What is the molar mass of fluorapatite (Ca5(PO4)3F)?

Answers

Answer 1

Answer: 504.3

Explanation: Add the respective weights of each of the elements in the compound together.


Related Questions

dictwbdjdiucgahsuxijsjaashduhsh

Answers

Answer:

stroke

Explanation:

Which do you predict to have the greater electron affinity, Na or Na+ ? And why?

Answers

Na is the most stable state of the atom. Therefore Na+ will have a greater electron affinity because it wants to bring its charge back to the neutral Na. Na^+ + e- = Na

Net ionic equation for Calcium hydroxide reacting with ammonium Chloride?

Answers

Answer:

Ca(OH)₂ (aq) + 2NH₄Cl (aq) → CaCl₂ (aq) + 2NH₃ (g) + 2H₂O (l)

Ca²⁺ + 2OH⁻ + 2NH₄⁺ + 2Cl⁻ → Ca⁺² + 2Cl⁻ + 2NH₃ (g) + 2H₂O (l)

2OH⁻ + 2NH₄⁺ → 2NH₃ (g) + 2H₂O (l)

Explanation:

ca (OH)2 + 2NH4CL------> CACL2 + 2NH3 + 2H2O

Imagine you are in Spain and begin cooking some pasta for your dinner.
You notice the recipe reads "Bring water to a boil at 100 C". What is the
temperature of your water in Kelvin?
Ο OK
100 K
273 K
373 K

Answers

373 because when you go from Celsius to Kelvin you add 273.

Which properties of a reaction make it a good choice for use in a heat engine?

Answers

Since the question is so broad, the answer to this question can vary. I am assuming this simple level general chemistry so any exothermic reactions should be of good use in a heat engine. Exothermic reactions release heat, whereas endothermic reactions absorb heat.

At 20°C, the volume of chlorine gas is
15dm3. Compute the resulting volume
if the temperature is adjusted to 318K
provided that the pressure remains
the same.

Given:
Unknown:
Formula:
Solution:
Final Answer:​

Answers

Solving typed question by you

20°C=293K

Apply charles law

V1T2=V2T115(318)=293V2V2=16.27dm³

Answer:

See below ~

Explanation:

Typed question

Given :

T₁ = 20 °C = 293 KV₁ = 15 dm³T₂ = 318 K

Unknown :

V₂

Formula :

V₁/T₁ = V₂/T₂

Solution :

15/293 = V₂/318V₂ = 318/293 x 15V₂ = 1.09 x 15V₂ = 16.35 dm³

Final Answer :

16.35 dm³

Question 3 (in attachment)

Given :

V₁ = 600 mLP₁ = 700 torrV₂ = 600(1 - 1/3) = 600(2/3) = 400 mL

Unknown :

P₂

Formula :

P₁V₁ = P₂V₂

Solution :

700 x 600 = P₂ x 400P₂ = 600/400 x 700P₂ = 1.5 x 700P₂ = 1050 torr

Final Answer :

1050 torr

A can of soda gets left in the car on a hot summer day. When the can was placed in the car it had an internal temperature of 10
and pressure of 2.07 atm. If the can heats up to 47.6 what will the pressure inside the can be? Remember to convert to Kelvin! (Report your answers to 2 decimal places)

Answers

Answer:

2.35 atm

Explanation:

According to the Ideal Gas Equation,

P₁/T₁ = P₂/T₂

Here :

P₁ = 2.07 atmT₁ = 10 °C = 283 KT₂ = 47.6 °C = 320.6 K

Solving :

P₂ = P₁T₂/T₁P₂ = 2.07 x 320.6 / 283P₂ = 663.642/283P₂ = 2.35 atm (rounded to 2 DP)


What is the relationship between the enthalpy (AH) and entropy (AS) of a
reaction that is spontaneous at higher temperatures but not at lower
temperatures?

Answers

The relationship between the enthalpy (ΔH) and entropy (ΔS) of a

reaction that is spontaneous at higher temperatures but not at lower

temperatures is +ΔH, - Δs.

Relationship between enthalpy and entropy

The relationship between enthalpy (ΔH) and entropy (ΔS) is given by Gibs free energy.

ΔG = ΔH - TΔs

When ΔH < 0 and Δs < 0, ΔG = -ve  (-ΔH, - Δs) (for lower temperature)

Also, when ΔH < 0 and  Δs = +, ΔG = -ve (-ΔH, +Δs)  (for all temperature)

When ΔH > 0 and Δs < 0, ΔG = -ve  (+ΔH, - Δs) (for higher temperature)

Thus, the relationship between the enthalpy (ΔH) and entropy (ΔS) of a

reaction that is spontaneous at higher temperatures but not at lower

temperatures is +ΔH, - Δs.

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[Co(H2O)6]2+ what is the name

Answers

try hexaaquacobalt(II) cation

Which process is necessary for the formation of igneous rocks?
(A) erosion (C) magma solidification
(B) deposition (D) metamorphism

Answers

Answer:

C - magma solidification

Explanation:

Igneous rock is created through heating and cooling of magma (lava).

As hot, molten rock rises to the surface, it undergoes changes in temperature and pressure that cause it to cool, solidify, and crystallize.

What dynasty came after China's Five Dynasties and Ten Kingdoms?

Answers

Answer:

The Five Dynasties and Ten Kingdoms (907-960) is a period of great division in Chinese history, and is also the collective name for the Five Dynasties and the Ten Kingdoms.

The Five Dynasties refer to the five regimes located in the Central Plains that were successively replaced after the fall of the Tang Dynasty, namely Later Liang, Later Tang, Later Jin, Later Han and Later Zhou. At the end of the Tang Dynasty, the Five Dynasties and the beginning of the Northern Song Dynasty, there were many separatist regimes outside the Central Plains, among which more than ten separatist regimes such as the former Shu, the latter Shu, and the Northern Han were collectively referred to as the Ten Kingdoms.

Explanation:

Answer:

Mongol Yuan dynasty.

Explanation:

What is the ionic equation of a neutrilisation reaction?

Answers

Answer:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCIH2O and NaCl.

Explanation:

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[tex]\\ \orange{MaggieEve}[/tex]

1. Calculate the molar mass of sucrose (C12 H11 O22)?

Answers

Answer:

=342g

Explanation:

atomic mass of C = 12g

atomic mass of H =  1g

atomic mass of O = 16g

Solution;

    C12 H22 O11

= 12 (12) + 22 (1) + 11(16)

= 144+ 22 + 176

= 342g

Propane boils at -42C. Octane boils at 126C Which is a gas at the freezing point of water?

Answers

The substance which is a gas at the melting point of water is the gas propane.

What is freezing point?

The term freezing point refers to the point at which a liquid turns to solid. It is often the temperature as the melting point.

Thus, the substance which is a gas at the melting point of water is the gas propane.

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Determine the volume of Oxygen gas produced by decomposition of 2.44g KClO3?

Answers

Answer:

0.956 grams O₂        or
0.956 milliliters O₂   or
9.56 x 10⁻⁴ L O₂

Explanation:

If the reactant were to decompose completely, the entire balanced reaction would look like this:

2 KClO₃ --> 2 K(s) + Cl₂(g) + 3 O₂(g)

To find the answer, (1) convert the grams of KClO₃ to moles (via molar mass from periodic table), then (2) convert moles KClO₃ to moles O₂ (via mole-to-mole ratio from balanced equation), then (3) convert moles O₂ to grams (via molar mass from periodic table).

Molar Mass (KClO₃) = 39.098 g/mol + 35.453 g/mol + 3(15.999) g/mol

Molar Mass (KClO₃) = 122.548 g/mol

Molar Mass (O₂) = 2(15.999) g/mol

Molar Mass (O₂) = 31.998 g/mol

2.44 g KClO₃           1 mole KClO₃             3 moles O₂             31.998 g
--------------------  x  --------------------------  x  --------------------  x  ------------------------
                                   122.548 g             2 moles KClO₃        1 mole O₂

= 0.956 grams O₂
= 0.956 milliliters O₂
= 9.56 x 10⁻⁴ L O₂

**The prompt askes to determine the volume. As far as I know, there is no easy way to find liters/milliliters with the given information. As such, I found the mass of O₂ instead. Technically, grams is equal to milliliters, so this may be what you are looking for. Then, you can convert from milliliters to liters by dividing by 1,000 (if necessary). **

What is the change in vapor pressure when 74.10 g fructose, C6H12O6, are added to 181.5 g water (H2O) at 298 K (vapor pressure of pure water at 298 K = 3.1690 kPa, molar mass of fructose = 180.156 g/mol, molar mass of water = 18.02 g/mol)?

Answers

The change in vapor pressure when 74.10 g fructose, C6H12O6, are added to 181.5 g water is 0.146.

What is vapor pressure?

Vapor pressure is the  measure or tendency of  a substance to change into a vapor or gaseous state.

[tex]\rm Mole\; fraction\; of\; water = \dfrac{nH_2O}{nH_2O+npent.}[/tex]

Calculate the moles of water and fructose

[tex]\rm Number\;of \;moles= \dfrac{181.5 g}{18.02}= 10.072\\\\\rm Number\;of \;moles= \dfrac{74.10 g }{180.156 g/mol}=0.4113[/tex]

The total number of moles are

[tex]\dfrac{10.072}{10.072 + 0.486} = \dfrac{10.072}{10.558} = 0.953[/tex]

Calculating the vapor pressure

0.953 x 3.1690 kPa = 3.023

Change in vapor pressure

3.1690 kPa - 3.023 = 0.146

Thus, the  change in vapor pressure is 0.146.

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A balloon contains 7.2 L of
He. The pressure is reduced
to 2.00 atm and the balloon
expands to occupy a volume
of 25.1 L. What was the initial
pressure exerted on the
balloon?

Given:
Unknown:
Formula:
Solution:
Final Answer:​

Answers

Apply Boyles law

P1V1=P2V27.2(2)=25.1P214.4=25.1P_2P_2=0.57atm

Remember

If Volume is four times increased pressure is 4 times decreased

# 20 of Equilibrium
At 1500°C the system:
2NO(g)
N₂(g) + O₂(g) was allowed to come to equilibrium. The equilibrium concentrations were:
NO(g) = 0.0021 M; N₂ = O₂ = 0.239 M.
What is the value of Ke at this temperature?
Select one:
O a.
27.2
O b.
7.7 x 10-5
O c.
3.7 x 10-²
d.
1.3 x 104
O e. 8.8 x 10-3

Answers

Answer:

# 20 of Equilibrium

At 1500°C the system:

2NO(g)

N₂(g) + O₂(g) was allowed to come to equilibrium. The equilibrium concentrations were:

NO(g) = 0.0021 M; N₂ = O₂ = 0.239 M.

What is the value of Ke at this temperature?

Select one:

O a.

27.2

O b.

7.7 x 10-5

O c.

3.7 x 10-²

d.

1.3 x 104

O e. 8.8 x 10-3

Explanation:

# 20 of Equilibrium

At 1500°C the system:

2NO(g)

N₂(g) + O₂(g) was allowed to come to equilibrium. The equilibrium concentrations were:

NO(g) = 0.0021 M; N₂ = O₂ = 0.239 M.

What is the value of Ke at this temperature?

Select one:

O a.

27.2

O b.

7.7 x 10-5

O c.

3.7 x 10-²

d.

1.3 x 104

O e. 8.8 x 10-3

Which you would expect to diffuse faster, A or B?
A a gas through another gas

B a liquid through another liquid


b) explain you answer

help pls!

Answers

Answer:

A

Explanation:

I would expect a gas to diffuse through another gas faster because gases generally diffuse much faster than liquids. Hence, A is the best option.

What environment will produce the largest crystal sizes?

Construct a short Essay (Make sure you include information about Temp, Pressure, amount of dissolved solids, & cooling time)

Is there support for your Claim?

Answers

Answer:

one factor is the speed at which crystals are formed

explanation:

crystals that are formed near or on the surface tend to crystalize faster and therefore are usually smaller crystals deeper in the crust tend to crystalize slower and therefore are larger

Identify all of the ions that are
formed when H3PO4 ionizes in water

Answers

Answer:

H3PO4 + H2O (Phosphoric acid + Water)

Explanation:hope its help

Heat flows–

A. from high places to low place.

B. from colder places to hotter places.

C. from hotter places to colder places.

D. from low places to high places

Answers

Answer:

A. from high places to low places

Find the empirical formula of a compound containing 26.56% potassium, 34.51% chromium, and the remainder oxygen.

Answers

Answer:

K₂Cr₂O₇

Explanation:

Finding % of O

% O = 100% - % K - % Cr% O = 100% - 26.56% - 34.51%% O = 73.44% - 34.51%% O = 38.93%

Steps

Change % of each element into grams.Convert grams of each element into moles by dividing grams by molar mass.Divide all moles by the smallest number of moles.If the moles are all whole numbers, then you’re done and that’s your empirical formula.If not, multiply all moles by number such that everything is a whole number.

Solving

We have 26.56g of K, 34.51g of Cr, and 39.93g of O

Moles of K, n(K) = 26.56/39.0983 =  0.68 molesMoles of Cr, n(Cr) = 34.51/51.9961 = 0.66 molesMoles of O, n(O) = 38.93/15.9994 = 2.43 molesK = 0.68/0.66 ≈ 1 x 2 = 2Cr = 0.66/0.66 = 1 x 2 = 2O = 2.43/0.66 = 3.5 x 2 = 7

The empirical formula is K₂Cr₂O₇

A camel hump contains 12 kg of triacyclglycerols,

a) Given that there are 0.491 moles of ATP per gram of fat, how many moles of ATP could be produced by the fat in the camel hump?
______moles

b) If the hydrolysis of ATP releases 7.3 kcal/mole, how many kilocalories are produced by the utilization of the fat?
______kcal

Answers

The answer is 5892 moles of ATP will be produced from 12 kg of triacyclglycerols, and 43012 kcal energy will be generated by the utilization of the fat .

What are Triacyclglycerols ?

Triacylglycerols are formed by linking fatty acids with an ester linkage to three alcohol groups in glycerol.

Triacylglycerols are the form in which fat energy is stored in adipose tissue.

A camel hump contains 12kg = 12000 gm of Triacyclglycerols

a) It is given that there are 0.491 moles of ATP per gram of fat ,

So for 12000 gm of fat in camel hump 12000 * 0.491 moles of ATP will be produced .

= 5892 moles

Therefore Answer is 5892 moles .

If Hydrolysis of ATP releases 7.3 kcal/mole

so 5892 moles will produce 5892 * 7.3 kcal  

=43012 kcal energy will be generated by the utilization of the fat.

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What is the percent composition of Cesium and Fluorine in CsF?

Answers

F - 12.5
Cs - 87.5

F mass - 19
Cs mass - 132.91

What is the molecular mass

Answers

100.08 is the molecular mass.

What kind of reaction is symbolized by AB + C → CB + A?
O A. Synthesis
O B. Single replacement
O C. Double replacement
O D. Decomposition

Answers

Answer:

B. Single replacement.

Explanation:

The A in compound AB was replaced by C to make CB. Since there was only one instance of replacement, it is a single replacement reaction.

What is the boiling point of c

Answers

Answer:

90 degree is the boiling point of c

soil? Which organism in the tundra food chain would use this recycled matter?
of organisms and animal wastes.

Answers

A model of a shopping centre is drawn to scale where 1 cm on the model represent 4 m on the ground. Music shop Thabo's Sports Ware Fati's Clothing shop Grocery store PARKING Coffee shop Toilets Restaurant Shoe store Physiotherapy Health and Fitness center 1.1 Which shop is on the right of the physiotherapy? (2) 1.2 Describe the position of the Coffee Shop in relation to the Toilets. (2)

At what temperature will 13.2 grams of neon gas occupy 12.30 liters at 1.95 atmospheres? Answer

Answers

median/ neutral temperature
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