When a pungent odor is detected during a sealed system recovery and/or repair which of the following is most likely

Answer:Referencing is a standardised method of acknowledging the sources of information and ideas you have used.

Explanation:Depending on the way in which they record sources, scholarly reference styles can be divided into three main categories: documentary notes styles, parenthetical (or author-date) styles, and numbered styles. Within each category there are several, slightly different reference styles.

Referencing allows you to acknowledge the contribution of other writers and researchers in your work. Any university assignments that draw on the ideas, words or research of other writers must contain citations. Referencing is also a way to give credit to the writers from whom you have borrowed words and ideas.

Answer: Gasoline cars are bad because

Explanation: They give off carbon emissions and pollute the ozone layer causing the greenhouse effect which leads to global warming

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

Answer:

m_added = 2 kg

Explanation:

From the question, we are told that the cylinder is allowed to fall 800 m in height. Thus, the potential energy will be converted into heat energy which will increase the temperature of water .

Now, let the mass of the falling cylinder be denoted by "m1" and let h be the height of fall.

Thus;

Formula for potential energy = mgh

Thus, as said earlier it's converted to heat generated. So heat generated = m1gh

Now let's calculate the heat absorbed;

heat absorbed = (m2)cΔt

Where;

ΔT is change in temperature

c is specific heat of water .

m2 is mass of water

Heat absorbed = heat generated

Thus;

(m2)cΔt = m1gh

Δt = m1gh/(m2•c)

Now, in both cases of the water and cylinder, m1, g , h and c are constant

Thus, we have;

Δt = (m1gh/m2) × 1/c

Where;

(m1gh/m2) is denoted as a constant k.

Thus;

Δt = K/m

For the first experiment, we have;

m = 2 kg

Δt = 2.4

Thus;

2.4 = K/2

Multiply both sides by 2 to get;

K = 4.8

For the second experiment, we have;

Δt = 1.2

Also,we have seen that K = 4.8

Thus;

Δt = K/m

Thus;

1.2 = 4.8/m

m = 1.2

m = 4 kg

Thus,mass added is;

m_added = 4 - 2

m_added = 2 kg

Answer:

tapping, horizontal dusting, slash drilling

Explanation:

Answer: There are no major convergent boundaries in the Atlantic, which is where these events are more likely to occur

Explanation:

Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load = [tex]\frac{wL}{2}[/tex]

w = maximum intensity of load , L = span of varying load

since AC = 6m( L )  then

Total load due to linearly varying load  = 3w  ------ ( 1 )

attached below is the detailed solution of the given problem

Answer:

Hello the circuit related to this question is missing attached below is the missing circuit

answer : 1.5 V

Explanation:

attached below is the detailed solution to the question

Applying Thevenin equivalent Circuit Theorem

First we perform Nodal analysis at Vth and draw the equivalent Thevenin circuits

Hence for a maximum power triangle

[tex]V_{RL} = \frac{V_{th} }{2} = \frac{-3}{2}[/tex]  = -1.5

therefore the value of v that maximizes the power dissipated in the voltage source

V = [tex]-V_{RL}[/tex] = 1.5 V

Explanation:

current- amperes

resistance- ohms

voltage- volts

electrical energy- kilowatt hours

electrical power- watts

hope it helps!

Answer:protection circuit overload as usual

circuit overload

Explanation:

it is ery easy for wverone

Answer:

decreases too

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

decreases

Explanation:

Since the gravitational force is directly proportional to the mass of interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases (decreases), the force of gravitational attraction between them also increases (decreases).

Explanation:

I won't answer each of these, but will give you an explaination of how to solve for each.

You'll need to use Ohm's Law and Kirchhoff's Voltage Law.

Remember Ohm's Law as [tex]V = IR[/tex].

Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.

[tex]E_T = E_1 + E_2 + E_3[/tex]

A couple of other helpful notes:

These three resistors are in series which means that the current flowing through them is equal.

So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]

Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).

Answer and Explanation: A fluid flow is steady when its properties (velocity, pressure and others) do not change over time: P = P(x,y,z), with P being any of the properties.

So, an unsteady flow does depend upon time: P = P(x,y,z,t).

1. V = [[tex]ay2e^{-bt}[/tex]]i : This velocity field is one-dimension, because there is only the component in the x-direction and unsteady, because it is dependent upon the variable time (t);

2. V = [tex]ax^{2}i+bxj+ck[/tex] : is a three-dimensional field, because there is one component for each direction (x, y and z) and is steady, since it's independent of time;

3. V = axyi - bytj : is a 2-dimensional field, and since it changes with time, it is unsteady;

4. V = axi - byj + ctk : is a 3-dimensional field and the flow is unsteady;

Answer:

Q ≅ 1.53 m³/s

Explanation:

From the given information:

The flow rate of the orifice is:

[tex]v = c_v \sqrt{2gh}[/tex]

[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]

where;

[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &

[tex]c_d = c_c \times c_v[/tex]

∴

[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]

[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]

[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]

Q ≅ 1.53 m³/s

Answer:

the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

Given that;

depth 1 = 71 ft

depth 2 = 10 ft

pressure p = 17 psi = 2448 lb/ft²

depth h = 71 ft - 10 ft = 61 ft

we know that;

p = P_air + yh

where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )

so we substitute;

p = 2448 + ( 49.3 × 61 )

= 2448 + 3007.3

= 5455.3 lb/ft³

= 37.88 psi

Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Solution :

The percentage of the students who have a chance of repeating their current year = 3%

The drop out students for the first year and the sophomores = 6%

Drop out rate of first year and the seniors = 4%

Now for the state space :

S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }

Therefore

the first year students are indicated as '1'

Sophomores are indicated as '2'

Juniors are indicated as '3'

Seniors are indicated as '4

Graduates are indicated as 'G'

Dropouts are indicated as 'D'

The transition diagram is attached below.

The probability of the students who have the chance of repeating their current year = 3/100 = 0.03

Probability of first year dropouts and sophomores = 6/100 = 0.06

Probability of dropout rate of juniors and seniors = 4/100 = 0.04

Therefore, the probability matrix can be made as :

              1        2        3        4       G        D

    [tex]\begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}[/tex]      [tex]\begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\ 0& 0.03 & 0.91 & 0 & 0 & 0.06\\ 0& 0 & 0.03 & 0.93 & 0 & 0.04\\ 0& 0 & 0 & 0.03 & 0.93 & 0.04\\ 0& 0 & 0 & 0 & 1 & 0\\ 0& 0 & 0 & 0 & 0 & 1\end{bmatrix}[/tex]  

Here, G represents 'graduates' and D represents 'Dropouts.'