Which comparison is correct?
0.29<0.279
1.32<1.319
0.420>0.42
3.544>3.455

Answers

Answer 1

Answer:

3.544>3.455

Step-by-step explanation:

This is because if you look at the numbers .5 is greater than (>) .4


Related Questions

PLEASE HELP ME 100 POINTS AND BRAINLY!!!

Answers

Answer:

1. 220 minutes

2. $45.6

Step-by-step explanation:

A rectangle is 4 ft long and 2 ft wide. find its area in square inches.​

Answers

[tex]\text{Area of rectangle} = \text{length} \times \text{width}\\\\~~~~~~~~~~~~~~~~~~~~~~~=4 ~\text{ft}~\times ~2 ~\text{ft}\\\\~~~~~~~~~~~~~~~~~~~~~~~=8~ \text{ft}^2\\\\~~~~~~~~~~~~~~~~~~~~~~~=1152~\text{in}^2[/tex]

ANSWER QUICK WITH THE ANSWER FOR EXTRA POINTS ⭐️⭐️⭐️⭐️!

Answers

your answer would be, B.


I NEED help ASAP!!!!!!!

Answers

Step-by-step explanation:

Step 1: Plot the points

L(1,2)

M(0,-1)

J(1,-2)

K(2,-1)

Step 2: Multiply each point by 5.

and record thise points so we have

L(5,10)

M(0,-5)

J(5,-10)

K(10,-5)

Step 3: Plot those points.

Answer:

Graph attached below.

Step-by-step explanation:

After dilation of 5, the new coordinates follow the rule :

(x, y) ⇒ (5x, 5y)The points are :J' = (1 x 5, -2 x 5) = (5, -10)K' = (2 x 5, -1 x 5) = (10, -5)L' = (1 x 5, 2 x 5) = (5, 10)M' = (0 x 5, -1 x 5) = (0, -5)

Please Helpp!!!! Pythagorean theorem

Answers

Answer:

12.6 = c

Step-by-step explanation:

The Pythagorean therom is a^2 + b^2 = c^2

We already know 2 varibles (12 and 4) so we can just plug them in.

12^2 + 4^2 = c^2

144 + 16 = c^2

160 = c^2

[tex]\sqrt{160}[/tex] = [tex]\sqrt{c^2}[/tex]

12.6 = c

Hope this helps :)

Roy and Stefan went to a computer fair with the same amount of money. After Roy spend $850 on a notebook and Stefan spend $300 on a printer, Stefen had three times as much money left as Roy.How much money did each of them have at first?

Answers

Answer:

$1125

Step-by-step explanation:

Check the attachment.

Find two positive numbers whose product is 192 and their sum is a minimum.

Answers

Answer:

Since we want a positive number, x = 24.  y = 192/x = 8

Step-by-step explanation:

Let x and y be the two positive numbers.

-  Their product is 192: x*y = 192

-  the sum of the first plus 3 times the second is a minimum:  x + 3y

From the first equation, y = 192/x.  Substitute that into the second equation:

x + 3y = x + 3(192/x) = x + 576/x

Now take the first derivative, set it to zero, and solve for x:

d(x + 576/x)/dx = 1 - 576/x2

0 = 1 - 576/x2

0 = x2 - 576                         [Multiplied both sides by x2]

576 = x2

√576 = √x2

±24 = x

Since we want a positive number, x = 24.  y = 192/x = 8

As a check, the factors of 192 are 192*1, 96*2, 48*4, 24*8, 16*12

192 + 3*1 = 195

96 + 3*2 = 102

48 + 3*4 = 60

24 + 3*8 = 48

16 + 3*12 = 52

24 + 3*8 is indeed the minimum

How much on average did she make a week, if she worked 15 hours a week at $11/hour? (Rounded to the nearest whole dollar. Do NOT put the dollar sign.)

Answers

Answer:

1265 i think

Step-by-step explanation:

add 11 15 times

Answer:165

Step-by-step explanation:

help please!!!!!!!!!

Answers

Answer:

Alright, so, the ratio is 2:5

In total, there are 7

So, 56/7=8

8x2=16

8x5=40

So after moving 2 students,

14 on the van, 42 on the bus

(you can use the true/false now)

Answer:

1. False

2. True

3. True

4. False

Step-by-step explanation:

Going to the museum:

Total: 56 students

van:bus = 2:5

2x + 5x = 56

7x = 56

x = 8

2x = 16

5x = 40

16 students go by van

40 students go by bus

40 - 16 = 24

Going back to school:

14 students go by van

42 students go by bus

van:bus = 14/42 = 1:3

42 - 14 = 28

Questions:

1. False

2. True

3. True

4. False

how i do this? help pls

Answers

Factor the left side of the equation.

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

Set the first factor equal to 0.

Set the next factor equal to 0 and solve.

Set the next factor equal to 0 and solve.

The final solution is all the values that make

Find the exact value, without a
calculator.
30°
sin 15° sin
tan 15º =
2
cos 15° 30°
2
COS
II
[ ? ] - [
] + [
Enter

Answers

[tex]sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \qquad cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1-cos(30^o)}{2}}\implies \sqrt{\cfrac{1-\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2-\sqrt{3}}{2}~~}{2}}[/tex]

[tex]\sqrt{\cfrac{2-\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2-\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2-\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1+cos(30^o)}{2}}\implies \sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2+\sqrt{3}}{2}~~}{2}} \\\\\\ \sqrt{\cfrac{2+\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2+\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ sin\left( \frac{30^o}{2} \right)~~}{cos\left( \frac{30^o}{2} \right)}\implies \cfrac{~~\frac{\sqrt{2-\sqrt{3}}}{2} ~~}{\frac{\sqrt{2+\sqrt{3}}}{2}}\implies \cfrac{\sqrt{2-\sqrt{3}}}{2}\cdot \cfrac{2}{\sqrt{2+\sqrt{3}}} \\\\\\ \cfrac{\sqrt{2-\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \blacktriangleright \sqrt{\cfrac{2-\sqrt{3}}{2+\sqrt{3}}} \blacktriangleleft[/tex]

A line passes through the points (0, 6) and (–9, 9). What is its equation in slope-intercept form?

Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answers

Answer:

[tex]y = -\frac{1}{3} x + 6[/tex]

Step-by-step explanation:

Slope-intercept form: [tex]y = mx + b[/tex], where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept.

The formula to find the slope of a line is [tex]m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex].

1) Plug the coordinates into this [tex]m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex].

[tex]m = \frac{9 -6 }{-9 - 0 }[/tex]

2) Solve it. Simplify it if possible.

[tex]m = \frac{3 }{-9}[/tex]

Simplified: [tex]m = \frac{1 }{-3 }[/tex]

3) Plug the result into [tex]y = mx + b[/tex].

[tex]y = \frac{1}{-3} x + b[/tex]

4) Plug one of the points ([tex]x_{1}, y_{1}[/tex] or [tex]x_{2}, y_{2}[/tex]) into [tex]y = \frac{1}{-3} x + b[/tex] to find [tex]b[/tex].

[tex]6 = \frac{1}{-3}(0) + b[/tex]

[tex]6 = 0 + b[/tex]

[tex]6 - 0 = b[/tex]

[tex]6 = b[/tex]

5) Plug the result of [tex]b[/tex] into [tex]y = \frac{1}{-3} x + b[/tex].

[tex]y = \frac{1}{-3} x + 6[/tex]

The negative situated in the denominator can be genaralised to the fraction.

Therefore, [tex]y = -\frac{1}{3} x + 6[/tex].

Dinasur is spelled Dinasur change my mind

Answers

Answer:

I cannot change what is the truth

Step-by-step explanation:

attempt to change the truth would resulted in dinaur catastrophe

Please help me on Mathematics

✨Nonsense answer Report✨
✨Rude answer Report ✨

✨ Correct answer Brainlest ✨
✨ Complete answer Brainlest ✨

Answers

Answer:

1. 20 km/hr (60km / 3h)

2. 70 m/hr (170m / 2h)

3. 6.5 hr (260cm / 40km)

4. 4.5 s (72cm / 16cm)

5. 184 km (46km * 4h)

Step-by-step explanation:

We'll use d = distance, t = time, s = speed.

Speed over time can be found by dividing distance by time

s = d / t

We can take this formula and manipulate it to find either distance or time if we know two of the values. Keeping in mind division and multiplication cancel each other.

If we wanted to find d for instance we can multiply both sides by t to get

s * t = d

For time we can divide both sides of the above formula by s to get

t = d / s

Answer:

1. 20 km/h

2. 70 m/h

3. 6.5 h

4. 4.5 s

5. 184 km

Step-by-step explanation:

For first two questions, you can use the following formula:

[tex]\displaystyle \large{s = \frac{d}{t}}[/tex]

I denote ‘s’ be speed, ‘d’ be distance and ‘t’ be time. Some books may use ‘v’ for speed instead of ‘s’ but I use ‘s’ variable instead so it makes the equation easier to memorize.

Therefore, speed = distance/time

( 1 ) The first question is given both distance be 60 km and time be 3 hours. Therefore:

[tex]\displaystyle \large{s=\frac{60}{3}}\\\displaystyle \large{s=20 \ \ \sf{km / h}}[/tex]

So for the first question, the speed is 20 km/h

( 2 ) The second is given both distance be 140 m and time be 2 hours. Therefore:

[tex]\displaystyle \large{s=\frac{140}{2}}\\\displaystyle \large{s=70 \ \ \sf{m / h}}[/tex]

Therefore, speed is 70 m/h

For the third and four questions, we will be finding time. From the speed formula:

[tex]\displaystyle \large{s=\frac{d}{t}}[/tex]

Multiply both sides by t.

[tex]\displaystyle \large{st=d}[/tex]

Divide both sides by s.

[tex]\displaystyle \large{t=\frac{d}{s}}[/tex]

Therefore, time = distance/speed

( 3 ) The question is given speed be 40 km/h and distance be 260 km. Therefore:

[tex]\displaystyle \large{t=\frac{260}{40}}\\\displaystyle \large{t=\frac{13}{2} \ \ \sf{h}}\\\displaystyle \large{t = 6\frac{1}{2} \ \ \sf{h}}\\\displaystyle \large{t= 6.5 \ \ \sf{h}}[/tex]

Therefore, time is 6.5 h

( 4 ) The question is given speed be 16 cm/s and distance be 72 cm. Therefore:

[tex]\displaystyle \large{t=\frac{72}{16}}\\\displaystyle \large{t=\frac{9}{2} \ \ \sf{s}}\\\displaystyle \large{t=4\frac{1}{2} \ \ \sf{s}}\\\displaystyle \large{t=4.5 \ \ \sf{s}}[/tex]

Therefore, time is 4.5 s

For the last question, we have to find distance. From the speed formula:

[tex]\displaystyle \large{s=\frac{d}{t}}[/tex]

Multiply both sides by t.

[tex]\displaystyle \large{st=d}\\\displaystyle \large{d=st}[/tex]

Therefore, distance = speed * time

( 5 ) The question is given time be 4 hours and speed be 46 km/h. Therefore:

[tex]\displaystyle \large{d=46 \cdot 4}\\\displaystyle \large{ d=184 \ \ \sf{km}}[/tex]

Therefore, distance is 184 km.

A Mathematics paper consists of 12 questions of which not more than ten are to be answered. Given that the number of candidates who answer ten questions is equal to the number of candidates who answer nine questions only. Find the probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 if all the questions have the same chance of being selected.​

Answers

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.

How to calculate probability?

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:

= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]

= 42/220 + 18/66

= 0.1909 + 0.2727

= 0.4179

In conclusion, the probability is 0.4179.

Learn more about probability on:

https://brainly.com/question/24756209

The ratio of two numbers is 4 to 3. The sum of the numbers is 49. What are the two numbers?​

Answers

Answer:

28/21

Step-by-step explanation:

28/21 is the equivalent to 4/3.

We know this is the fraction we are looking for because 28 + 21 = 49

Hope that helps!

Answer 3. and 4. Please help me

Answers

Question 3

Let the number of times an odd number was chosen be x. Then, the number of times an even number was chosen is x+4.

[tex]x+x+4=50\\\\2x+4=50\\\\2x=46\\\\x=23[/tex]

So, the answer is 23 times.

Question 4

If 8 ordered pizza, 4 did not order pizza.

[tex]\frac{4}{12}=\frac{1}{3}[/tex]

So, the answer is 1 out of 3.

Suppose $f(3) = 4$. Name a point that must be on the graph of $y=f(x)+4.$

Enter your answer as an ordered pair.

Answers

Answer:

  (x, y) = (3, 8)

Step-by-step explanation:

The graph for y is a translation upward 4 units of the graph of f(x).

__

A point on the graph of f(x) is given as ...

  (x, f(x)) = (3, f(3)) = (3, 4)

Then a point on the graph of y will be ...

  (x, y) = (x, f(x) +4)) = (3, f(3)+4) = (3, 4 +4)

  (x, y) = (3, 8)

Volume of 12m height base and 6m base cone

Answers

750 is your answer because I’m smart and know a lot

Answer:

452.16 m³

Step-by-step explanation:

Given

height, h = 12 mbase radius, r = 6 m

Formula

V = 1/3πr²h

Solving

V = 1/3 x 3.14 x 36 x 12V = 3.14 x 144V = 452.16 m³

Kari and two of her friends are entering their senior year of high school. The tables below show the estimated expenses at three tied of schools they are considering. Complete the blanks in each table and use the information to help you answer questions 1-3

Answers

The expenses for the duration of the four years that Kari will use in the university is $68600.

How to calculate expenses?

From the complete information, the expenses for the four years stay in the university will be calculated thus:

Tution = $8500

Room = $6700

Books = $1250

Miscellaneous expense = $700

Total = $17150

The expenses for the four years will be:

= $17150 × 4

= $68600

Learn more about expenses on:

https://brainly.com/question/14697297

HELP PLEASE ! What is the solution to the equation x + 9.5 = 27.5? (1 point)

a
x = 2.9

b
x = 18

c
x = 20

d
x = 37

Answers

Answer:

B

Step-by-step explanation:

Group like them

such that the coefficient stands alone

by subtracting both sides by 9.5

please help find the area!
Ill mark brainliest!

Answers

the awnser is 18 the area

This figure represents a garden box that is to be filled with soil.

How much soil will it take to fill the garden box?

Enter your answer in the box.

Answers

Answer:

1728 ft³

Step-by-step explanation:

Lower part:

volume = 19 ft × 12 ft × 6 ft = 1368 ft³

Upper part:

volume = 10 ft × 12 ft × 3 ft = 360 ft³

Total Volume = 1728 ft³

At noon, there are 700 juniors and 1,100 seniors at a college fair. After 12:00 p.m., 20 juniors arrive every 15 minutes and 45 seniors leave every 15 minutes. What is the ratio of juniors to seniors at 2:00pm in fraction form

Answers

Answer:

find the common factor in the given algebraic expressions 4 (x-y) , 6(y-x)

What is the area of parallelogram ABDC?



9 cm 2
12.25 cm 2
7 cm 2
12 cm 2

Answers

Answer:

I guess it is 9 cm²

Step-by-step explanation:

Hope it helps.....

Which statement describes the graph of the function?
The function has holes when x = 0 and x = 4.
The function has vertical asymptotes when x = 0 and x = 4.
The function has a vertical asymptote when x = 0 and a hole when x = 4.
The function has a hole when x = 0 and a vertical asymptote when x = 4.

Answers

Answer:

the function has vertical asymptotes when x = 0 and x = 4

Step-by-step explanation:

÷what expression could be used to solve 2/5 ÷ 3/4

Answers

Answer:

The expression is division.

Step-by-step explanation:

2/5 ÷3/4=0.075

Answer:

[tex]\frac{2}{5} \times\frac{4}{3}[/tex]

Step-by-step explanation:
To find the answer we use KCF (Keep, Change, Flip).

[tex]\frac{2}{5} \div\frac{3}{4}[/tex]
[tex]\frac{2}{5} =\frac{2}{5}[/tex]
[tex]\div=\times[/tex]
[tex]\frac{3}{4} =\frac{4}{3}[/tex]
[tex]\frac{2}{5} \times\frac{4}{3}[/tex]

Which means the expression used to find the answer would be "2/5 × 4/3."

Hope this helps.

7. A company invests in a new project and it is expected that after years of running the cumulative project in millions of shillings from the project is given by the function f(t)=10.5t-+- 20 where t represents time in years. The project can run for maximum of nine years required (1) Draw a graph which represent the profit functions (Smarks)​

Answers

Answer:

what are the objectives of census class 7

Sara used 6_1/2 packs of pencils in the first 1/2 of the year. At what rate is Sara using pencils?
⚫️13 packs per year
⚫️8_1/2 packs per year
⚫️14 packs per year
⚫️12_1/2 packs per year

Answers

13 packs a year. 6.50 (.50 comes from 1/2) since the question states that she uses 6_1/2 packs of pencils in the first “1/2” of the year we need to multiply the 6_1/2 by 2 and we get our answer.
13 packs per year because 6 1/2 x 2 = 13 so it would be 13

Find the distance between the two points in simplest radical form.
(-8,3) and (-2,-5)

Answers

Explaination :

Here we would be using distance formula to calculate the distance between those two points.

Points are,

(-8,3) (-2,5)

Distance Formula :

[tex]\huge \large \boxed{\sf{{d \: = \: \sqrt{(x _{2} - x _{1}) {}^{2} \: + \: (y _{2} - y _{1}) {}^{2} }}}} \: \red\bigstar[/tex]

We have :

x1 = -8 x2 = -2 y1 = 3 y2 = -5

Substituting the values :

Refer the attachment.Additional Information :

Centroid of a triangle :-

[tex]\boxed{ \sf{Centroid \: = \: \dfrac{x_1 \: + \: x_2 \: + \: x_3}{3} }} \: \pink\bigstar[/tex]

Midpoint of two points:-

[tex]\boxed{ \sf{M \: = \: \dfrac{x_1 \: + \: x_2 }{2} \: , \: \dfrac{y_1 \: + \: y_2 }{2}}} \: \pink\bigstar[/tex]
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