what is this? please help​

Answer:

x+1y=-4

Step-by-step explanation:

use ax+by=c

Answer:

see the attachment.

i hope this can help you!

The height of the square-based pyramid is 3.5 in.

The volume of the square-based pyramid is the product of the base area multiplied by one-third of the height of the square-based pyramid.

Mathematically;

[tex]\mathbf{V = a \times \dfrac{1}{3}h}[/tex]

[tex]\mathbf{V = a \times \dfrac{h}{3}}[/tex]

Given that:

[tex]\mathbf{10.5 = 9 \times \dfrac{h}{3}}[/tex]

[tex]\mathbf{10.5 =3\times h}[/tex]

[tex]\mathbf{h = \dfrac{10.5}{3}}[/tex]

h = 3.5 in

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Answer:

3.5 or third option

Step-by-step explanation:

I got it right on edge

Answer:

(0, 1)

Step-by-step explanation:

right 2 units: add 2 to x

up 4 units: add 4 to y

Answer: (0, 1)

The depth of the water at the deepest point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)

In this question we should apply the concepts of right triangles and trigonometric functions to determine the height of the water within the waterslide. A geometric diagram of the cross section of the waterslide is presented below, which indicates the existence of circular symmetry.

Now we proceed to determine the height of the water:

cos α = (0.5 m/0.75 m)

α ≈ 48.190°

y = (0.75 m) · sin 48.190°

y = 0.559 m

x = 0.75 m - 0.559 m

x = 0.191 m

The depth of the water at the deepest point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)

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Answer:

See below

Step-by-step explanation:

x = 3 cos (-5pi/3)   =  1.5

y = 3 sin (-5pi/3) = 2.598

Answer:

12 ft

Step-by-step explanation:

Tim Height: Tim Shadow
5ft              : 2ft

Tree Height: Tree Shadow
30ft              : ?ft

Using this knowledge, we can compare Tim's Height to the Tree's Height. The tree's height is 6 times more than Tim (5x6=30). We can find the shadow of the tree if we multiple tim's shadow by 6.

Therefore, 2ft x 6 = 12ft

The Tree's Shadow is 12ft.

Answer: B

Step-by-step explanation:

Answer:

6.42 %

Step-by-step explanation:

3412.23 = 2500(1+i)^5

i = 6.42%

Area of larger :- length× width

[tex]27 \times 36 = 972 {in}^{2} [/tex]

Area of the smaller screen= 40% of larger area

[tex] area = \frac{40}{100} \times 972 \\ area = \frac{4 \times 972}{10} \\ area = \frac{3888}{10 } = 388.8 {in}^{2} [/tex]

Answer:

[tex]-2\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\textsf{Given expression}: \quad(\sqrt{3}+1)(\sqrt{3}-3)[/tex]

[tex]\textsf{Use the FOIL method to expand}\quad(a+b)(c-d)=ac-ad+bc-bd:[/tex]

[tex]=\sqrt{3}\sqrt{3}-3\sqrt{3}+1\sqrt{3}+1(-3)[/tex]

[tex]=\sqrt{3}\sqrt{3}-3\sqrt{3}+1\sqrt{3}-3[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{a}\sqrt{a}=a:[/tex]

[tex]=3-3\sqrt{3}+\sqrt{3}-3[/tex]

[tex]\textsf{Collect like terms}:[/tex]

[tex]=3-3-3\sqrt{3}+\sqrt{3}[/tex]

[tex]\textsf{Combine like terms}:[/tex]

[tex]=0-2\sqrt{3}[/tex]

[tex]=-2\sqrt{3}[/tex]

Answer:

The length of the unknown leg is 5.66 yards

Step-by-step explanation:

[tex]Hypotenuse^2=opposite^2-adjacent^2[/tex]

[tex]Hyp^2=opp^2+adj^2[/tex]

[tex]Hyp=\sqrt{42.8}[/tex] [tex]yards[/tex]

[tex]Opp=\sqrt{11}[/tex] [tex]yards[/tex]

[tex]Adj=?[/tex]

[tex]Adj^2=Hyp^2-opp^2[/tex]

[tex]=(\sqrt{42.8} )^2-(\sqrt{11} )^2[/tex]

[tex]=42.8-11[/tex]

[tex]=31.8[/tex] → [tex]32[/tex]

[tex]Adj^2=32[/tex]

[tex]Adj=\sqrt{32}[/tex]

= 5.66 yards

Answer:

Y = 2

X = - 2

Step-by-step explanation:

8x-4y= - 24 eq 1

4x-12y = - 32 eq 2

Multiply equation 2 by (×-2)

Then

-8x +24 y = 64. Eq 3

Add eq 1 to eq 3

20y = 40 then y = 2

From eq 1

8x - 4(2) = - 24

8x = - 16

X = - 2

The value of the definite integral corresponds to the total area of two triangles (see attached plot).

[tex]\displaystyle \int_{-4}^3 \left|\frac x2\right| \, dx = \dfrac12 \times 2 \times 4 + \dfrac12 \times 3 \times \dfrac32 = \boxed{\frac{25}4}[/tex]

I assume you're asking to solve for the n-th term in the sequence, [tex]a_n[/tex].

From the given recursive rule,

[tex]a_n = a_{n-1} + 2 \implies a_{n-1} = a_{n-2} + 2[/tex]

and by substitution,

[tex]\implies a_n = a_{n-2} + 2\times2[/tex]

Similarly,

[tex]a_n = a_{n-1} + 2 \implies a_{n-2} = a_{n-3} + 2[/tex]

[tex]\implies a_n = a_{n-3} + 3\times2[/tex]

The pattern continues, so that we can write the n-th term in terms of the 1st one:

[tex]a_n = a_1 + (n-1)\times2 \implies a_n = 10 + 2(n-1) = \boxed{2n+8}[/tex]

So the first few terms of the sequence are

{10, 12, 14, 16, 18, 20, …}

A can with a radius of 60 mm and a height of 160 mm. Then the surface area of the cylinder will be 1808640 mm³.

The lateral surface area of a cylinder is also called the curved surface area of the cylinder.

Suppose that:

Radius of the considered cylinder = 'r' units

Height of the considered cylinder = 'h' units

Then, the lateral surface area of that cylinder is:

SA = πr²h

A can with a radius of 60 mm and a height of 160 mm. Then the surface area of the cylinder will be

SA = π x (60)²  x 160

SA = 3.14 x 3600 x 160

SA = 1808640 mm³

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Answer:

There are two sets of degrees going in opposite directions along an arc. The top of the arc shows degrees from 0º to 180º from left to right. The bottom of the arc shows degrees from 180º to 0º from left to right. The smallest "tick marks" along the edge of the protractor represent 1º intervals.

Step-by-step explanation:

Answer:

21.6 units² (nearest tenth)

Step-by-step explanation:

[tex]\textsf{Area of a trapezoid}=\dfrac{1}{2}(a+b)h \quad \textsf{(where a and b are the bases and h is the height)}[/tex][tex]\textsf{Area of a semicircle}=\dfrac12 \pi r^2 \quad \textsf{(where r is the radius)}[/tex]

Given:

[tex]\begin{aligned}\textsf{Area of figure} & =\textsf{area of trapezoid + area of semicircle}\\& = \dfrac{1}{2}(a+b)h+\dfrac{1}{2} \pi r^2\\& = \dfrac{1}{2}(2+8)(4)+\dfrac{1}{2} \pi (1)^2\\& = 20+\dfrac{1}{2} \pi\\& = 21.6\: \sf units^2 \:(nearest\:tenth)\end{aligned}[/tex]

Area of the trapezium

Area of semicircle

Total area

Answer:

  (a)  452 m²

Step-by-step explanation:

The lateral area of a cylinder is given by the formula ...

  A = 2πrh . . . . radius r, height h

__

The given tube has an outside (or inside) area of ...

  A = 2(3.14)(5 m)(14.4 m) = (3.14)(144 m²) ≈ 452 m²

Each curved surface of the tube has an area of about 452 m².

The length of the petals of the rose is 8 units

The polar equation is given as:

r = 8 cos(30)

The amplitude of the above equation is:

A = 8

This is the same as the length of the petals

i.e.

Length = 8

Hence, the length of the petals of the rose is 8 units

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Answer:

temperature > -15

Answer:

e.  0.308.

Step-by-step explanation:

I can't draw the tree diagram but the answer is

P(red first) = 7/14 = 1/2

P( then black)  = 4/13

P(red then black) = 1/2 * 4/13 = 2/13

P(black first) = 4/14 =  2/7

P( then red)  = 7/13

P(black then red) =2/7 * 7/13 = 2/13

So Probability of red and black in any order

= 2/13 + 2/13  = 4/13

= 0.308.

Answer:

D. 3x² - x - 6

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

Step-by-step explanation:

photos explain. in the second photo, A didnt start at 0 so it looked not accurate

The potential energy of the 10-kg object is 294 joules.

Variation is a mathematical term that shows the relationship between two or more parameters or quantities in an equation.

Analysis:

let potential energy be = P

let mass be = m

let height be = h

P ∝ mh

P = kmh

when P = 784, m = 40kg, h = 2 meters

784 = k x 40 x 2

k = 9.8

P = 9.8mh

when m = 10kg, h = 3 meters

P = 9.8 x 10 x 3 = 294 joules.

In conclusion, the potential energy of the object at 3 meter height is 294 joules.

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Answer:

C.) 2(x-3)(x-4)

Step-by-step explanation:

I think so

Answer:

Step-by-step explanation:

Percentage of birds in Forest B that are robins :

Percentage of sparrows that are in Forest A :

Percentage of birds in Forest A :

Answer:

36%

20%

20%

Step-by-step explanation:

Percentage of birds in Forest B that are robins :

No. of robins in Forest B / birds in Forest B

36 / 100

0.36

36%

Percentage of sparrows that are in Forest A :

Sparrows in Forest A / total sparrows

16 / 80

0.2

20%

Percentage of birds in Forest A :

Birds in Forest A / Total birds

25 / 125

0.2

20%