotating Ferris wheel have, different linear velocity (True), different angular velocity (false), equal linear velocity (false) and equal angular velocity (True).

The angular velocity of a rotating Ferris is calculated as follows;

[tex]\omega = \frac{v}{r} = 2\pi N[/tex]

The linear velocity of a rotating Ferris is calculated as follows;

v = ωr

where;

The linear velocity increases with increase in radius.

Thus, we can conclude that, at various radial points on a rotating Ferris wheel have;

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Answer: A. The gravity of Venus will boost the speed of the space probe

Explanation: Hope this helped in time (:

Answer:

1) solvent

2) liquid-solid

3) gas - gas

Explanation:

1) A solution is the homogenous mixture of two or more substances in such a way that its components are uniformly distributed. In any solution, the solvent make up the greatest quantity or volume while the solute is of lesser quantity.

2) liquid-solid is the most common type of solution.

3) A gas solution can be a gas dissolved in a gas, or a liquid dissolved in a gas, or a solid dissolved in a gas.  Air is a gas - gas solution, it is composed of oxygen and other dissolved gases in nitrogen

Answer:

B, A, B

Explanation:

had this USA test prep

Answer:

basically I will tell you the definition

Explanation:

so when charges are unbalanced statistic energy is formed positive attract negative and negative attracts positive like repell while unlike attract .

Explanation: That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

Answer:

F= 11.25*10⁵ N to the right.

Explanation:

      [tex]F_{13} = \frac{K*q_{1}*q_{2}}{r_{13} ^{2} } = \frac{9e9*(-3.00C)(1.00C)}{(200m)^{2}} = -6.75e5 N (1)[/tex]

      [tex]F_{23} = \frac{K*q_{3}*q_{2}}{r_{23} ^{2} } = \frac{9e9*(2.00C)(1.00C)}{(100m)^{2}} = 18e5 N (2)[/tex]

Answer:

there is not a picture below  but it would be because the beaker was put in cold water then the temp decreased

Explanation:

Explanation:

The most established layers are on the base, and the most youthful layers are on the top. Since dregs here and there incorporate once-living creatures, sedimentary stone regularly contains a great deal of fossils. Fossils are once living beings that have been transformed into rock, fit as a fiddle or type of the creature can in any case be seen.