Which observation is the best evidence that some colors of visible light are
being absorbed in this photo?
A. The man's head is distorted under the water.
B. The top of the man's head appears disconnected.
C. The shape of the man's arm is clearly seen underwater.
D. The snorkel in the man's mouth appears yellow.

Answer:

Explanation:

He can not walk on the ice because ice is frictionless . But he can move to shore or side using law of conservation of momentum . He will throw the bag of gold towards the side opposite to shore . This will create a motion in himself in opposite direction according to law of conservation of momentum.

Let m and M be mass of bag and prospector , v and V be velocity created in bag and prospector after throw of bag . Initially , both bag and prospector were at rest so initial momentum = 0 . Final momentum of both = mv - MV .

negative sign is due to their opposite motion .

According to law of conservation of momentum

MV - mv = 0

MV = mv

In this way he can create motion in himself to move to side .

Answer:

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Explanation:

If a ball is thrown horizontally with a speed of 65 miles per hour, then it would fall 4.32 meters while traveling 90 ft of horizontal distance.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

As given in the problem If a ball is thrown horizontally with a speed of 65 mph, then we have to find out  how far will it fall while traveling 90 ft of horizontal distance,

1 mile = 1609 meters

65 miles = 65*1609 meters

               =104585 meters

65 miles per hour = 104585 meters per hour

The speed in meters per second = 104585/3600

                                                       =29.05 meters / second

1 feet = 0.3048 meters

90 feets = 90*0.3048

              =27.432 meters

The time is taken by the ball = 27.432/29.05

                                                =0.945

S = ut + 1/2*a*t²

   = 0 + 0.5*9.81*0.945²

S = 4.32 meters

Thus, the ball would fall 4.32 meters while traveling 90 ft of horizontal distance.

To learn more about equations of motion from here, refer to the link ;

brainly.com/question/5955789

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Answer:

d = 8.06 (units)

Explanation:

In this problem, we are given two points with X & y coordinates. therefore we must use the Pythagorean theorem with the respective coordinates of each point to determine the required distance.

[tex]A = (-6, 1)\\B = (2, 2)[/tex]

Now using the Pythagorean theorem.

[tex]d=\sqrt{(x_{1}-x_{0})^{2} +(y_{1}-y_{o})^{2} }\\d=\sqrt{(2-(-6))^{2} +(2-1)^{2} }\\d=\sqrt{64+1} \\d=8.06[/tex]

Explanation:

We need to use the conservation of energy to help us solve this one.

The energy imparted onto the bullet projectile is equal to the energy imparted into the recoiling gun. We can ignore potential energy and only consider the kinetic energy of the two masses (bullet and gun).

Remember that kinetic energy is expressed as [tex]K_E = \frac{1}{2}mv^2[/tex]

Conservation of energy means that both the gun and the bullet have the same amount of energy.

[tex]\frac{1}{2}m_gv_g^2 = \frac{1}{2}m_b v_b^2[/tex]

We'll want to put the mass terms into the same units. So the gun has a mass of 2340 grams.

Answer:

t = 8.24 [min]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 25 [km/h]

Vo = initial velocity = 2 [m/s]

a = acceleration = 0.01 [m/s²]

t = time [s]

Now we must convert the speed from kilometers per hour to meters per second.

[tex]25[\frac{km}{h} ]*[\frac{1h}{3600s}]*[\frac{1000m}{1km} ]=6.94[m/s][/tex]

Now replacing:

[tex]6.94=2+0.01*t\\t=494 [s]\\or\\t=8.24[min][/tex]

Question:

A spherical balloon with a 36 cm diameter is being deflated. Its volume V is a function of its radius r according to [tex]V(r) = \frac{4}{3}\pi r^3.[/tex]

As it's deflating, it is much easier to measure its radius than its volume. Suppose the radius of the balloon is [tex]r(t) = 18 - 18e^{-0.24t}[/tex] cm at t seconds.

Answer:

[tex]V'(4) = 201.143[/tex]

[tex]r(4) = 11.106[/tex]

Explanation:

Given

[tex]V(r) = \frac{4}{3}\pi r^3.[/tex]

[tex]r(t) = 18 - 18e^{-0.24}[/tex]

Solving (a):  V'(4)

First, we determine V('r)

[tex]V(r) = \frac{4}{3}\pi r^3.[/tex]

Differentiate w.r.t r

[tex]V'(r) = 3 * \frac{4}{3}\pi r^{3-1}[/tex]

[tex]V'(r) = 3 * \frac{4}{3}\pi r^2[/tex]

[tex]V'(r) = 4\pi r^2[/tex]

Substitute 4 for r and take [tex]\pi = \frac{22}{7}[/tex]

[tex]V'(4) = 4 * \frac{22}{7} * 4^2[/tex]

[tex]V'(4) = 4 * \frac{22}{7} * 16[/tex]

[tex]V'(4) = \frac{4 * 22* 16}{7}[/tex]

[tex]V'(4) = \frac{1408}{7}[/tex]

[tex]V'(4) = 201.143[/tex]

This means that the volume of the balloon when the radius is deflated to 4 seconds is 201.143 cm^3

Solving (b): r(4)

Substitute 4 for t in [tex]r(t) = 18 - 18e^{-0.24t}[/tex]

[tex]r(4) = 18 - 18e^{-0.24*4}[/tex]

[tex]r(4) = 18 - 18e^{-0.96}[/tex]

[tex]r(4) = 18 - 18*0.383[/tex]

[tex]r(4) = 11.106[/tex]

This means that the radius of the balloon when at 4 seconds of deflation is 11.106 cm

Answer:0.2167 m/s

Explanation:

Given

mass of brick M=8.5 kg

mass of toy truck m=6.5 kg

the velocity of truck u=0.5 m/s

Suppose v is the velocity after brick is landed on the truck

There is no external force acting so momentum is conserved

mu=(M+m)v

[tex]v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s[/tex]

Answer:

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Answer:

Explanation:

Electrical energy is energy derived from electric potential energy or kinetic energy.

Or,

Electrical energy is a form of energy resulting from the flow of electric charge. Lightning, batteries and even electric eels are examples of electrical energy.People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.

Hope it helped you.

Answer:

W = 113.98 N

Explanation:

Given that,

Radius of Potatoine[tex]R=6.4\times 10^6\ m[/tex]

Mass of Potatoine, [tex]M=2\times 10^{24}\ kg[/tex]

Mass of Marvin, m = 35 kg

We need to find his weight on Potatoine. Weight of an object is given by :

W = mg

g is acceleration due to gravity, [tex]g=\dfrac{GM}{R^2}[/tex]

So,

[tex]W=\dfrac{GMm}{R^2}\\\\W=\dfrac{6.67\times 10^{-11}\times 35\times 2\times 10^{24}}{(6.4\times 10^6)^2}\\\\W=113.98\ N[/tex]

So, his weight on Potatoine is 113.98 N.

Answer:

R = 1.699 × [tex]10^{4}[/tex]

Explanation:

given data

height H = 1.70 m

time is t = 11.1 s

to find out

radius r of Earth

solution

we get here cosθ so

cos(θ) = R ÷ (R+1.70)          ................1

here θ = 360 × 11.1 ÷ (24×60×60)

θ = 0.04625

so put here value in eq 1

cos(0.04625) = R ÷ (R+1.70)

so radius R will be

0.9999 = R ÷ (R+1.70)

1.6999 + 0.999 R = R

R = 1.699 × [tex]10^{4}[/tex]

Answer:

Heat stroke

Explanation:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention.

Answer:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.

Explanation:

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Complete question is:

Tech A says that when testing a relay winding with an ohmmeter,  it should show the winding is open. Tech B says that the solenoid closes a set of heavy contacts that send current flow to the starter motor. Who is correct?

Answer:

Tech B is correct

Explanation:

First we need to know the basic working principle or relays. It is basically an electromagnetic switch controlled by a coil. When voltage is applied to the coil, the generated current produces an electromagnetic pulling the internal contacts and activating the switch.

Now, lets review each statement:  

This is False. The winding is made of a conductive filament, like copper, so testing with an ohmmeter will show a closed circuit, usually with a low resistance value.

This is True. As the explanation above, the solenoid produces an electromagnetic field that activates the contacts, switching on or off the desired circuit.

Answer:

energy of position

Explanation:

I think that is the answer

Answer:

Chemical

Explanation:

Answer:

13.33m/s

Explanation:

Given data

m1= 2000kg

u1= 20m/s

m2= 1500kg

u2= 0m/s

v1= 10m/s

Required

The speed of the sticks

We know that  from the expression for the conservation of momentum

m1u1+m2u2= m1v1+m2v2

2000*20+1500*0=2000*10+1500*v2

40000=20000+1500v2

collect like terms

40000-20000= 1500v2

20000= 1500v2

v2= 20000/1500

v2= 13.33 m/s

Hence the velocity of the sticks is 13.33m/s

Answer: The dependent variable is always the opposite of the independent variable. False ... Scientific theories are broad explanations that are widely accepted as true.

Explanation:

Answer:

The word "hurricane" is widely known and recognized, but its etymology is lesser-known. Named for Mayan God The English word "hurricane" comes from the Taino (the indigenous people of the Caribbean and Florida) word "Huricán," who was the Carib Indian god of evil. Their Huricán was derived from the Mayan god of wind, storm, and fire, "Huracán."

Explanation:

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Answer:

Weight of the runner is 60 kilograms

Explanation:

Momentum is the product of weight and velocity.

The formula is : p=mv   where m is mass in kg and v is velocity in m/s

Given in the question ;

v= 20 m/s  and p=1200 kg*m/s

Applying the formula as;

p= mv

1200 = m * 20

1200/20 = m

60 kg = m

Answer:

The weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].

Explanation:

First of all, we need to find the acceleration of gravity at 2R. Using the gravitational force equation

[tex]F=G\frac{mM}{R^{2}}[/tex]

Where:

M is the mass of the earth

m is the mass of the object

G is the gravitational constant

R is the radius of the earth

We can equal the gravitational force with the second Newton's law (F=ma)

[tex]F=G\frac{mM}{R^{2}}[/tex]

[tex]mg=G\frac{mM}{R^{2}}[/tex]

We know the weight at the earth surface is 90 N, which means:

[tex]90=G\frac{mM}{R^{2}}[/tex]    

Now, we have the same equation in the case of 2R as a distance from the surface of the object. Let's remember we need to use the distance from the center of the mass of the earth, so in this case, will be 3R.

[tex]F'=G\frac{mM}{(3R)^{2}}[/tex]            

[tex]F'=G\frac{mM}{9R^{2}}[/tex]  

[tex]F'=\frac{1}{9}G\frac{mM}{R^{2}}[/tex]  

Using the above equation we have:

[tex]F'=\frac{1}{9}90[/tex]  

[tex]F'=\frac{90}{9}[/tex]  

Therefore, the weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].

I hope it helps you!

Answer:

As the service marks the start of every rally and subsequently dictates its flow, it is a crucial aspect of the game to get right in badminton.

These are the four main types of services in badminton and most can be executed with either your forehand or backhand.

1. Low serve

This low serve is almost a gentle tap over the net with the shuttle, with the aim of flying just over the net, yet falling just over the front line of his service court. It must not be too high or predictable, otherwise it would be easy for your opponent to do an outright smash or net kill.

2. High serve

The high serve is a powerful strike upwards with the shuttle, that aims to travel a great distance upwards and fall deep at the rear end of the court.

Although it is a strong serve and the popular choice of beginner players, its a serve that isn't so easy to disguise especially since you're using a forehand grip. Your opponent will already expect the shuttlecock to land at the back of the court.

Do remember that shuttlecocks have to fall within the corresponding service areas and this is different in singles and doubles.

3. Flick serve

This flick serve is also played upwards but at a much lesser altitude. It is most common for players to use their backhand to execute the flick serve and the trajectory is lower as this grip has less power.

The whole point of the backhand flick serve is deception, by mixing your serves up and making it look like you're doing a low serve. For this reason, serving with your backhand is thus very popular with competitive players.

It becomes hard for your opponent to predict if you are going to do a flick or a low serve as your stroke will look exactly the same until the point of contact.

4. Drive Serve

This is an attacking serve that is used by top badminton players like Lin Dan. The idea is to hit the shuttle directly at your opponent, limiting their return options and catching them off guard, winning you easy points. It's a good change of pace but it is also risky as if your opponent is prepared, he could just smash the shuttlecock back at you.

This serve is executed with your forehand through underarm action and following through. The shuttle should be dropped a bit sideways rather than in front of your body and hit flatter.

Now that you've determined the type of serve you want to make, here are a four tips on how to execute these serves well.

1. Keep your feet still

During the service, some part of both your feet must be in contact with the ground for it to be a legal serve.

2. Disguise your shots

Make sure your stroke is the same up to the point of contact with the shuttle. This will make your serve possible to predict only at the last possible second. Advanced players can try to trick their opponent by making it deliberately look like you're leaning back and about to do a high serve when you're really going to do a low serve.

3. Observe your opponents position

Is your opponent leaning towards the back already anticipating a high serve to the rear-court? In that case, you may want to execute a low serve to catch him off-guard. Always be aware of the position of your opponent. Try to imagine what he's expecting and do the opposite to gain an advantage.

4. Mix up your serves

Using just one type of service will make you too easy to predict. Make sure you incorporate at least two types of serves into your play. Once you've mastered the basic high and low serves, you can learn the flick and drive serves to add more dimension to your play.

In a nutshell, executing a service well allows you to start the rally strong and dictate its flow.

Explanation:

I hope it's help

I suppose you mean to say that the wall is frictionless in the first scenario? Also, I assume the block is to held in place. Construct a free body diagram for the block. There are 3 (in part A) or 4 (in part B) forces acting on it.

• its weight w, pulling it downward

• the normal force (magnitude n), pushing outward from the wall to the left

• the push as described, with magnitude p

• static friction (mag. f ), opposing the upward net force and thus pointing downward.

The static friction force has a magnitude proportional to that of the normal force. If the coefficient of static friction is µ, then

f = µ n

so if the wall is frictionless with µ = 0, then f = 0 and does not need to be considered.

(A) If µ = 0, then by Newton's second law we have

• net vertical force:

∑ F = p sin(50°) - w = 0

and we don't need to consider the net horizontal force to determine p from here. We get

p = w / sin(50°) = (4 kg) (9.8 m/s²) / sin(50°) ≈ 51 N

(B) If µ = 0.25, then Newton's second law gives

• net vertical force:

∑ F = p sin(50°) - w - f = 0

p sin(50°) - f = (4 kg) (9.8 m/s²)

p sin(50°) - f = 39.2 N

• net horizontal force:

∑ F = p cos(50°) - n = 0

p cos(50°) - f /0.25 = 0

[since f = 0.25 n]

p cos(50°) - 4f = 0

Multiply the first equation by -4, then add it to the second equation to eliminate f and solve for p :

-4(p sin(50°) - f ) + (p cos(50°) - 4f ) = -4 (39.2 N) + 0

p (cos(50°) - 4 sin(50°)) = -156.8 N

p = (156.8 N) / (4 sin(50°) - cos(50°)) ≈ 65 N

Answer:

A medium in which speed of light is more is known as optically rarer medium and a medium in which speed of light is less is said to be optically denser medium. For example in air and water, air is raer and water is a denser medium.

Explanation:

Answer:Rarer medium is less dense

Explanation:

Rarer medium is less dense than dense medium because rarer medium doesn't have a very high amount of particles packing it together. It's easier to see through a rarer medium, so you're able to get a clearer picture of what's on the other side of it. Denser medium is, simply put, more dense.

Answer:

d. 268 s

Explanation:

Constant Speed Motion

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

[tex]\displaystyle v=\frac{d}{t}[/tex]

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

[tex]\displaystyle t=\frac{d}{v}[/tex]

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

[tex]\displaystyle t=\frac{5}{67}[/tex]

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

Answer:

40m to the East

Explanation:

Displacement is the distance moved in a specific direction. When writing the displacement value of a moving body, the direction must be put in the description.

Displacement takes into account the start and finish position of a body.

                                                 100m

Start         --------------------------------------------------------------  →

                                                               60m

                                       Final ←----------------------------------

Displacement  = 100m  - 60m  = 40m

 Therefore, the displacement is 40m due east

Answer:

The distance of the object from the concave mirror determines if it is a virtual or real image

Explanation:

Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.

Answer:

f = 0.0833 Hz

Explanation:

Frequency is defined as the no. of cycles per unit time. The frequency of water waves can be given by the following formula:

[tex]Frequency\ of\ waves = f = \frac{No.\ of\ Waves}{time}\\[/tex]

here,

No. of Waves = No. of times seagull moves up and down = 5

Time = 1 minute = 60 sec

Therefore, using these values in the formula, we get:

[tex]f = \frac{5}{60\ sec}[/tex]

f = 0.0833 Hz

Answer:

F₁₋₂ = 1.036*10⁻⁵ [N]

Explanation:

In order to solve this problem, we must use the law of universal gravitation, which can be defined by means of the following expression.

[tex]F_{1-2}=G*\frac{m_{1}*m_{2}}{d^{2} }[/tex]

where:

F₁₋₂ = Force among the two bodies [N]

G = Universal gravity constant = 6.67 *10⁻¹¹ [N*m²/kg²]

m₁ = mass of the first body = 3.5*10 [kg]

m₂ = mass of the second body = 3*10¹² [kg]

d = separation distance = 26000 [m]

Now replacing:

[tex]F_{1-2}=6.67*10^{-11}*\frac{3.5*10*3*10^{12} }{26000^{2} } \\F_{1-2}=1.036*10^{-5}[N][/tex]