What unit of measurement is used for liquid volume

Answer:

Below.

Step-by-step explanation:

7)  c^2 = a^2 + b^2

15^2 = 11^2 + b^2

b^2 = 225 - 121 = 104

b = √104

= √4√26

= 2√26.m

8). 4^2 = a^2 + (√6)^2

a^2 = 16 - 6

a^2 = 10

a =  √10.

Answer:

Step-by-step explanation:

Let the width is x, then the length is:

Perimeter is:

Dimensions are:

Correct choice is C

Answer:

1and 3 are not a function 2 and 4 are a function 6 not enough

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

step1 Isolate the square root on the left hand side

    Original equation

    √2x-5-4 = -x

    Isolate

    √2x-5 = 4-x

step2 eliminate the radical on the left hand side

    Raise both sides to the second power

    (√2x-5)2 = (4-x)2

    After squaring

    2x-5 = x2-8x+16

step3 Solve the quadratic equation

    Rearranged equation

    x2  - 10x  + 21 = 0

    This equation has two rational roots:

      {x1, x2}={7, 3}

step4 Check that the first solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 7 for  x  

     √2•(7)-5 = 4-(7)

     Simplify

     √9 = -3

     Solution does not check

     3 ≠ -3

step5 Check that the second solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 3 for  x  

     √2•(3)-5 = 4-(3)

     Simplify

     √1 = 1

     Solution checks !!

    Solution is:

     x = 3

Answer:

-3

Step-by-step explanation: i got it right on my test

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

Answer:

Step-by-step explanation:

The slope is - 2/3 and the point on the line is (-3, -1).

Find the y-intercept:

The line is:

Correct choice is D

Equation in point slope form

Option D

Answer:

-72

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]a^{-m}=\dfrac{1}{a^{m}}\\\\8^{-3}=\dfrac{1}{8^{3}}=\dfrac{1}{8*8*8}=\dfrac{1}{512}[/tex]

Answer:

Step-by-step explanation:

x-4+2x+7=90

3x+3=90

   -3    -3

3x=87

x=29

m<A= 29-4

      =25

m<B=2(29)+7

       =58+7

       =65

[tex] {\large\underline{\sf{Solution-}}}[/tex]

Given function is

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

We know

Domain of a function is defined as set of those real values of x for which function is well defined.

So, y is defined when

[tex]\rm \longmapsto\: {x}^{2} - 4 \geqslant 0[/tex]

[tex]\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0[/tex]

[tex]\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0[/tex]

[tex]\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2[/tex]

[tex]\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

Now, To find the range of function

We know,

Range of a function is defined as set of those real values which is obtained by assigning the values to x.

So,

[tex]\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4} [/tex]

On squaring both sides, we get

[tex]\rm \longmapsto\: {y}^{2} = {x}^{2} - 4[/tex]

[tex]\rm \longmapsto\: {y}^{2} + 4= {x}^{2}[/tex]

[tex]\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 } [/tex]

Now, x is defined when

[tex]\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number[/tex]

But,

[tex]\rm \longmapsto\:y \geqslant 0[/tex]

Hence,

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

So, we have

[tex]\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )[/tex]

and

[tex]\rm\implies \:Range \: of \: function \: = [0, \: \infty )[/tex]

Step-by-step explanation:

length of missing side = sqrt(5^2 + 12^2) = sqrt(169) = 13

distance = sqrt(50^2 +25^2) =sqrt(3125)= 55.90metres

Answer:

Simplifying

-5 + -1(3a + b) + (2a + -7b) = 0

-5 + (3a * -1 + b * -1) + (2a + -7b) = 0

-5 + (-3a + -1b) + (2a + -7b) = 0

Remove parenthesis around (2a + -7b)

-5 + -3a + -1b + 2a + -7b = 0

Reorder the terms:

-5 + -3a + 2a + -1b + -7b = 0

Combine like terms: -3a + 2a = -1a

-5 + -1a + -1b + -7b = 0

Combine like terms: -1b + -7b = -8b

-5 + -1a + -8b = 0

Solving

-5 + -1a + -8b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + -1a + 5 + -8b = 0 + 5

Reorder the terms:

-5 + 5 + -1a + -8b = 0 + 5

Combine like terms: -5 + 5 = 0

0 + -1a + -8b = 0 + 5

-1a + -8b = 0 + 5

Combine like terms: 0 + 5 = 5

-1a + -8b = 5

Add '8b' to each side of the equation.

-1a + -8b + 8b = 5 + 8b

Combine like terms: -8b + 8b = 0

-1a + 0 = 5 + 8b

-1a = 5 + 8b

Divide each side by '-1'.

a = -5 + -8b

Simplifying

a = -5 + -8b

Step-by-step explanation:

Answer:

1/6

Step-by-step explanation:

the form you're using is slope-intercept. That is

y=mx+b

where y= y coordinate

m=slope

x= x coordinate

and b= y intercept

so, m in that equation is 1/6, so the slope is 1/6

Hope this helps!

Answer:

2^-2

Step-by-step explanation:

When multiplying indices or exponents with the same base number, you can add the powers:

2^4 x 2³ = 2^7 (4 + 3 = 7)

2^5 x 2^4 = 2^9 (5 + 4 = 9)

When dividing indices or exponents with the same base number, you can subtract the powers:

2^7 ÷ 2^9 = 2^-2 (7 - 9 = -2)

Answer:

60

Step-by-step explanation:

time * speed

in seconds 60x *4 = 2.5(60x + 900)

x= 25

25 min * 4cm/2

distance = 60 meters

CHEck!!!

Using a system of linear equations, the distance between points A and B is 6000 cm

Time taken = Distance / speed

Let ; distance = d

To time :

Fro time :

(t + 15 × 60) = d / 2.5

2.5(t + 900) = d

2.5t + 2250 = d ______(2)

Equate (1) and (2)

4t = 2.5t + 2250

4t - 2.5t = 2250

1.5t = 2250

t = 1500 seconds

From (1) :

d = 4t

d = 4(1500)

d = 6000 cm

Therefore, the distance from point A to B is 6000 cm

Learn more : https://brainly.com/question/14000187

Step-by-step explanation:

for measuring the angle use the protractor !

Answer:

-4x-1

Step-by-step explanation:

-4x-1

Answer:

C

Step-by-step explanation:

Look at the angle markings. Angle C has one mark, Angles E and S have two marks, and Angles D and R have three marks.

Therefore, these angles correspond with one another and determine the order of the letters.

Answer:

c = m + 4

you solve for c by simplifying both sides of the equation, then isolating the variable.

Answer:

Your answer is

c = m + 4

Answer:4

Step-by-step explanation:

Answer:

Hundreds :)

Step-by-step explanation:

Answer:

1.She has 115 dimes because 0.10*115=11.5 0.25*4=1.00 11.5+1.00=12.5

2.She has 100 dimes because 0.10*100=10.00 and 0.25*10= 2.5 10+2.5=12.5

3.I think they don’t function because quarters are worth more than a dime.

4.he has 40 quarters because 0.25*40=10.00 0.10*25=2.5 10.00+2.5=12.5.

5.She has 38quarters because 0.25*38=9.5 0.10*30=3 9.5+3=12.5

6.Yes they can function because q=dx-12.5

The Questions:

Question 1 - 1 pts

If Jada has 4 quarters, how many dimes does she have?

Question 2 - 1 pts

If Jada has 10 quarters, how many dimes does she have?

Question 3 - 1 pts

Is the number of dimes a function of the number of quarters? If yes, write a rule (that starts with d =...) that you can use to determine the output, d, from a given input, q. If no, explain why not.

Question 4 - 1 pts

If Jada has 25 dimes, how many quarters does she have?

Question 5 - 1 pts

If Jada has 30 dimes, how many quarters does she have?

Question 6 - 1 pts

Is the number of quarters a function of the number of dimes? If yes, write a rule (that starts with q =...) that you can use to determine the output, q, from a given input, d. If no, explain why not.

The answer is

[tex]5\frac{6}{7}[/tex]

Answer:

5.857

or

5 6/7

Step-by-step explanation: both are the same just one in decimal and the other is in fraction form

Answer: i dont know

Step-by-step explanation:

If you edit the question or repost I can answer if you provide an image! :D

Answer:

Step-by-step explanation:

The order of the decimals are 15.03, 15.2, then 15.25. Casey ran the farthest. (Casey is 15.25) I hope this helps you even though this was 2 weeks ago. :>

Answer:

4^3 x 5^2

Step-by-step explanation:

Index notation just makes the numbers being multiplied by themselves easier to read.

Answer:

4³×5²

Step-by-step explanation:

chill bro it's basic

Answer:

-73 sorry if im wrong

Step-by-step explanation:

find nth term but replace n with 50 equation is -2n+27

Answer: no.of days in 5 weeks= 5× 7= 35

ratio of 5 days to 5 weeks= 5/35

=1/7

answer= 1:7

Step-by-step explanation: .