Lizard belongs to chordate phylum.
hope it helps you.
Need answer ASAP! A car runs out of gas and slowly coasts to a stop. This is an example of the following?
O A. short time, small force
B. long time, small force
O c. short time, large force
D. long time, large force
Answer: long time, small force
Dephosphorylation of glycogen synthase: ____________
a. Increase in the concentration of inorganic phosphate ion
b. Increase in the activity of glycogen phosphorylase
c. Increase of ATP concentration
d. Decreasing glycogen synthesis Increasing glycogen synthesis
e. No effect on glycogen synthesis
Answer:
b. Increase in activity of glycogen phosphorylase.
Explanation:
Glycogen synthase exists in two forms which is phosphorylated form which is covalent modification of serine residues by ATP and dephosphoryated form which is obtained using phosphatase on phosphorylated form. Glycogen phophorylase catalyzes hydrolysis of glycogen which shortens glycogen molecules.
If you were rolling dice in a casino and observed results comparable to those observed in Part 2, would you assume the dice were faulty or rigged? Explain your answer using data from your chi-square analysis.
Answer:
Yes, I would guess that the dice are faulty or rigged.
Explanation:
Yes, I would guess that the dice are faulty or rigged.
This is because the chi-square analysis indicates that there is a less than 5% probability that the difference between the expected and observed results were due to pure chance.
Is the word ‘Autotroph’ rightly used to describe animals based on nutrition? Justify
Answer:
Autotrophs are the producers in the food chain, meaning they create their own nutrients and energy
Answer: I don't think that they are known as 'Autotroph'
Explanation: Encyclopedic entry. An autotroph is an organism that can produce its own food using light, water, carbon dioxide, or other chemicals. Because autotrophs produce their own food, they are sometimes called producers.
The MN blood group in humans is under the control of a pair of co-dominant alleles, M (we will call the frequency of M, p) and N (we will call the frequency of N, q). In a group of 556 individuals, the following numbers of individuals are found for each of the genotypes:
167 MM
280 MN
109 NN
a) What is the frequency of each allele? p= q=
b) What is the value of the Chi-square statistic test to find if in this particular case the genotypic frequencies conform to the Hardy-Weinberg distribution.
Chi square value =
c) What is the probability associated with you chi square statistic calculated above? Please complete the blanks below with the corresponding symbol, < OR > than the critical value, your conclusion with respect to the null hypothesis of Hardy Weinberg equilibrium, Retain or Reject.
P value __ than 0.05
Conclusion ___ the null hypothesis of HW equilibrium
Answer:
a) f(M) = p = 0.55
f(N) = q = 0.45
b) X² = 12.12
c) P₀.₀₅ = 5.991
d) P₀.₀₅ < X²
e) Reject the null hypothesis of HW equilibrium
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
Can somebody help me
Answer:
sure what's your problem.
Explanation:
Tell me.
Reactive hyperemia is an example of .......... control of local blood flow .
and is a ........ response
A) Myogenic-Short term
B) Chemical-Long term
C) Neural-Short term
D) Metabolic-Short term
Answer:
metabolic short termExplanation:
Reactive hyperemia is the blood flow response to blood flow Occlusion whereas active active is a blood flow response to increase tissue metabolic activityFertilization, Fruit and Seed Formation x3 3. a. name the two processes that lead to seed formation in flowering
Answer:
Pollination, the transfer of pollen from flower-to-flower in angiosperms or cone ... In angiosperms, the process of seed development begins with double ...
Missing: x3 | Must include: x3
describe any four factors affecting the distribution and diversity of crustaceans in marine ecosystems
Answer:
En marina es: sobre pesca, cambio climático, especies invasoras, acuicultura. En terrestres es: inundaciones, calentamiento global, gases de invernadero, radiación reflejada.Explanation:ponme coronaOn a plant, stomates are small openings that regulate the passage of air and water vapor to and from the plant. Generally, the stomates open during sunlight and exchange gases with the atmosphere. The stomates of a few specialized desert plants can open only at night. The best explanation for the pattern of stomate opening and closing is that the desert plants are adapted to protect against
(1) harmful insects
(2) dust particles
(3) destructive plant disease
(4) excess water loss
(5) total energy loss
Please help me somebody answer this.
Answer:
4
Explanation:
this is because when the stomata opens during the day it would lose much water to the atmosphere so it tends to open during the night and close during the day
In terms of the hierarchical scales of biological organization, __1__ are a very large scale, __2__ are a very small scale, and __3__ is between them.
Answer:
ecosystem, and biosphere
organelle and cells
tissues, organs, organ systems, organisms, populations, communities,
Explanation:
In terms of the hierarchical scales of biological organization, ecosystem, and biosphere are a very large scale, organelle and cells are a very small scale, and tissues, organs, organ systems, organisms, populations and communities, are present between them. The biological levels of organization of living things arranged from the simplest to most complex are organelle, cells, tissues, organs, organ systems, organisms, populations, communities, ecosystem, and biosphere.
Which of the following are what
the different wavelengths of light
we can see make up?
A. carotene
B. the fundamental colors
C. the visible spectrum
D. light-absorbing molecules
Answer:
C. The visible spectrum
Explanation:
The visible spectrum of light makes up all of the different light wavelengths that we can see with our own eyes.
This is called visible light, and it is made up of the 7 colors of the rainbow.
The human eye can naturally detect these wavelengths of light.
So, the correct answer is C. The visible spectrum
geosphere burying organisms
hydrosphere respiration of marine life
biosphere photosynthesis atmosphere burning things
Answer:
This question is incomplete, the question is asking to match each activity with the sphere to which it adds carbon or CO2.
ANSWERS:
Geosphere = burying organisms
hydrosphere = respiration of marine life
biosphere = photosynthesis atmosphere = burning things
Explanation:
This question describes the types of spheres we have. The respective activities that occur in each sphere that adds CO2 or carbon are as follows:
- Geosphere: This refers to the solid part of the Earth. Dead organisms are buried in the geosphere (soil) where their carbon remains can be deposited.
- Hydrosphere: This constitutes all of the water bodies (sea, river, stream, ocean) on the Earth. When marine organisms respire in water, carbon dioxide (CO2) is released.
- Biosphere: A sphere consisting of all living things (plant, animal, microbes etc.) on Earth. Plants as a living organisms photosynthesize and make use of carbon dioxide to produce glucose, which stores in the plant.
Atmosphere: The gaseous component of the Earth. Burning substances release carbon based gases into the atmosphere.
An enzyme is a _____ molecule.
a. polysaccharide
b. nucleic acid
c. carbohydrate
d. protein
Antimicrobial susceptibility testing was performed to screen a novel compound. The MIC was found to be 10ng/mL. Use the following data to determine the percent recovery for each treatment group. What is the MBC and would you describe the antimicrobial tested as static or cidal?
Novel compound concentration CFU/mL Present Recovery
0ng mL 3.4 x 10^5
10ng/mL 2.4 x 10^5
20ng/mL 6.4 x 10^4
40ng/mL 1.4 x 10^4
80n mL 4.4 x 10^3
160n mL 0
Answer:
a) Percent recovery
100%, 70.58%, 4.11%, 1.29% , 0%
b) MBC = 160 ng mL
c) Static
Explanation:
A) Calculate the percent recovery for each group
i) for 0ng mL
( 3.4*10^5 / 3.4*10^5 ) * 100 = 100%
ii) for 10ng mL
( (2.4 * 10^5) / (3.4 * 10^5) ) * 100 = 70.58%
iii) for 20ng mL
( ( 6.4 * 10^5 ) / ( 3.4 * 10^5 ) ) * 100 = Nil
iv) for 40 ng mL
( ( 1.4 * 10^4 ) / ( 3.4 * 10^5 ) ) * 100 = 4.11 %
v) for 80 ng mL
( ( 4.4 * 10^3 ) / ( 3.4 * 10^5 ) ) * 100 = 1.29%
vi) for 160 n mL
percentage recovery = 0%
B) what is the MBC
The value of MBC = 160 n mL because at this concentration CFU/mL = 0
c) determine if the antimicrobial tested is static or cidal
condition : If, the ratio of MBC : MIC is ≤4 then novel compound is Cidal
MBC / MIC = 160ng / 10ng = 16 : 1
hence we can conclude that the antimicrobial tested is STATIC
what is cyclic and noncyclic photo-phosphorylation
Explanation:
The photophosphorylation process which results in the movement of the electrons in a cyclic manner for synthesizing ATP molecules is called cyclic photophosphorylation. ... During cyclic photophosphorylation, the electrons are transferred back to P700 instead of moving into the NADP from the electron acceptor
hope it helps you
8.the following one is considered as safety rule in laboratory
1 point
never eat or drink anything in the science lab
always clean up when you have finished the experiment
wear safety goggles while doing experiments
all the above
Unlike skeletal muscle, the muscle cells of the heart (called "cardiomyocytes") metabolize very little glucose, relying almost exclusively on metabolism of fatty acids for their energy. Which of the following statements are likely to be true of cardiomyocytes, but NOT skeletal myocytes? (select two answers)
a. low levels of glycogen storage, even when blood glucose is high
b. high levels of glycogen storage, even when blood glucose is low
c. low lactate production, even at high activity
d. high lactate production, even at low activity
e. many mitochondria compared to other cells
f. few mitochondria compared to other cells
Answer: A. low levels of glycogen storage, even when blood glucose is high.
C. low lactate production, even at high activity.
Explanation:
Cardiomyocytes are also known as the myocardiocytes. They are the cells which makes up make up the muscle if the heart. They're responsible for the generation of the contractile force in the heart which helps in the pumping if blood.
From the options given, the statements that are likely to be true of cardiomyocytes, but not of skeletal myocytes include:
• low levels of glycogen storage, even when blood glucose is high.
• low lactate production, even at high activity.
Answer:
The answer is A and C
Explanation:
Since cardiomyocytes are dependent on fatty acids, they rely on oxidative phosphorylation to generate energy, and consume very little glucose. Due to this, they have very low need for fermentation of pyruvate. In fact, they can absorb lactate generated by skeletal myocytes and erythrocytes and oxidize it for additional energy. Another consequence of this metabolism is that cardiomyocytes store little or no glucose as glycogen.
Skeletal myocytes and cardiomyocytes both have high energy needs and thus have more mitochondria than other cells. Cardiomyocytes have an even greater density of mitochondria than skeletal myocytes because they depend almost entirely on oxidative phosphorylation for their energy needs. This dependence on oxidative phosphorylation also explains the extraordinary sensitivity of cardiac muscle to hypoxic (low-oxygen) events. Without oxygen, cardiomyocytes rapidly run out of energy and can quickly die.
Close examination of a healthy organ reveals a lining of several layers of cells. The layers do not contain any blood vessels and one surface of the cells lines the cavity of the organ. This tissue is a type of
Answer:
fat tissue
Explanation:
is important to the transmission of nerve impulses.
a) Zinc
b) Calcium
c) Sodium
d) Iron
Please help thx
is important to the transmission of nerve impulses.
a) Zinc
b) Calcium
c) Sodium
d) Iron
[tex] \bold \pink{sodium}[/tex]
Answer:
B)Calcium
Explanation:
Have a nice day
Importance of antimicrobial emulsion
Answer:
Citral is a typical essential oil used in the food, cosmetic, and drug industries and has shown antimicrobial activity against microorganisms. Citral is unstable and hydrophobic under normal storage conditions, so it can easily lose its bactericide activity. Nanoemulsion technology is an excellent way to hydrophilize, microencapsulate, and protect this compound. In our studies, we used a mixed surfactant to form citral-in-water nanoemulsions, and attempted to optimize the formula for preparing nanoemulsions. Citral-in-water nanoemulsions formed at So 0.4 to 0.6 and ultrasonic power of 18 W for 120 seconds resulted in a droplet size of < 100 nm for nanoemulsions. The observed antimicrobial activities were significantly affected by the formulation of the nanoemulsions. The observed relationship between the formulation and activity can lead to the rational design of nanoemulsion-based delivery systems for essential oils, based on the desired function of antimicrobials in the food, cosmetics, and agrochemical industries.
What are the student’s observations and inferences before he starts his investigation?
Answer:
Hypothesis. A Hypothesis is an estimation of what might happen and the student's observation before moving on to investigate.
Schistosoma becomes infectious to humans during which of the following stages?
After cercariae migrate to the liver
After the eggs are released in urine
After it is released from the snail
After mating of male and female worms
Before the eggs hatch
Which of the following groups includes a protozoan that is transmitted sexually?
Chromalveolata
Excavata
Amoebazoa
Archaeplasteda
Rhizaria
Schistosoma becomes infectious to humans during which of the following stages?
After cercariae migrate to the liver
After the eggs are released in urine
After it is released from the snail
After mating of male and female worms
Before the eggs hatch
Which part of a mushroom would be eaten?
Thallus
Sporangium
Mycelium
Septum
Hyphae
Answer:
After it is released from the snailExcavata SporangiumExplanation:
Schistosoma life cycle:
1. Human excretes schistosomes eggs through feces and/or urine. These eggs eventually reach the water.
2. Once in the water, schistosomes eggs hatch and release immature larvae named miracides.
3. Miracides swim and penetrate a freshwater snail, which is an intermediary host.
4–5. Once inside the snail, miracides turn into sporocites and then into cercariae. Cercariae characterize by having a bifurcated tail. Snails release the cercariae in water, and they swim until they get in touch with a mammal. Once they reach the mammal, they penetrate the skin and get into the body. This is the stage in which the parasite becomes infectious to humans. Just a few cercariae are enough to infect a person.
6. When cercariae penetrate their host body, they lose their tails and turn into schistosomules. These new forms travel to the liver, where they end their maturation process.
7. Males and females mate in the liver and migrate to veins of the intestine or bladder. Once there, the females lay the eggs, which are then excreted by the host. And the cycle begins again.
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Excavata are asymmetrical protists. The group receives its name because of the appearance of the feeding groove. Excavata is composed of many protists. One of them is Parabasalid.
Parabasalids are parasitic protists, and one of them is Trichomonas vaginalis, which is transmitted sexually.
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Sporangium. This is the reproductive structure of the mushroom and the one that is usually eaten. Spores develop inside the sporangium. Its surface is covered by a protector cuticle. It can be eaten when it is closed or when it is already open. However, when open is tastier.
Which organism exhibits behavioral adaptation?
Answer:
Humans
Birds
Bears
Chameleons
Cicadas
Explanation:
A Behavioral Adaptation is something an animal does - how it acts - usually in response to some type of external stimulus.
Examples of some Behavioral Adaptions:
Migration, Hibernation, Dormancy, Camouflage.
Answer:
Behavioral adaptations are the actions that organisms take in order to stay alive. Behavioral adaptations include things like bird cries and migration. Evolution produces adaptations. Evolution is a long-term change in a species.
OAmalOHopeO:
In the oceans on either side of the Isthmus of Panama are 30 species of snapping shrimp, 15 species on the Pacific side and 15 different species on the Atlantic side. Species live at different water depths. Morphological and genetic data show that Atlantic and Pacific species that live at similar depths are sister species. The sister species on each side of the isthmus cannot interbreed because the water in the canal is fresh water, not salt water, and provides a barrier to reproduction. A sea-level, salt-water canal between the two oceans has been proposed to make transport across the isthmus easier. Which of the following outcomes is the most likely result if such a canal were built?
A. greater percentage of difference in DNA sequences between sister species that inhabit deep water than between sister species that inhabt stalow water
B. greater percentage of difference in DNA sequences between sister species that inhabit shallow water than between sister species that inhabit deep water
C. similar percentages of difference in DNA sequences between all pairs of sister species
D. greater percentage of difference in DNA sequences between Atlantic species than between Pacific species
Answer:
The options of this question are wrong, you can find the correct options by navigating on the web. The options of this question are as follow:
1) The sister species will continue to diverge from each other.
2) None of the sister species will interbreed with each other.
3) The Atlantic and Pacific shrimp will continue to live in their respective oceans and not enter the new canal.
4) Shallow-water species from the two oceans that are sister species would be more likely to interbreed with each other than would be deep-water species.
Answer:
4) Shallow-water species from the two oceans that are sister species would be more likely to interbreed with each other than would be deep-water species
Explanation:
In evolutionary biology, sister species are defined as descendant species formed when one species splits during the course of evolution. Moreover, adaptation refers to the evolutionary process of adjustment of organisms to the environment, which is usually due to natural selection. During the course of evolution, organisms under different environments must change to adapt to their environments. In this case, it is expected that sister species that live in similar environmental conditions (i.e., shallow-water species) exhibit fewer phenotypic differences, being therefore more likely to interbreed with each other.
H. pylori cannot grow in other microenvironments of the human body because the conditions are unsuitable for its growth, but other species require different conditions.
a. True
b. False
Answer:
it should be an true statement
define structure and function
Answer:
(biology) An arrangement or organization of parts to form an organ, system, or living thing. (2) (ecology) A network or a hierarchy of interrelated parts of a system. ... (4) The formation or mode of construction of a body or system from distinct units.
What two aspects of internal control must the auditor assess when performing procedures to obtain an understanding of internal control?
Explain factors that impact North Carolina ecosystems. (Examples: acid rain effects in mountains, beach erosion, urban development in the Piedmont leading to habitat destruction and water runoff, waste lagoons on hog farms, Kudzu as an invasive plant, etc.)
Answer:
Temperature, moisture, topography, elevation, soils, hydrology and disturbance.
Explanation:
Temperature, moisture, topography, elevation, soils, hydrology and disturbance are the factors that impact North Carolina ecosystems. Pollution, urbanization and invasive species inversely affected the ecosystem of North Carolina. Industries produces harmful gases that causes pollution as well as make the rainfall acidic which adversely affected the infrastructure as well as plants and animals. The introduction of invasive species also has a negative impact on the plants and animals of that ecosystem.
The large number of alveoli in lungs improve gas exchange by ________. increasing the surface area for diffusion decreasing the distance for diffusion changing the diffusion constant increasing the concentration difference
Answer:
Explanation:
The large number of alveoli in lungs improve gas exchange by . increasing the surface area for diffusion
