Answer:
ozone layer
Explanation:
The ozone layer forms a thin shield in the upper atmosphere protecting life on earth from UV rays. Ozone is a naturally occurring gas that is found in two layers of the atmosphere
If a ball is thrown horizontally with a speed of 65 mph, how far will it fall while traveling 90 ft of horizontal distance?
Answer:
install socrati it give you all answers
Explanation:
If a ball is thrown horizontally with a speed of 65 miles per hour, then it would fall 4.32 meters while traveling 90 ft of horizontal distance.
What are the three equations of motion?There are three equations of motion given by Newton
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
Note that these equations are only valid for a uniform acceleration.
As given in the problem If a ball is thrown horizontally with a speed of 65 mph, then we have to find out how far will it fall while traveling 90 ft of horizontal distance,
1 mile = 1609 meters
65 miles = 65*1609 meters
=104585 meters
65 miles per hour = 104585 meters per hour
The speed in meters per second = 104585/3600
=29.05 meters / second
1 feet = 0.3048 meters
90 feets = 90*0.3048
=27.432 meters
The time is taken by the ball = 27.432/29.05
=0.945
S = ut + 1/2*a*t²
= 0 + 0.5*9.81*0.945²
S = 4.32 meters
Thus, the ball would fall 4.32 meters while traveling 90 ft of horizontal distance.
To learn more about equations of motion from here, refer to the link ;
brainly.com/question/5955789
#SPJ2
Kinetic energy is the energy of movement describe how kinetic energy plays a role in transferring heat from one object to another
Friction
Questions
1 Jo, Daniel and Helen are pulling a metal ring. Jo pulls with
a force of 100N in one direction and Daniel with a force
of 140 N in the opposite direction. If the ring does not
move, what force does Helen exert if she pulls in the same
direction as Jo?
Answer:
Helen's force must be of 40 N in the same direction as Jo.
Explanation:
Net Force
When a number of forces are applied to an object, the net force is the sum of all the forces considered as vectors.
When all forces act on a straight line, only two possible directions are considered and they can be arbitrarily assigned positive and negative signs.
Jo pulls with a force of 100 N in a direction considered as positive (for example). Daniel applies a force of 140 N in the opposite direction, obviously negative. The net force of these two forces is 100 N - 140 N = - 40 N.
This means there is a resultant non-zero force in the direction of Daniel's. If we are told the net force is zero because of Helen's force, it must be applied in the same direction as Jo's force to balance.
Helen's force must be of 40 N in the same direction as Jo.
Question 16 The aerodynamics of a blimp in air are to be tested in a geometrically similar small scale model in a laboratory water tunnel. The model scale is 10:1, the kinematic viscosity of air is 1.46*10-5 m2/s, and the kinematic viscosity of water 1.12*10-6 m2/s. if the prototype is to be tested at a speed of 10 m/s, what speed should the model be tested in water for similitude
jei ghotona i ji ka mandir k bol rahe the j to be a
what is physical quantity
A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.
Answer:
a property of a material or system that can be quantified by measurement
have a nice day!!!
The dependent variable is always opposite of the independent variable? True or false?
Answer: The dependent variable is always the opposite of the independent variable. False ... Scientific theories are broad explanations that are widely accepted as true.
Explanation:
A playground merry-go-round is a solid disk of radius 2 m and mass 500 kg. If four children with masses of 27 kg each are standing on the edge (holding on), how hard would an AP Physics student have to push tangent to the edge to accelerate the whole thing at 3.1 rad/s^2
Answer:
F = 2220 N
Explanation:
There exists a fixed relationship, that resembles Newton's 2nd Law (applied to rigid bodies) between an external net torque (τ), the rotational inertia (I) of the body, and the angular acceleration (α) due to the torque, as follows:[tex]\tau = I * \alpha (1)[/tex]
By definition, the magnitude of the torque is given by the following expression:τ = F* r* sinθ (2)where F is the applied force, r is the distance to the center of rotation, and θ is the angle between the force and the position vector from the center of rotation to the line of action of the force.In this case, as the force is tangential to the edge, both vectors are perpendicular each other, so (2) becomes simply as follows:τ = F*r (3)Replacing in (1), we have:F*r = I*α (4)I is the total rotational inertia, that is composed by two terms, one is the rotational inertia of the disk, Idisk, which is given by the following expression:[tex]I_{disk} = m*\frac{r^{2} }{2} (5)[/tex]
The other component of I, is due to the four children.Assuming that we can treat them as point masses, the rotational inertia due to any of them is as follows:[tex]I_{child} = m_{child} * r^{2} (6)[/tex]
So, the rotational inertia will be (5) plus (6) times 4 (due to there are 4 children at the same distance r from the center of rotation), as follows:[tex]I_{t} = I_{disk} + 4* I_{child} (7)[/tex]
Replacing by the givens, we get:[tex]I_{t} = \frac{500kg*(2.00m)^{2}}{2} + (4* 27 kg* (2.00m)^{2}) = 1432 kg*m2 (8)[/tex]
Replacing by the values of I, r and α in (4), and solving for F, we get:[tex]F = \frac{I*\alpha }{r} = \frac{1432kg*m2*3.1 rad/sec2}{2.00m} = 2220 N (9)[/tex]
*Astronomy not physics
How long does it take a message to travel from Earth at Pluto at its average distance from Earth (about 5.9
billion km)?
Write down short notes on:
c. Power
Answer: In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.
Explanation: SI unit: watt (W)
In SI base units: kg⋅m2⋅s−3
Derivations from other quantities: P = E/t; P = F...
Why are Newton’s 3 laws important?
Answer:
Newton's law are very important because they tie into almost everything we see in everyday life. ... Newton's laws speak very generally all forces, but to use them for any specific problem, you have to actually know all the forces involved, like gravity, friction, and tension.
The force of water flowing over a dam spillway is to be measured in a geometrically similar small-scale laboratory model. The width of the prototype is 30 m and the width of the model is 2 m. If the force on the model spillway is measured to 10 kN, the expected force on the prototype spillway for dynamically similar conditions is:
Answer:
Jay shree krishna j to the same time kr rhe h u have UCC fm rob and studing a few minutes ago
Which heat related illness requires immediate medical attention
Answer:
Heat stroke
Explanation:
Heat Stroke is the most serious heat-related illness and requires immediate medical attention.
Answer:
Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.
Explanation:
I HOPE THIS HELPS * pls mark me brainliest }
Measurement is advantageous in daily life. Why?
Write down short notes on:
a. Electrical energy
Answer:
Explanation:
Electrical energy is energy derived from electric potential energy or kinetic energy.
Or,
Electrical energy is a form of energy resulting from the flow of electric charge. Lightning, batteries and even electric eels are examples of electrical energy.People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.
Hope it helped you.
A 8.5 kg brick is dropped onto a 6.5 kg toy truck, which is moving across a level floor at 0.50 m/s. With what velocity do the truck and brick continue to move, after the brick has landed on the truck?
Answer:0.2167 m/s
Explanation:
Given
mass of brick M=8.5 kg
mass of toy truck m=6.5 kg
the velocity of truck u=0.5 m/s
Suppose v is the velocity after brick is landed on the truck
There is no external force acting so momentum is conserved
mu=(M+m)v
[tex]v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s[/tex]
An asteroid with a mass of 3.5x10kg is 26,000m from a second asteroid with a
mass of 3.0x1012 kg.
Calculate the gravitational force between the two asteroids.
Answer:
F₁₋₂ = 1.036*10⁻⁵ [N]
Explanation:
In order to solve this problem, we must use the law of universal gravitation, which can be defined by means of the following expression.
[tex]F_{1-2}=G*\frac{m_{1}*m_{2}}{d^{2} }[/tex]
where:
F₁₋₂ = Force among the two bodies [N]
G = Universal gravity constant = 6.67 *10⁻¹¹ [N*m²/kg²]
m₁ = mass of the first body = 3.5*10 [kg]
m₂ = mass of the second body = 3*10¹² [kg]
d = separation distance = 26000 [m]
Now replacing:
[tex]F_{1-2}=6.67*10^{-11}*\frac{3.5*10*3*10^{12} }{26000^{2} } \\F_{1-2}=1.036*10^{-5}[N][/tex]
A prospector finds himself holding his bag of gold and standing in the middle of a large pond of frictionless ice. Use the Law of Conservation of Momentum to explain how he can get to the side before he freezes
Answer:
Explanation:
He can not walk on the ice because ice is frictionless . But he can move to shore or side using law of conservation of momentum . He will throw the bag of gold towards the side opposite to shore . This will create a motion in himself in opposite direction according to law of conservation of momentum.
Let m and M be mass of bag and prospector , v and V be velocity created in bag and prospector after throw of bag . Initially , both bag and prospector were at rest so initial momentum = 0 . Final momentum of both = mv - MV .
negative sign is due to their opposite motion .
According to law of conservation of momentum
MV - mv = 0
MV = mv
In this way he can create motion in himself to move to side .
A 2000-kg car moving with a speed of 20 m/s collides with and sticks to a 1500-kg car at rest at a stop sign. Show that because momentum is conserved in the rest frame, momentum is also conserved in a reference frame moving with a speed of 10 m/s in the direction of the moving car.
Answer:
13.33m/s
Explanation:
Given data
m1= 2000kg
u1= 20m/s
m2= 1500kg
u2= 0m/s
v1= 10m/s
Required
The speed of the sticks
We know that from the expression for the conservation of momentum
m1u1+m2u2= m1v1+m2v2
2000*20+1500*0=2000*10+1500*v2
40000=20000+1500v2
collect like terms
40000-20000= 1500v2
20000= 1500v2
v2= 20000/1500
v2= 13.33 m/s
Hence the velocity of the sticks is 13.33m/s
Suppose a forklift hoists a container weighing 2670 Netwons up from
ground level, setting it down on aloading dock 4.5 meters above ground
level. How much work was done by the forklift in this maneuver?
Answer:
12,015JoulesExplanation:
Work is said to be done when the force applied to an object cause it to move over a distance.
Workdone = Force * Distance
Given
Force = 2670 N
Distance = 4.5 meters
Substitute the given values
Work done = 2670 * 4.5
Workdone = 12,015Joules
Hence the amount of work done by the forklift is 12,015Joules
3. A soccer player applies an average force of 180 N during a kick. The kick accelerates a .45 kg soccer ball from rest to a speed of 18 m/s. What is the impulse imparted to the ball
Answer:
8.1Ns
Explanation:
Impulse is expressed as the product of Force and time
Impulse = Ft
F is the force = 180N
Get the time using the equation of motion
v = u+at
18 = 0+F/m(t)
18 = 180/0.45(t)
18 = 400t
t = 18/400 secs
Recall that;
Impulse = Ft
Impulse = 180×18/400
Impulse = 8.1Ns
Hence the impulse imparted to the ball is 8.1Ns
can someone give me a 5 day fitness plan with all the reps and sets for 3 only and 4 exercises a day
Answer:
Classic 5 Day Split
Day 1 – Chest
Day 2 – Legs
Day 3 – Rest
Day 4 – Back
Day 5 – Arms
Day 6 – Shoulders
Day 7 – Rest
Upper Lower Push Pull Legs
Day 1 – Upper
Day 2 – Lower
Day 3 – Rest
Day 4 – Push
Day 5 – Pull
Day 6 – Legs
Day 7 – Rest
5 Day Split Variation
Day 1 – Chest
Day 2 – Legs & Shoulders
Day 3 – Back
Day 4 – Biceps & Triceps
Day 5 – Core & Cardio
Day 6 – Rest
Day 7 – Rest
Explanation:
Marvin Martian is standing on planet Potatoine.
Potatoine has the following physical data:
Radius: 6.4x106 m
Mass: 2.0x1024 kg
If Marvin's mass is 35 kg, calculate his weight on Potatoine.
Answer:
W = 113.98 N
Explanation:
Given that,
Radius of Potatoine[tex]R=6.4\times 10^6\ m[/tex]
Mass of Potatoine, [tex]M=2\times 10^{24}\ kg[/tex]
Mass of Marvin, m = 35 kg
We need to find his weight on Potatoine. Weight of an object is given by :
W = mg
g is acceleration due to gravity, [tex]g=\dfrac{GM}{R^2}[/tex]
So,
[tex]W=\dfrac{GMm}{R^2}\\\\W=\dfrac{6.67\times 10^{-11}\times 35\times 2\times 10^{24}}{(6.4\times 10^6)^2}\\\\W=113.98\ N[/tex]
So, his weight on Potatoine is 113.98 N.
Using the diagram to the right to answer question # 18. Fig shows a ball fired horizontally from a cannon while simultaneously another is dropped from the same height. Which best describes what happens to these objects?
The one dropped vertically will reach the ground first
The one shot out of the cannon will reach the ground first
They will both reach the ground at the same time
The one shot out of the cannon will keep traveling to the right forever.
If you exert a force of 10.N to lift a box over 1 m how much work do you do?
5
20
10
Answer:
The work done is 10 Joules
Explanation:
Mechanical Work
It is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being the force vector and the displacement vector, the work is calculated as:
[tex]W=\vec F\cdot \vec s[/tex]
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
If a force of F=10 N is used to lift a box over a distance of s=1 m, the work done is:
W = 10 N * 1 m
W = 10 J
The work done is 10 Joules
A tank is is half full of oil that has a density of 900kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 for g and 3.14 for . Round your answer to three significant digits.)
Image of the tank has been attached.
From online sources, we will use radius r = 9 meters with a spout of height h = 3 meters.
Answer:
W = 75800 KJ
Explanation:
Let's assume that we inscribe a cylinder which is x units from the center of the sphere and also has a height denoted by ∆x.
Now, At the center of the sphere with radius r, the equation of the sphere is given as:
x² + y² + z² = r².
Now, at the point location where the cylinder is x units from the center point, the width(y) of the sphere will be gotten as:
0² + y² + x² = 9²
y² + x² = 81
y² = 81 - x²
Thus;
y = √(81 - x²)
So y = r is the radius of the cylinder.
Thus; volume of the cylinder is given as:
V = πr²h
∆V = π(81 - x²)∆x
Integrating, we have;
V = π(81 - x²)
The weight of the water is given as:
F = mg
We know that density is;
ρ = m/V
So, m = ρV
Thus;
F = ρVg
F = (900)[π(81 - x²)](9.8)
F = 8820π(81 - x²)
Work needed to move this water up is;
W = Fd
The water will move up x to units to the center which is 9 units up to the top of the sphere, and 3 units to get to the top of the spout. Thus, d = 9 + 3 + x = 12 + x
Thus;
W = 8820π(81 - x²)(12 + x).
Due to the fact that x varies from -9 to 0 at the bottom half of the sphere, the required work will be;:
W = ∫8820π(81 - x²)(9 + x)dx (from x = -9 to 0)
Using online integral calculator, we have;
W = 8820π × 2733.75
W = 75749.061 KJ
To 3 significant figures = 75800 KJ
A cruise ship can accelerate at 0.01 m/s2, if it starts from rest how long does it take
to reach a speed of 25 km/h? How long would it take if it started from a speed of
2.0 m/s?
Answer:
t = 8.24 [min]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
Vf = final velocity = 25 [km/h]
Vo = initial velocity = 2 [m/s]
a = acceleration = 0.01 [m/s²]
t = time [s]
Now we must convert the speed from kilometers per hour to meters per second.
[tex]25[\frac{km}{h} ]*[\frac{1h}{3600s}]*[\frac{1000m}{1km} ]=6.94[m/s][/tex]
Now replacing:
[tex]6.94=2+0.01*t\\t=494 [s]\\or\\t=8.24[min][/tex]
Equal amounts of heat are added to equal masses of the four substances
listed in the table. All four substances are initially at room temperature. Which
of the substances will have the highest increase in average molecular kinetic
energy?
Substance
air
glass
plastic
wood
Specific heat capacity (kJ/kg•°C)
1.01
0.84
2.60
1.68
A. Glass
B. Air
O O O O
C. Plastic
D. Wood
Answer:
the answe is letter c.plastic
A ball is dropped from the roof of a building. Points A, B, C, and D in the diagram below represent positions of the ball as it falls. At which position will the ball have the greatest kinetic energy?
Answer:
C. C
Explanation:
The ball will have its greatest kinetic energy just before it touches the ground which is at point C.
Kinetic energy of a body is the energy due to the motion of the body. As a body moves and its speed increases as a result of acceleration, then the kinetic energy will increase more.
As the body starts from rest, at point A, through B and C, the velocity increases drastically due the pull of the earth.
So, point C will show the greatest velocity and hence the most kinetic energy by the body.
The weight of an object at the surface of Earth is 90 N. What is its weight at a distance 2R from the surface of Earth
Answer:
The weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].
Explanation:
First of all, we need to find the acceleration of gravity at 2R. Using the gravitational force equation
[tex]F=G\frac{mM}{R^{2}}[/tex]
Where:
M is the mass of the earth
m is the mass of the object
G is the gravitational constant
R is the radius of the earth
We can equal the gravitational force with the second Newton's law (F=ma)
[tex]F=G\frac{mM}{R^{2}}[/tex]
[tex]mg=G\frac{mM}{R^{2}}[/tex]
We know the weight at the earth surface is 90 N, which means:
[tex]90=G\frac{mM}{R^{2}}[/tex]
Now, we have the same equation in the case of 2R as a distance from the surface of the object. Let's remember we need to use the distance from the center of the mass of the earth, so in this case, will be 3R.
[tex]F'=G\frac{mM}{(3R)^{2}}[/tex]
[tex]F'=G\frac{mM}{9R^{2}}[/tex]
[tex]F'=\frac{1}{9}G\frac{mM}{R^{2}}[/tex]
Using the above equation we have:
[tex]F'=\frac{1}{9}90[/tex]
[tex]F'=\frac{90}{9}[/tex]
Therefore, the weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].
I hope it helps you!
Which stimulus increases blood glucose levels?
Time between meals.
Body cells taking up glucose.
Consuming food.
