Mathematics High School

Which expressions are equivalent?

Answers

Answer 1

Answer:

3x -7y = -7y+3x

Step-by-step explanation:

3x is positive and 7y is negative

We can reverse the order

3x -7y = -7y+3x

Answer 2

3x - 7y and 7y + 3x bc they're interchangeable

Related Questions

please help me on this

Answers

Answer:

it is the answer on the top

In Debi's Girl Scout troop, of the girls have brown eyes, of the girls have blue eyes, and of the girls have hazel eyes. What fraction of the
either brown eyes or hazel eyes? [Note: Write your answer in simplest form.]
Save and Exit
Next
Subm
O
-IN

Answers

5/6 girls have either blue or brown eyes. Since 2/9=4/18

And 11/18 + 4/18 = 15/18

You can simplify 15/18 to 5/6

What is the median of the data set represented by the plot?

Answers

Answer:

Step-by-step explanation:

It's in the middle of all the numbers

If you do need a more in-depth explanation just comment under here and I'd be happy to show you how I did it :)

Amanda invited 5 friends over for a sleepover. They decided to bake cupcakes. By the end of the night they had baked 6 dozen cupcakes. If the girls planned to use a third of the cupcakes for a bake sale and wanted to split the rest equally, how many would each girl receive?

Answers

correct me if i’m wrong but i think the answer is 4.8

reasoning: a dozen is 12 so 6 times 12 is 72 and a third of that is 24 so i did 24 divided by 5 (24/5) and got 4.8

Answer:

Step-by-step explanation:

After saving 1/3 of 6 dozen for the bake sale, the girls had 2/3 of 6 dozen left to split between them. Each of the 6 girls would receive 2/3 of 1 dozen, or 12×2/3 = 8 cupcakes.

Choose the function that represents the data in the table.
х
0
-3
1
-1
2
5
3
15
4
29
5
47
y
Oy - 3
0 y= 2* – 3
O y = 2x - 3
O y = 2x2 – 3

Answers

Answer:

Option (D): f(x) = 2x^2 – 3

Step-by-step explanation:

Math.

The function that represents the data in the table is y=2x²-3

What is a function?

A relation is a function if it has only One y-value for each x-value.

Let us check the function of the given data by plugging any ordered pair in the given functions

Let us take a point (1, -1) to check each function

(a) y=x/2-3

-1= 1/2-3

-1=-5/2

So y=x/2-3 is not the function

(b) y=2ˣ-3

-1=2-3

-1=-1

Now let us check for other point

5=4-3

5=1

This function is not satisfied for all points

-1=-1

For point (2, 5)

5=-1

This function is not satisfied for all points

(d) y=2x²-3

-1=2-3

-1=-1

Now 5=8-3

5=5

Hence, the function that represents the data in the table is y=2x²-3

To learn more on Functions click:

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Как это решать (отмечено красным)

Answers

Answer:

it’s 3 because chinese had the era.

Step-by-step explanation:

Please show me the steps of solving this and the answer 2n² +3n-9

Answers

Answer: n=-3 and n=3/2

Step-by-step explanation:

To solve the expression, we want to find the values of n. Since there are no common factors in 2, 3, -9, we directly multiply the "a" and "c" values.

2×(-9)=-18

This means, we want to find two numbers that multiply to -18 and adds to 3. This can also be known as the cross method.

We will find that 6 and -3 multiply to -18, and adds to 3.

In our box method, we want to find the common factors.

|2n²|6n|

|-3n|-9|

Note: Just pretend the lines line up and form a square box, with a term in each box.

After finding that is in common between the boxes, we get (n+3)(2n-3)=0

To solve, we set each factor equal to 0.

n+3=0

n=-3

2n-3=0

2n=3

n=3/2

Sort each type of expense into the category where it fits best.
clothing expenses
fixed expenses
variable expenses
mortgage expenses
rent
food expenses
loan payments

Answers

The categories that the expenses best fit into are:

fixed expenses :

mortgage expensesrentloan payments

variable expenses:

clothing expensesfood expenses

What are fixed and variable expenses?

Fixed expenses are the expenses that are constant. They do not vary with the quantity bought. Variable expenses are the expenses that vary. More quantities can be bought and this increases the expenses.

To learn more about fixed cost, please check: https://brainly.com/question/27127934

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Solve the following systems of equations:
[tex]1.& \left\{\begin{matrix} 5x-3y-z=1&\\ x+4y-6z=-1& \\ 2x+3y+4z=9& \end{matrix}\right.\\ \ \\ 2.& \left\{\begin{matrix} x+y=7& \\ x\times y=12& \end{matrix}\right.\\ \ \\ 3.& \left\{\begin{matrix} x^2+y^2=169& \\ x+y=17& \end{matrix}\right.\\ \ \\ 4. & \left\{\begin{matrix} y^2-2y+1=x & \\ \sqrt{x}+y=5 & \end{matrix}\right. \end{align*}[/tex]

Answers

[tex]\large\displaystyle\text{$\begin{gathered}\sf 1) \ \left\{\begin{matrix} 5x-3y-z=1&\\ x+4y-6z=-1& \\ 2x+3y+4z=9& \end{matrix}\right. \end{gathered}$}[/tex]

The coefficient matrix associated with the system is constructed and the columns and rows are reduced.

[tex]\left ( \begin{array}{ccc|c} 5 & -3 &-1 &1\\ 1 & 4 & -6 &-1\\ 2 & 3 & 4 & 9 \end{array} \right ) \begin{array}{c} \xrightarrow[\textup{F}_3- 2\textup{F}_2]{\textup{F}_1 - 5\textup{F}_2} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & -5 &16 & 11 \end{array} \right )\\ \ \\ \ \\ \begin{array}{c} \xrightarrow[]{23\textup{F}_3 - 5\textup{F}_1} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & 0 & 223 & 223 \end{array} \right )[/tex]

So, z=1. Translating the last matrix to the associated system of equations, we have that x=1, y=1, since:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \begin{align*} y&=\dfrac{6-29}{-23}=\dfrac{-23}{-23}=1\\ x = -1+6-4=1 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{2) \ \left\{\begin{matrix} x+y=7& \\ x\times y=12& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ y=7-x \quad \Longrightarrow \quad 12=x(7-x)=7x-x^2 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ 0=x^2-7x+12=(x-4)(x-3); } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{3) \ \left\{\begin{matrix} x^2+y^2=169& \\ x+y=17& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ y=17-x \quad \Longrightarrow \quad 169=x^2 +(17-x)^2=x^2+x^2 -34x+289 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ 0=2x^2-34x+120=2(x^2-17+60)=2(x-12)(x-5); } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{4 \ \left\{\begin{matrix} y^2-2y+1=x & \\ \sqrt{x}+y=5 & \end{matrix}\right. } \end{gathered}$}[/tex]

Substitute the expression that represents x into the second equation. Then both sides of the equation are squared and solved.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ \sqrt{y^2-2y+1}+y=5\quad \Longrightarrow\quad \left ( \sqrt{y^2-2y+1} \right )^2=(5-y)^2 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y^2-2y+1=y^2-10y+25\quad \Longrightarrow\quad 8y=24; } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y=6 \qquad x=4 } \end{gathered}$}[/tex]

What is the volume of this cylinder?
Use ≈ 3.14 and round your answer to the nearest hundredth.
18 in
19 in
cubic inches
I

Answers

Answer:

V = 19329.14 cubic inches

Step-by-step explanation:

Volume of cylinder

[tex]V = \text{area of circle} \times \text{height}\\V = \pi r^2 \times h[/tex]

r ... radius of circle
h ... height of cylinder

Given information:

r = 18 in

h = 19 in

Now let's substitute the values in formula.

[tex]V = \pi r^2 \times h \\V = \pi (18)^2 \times 19\\V = 6156\pi\\V = 6156 \times 3.14\\V = 19329.84 \text{ in}^2[/tex]

In the figure, ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If ∠DBC = 55° and ∠BAC 45°, Find ∠BCD.