What is the radius of a cone with a volume of 96π cubic inches and a height of 18 inches? 1. rewrite the formula using the base area: 2. substitute the values into formula: 3. simplify the right side: 4. undo the multiplication of 6π: 5. undo the square: what is the radius of the cone? inches v = one-third pi r squared h. 96 pi = one-third pi r squared (18). 96 pi = 6 pi r squared. 16 = r squared. startroot 16 endroot = startroot r squared endroot.

Answer:

infrasound

Explanation:

Answer:

A. It pulls objects towards the center of Earth.

Explanation:

Think about dropping something, where does it go? If you are on earth, this goes down towards the ground due to the attractive force of gravity on every object (to pull everything to center of earth). Like Newton's apple.

Answer:

Length of steel = 5.5 m

Increase in length = 0.0012 m

α of steel = 12 x 10-6/K

To find:

Temperature change needed ?

Calculation:

Let the required temperature change be ∆T. (in the photo)

So, temperature change of 18.1 Kelvin is required

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Answer:

V = f λ     speed of wave in terms of frequency and wavelength

t = S / V      time for wave to travel a distance S

t = 91.4 m / 344.5 m/s = .265 sec        time to travel 91.4 m

A diverging lens is used to permit clear vision of an object placed at infinity. The focal length of the lens is -100 cm.

The focal length is half of the radius of curvature of the focal lens.

By the lens maker formula,

1/f = 1/v +1/u

where, v is the image distance and u is the object distance.

Give, the object is at infinity and the image must form at 100 cm, the the focal length will be

1/f = 1/ -100 + 1/∞

f = -100 cm

The focal length must be -100 cm for the diverging lens.

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Answer:

150w

Explanation:

power = workdone/time

9000/60

150w

The statement 'research indicates that high serotonin levels may increase aggression' is FALSE.

Serotonin is a chemical messenger (i.e., a hormone) used to transmit messages through the body.

In conclusion, the statement 'research indicates that high serotonin levels may increase aggression' is FALSE.

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Answer:

lonic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion.

Explanation:

Answer:Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion.

Explanation:

Remember the formula

[tex]\\ \rm\Rrightarrow A(t)=A_o(0.5)^{\frac{t}{h}}[/tex]

[tex]\\ \rm\Rrightarrow A(7.82\times 10)=A(78.2)[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{\frac{78.2}{3.91\times 10^{5}}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{20\times 10^{-5}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{0.0002}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.998)[/tex]

[tex]\\ \rm\Rrightarrow 4.10178\times 10^{76}[/tex]

Why no options matched?

That time given in end i.e 7.82×10

The number of nuclei  of calcium-47 left after 7.82 x 10⁵s is 1.03 x 10¹⁶.

This can be found out using half life and laws of radioactive disintegration.

The Law of radioactive disintegration states  the number of  radioactive decay per unit time is proportional to the number of nuclei present in the sample initially.

So,  ΔN/Δt = λN

Where, ΔN = number of radioactive nuclei decayed

Δt = time taken for decay

N = No of nuclei present initially

λ= decay constant

Half life is the time taken for the radioactive nuclei to reach half of its initial value.

Half life is given by

 [tex]t_{1/2}[/tex] =  λ/t

Given here,  [tex]t_{1/2}[/tex] =  3/91 x 10.⁵s

N = 4.11 x 10¹⁶.

t = 7.82 x 10.⁵s

We see  here that  t = 2([tex]t_{1/2}[/tex])

Now, number of radioactive nuclei left undecayed in  one half life is N/2

So number of nuclei left undecayed in 2 half lives will be 1/2(N/2) = N/4

So number of nuclei left in the sample will be N/4 = (4.11 x 10¹⁶.)/4

So Number of nuclei left in the sample = 1.03 x 10¹⁶.

Hence 1.03 x 10¹⁶is the correct answer.

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The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.

The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.

The formula for the enthalpy of the fusion is;

[tex]\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ[/tex]

Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.

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Answer:

23,49 m/s

Explanation:

Ep= Ek

mgh=mv2/2

6×10×30=6v2/2

1800=6 v2/2

6 v2=3600

v2 =600

v=24,49 m/s

The velocity of the stone, if a stone of mass 6 kg is released from a height of 30 m, is 24.5 m/s.

When something is moving, its velocity shows how quickly its location is changing as seen from a certain angle and as measured by a particular unit of time.

If a point moves a certain distance along its path in a predetermined length of time, its average speed throughout that time is equal to the distance traveled divided by the travel time. For instance, a train traveling 100 km in two hours is doing it at an average speed of 50 km/h.

Given:

The mass of the stone, m = 6 kg,

The height of the release, h = 30 m,

The value of gravity, g = 10 m/s,

Calculate the velocity using energy conservation as shown below,

The kinetic energy = potential energy  (Energy conservation)

1/2 × 6 × v² = 6 × 10 × 30

v² = 300 × 2

v² = 600

v = √600

v = 10√6

v = 10 × 2.45

v = 24.49 or 24.5 m/s

Thus, the velocity is 24.5 m/s.

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Explanation:

the answer is 2.46 × 10^12

The tension on the string when the coefficient of sliding kinetic friction between the block and floor is 0.2 is calculated as 19.8N

The force acting on the block in the horizontal direction is given by:

F_net = ma

where F_net is the net force acting on the block, m is the mass of the block, and a is its acceleration.

The force of friction opposing the motion of the block is given by:

F(friction) = μKN

where μK is the coefficient of kinetic friction between the block and the floor, and N is the normal force acting on the block due to the floor.

Since the block is pulled horizontally, the normal force acting on the block is equal and opposite to the weight of the block, which is given by:

N = mg

where g is the acceleration due to gravity.

Therefore, the net force acting on the block is:

Fnet = T - F (friction) = ma

where T is the tension in the string.

Substituting the expressions for F (friction), N, and Fnet, we get:

T - μKmg = ma

Solving for T, we get:

T = ma + μKmg

Substituting the given values, we get:

T = (5.0 kg)(2 m/s^2) + (0.2)(5.0 kg)(9.8 m/s^2)

Simplifying, we get:

T ≈ 19.8 N

Therefore, the tension in the string is approximately 19.8 N.

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Answer:

The energy efficiency represents the things you can do with some amount of energy, and if you can do more with less, than it reduces the energy consumption.

Explanation:

The answer to this question is actually very simple. Imagine that you use only the half of the energy you produce, an efficiency of 50%. Lets say you need 5kJ, so you would need to produce 10kJ, because you can consume only the half. Now, imagine you increase the efficiency, you use exactly what you can generate, (efficiency of 100%). In this case, if you needed only 5kJ you would need to generate only 5kJ.

Answer:

F = M a

F = 2350 kg * 2 m/s^2 = 4700 Newtons

That is in addition to the force of

F = 2350 * 9.8 m/s^2 = 23,030 N needed for a stopped elevator

Answer:

Explanation:

Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth

Answer:

Violet (Shortest Wave Length)

Explanation:

Violet waves have the highest frequencies. The highest frequencies have the shortest wave length.

Answer:

Approximately [tex]15\; {\rm m\cdot s^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

Let [tex]m[/tex] denote the mass of this vehicle, and let [tex]g[/tex] denote the gravitational field strength.

Since the road is level, the normal force that the road exerts on the vehicle would be equal in magnitude to the weight [tex]m\, g[/tex] of this vehicle. That is: [tex]F_\text{normal} = m\, g[/tex].

Let [tex]\mu_{k}[/tex] denote the coefficient of (kinetic) friction between the tires of this vehicle and the road. The maximum friction that the road could exert on this vehicle would be:

[tex]\begin{aligned}& F_\text{max. friction} && (\text{max. friction}) \\ =\; &\mu_{k}\, F_\text{normal} && (\text{coefficient of friction}) \,(\text{normal force}) \\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].

Also because this road is level, the only unbalanced force on this vehicle would be friction. Thus, the net force on this vehicle would be equal to the friction that the road exerts on the vehicle, which is at most [tex]\mu_{k}\, m\, g[/tex]:

[tex]\begin{aligned}& F_\text{net} && (\text{net force}) \\ =\; & F_\text{friction} && (\text{friction}) \\ \le \; & F_\text{max. friction} && (\text{max. friction})&\\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].

In other words, [tex]F_\text{net} < \mu_{k}\, m\, g[/tex]. This inequality could provide an upper bound on the acceleration of this vehicle:

[tex]\begin{aligned}& a && (\text{acceleration}) \\ =\; & \frac{F_\text{net}}{m} && \genfrac{}{}{0em}{}{(\text{net force})}{(\text{mass})}\\ \le \; & \frac{\mu_{k}\, m\, g}{m} \\ =\; & \mu_{k}\, g\end{aligned}[/tex].

Thus, the maximum acceleration of this vehicle on this road would be [tex]a_\text{max} = \mu_{k}\, g[/tex].

Let [tex]r[/tex] denote the radius of this circle. When the vehicle is moving around this circle at a speed of [tex]v[/tex], the (centripetal) acceleration of this vehicle would continuously be [tex]a = (v^{2} / r)[/tex].

Since the upper bound of the acceleration of this vehicle is [tex]a_\text{max} = \mu_{k}\, g[/tex], rearrange the equation [tex]a = (v^{2} / r)[/tex] to find an upper bound on speed [tex]v[/tex]:

[tex]\begin{aligned}\frac{v^{2}}{r} &= a \\ & \le a_{\text{max}} \\ &= \mu_{k}\, g\end{aligned}[/tex].

[tex]v^{2} \le \mu_{k}\, g\, r[/tex].

[tex]v \le \sqrt{\mu_{k}\, g\, r}[/tex].

In other words, when the radius of the circle is [tex]r[/tex], the coefficient of friction between the tire and the ground is [tex]\mu_{k}[/tex], and the gravitational field strength is [tex]g[/tex], the maximum speed of the vehicle would be [tex]\sqrt{\mu_{k}\, g \, r}[/tex].

In this question, it is given that [tex]r = 40.0\; {\rm m}[/tex] whereas [tex]\mu_{k} = 0.60[/tex]. Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the maximum speed of this vehicle would be:

[tex]\begin{aligned}v_\text{max} &= \sqrt{\mu_{k}\, g\, r} \\ &= \sqrt{0.60 \times 9.81\; {\rm m\cdot s^{-2}} \times 40.0\; {\rm m}} \\ &\approx 15\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

The statement a,d and e are correct. The chemical equation must be balanced.

One or more compounds, known as reactants, are transformed into one or more distinct substances, known as products. Such a process is known as a chemical reaction.

The given equation is;

[tex]\rm CH_4+2O_2 \arrow \rightarrow CO_2+2H_2O[/tex]

The statements that apply in order to complete the model is;

a) The products must equal the reactants.

d) One carbon atom and two oxygen atoms are needed to balance the equation.

e) One carbon dioxide molecule should be added to the product side of the equation.

Hence, statement a,d and e are correct.

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Answer:

Taking forces along the plane

F cos θ - M g sin θ -100 = M a       net of forces along the plane

F = (M a + M g * .5 + 100) / .866     solving for F

F = (80 * 1.5 + 80 * 9.8 * .5 + 100) / .866 = 707 N

F = 707 N acting along the plane

Fn = F sin θ + M g cos θ       forces acting perpendicular to plane

Fn = 707 * 1/2 + 80 * 9.8 * .866 = 1030 Newtons   forces normal to plane

(this would give a coefficient of friction of 100 / 1030 = .097 = Fn)

Explanation:

-226 of 1600

-14 of 5730

-226×16÷100= -36.16

-14×57.3÷100= -802.2

The decay constant for radium-226 is larger than the decay constant for carbon-14.

Decay constant of radioactive substance is its probability of decay per unit time.

Decay constant for radium-226 is [tex]1.4*10^{-11} /sec[/tex]  and for carbon-14 is [tex]3.8*10^{-12} /sec[/tex].

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Answer:

The answer is C.

Explanation:

Answer:

[tex]\huge\boxed{\sf Option \ 3}[/tex]

Explanation:

[tex]\rule[225]{225}{2}[/tex]

Answer:

nerves

Explanation:

The optic nerve is the nerve in each eye that carries the signal from your eye to your brain.

Answer:

they carry a heavier load

Explanation:

Answer:

The wheels of buses and trucks are heavier than the wheels of car or scooters because the buses and trucks are heavy and require to exert less pressure. We know that when pressure decreases an area of contact increases, so the tires are broadened so that they exert less pressure on the road and move easily.  

Explanation:

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Answer:

$ .0248      or   2.48 cents

Explanation:

60 + 100 + 150 = 310 watts

  for one hour  =  310 watt- hr    or    .31 kw- hr

      .31 kw-hr   *  .08 / kw-hr  =  .0248

Answer:

90 mAmps

Explanation:

V=IR

V/R = I

9 v / 100 ohm = .09 amps = 90 mAmps