Which factor do 64x2 + 48x + 9 and 64x2 – 9 have in common?

The height of the rectangular prism is 3.1

[tex]6.9x=21.39[/tex]

[tex]21.39[/tex] ÷ [tex]6.9=3.1[/tex]

Sure hope this helps

Answer:

The formula for volume is V=l*w*h

(6×4×2)×2=96 cubic feet

Answer:

The winter evening settles down

With smell of steaks in passageways.

Six o'clock.

The burnt-out ends of smoky days.

And now a gusty shower wraps

The grimy scraps

Of withered leaves about your feet

And newspapers from vacant lots;

The showers beat

On broken blinds and chimney-pots,

And at the corner of the street

A lonely cab-horse steams and stamps.

And then the lighting of the lamps.

Alfred Tennyson - Summer Night

Alfred Tennyson was another poet who made great use of visual imagery. See if you can get a clear picture of the summer night he describes in this poem "Summer Night:"

Now sleeps the crimson petal, now the white;

Nor waves the cypress in the palace walk;

Nor winks the gold fin in the porphyry font:

The firefly wakens: waken thou with me.

Now droops the milk-white peacock like a ghost,

And like a ghost she glimmers on to me.

Now lies the Earth all Danaë to the stars,

And all thy heart lies open unto me.

Now slides the silent meteor on, and leaves

A shining furrow, as thy thoughts in me.

Now folds the lily all her sweetness up,

And slips into the bosom of the lake.

So fold thyself, my dearest, thou, and slip

Into my bosom and be lost in me.

William Wordsworth - I Wandered Lonely as a Cloud

Next is an excerpt from "I Wandered Lonely as a Cloud" by William Wordsworth. The first and last stanzas show a progression of the poet's emotions using visual imagery.

I wandered lonely as a cloud

That floats on high o'er vales and hills,

When all at once I saw a crowd,

A host, of golden daffodils;

Beside the lake, beneath the trees,

Fluttering and dancing in the breeze.

For oft, when on my couch I lie

In vacant or in pensive mood,

They flash upon that inward eye

Which is the bliss of solitude;

And then my heart with pleasure fills,

And dances with the daffodils.

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Theodore Rothke - My Papa’s Waltz

This famous poem by Theodore Rothke is an excellent example of olfactory and tactile imagery with plenty of visual imagery thrown in for good measure. The effect is powerful.

The whiskey on your breath

Could make a small boy dizzy;

But I hung on like death:

Such waltzing was not easy.

We romped until the pans

Slid from the kitchen shelf;

My mother’s countenance

Could not unfrown itself.

The hand that held my wrist

Was battered on one knuckle;

At every step you missed

My right ear scraped a buckle.

You beat time on my head

With a palm caked hard by dirt,

Then waltzed me off to bed

Still clinging to your shirt.

William Carlos Williams - This Is Just to Say

"This Is Just to Say" is an amazing example of gustatory imagery or imagery involving taste. There’s more going on beneath the surface of this poem, but the vivid description of taste draws the reader in.

I have eaten

the plums

that were in

the icebox

and which

you were probably

saving

for breakfast

Forgive me

they were delicious

so sweet

and so cold

Step-by-step explanation:

Answer:

x≤5p

Step-by-step explanation:

40/8=5 Kaitlin can buy UP TO 5 pounds of candy at $8/pound. So she will buy less than or equal to 5 pounds

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

Use the Intersecting Chords Theorem to solve for x:

[tex]\overline{\rm TP}\cdot\overline{\rm PR}=\overline{\rm QP}\cdot\overline{\rm PS}\\\\(x+3)(x)=(6-x)(2x)\\\\x^2+3x=12x-2x^2\\\\3x^2+3x=12x\\\\3x^2-9x=0\\\\3x(x-3)=0\\\\x=0,\: x=3[/tex]

The solution [tex]x=0[/tex] however, does not make sense because the chords have lengths, so [tex]x=3[/tex] is the only sensible answer.

Intersecting Chords Theorem States:

As Length cannot be zero or negative here. x = 3

Answer:

$1525

Step-by-step explanation:

Area of hexagon

Now

area of upper 6 triangles

Total area

Answer:

770 m²

Step-by-step explanation:

The surface area of a regular pyramid comprises the area of the base (regular polygon) and the area of each of the slanted sides (triangles).

Apothem:  The line segment from the center of the regular polygon to the midpoint of one of its sides.

Area of the base

The base of the prism is a regular polygon with 6 sides (hexagon).

[tex]\textsf{Area of a regular polygon}=\sf \dfrac{1}{2}nsa[/tex]

where:

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Base area}& =\sf \dfrac{1}{2}\cdot 6 \cdot 12 \cdot 6\sqrt{3}\\ & = \sf 216\sqrt{3}\:m^2\end{aligned}[/tex]

Area of one side

The sides of the regular pyramid are congruent triangles.

[tex]\textsf{Area of a triangle} = \sf \dfrac{1}{2} \times base \times height[/tex]

Given:

Substitute the given values into the formula:

[tex]\implies \textsf{Area of a triangle} = \sf \dfrac{1}{2} \times 12 \times 11=66\:m^2[/tex]

Total Surface Area

[tex]\begin{aligned}\implies \textsf{Total Surface Area} & = \sf base \: area + 6 \times side \: area\\& = \sf 216\sqrt{3}+6 \cdot 66\\& = \sf 216\sqrt{3}+396\\& = \sf 770\:m^2\:(nearest\:whole\:number)\end{aligned}[/tex]

Answer:

9000

Step-by-step explanation:

1,2,3,4 round down

5,6,7,8,9 round up

Look at the 100's column for rounding to the nearest 1000

Step-by-step explanation:

it seams like this question is wrong

3rd

Step-by-step explanation:

i am not sure though so confirm it

Answer:

Its the THIRD choice.

Step-by-step explanation:

The values in ascending order are:

6 6 7 9 11 14 15 15 17 19 21 23 23 23 28 31

So the median = (15+17)/2 = 16.

The lowest and highest values are 6 and 31.

The lower quartile is 10.

The upper quartile is 23.

Answer:

10y^2 + 39y + 35

Step-by-step explanation:

Simplify using FOIL

Answer:

300,000

Step-by-step explanation:

[tex]2000000 - 50000 = 150000[/tex]

[tex]150000 \times 2 = 300000[/tex]

Answer:

so far he has saved 27 dollars however he needs 33 more dollars

Step-by-step explanation:

okay so if it says "____ of x" you normally have to multiply (of is a hint)

so first lets see how much he saved

0.45(60) = 27

he saved 27 dollars so far. to find how much more he has to save, you have to do the amount he needs minus the amount he already has

sooo

60 - 27 = 33

uhhh im not sure what the graph table thing on the right is, but i hope this helps a little

edit: ohhhhh so in the table all you have to do is fill in the information. im sure u can do it, but if you still dont know how to just reply here and ill help!

The equation that represents the total area of the blueberry field will be y = 84x.

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Six workers are hired to harvest blueberries from a field.

Each is given a plot with an area of 84 square ft.

Then the equation that represents the total area of the blueberry field will be

Let x be the number of workers and y be the total area field. Then we have

y = 84x

Then the area of the total field will be

y = 84 (6)

y = 504 square ft

More about the linear system link is given below.

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Answer:

This was a nice way to spend my time :) how'd I do?

Step-by-step explanation:

Total: 6

1. +8

After stop 1, total is 14 people

2. +4, -2

After stop 2, total is 16 people

3. +15, -4

After stop 3, the total is 27 people

4. -8

Total # of people on the bus: 19

(A little voice in the back of my mind is telling me that I overthought this entire problem, and that the answer is just 6)

Answer:

the odds that it not blue is 9 /13 or .692

Step-by-step explanation:

Answer:

60th percentile = 23.5

Step-by-step explanation:

Put numbers in order from lowest to highest:

14, 14, 14, 15, 15, 15, 16, 18, 19, 21, 23, 23, 24, 24, 25, 25, 25, 26, 29, 29

Formula:

60th percentile = 60% x Total number of elements

We have 20 scores,

60th percentile = 60% x 20

                          = 0.60 x 20

                          = 12

the 60th percentile is the 12th number on the list

14, 14, 14, 15, 15, 15, 16, 18, 19, 21, 23, 23, 24, 24, 25, 25, 25, 26, 29, 29

The 60th percentile is between 23 and 24

23 + 24 / 2 = 23.5

Answer:

∠ FLW = 112°

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ FLW is an exterior angle of the triangle , then

∠ FLW = x + 32 , that is

2x - 48 = x + 32 ( subtract x from both sides )

x - 48 = 32 ( add 32 to both sides )

x = 80

Then

∠ FLW = 2x - 48 = 2(80) - 48 = 160 - 48 = 112°

Answer:

150 minutes

Step-by-step explanation:

30 × 5 = 150 minutes

I will help u so fast, first

you help me

can u answer this

some fanicial and environmental damages that have been made by cars.

please help me

this is exam

teacher giving us 10 minutes to discuss about and I am in washroom of school writing this

Answer:

Step-by-step explanation:

(9 + 3)/(2 - 2)= 12/0= undefined

Answer:

111.75 degrees

Step-by-step explanation:

EDF = cos^-1((b²+c²-a²)/2bc)

EDF = cos^-1((10.4²+19.6²-13.2²)/2(10.4)(19.6))

EDF = 111.75 degrees

Answer:

The correct answer is b)

Step-by-step explanation:

The required steps are explained below to convert the quadratic function into a perfect square.

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

Let the quadratic function be y = ax² + bx + c.

The first step is to take common the coefficient of x². We have

[tex]\rm y = a \left (x^2 + \dfrac{b}{a}x \right) + c[/tex]

Add and subtract the half of the square the coefficient of x,

[tex]\rm y = a \left (x^2 + \dfrac{b}{a}x + \dfrac{b^2}{4a^2} \right) - a \times \dfrac{b^2}{4a^2} + c[/tex]

Then we have

[tex]\rm y = a \left (x + \dfrac{b}{a} \right)^2 - \dfrac{b^2}{4a} + c[/tex]

These are the required step to get the perfect square of the quadratic function.

More about the parabola link is given below.

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[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{-15})\qquad (\stackrel{x_2}{14}~,~\stackrel{y_2}{r}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{r}-\stackrel{y1}{(-15)}}}{\underset{run} {\underset{x_2}{14}-\underset{x_1}{2}}}~~ = ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{4}}\implies \cfrac{r+15}{12}~~ = ~~\cfrac{3}{4}\implies r+15 = \cfrac{12\cdot 3}{4} \\\\\\ r+15=9\implies \boxed{r=-6}[/tex]

The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.

The first step is to determine the volume of the cylinder.

Volume of the tub = πr²h

Where:

3.14 x 9² x 20 = 5086.8 in³

The second step is to determine the volume of the 6 balls.

Volume of a sphere= 4/3πr³

r = diameter / 2 = 8/2 = 4 inches

6 x (3.14 x 4/3 x 4³) = 1607.68 in³

Volume that remains in the tub = 5086.8 in³  -  1607.68 in³ = 3479.12 in³

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The provided log can be written as sum of (1/5)log₃(x) + log₃(y) after using the log property.

It is another way to represent the power of numbers, and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.

[tex]\rm a^b = c\\log_ac =b[/tex]

We have:

[tex]= \rm log_3(\sqrt[5]{x} . y)[/tex]

As we know:

log(mn) = logm + logn

logmⁿ = nlogm

[tex]= \rm log_3({x^{\dfrac{1}{5}}} . y)\\\\= \rm log_3({x^{\dfrac{1}{5}}} )+log_3 (y)\\\\= \rm \dfrac{1}{5}log_3({x^{}} )+log_3 (y)\\\\[/tex]

Thus, the provided log can be written as sum of (1/5)log₃(x) + log₃(y) after using the log property.

Learn more about the Logarithm here:

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Answer:

x = 42

Step-by-step explanation:

a striaght line = 180°

z + y + x = 180

103 + 135 + x = 180

138 + x = 180

subtract 138 from both sides

138 - 138 + x = 180 - 138

x = 42

Answer:

what shape it is

Step-by-step explanation:

wat is the shape

Answer:

  see attached

Step-by-step explanation:

We prefer to solve these by rewriting the equations to the form f(x) = 0, then having a graphing calculator show us the x-intercepts of f(x). This is illustrated in the second attachment.

__

The applicable rules of logarithms are ...

We can apply these rules to the given expressions to solve for x algebraically.

__

Taking antilogs, we have ...

  (x -1)(5x) = 10^2 = 100

  x(x -1) = 20 . . . . . . . . . . . divide by 5

  x² -x -20 = 0 . . . . subtract 20, put in standard form

  (x -5)(x +4) = 0 . . . . factor

  x = 5  or  x = -4 . . . . . . the latter is an extraneous solution

  x = 5 only

__

Taking antilogs, we have ...

  x +5 = (x +1)(x -1)

  x² -x -6 = 0 . . . . . . . subtract (x+5), write in standard form

  (x -3)(x +2) = 0 . . . . factor

  x = 3  or  x = -2 . . . . . . the latter is an extraneous solution

  x = 3 only

__

Taking natural logarithms, we have ...

  x² = 4x +5

  x² -4x -5 = 0 . . . . . write in standard form

  (x -5)(x +1) = 0 . . . . factor

  x = 5  or  x = -1 . . . . values that make the factors zero

__

Taking antilogs, we have ...

  5x² +2 = x +8

  5x² -x -6 = 0 . . . . . write in standard form

  (5x -6)(x +1) = 0 . . . . factor

  x = 6/5  or  x = -1 . . . . values that make the factors zero

_____

Additional comment

A solution is extraneous when it does not satisfy the original equation. Here, solutions are extraneous because they make the argument of the log function be negative in the original equation. The log function is not defined for negative arguments. (Actually, it gives complex values for negative arguments.)

We could have gone to the trouble to determine the applicable domain of each of the log equations. It is easier to (a) use a graphing calculator, or (b) test the solutions found.