Answer:
y=-1/4x+1
Step-by-step explanation:
y-y1=m(x-x1)
y-3=-1/4(x-(-8))
y-3=-1/4(x+8)
y=-1/4x-8/4+3
y=-1/4x-2+3
y=-1/4x+1
PLEASE HELP ASAP!!!!!Sunny earns $22.75 per week delivering newspapers. He worked as a delivery boy for 3 weeks. He also earned $32.75 last
month doing chores around the house. He spent $14.25 of his total earnings to download music on his mobile device. Sunny put
of the remaining money in his savings account. Sunny used the following steps to find the total money he put in his savings
5
account:
Step 1: [($22.75 + 3) + $32.75 - $14.25)
5
Step 2: [$44.25)
Step 3: $11.0625
In which step did Sunny first make an error? Use words to explain how Sunny can correct his error.
Answer:
error in step one
Step-by-step explanation:
Sunny earns $22.75 per week delivering. delivery boy for 3 weeks.
That means $22.75 x 3 not $22.75 + 3
He can correct his mistake by doing this:
Step 1: [($22.75 * 3) + $32.75 - $14.25] * 1/ 5
Step 2: [$86.75] *1/5
Step 3: $17.35
Answer:
putting this so the other might be brainliest!
Step-by-step explanation:
also, be extremely careful, you put the link for your school and your teachers name on the top of the photo! sorry if i sound creepy lol, but yeah :)
2. Terrence is tracking his own grades. On his first quiz, he got 3 points correct out of 20
points possiblé, or 15%. On his second quiz, he got all 30 points correct.
a. How many points has Terrence earned so far?
SAS
b. How many total points were available on the two quizzes?
c. What is Terrence's percentage grade right now?
Answer:
a) 33
b) 50
c) 66%
Step-by-step explanation:
a) 3+30
b) 20+50
c) 33/50 * 100% = 66%
Also with explanation
The equation T squared = A cubed shows the relationship between a planet's orbital period, T, and the planet's mean distance from the sun, A, in astronomical units, AU. If planet Y is k times the mean distance from the sun as planet X, by what factor is the orbital period increased? k Superscript one-third k Superscript one-half k Superscript two-thirds k Superscript three-halves
Answer:
Ty = √k * Tx
The orbital period of Y has to be be multiplied by √k . or . k∧1/2
Step-by-step explanation:
The general equation:
T² = A³
is for the case of planet X
Tₓ² = Aₓ³
In the case of planet Y
Ty² = k * Aₓ³ . and Aₓ³ = Tₓ²
By substitution:
Ty² = k *Tₓ²
Ty = √k * Tx
Answer:
D: K^3/2
Step-by-step explanation:
Just took the test and this is right
To qualify for a certain car loan, a customer must have a credit score of at least 600. In addition, the cost of the car must be at least $5000. Define the variables, write a system of inequalities to represent this situation, and name one possible solution.
Answer:
c ≥ 600
p ≥ 5000
Step-by-step explanation:
Let :
credit score = c
Cost of car, p
To qualify :
Credit score must be atleast 600 ;
c ≥ 600
Cost of car must be atleast 5000
p ≥ 5000
All points of the step function f(x) are graphed.
On a coordinate plane, a step graph has horizontal segments that are each 2 units long. The left end of each segment is an open circle. The right end of each segment is a closed circle. The left-most segment goes from (negative 4, 1) to (negative 2, 1). Each segment is 1 unit higher and 2 units farther to the right than the previous segment. The right-most segment goes from (2, 4) to (4, 4).
What is the domain of f(x)?
{x| –4 < x ≤ 4}
{x| –3 < x ≤ 4}
{x| 1 < x ≤ 4}
{x| 2 < x ≤ 4}
Answer:
A. {x| –4 < x ≤ 4}
Step-by-step explanation:
Answer:
{x| –4 < x ≤ 4}
Step-by-step explanation:
Edge Quiz 2023
resolute academy algebra 1
Answer:
B
Step-by-step explanation:
We can see in the expression that there are 2 x² blocks, 4 -x blocks, and 3 -1 blocks. Therefore, we can write this as
2 * x² + 4 * (-x) + 3 * (-1) = 2x²-4x-3
Comparing this with each answer, we have
A: x²-2x-4 + x² + 2x-1 = 2x²-5. This is not correct
B: 3x²-7x+1-(x²-3x+4) = 3x²-7x+1 -x²+3x-4 = 2x²-4x-3. This seems correct but we can check the other answers to be sure
C: (2x+1)(x-3) = 2x²-6x+x-3 = 2x²-5x-3. This is incorrect
D: [tex]\frac{8x^{12} - 16x^7 - 12x^6}{4x^6} = 2x^6 - 4x - 3[/tex]. This is incorrect
Answer:
C. 2(x + 10)(x - 10)
Step-by-step explanation:
2x^2-200\\2(x^2-100)\\2(x+10)(x-10)
The scale on a map is 1 inch = 10 miles.
What is the distance, in inches, on the map
between two towns that are m miles apart?
F.
m/10
G. M/5
H.5m
J.10m
K.m+10
Answer:
F. m/10.
Step-by-step explanation:
10 miles = 1 inch
1 mile = 1/10 of an inch so
m miles = m/10 inches.
When investing money in a bank account, in which situation will you have the most money in your account at the end of three years?
Compounded semiannually
Compounded yearly
Compounded quarterly
Compounded monthly
Answer:
continuously is the most, and what is actually done at the banks...
as for your answer:
Compounded monthly
Step-by-step explanation:
When investing money in a bank account, you will have the most money in your account at the end of three years when compounded monthly.
What is compound interest?Compound interest is the interest you earn on interest.
[tex]A = P(1 + \frac{r}{n} )^{nt}[/tex]
Where,
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
To check in which situation we will earn the most money in end of three years, we calculate the final amount in each situation keeping other variables constant.
Let
P = 5000
r = 5%
t = 3 years
When compounded annually,
[tex]A = 5000(1 + 0.05)^{3} = 5788.125[/tex]
When compounded semiannually,
[tex]A = 5000(1 + 0.025)^{6} = 5798.467[/tex]
When compounded quarterly,
[tex]A = 5000(1 + 0.0125)^{12} = 5803.772[/tex]
When compounded monthly,
[tex]A = 5000(1 + 0.0125)^{12} = 5807.361[/tex]
Thus, it can be said that you have the most money in your account at the end of three years when compounded monthly.
Learn more about compound interest here
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The equation of the line in the xy-plane that has slope 7/6 and passes through (9.-6) is
a. O 6x-7y+27 = 0
b. O 7x+6y-27 = 0
c. O 6x+7y-27=0
d. 0 6x+7 y+27 = 0
e. O -7x+6y+99 = 0
f.
No Answer
Answer:
0 = 7x-6y -99
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = 7/6x+b
Using the point
-6 = 7/6(9) +b
-6 = 7*3/2 +b
-6 = 21/2 +b
Subtract 21/2 from each side
-12/2 -21/2 = b
-33/2 = b
y= 7/6x -33/2
Multiply each side by 6
6y = 7x - 99
Subtract 6y from each side
0 = 7x-6y -99
Find the lateral area of this square
based pyramid.
10 in
Sin
[ ? Jin?
Perimeter:-4a
[tex]\\ \large\sf\longmapsto 4(5)=20in[/tex]
Height=10in[tex]\boxed{\sf LSA=Height\times Perimeter}[/tex]
[tex]\\ \large\sf\longmapsto LSA=10\times 20[/tex]
[tex]\\ \large\sf\longmapsto LSA=200in^2[/tex]
Look at the figure. How can you prove ∆ABD and ∆ACD are congruent?
A.It is not possible to determine if the triangles are congruent.
B. ∆ABD ≅ ∆ACD by the SSS Postulate.
C. ∆ABD ≅ ∆ACD by the SAS Postulate.
Answer:
Options (C)
Step-by-step explanation:
For the congruence of the triangles ΔADB and ΔADC,
Statements Reasons
1). AB ≅ AC 1). Given
2). AD ≅ AD 2). Reflexive property
3). ∠BAD ≅ ∠CAD 3). Given
4). ΔABD ≅ ΔCAD 4). SAS postulate
Therefore, Options (C) will be the correct option.
5.3.8 Higher / Lower 2.0
Answer:
Higher...
Step-by-step explanation:
5.3.8 isn't really a legal number... if you meant 5.38 then it would be higher than 2. If you really meant 5.3.8 then I don't know.
Or is this code?
Say you have this: (sorry there's no indentation)
my_float = round(3.3312, 2)
while True:
guess = float(input("Guess my number: "))
if guess > round(my_float, 2):
print ("Too high!")
elif guess < round(my_float, 2):
print ("Too low!")
elif round(guess,2) == round(my_float, 2):
print("Correct!")
break
print("Great job guessing my number!")
You should be able to use the round function just like you do in the if statement. This can be done on a separate line between taking input and the if or it can be done on the same like.
guess = round(guess, 2)
Or:
guess = round(float(input(“Guess my number: “)), 2)
Hope this helped! Have a nice day!
Arc measurement with equations
Answer:
thats the question?
Step-by-step explanation:
please help me i will give 20 points for this question
Answer:
1. a. 2
b. -½
c. y - 3 = -½(x - 8) => point-slope form
y = -½x + 7 => slope-intercept form
2. a. -1
b. 1
c. y - 5 = 1(x - 3) => point-slope form
y = x + 2 => slope-intercept form
Step-by-step explanation:
1. (8, 3) and (10, 7):
a. The gradient for the line joining the points:
Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Let,
[tex] (8, 3) = (x_1, y_1) [/tex]
[tex] (10, 7) = (x_2, y_2) [/tex]
Plug in the values
Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]
Gradient = [tex] \frac{4}{2} [/tex]
Gradient = 2
b. The gradient of the line perpendicular to this line = the negative reciprocal of 2
Negative reciprocal of 2 = -½
c. The equation of perpendicular line if it passes through the first point, (8, 3):
Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).
Where,
(a, b) = (8, 3)
Slope (m) = -½
Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).
Thus:
y - 3 = -½(x - 8) => point-slope form
We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:
Thus:
y - 3 = -½(x - 8)
y - 3 = -½x + 4
y - 3 + 3 = -½x + 4 + 3
y = -½x + 7
2. (3, 5) and (4, 4):
a. The gradient for the line joining the points:
Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Let,
[tex] (3, 5) = (x_1, y_1) [/tex]
[tex] (4, 4) = (x_2, y_2) [/tex]
Plug in the values
Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]
Gradient = [tex] \frac{-1}{1} [/tex]
Gradient = -1
b. The gradient of the line perpendicular to this line = the negative reciprocal of -1
Negative reciprocal of -1 = 1
c. The equation of perpendicular line if it passes through the first point, (3, 5):
Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).
Where,
(a, b) = (3, 5)
Slope (m) = 1
Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).
Thus:
y - 5 = 1(x - 3) => point-slope form
We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:
Thus:
y - 5 = 1(x - 3)
y - 5 = x - 3
y - 5 + 5 = x - 3 + 5
y = x + 2
what is answer guys
[tex]2x(x + 1) + 1(x + 1)[/tex]
Step-by-step explanation:
ᵉᵃˢʸ ᵖᵉᵃˢʸ
2x²+2x+x+1
2x²+3x+1
There is a distance marker every 100 m and a pole every 80 m along a straight road. There is a distance marker and a pole together at the start of the road. How far along the road will there be a distance marker and a pole together again?
Answer:
At a distance of 400 m.
Step-by-step explanation:
From the information in the given question, a distance marker and pole are together at the start of the road.
Thus,
the distance marker would mark the road 100 m, 200 m, 300 m, 400 m, 500 m etc.
Also,
the pole would be located 80 m, 160 m, 240 m, 320 m, 400 m, 480 m etc.
Comparing the distance of location of the marker and pole, it would be observed that the next location where the two would be together is 400 m from the starting point.
Therefore, there would be a distance marker and a pole together at 400 m from the stat of the road.
Can anyone help me with this it’s question 2 help please
Answer: 2x³ + 2x² + 36
Working:
= (2x + 6) × (x² - 2x + 6)
= 2x³ - 4x² + 12x + 6x² - 12x + 36
= 2x³ -4x² + 6x² +12x -12x +36
= 2x³ + 2x² + 36
Answered by Gauthmath must click thanks and mark brainliest
Simplify the following
Answer:625/16 or 39,0625
Step-by-step explanation:
=5*5/2*5÷2*3/5*3
=160/64÷8/125
=625/16 or 39,0625
Answer:
Alternate form is 1525.87891
A taxi ride cost $2 for the first 1/5 of a km and 40 cents for each additional fifth of a km. Dan has $9.60. What is the longest taxi ride he can afford, in kilometres?
Answer:
4 kilometers
Step-by-step explanation:
First! Let's create an equation, with our variable (x) representing the number of additional fifth kilometers Dan can afford.
2 + 0.40x = 9.60
Now, we have to solve for our x value by subtracting 2 from both sides.
0.40x = 7.60
Next, we can divide both sides by 0.40 to find out what our x value is equal too.
x = 19
Don't forget this x value is just for the number of additional fifth kilometers Dan can afford on top of his first fifth mile.
So! Dan can afford 20 fifth kilometers, which in turn in is 4 kilometers in total.
Hope this Helps! :)
Have any questions? Ask below in the comments and I will try my best to answer.
-SGO
Find the surface area of the figure.
12 in.
SA = [ ? ]in.?
5 in.
16 in.
Answer:
SA = 664 in.²
Step-by-step explanation:
Surface area of the rectangular prism = 2(LW + LH + WH)
Where,
Length (L) = 16 in.
Width (W) = 5 in.
Height (H) = 12 in.
Substitute the values
Surface area of the rectangular prism = 2(16*5 + 16*12 + 5*12)
= 2(80 + 192 + 60)
= 2(332)
= 664 in.²
6.
Ahmad claims that the difference of squares method of factoring can be used even when the values aren't perfect squares. An example of his thinking is shown.
Answer:
Below.
Step-by-step explanation:
a. (x - √5)(x + √5)
= x(x + √5) - √5(x + √5)
= x^2 + √5x - √5x - 5
= x^2 - 5.
b. 10 - 3x^2
= (√10 - √3x) (√10 + √3x)
(a) Ahmad's factorization is correct.
(b) (√10 - √3x)(√10 + √3x)
Given equation as
x² - 5 = (x - √5)(x + √5)
What is a Perfect Square?
A Perfect Square is defined as when multiplying an integer by itself, we get a perfect square, which is a positive integer. In simple words, we can say that perfect squares are numbers that are the products of integers by themselves.
Solution of (a)
Taking RHS from the given equation
⇒ (x - √5)(x + √5)
⇒ x(x + √5) - √5(x + √5)
⇒ x² + √5x - √5x - 5
⇒ x² - 5.
So, RHS = LHS
Hence, Ahmad's factorization is correct.
Solution of (b)
⇒ 10 - 3x²
According to Ahmad's strategy
⇒ √10(√10 + √3x) - √3x(√10 + √3x)
⇒ (√10 - √3x)(√10 + √3x)
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Help plz!! Trig question
Answer:
5 meters tall.
Step-by-step explanation:
We know that angle A (the bird) is 55. The opposite side from this angle is 4.5 meters, since that is the distance she is from the tree. From this, we can set up an equation tan(55)=4.5/x and simplify it to x= 4.5/tan(55). This would be height x, but it is not accounting for the 1.5 meters the apple is off the ground, so you need to add 1.5 to the result. The final answer would be 4.65 but you need to round to the nearest meter so it would be 5.
5. Dylan walks into a video arcade with a pocketful of quarters. He spends them
at a rate of nine every half hour until he runs out. If the amount of quarters Dylan
has is graphed over time, which feature of the graph corresponds to Dylan's
initial amount of quarters, before he spends the first one?
The y-intercept
The slope
The x-intercept
The minimum value
Answer:
The y-intercept
Step-by-step explanation:
Have a good day :)
Find the missing segment in the image below
Answer:
Step-by-step explanation:
Given the preimage and image, find the dilation scale factor
Answer:
1/2
Step-by-step explanation:
the dilation factor should be 1/2
if u count the dots on the sides of the preimage there are 2 dots that's the length if u count the dots on the real image it's 4therefore 2/4 to it's lowest term is 1/2 so 1/2 is the scale factorAnswer:
should be 1/2 as your answer
Angela works a basic week of 40 hours and her hourly rate of pay is $12.50. Calculate her weekly wage.
Answer:
$500
Step-by-step explanation:
Answer:$500
Step-by-step explanation:
To calculate the weekly wage, take the hourly rate and multiply it by the number of hours worked. For this question it would be:
$12.50 x 40
=$500
That is your weekly wage
Hope this helped! <3
pls pls pls help meeeeee
Answer:
i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3
Step-by-step explanation:
Pls help and fast! 17 points!
Answer:
54 square units
Step-by-step explanation:
144 - 18 - 4(18) = 54 square units
The volume of a sphere is 3,000π m3. What is the radius of the sphere to the nearest meter?
Answer:
13m
Step-by-step explanation:
volume of sphere = [tex]\frac{4}{3} * pi * r^{3}[/tex] = 3000π
4r^3/3 = 3000
r^3 =2250
r = ∛2250 = 13.10370 = 13
Answer:
Radius of the sphere is 13.1 m.
Step-by-step explanation:
Volume:
[tex]{ \boxed{ \pmb{volume = { \bf{ \frac{4}{3}\pi {r}^{3} }}}}}[/tex]
Substitute:
[tex]{ \tt{3000\pi = \frac{4}{3} \times \pi \times {( {r}^{3}) } }} \\ \\ { \tt{ {r}^{3} = \frac{3000 \times 3}{4} }} \\ \\ { \tt{r = \sqrt[3]{ \frac{3000 \times 3}{4} } }} \\ { \tt{r = 13.1 \: m}}[/tex]
