which is perpendicular to the line x-2y=2

Answer:

2:4

3:6

4:8

Step-by-step explanation:

Step-by-step explanation:

wow, how complicated can one phrase this ...

the point being :

1 ft = 12 in and vice versa (1 in = 1/12 ft)

so, any measurements given in feet but needed in inches need to be multiplied by 12.

and any measurements given in inches but needed in feet need to be divided by 12.

so,

3.5 ft = 3.5×12 = 7/2 × 12 = 7×6 = 42 in

27 in = 27/12 = 9/4 = 2 1/4 or 2.25 ft

Answer:When converting from inches to feet, the measurement in inches, m, of an object varies directly with its measurement in feet, f, with the constant of variation being 12.

What is the equation relating these two quantities?

✔ m = 12f

How many inches would a 3.5-foot object measure?

✔ 42

inches

How many feet would a 27-inch object measure?

✔ 2.25

feet

Step-by-step explanation:

Answer:

34 N.

Step-by-step explanation:

Net force in x direction = 65 cos 58

= 34 N.

Answer:

34N is the answer :)

Step-by-step explanation:

1) 4<7

×7 ×7

28<49

×6 ×6

168<294

×3 ×3

504<882

×10 ×10

5040<8820

2) 11>-2

+5 +5

16> 3

+3 +3

19>6

+-4 +-4

15>2

3) -4<-2

-6 -6

-10<-8

-8 -8

-18<-16

-2 -2

-20<-18

4) -8<8

÷-4 ÷-4

2<-2

÷-2 ÷-2

-1< 1

5) ~The affect of the inequality sign didn't change. If you add or subtract the same positive or negative number to both sides of an inequality or an equation, the inequality stays the same. If you multiply or divide both sides of an inequality or an equation by the same positive number, the inequality stays the same. This is because when manipulating inequalities there are rules this if a < b then a + c < b + c so we get a new number that replaces a and b yet the inequality symbol stays the same so a still is smaller than b.

Hope this helped you- have a good day bro cya)

Answer:

P

=

a

+

b

+

c

Step-by-step explanation:

Answer:

C = 8

Step-by-step explanation:

Rearrange the equation to make C the subject.

C - 12 = -4

Add 12 to both sides.

C - 12 + 12 = -4 + 12

C = -4 + 12

C = 8

Check it:

C = 8

So substitute the new found value into the original equation:

C - 12 = -4

8 - 12 = -4

-4 = -4

All good.

Answer:

C = 8

Hope this helps!

Step-by-step explanation:

C - 12 = -4

C - 12 + 12 = -4 + 12    ( Add both sides by 12 )

C = 8      ( Simplify )

Answer:

1

Step-by-step explanation:

5/5=1

Answer:

4/5

Step-by-step explanation:

You move up four on the y-axis and over 5 on the x-axis and it would meet the next point

Hope this Helps

Answer:

x = -2

Step-by-step explanation:

Add 10 to both sides of the equation

x−10=−12

−10+10=−12+10

Simplify

Solution:

x= -2

Answer:

6

Step-by-step explanation:

In equilateral triangle, all the sides are congruent.

3x - 6 = 12

Add 6 to both sides

3x = 12 + 6

3x = 18

Divide both sides by 3

x = 18/3

x = 6

Answer: f(x) = 1.19x, where f(x) is the total cost, and x is the cost per bottle

Cost of 15 bottles: $17.85

Step-by-step explanation:

This question describes a straightforward relation between cost per bottle, and cost for all the bottles.  As such, simply equate one variable to the value of one bottle, and f(x) as the value of every bottle.

Hope it helps :) and let me know if you want me to elaborate.

P.S. f(x) can simply be substituted for "y"

Let

no of bottles be x

.The function is given by

[tex]\\ \sf\longmapsto f(x)=1.19x[/tex]

Now

Cost:-

[tex]\\ \sf\longmapsto f(15)[/tex]

[tex]\\ \sf\longmapsto 1.19(15)[/tex]

[tex]\\ \sf\longmapsto 17.89[/tex]

Answer:

140

Step-by-step explanation:

∫P=700

∫T=2

∫R=10% after a few calculating you get 140.....the answer is right just sorry for my bad explaining

Answer: [tex]196m^2[/tex]

Step-by-step explanation:

since it's a cube the floor is in square shape

Answer:

SINCE ITS A CUBE OF FLOOR SHAPE.

=4

=169m²Ans.

[tex] \large\underline{\sf{Solution-}}[/tex]

Given Logarithmic expression is

[tex]\rm \longmapsto\: log_{ \sqrt{3} }(729) [/tex]

Let first factorize 729

[tex]\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{3}}}&{\underline{\sf{\:\:729 \:\:}}}\\ {\underline{\sf{3}}}& \underline{\sf{\:\:243 \:\:}} \\\underline{\sf{3}}&\underline{\sf{\:\:81\:\:}} \\ {\underline{\sf{3}}}& \underline{\sf{\:\:27 \:\:}} \\ {\underline{\sf{3}}}& \underline{\sf{\:\:9\:\:}}\\\underline{\sf{}}&{\sf{\:\:3 \:\:}} \end{array}\end{gathered}\end{gathered}\end{gathered}[/tex]

So,

[tex] \purple{\rm \longmapsto\:729 = 3 \times 3 \times 3 \times 3 \times 3 \times 3}[/tex]

[tex] \purple{\rm \longmapsto\:729 = {3}^{6} }[/tex]

[tex] \purple{\rm \longmapsto\:729 = {( [{ \sqrt{3} ]}^{2}) }^{6} }[/tex]

[tex] \purple{\rm \longmapsto\:729 = {( \sqrt{3} )}^{12}}[/tex]

So,

[tex]\rm \longmapsto\: log_{ \sqrt{3} }(729) [/tex]

can be rewritten as

[tex]\rm \:  =  \: log_{ \sqrt{3} }( {( \sqrt{3}) }^{12} ) [/tex]

We know,

[tex] \purple{\rm \longmapsto\:\boxed{\tt{ log_{a}( {a}^{x} ) \: = \: x \: }}}[/tex]

So, using this identity, we get

[tex]\rm \:  =  \: 12[/tex]

Hence,

[tex] \green{\rm\implies \:\boxed{\tt{ \: \: log_{ \sqrt{3} }(729) \: = \: 12 \: \: }}}[/tex]

Answer:

hope this helps

Answer:

A

Step-by-step explanation:

The salary differences are found to be statistically significant.

Statistical significance refers to the claim that a result from data generated by testing or experimentation is not likely to occur randomly or by chance but is instead likely to be attributable to a specific cause.

It is given that

Average 6 foot plus male’s salary = $55,000

Average male’s salary under 6 foot tall = $47,000

p-value = 0.45

As the p-value 0.45 is greater than p-value 0.05,

So statement men over 6 feet tall earn more than men under 6 feet is acceptable, we can say that salary differences are statistically significant.

Therefore, The salary differences are found to be statistically significant.

To get more about statistical significance visit:

https://brainly.com/question/15848236

Answer:

The blur of the photo I do not understand sorry

Step-by-step explanation:

ty for the points

[tex]\large\underline{\sf{Solution-}}[/tex]

Given:

[tex] \rm \longmapsto x = a \sin \alpha \cos \beta [/tex]

[tex] \rm \longmapsto y = b \sin \alpha \sin \beta [/tex]

[tex] \rm \longmapsto z = c\cos \alpha[/tex]

Therefore:

[tex] \rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta [/tex]

[tex] \rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta [/tex]

[tex] \rm \longmapsto \dfrac{z}{c} = \cos \alpha[/tex]

Now:

[tex] \rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } [/tex]

[tex] \rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha [/tex]

[tex] \rm = 1[/tex]

Therefore:

[tex] \rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1[/tex]

Up 8 Units, Hope this helps :)

Answer:

What do you need me to do

Step-by-step explanation:

Answer: im pretty sure its 21 mi per gal

Step-by-step explanation:

Answer:

3n+1

Step-by-step explanation:

2n-3+n+4=3n+1

...............

Answer:

x > 3

Step-by-step explanation:

Answer:

Infinite solutions

Step-by-step explanation:

If you look at the equation, you will see that if you multiply everything by two (On the 1st equation), you get the 2nd equation. This means that the lines are the same, so infinite solutions.

Step-by-step explanation:

infinitely many solutions :)

Answer:

5, -5

hope this helps

Answer:

Train to BaDussy

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

Given function is

[tex]\rm \longmapsto\:f(x) = \dfrac{1}{ \sqrt{ |cosx| + cosx} } [/tex]

Now,

[tex]\rm \longmapsto\:f(x) \: is \: defined \: if \: |cosx| + cosx > 0[/tex]

We know,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |x| = \begin{cases} &\sf{ - x \: \: when \: x < 0} \\ \\ &\sf{ \: \: x \: \: when \: x \geqslant 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |cosx| + cosx = \begin{cases} &\sf{ \: \: 0 \: \: when \: cosx \leqslant 0} \\ \\ &\sf{ \: \: 2 \: cosx \: \: when \: cosx > 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\rm\implies \:f(x) \: is \: defined \: when \: cosx > 0[/tex]

So, from graph we concluded that cosx > 0 in the following intervals.

[tex]\begin{gathered}\boxed{\begin{array}{c|c} \bf cosx & \bf \: x \: \in \: \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf + ve & \sf \bigg( - \dfrac{\pi}{2} ,\dfrac{\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{3\pi}{2} ,\dfrac{5\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{7\pi}{2} ,\dfrac{9\pi}{2} \bigg) \end{array}} \\ \end{gathered}[/tex]

So, if we generalized this we get

[tex]\rm\implies \:cosx > 0 \: when \: x \: \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z[/tex]

Hence,

Domain of the function is

[tex]\red{\rm\implies \boxed{\tt{ \: x \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z}}}[/tex]

[tex]\textsf{More to know :-} \\[/tex]

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf T-eq & \bf Solution \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf sinx = 0 & \sf x = n\pi \: \forall \: n \in \: Z\\ \\ \sf cosx = 0 & \sf x = (2n + 1)\dfrac{\pi}{2}\: \forall \: n \in \: Z\\ \\ \sf tanx = 0 & \sf x = n\pi\: \forall \: n \in \: Z\\ \\ \sf sinx = siny & \sf x = n\pi + {( - 1)}^{n}y \: \forall \: n \in \: Z\\ \\ \sf cosx = cosy & \sf x = 2n\pi \pm \: y\: \forall \: n \in \: Z\\ \\ \sf tanx = tany & \sf x = n\pi + y \: \forall \: n \in \: Z\end{array}} \\ \end{gathered}\end{gathered}[/tex]

The common difference is the amount between each number in an arithmetic sequence.

For example, the sequence 4,7,10,13,... has a common difference of 3.

Answer:

16g + 12

Step-by-step explanation:

6(3g + 2) - 2g

18g + 12 - 2g

16g + 12