what is the differences in length between a 1 1/4 inch butten and a 3/8 inch button

Answer:

1,000 + 200 + 50 + 6

Yes it is.

Use the Pythagorean Theorem:

a²+b²= c²

So, 17²+144²=145²

289+20736=21025

289+20736=21025

21025=21025

x=5/4

the explantion would be to long lol

Answer:

x = [tex]\frac{5}{4}[/tex]

Step-by-step explanation:

3(x - 5) - 5x = - 25 + 6x ← distribute parenthesis and simplify left side

3x - 15 - 5x = - 25 + 6x

- 2x - 15 = - 25 + 6x ( subtract 6x from both sides )

- 8x - 15 = - 25 ( add 15 to both sides )

- 8x = - 10 ( divide both sides by - 8 )

x = [tex]\frac{-10}{-8}[/tex] = [tex]\frac{5}{4}[/tex]

The correct answer would be 3. f(x) = -1, so you got to find the -1 in the y row of the table and just say that x =3 if y =-1.

Answer:

x = 3

Step-by-step explanation:

The question is asking for which value of x gives -1

You don't have an equation, however you do have a table of values

Y is similar to f(x) in the sense that it is the output, while x is the input.

All you must do is see where y = -1, this is the same for when f(x) = -1

So, there is only one moment where y = -1, which is when x = 3

With this, we can conclude that for the value of x = 3, f(x) = -1

Answer:

[tex]d=2[/tex] and [tex]d=3[/tex]

Step-by-step explanation:

[tex]d^2-5d+6=0[/tex]

[tex](d-2)(d-3)=0[/tex]

[tex]d=2[/tex] and [tex]d=3[/tex]

Answer:

22.

Step-by-step explanation:

About 22 chicken wings must be purchased for the total cost at Buffalo Bart’s Endless Wings and The Spicy Chicken to be the same.

Let's represent the number of chicken wings as "x".

The total cost at Buffalo Bart’s Endless Wings would be the sum of the initial cost for sides and a drink ($5.60) and the cost per chicken wing ($0.40 per wing times x):

Total cost at Buffalo Bart’s Endless Wings = $5.60 + $0.40x

The total cost at The Spicy Chicken would be the sum of the initial cost for sides and a drink ($10) and the cost per chicken wing ($0.20 per wing times x):

Total cost at The Spicy Chicken = $10 + $0.20x

To find the number of chicken wings where the total costs are the same, we'll set up an equation:

$5.60 + $0.40x = $10 + $0.20x

Now, solve for "x":

$0.40x - $0.20x = $10 - $5.60

$0.20x = $4.40

Divide both sides by $0.20:

x = $4.40 / $0.20

x = 22

So, about 22 chicken wings must be purchased for the total cost at Buffalo Bart’s Endless Wings and The Spicy Chicken to be the same.

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Answer:

heres the square root of 20 4.47214 but i dont know what else to do for this answer. (sorry)

Step-by-step explanation:

√20 = √(4 * 5) = √4 * √5 = 2√5 ≈ 4.47214

Answer:

The linear model means that there is a uniform increase and in this case of US population from  92  million people in  1910  to  250  million people in  1990 .  

This means an increase of  250 − 92 = 158  million in  1990 -1910 = 80  years or   158 80 = 1.975  million per year and in  x  years it will become   92 + 1.975 x  million people. This can be graphed using the linear function  1.975 ( x − 1910 ) + 92 ,

graph{1.975(x-1910)+92 [1890, 2000, 85, 260]}

The exponential model means that there is a uniform proportional increase i.e. say  p %  every year and in this case of US population from  92  million people in  1910  to  250  million people in  1990 .  

This means an increase of  250 − 92 = 158  million in  1990 − 1910 = 80  years or  

p %  given by  92 ( 1 + p ) 80 = 250  which gives us  ( 1 +p ) 80 = 250 92  which simplifies to  p = ( 250 92 ) 0.0125 − 1 = 0.0125743  or  1.25743 % .  

This can be graphed as an exponential function  92 × 1.0125743 ( x − 1910 ) , which gives population in a year  y  and this appears as graph{92(1.0125743^(x-1910)) [1900, 2000, 85, 260]}

Step-by-step explanation:

Hope this helps

Answer:

24 kilograms of catfish

Step-by-step explanation:

Take the percentage of catfish as a decimal or fraction and multiply it by the total amount of fish caught. The percent of catfish is 40% which is the same thing as 0.4. Multiply that by the total 60 kg of fish to get 24 kg of catfish.

Answer:

B. between -2 and -1

Step-by-step explanation:

Brainlyist please

Answer:

where is your Question??????

Answer:

3/8 is is bigger then 3/12

Step-by-step explanation:

The reason is that 3/12 is equivalent to 2/8 and 3/8 is equivalent to 6/16

Sorry if its wrong! ^^""

As, 0.375> 0.25, so, 3/8 is greater than 3/12.

Here, we have,

To get the answer, we first convert each fraction into decimal numbers.

We do this by dividing the numerator by the denominator for each fraction as illustrated below:

3/8 = 0.375

3/12 = 0.25

Then, we compare the two decimal numbers to get the answer.

0.375 is greater than 0.25.

i.e. 0.375> 0.25, as 0.375 - 0.25 = 0.125

Therefore, 3/8 is greater than 3/12.

Hence, As, 0.375> 0.25, so, 3/8 is greater than 3/12.

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78

Step-by-step explanation

by adding all the number and divide by the number of number

Answer:

78

Step-by-step explanation:

add all and divide by 7

Answer:

x=21

Step-by-step explanation:

[tex]x-5=16[/tex]

[tex]x-5+5=16+5[/tex] (Add 5 to bth sides)

[tex]x=21[/tex]

Answer:

1/2

Step-by-step explanation:

8×+1=5

8×=5-1

8×=4

×=4/8=1/2

Answer:

uhj hdctui nomar binary 34.89

Answer:(0,4)

Step-by-step explanation:

Answer:

m = -15/29

Step-by-step explanation:

1) Distribute

[tex]\frac{m}{5} =6m+3[/tex]

2) Subtract 6m from both sides of the equation

[tex]\frac{m}{5} -6m=6m+3-6m[/tex]

3) Simplify

a. Find common denominator

[tex]\frac{m}{5} +\frac{5(-6)m}{5} =6m+3-6m[/tex]

b. Combine fractions with common denominator

[tex]\frac{m+5(-6)m}{5} =6m+3-6m[/tex]

c. Multiply the numbers

[tex]\frac{m-30m}{5} =6m+3-6m[/tex]

d. Combine like terms

[tex]\frac{-29m}{5} =6m+3-6m[/tex]

e. Combine like terms

[tex]\frac{-29m}{5} =3[/tex]

4) Multiply all terms by the same value to eliminate fraction denominators

[tex]5 *\frac{-29m}{5} =5*3[/tex]

5) Cancel multiplied terms that are in the denominator

[tex]-29m=5*3[/tex]

6) Multiply the numbers

[tex]-29m=15[/tex]

7) Divide both sides of the equation by the same term

[tex]\frac{-29m}{29} =\frac{15}{-29}[/tex]

8) Simplify

a. Cancel terms that are in both the numerator and denominator

[tex]m=\frac{15}{-29}[/tex]

b. Divide the numbers

[tex]m=-\frac{15}{29}[/tex]

The inequality that represents all possible values for x is  x ≥ -27.

Linear inequality refers to the relation between a linear algebraic expression to some known value that contains inequality sign.

Unlike a linear equation it can have a range of values inside an interval.

The given statement can be written in terms of inequality as,

2/3x - 6 ≥ -24

=> 2/3x  ≥ -24 + 6

=> 2/3x  ≥ -18

=> x ≥ -27

Hence, the inequality expression for the given problem can be written as x ≥ -27.

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Answer: HEre finnaly this is right..

Part A: When the marine biologist concluded her study, the length of the fish was approximately 6.86 cm. What is a reasonable domain to plot the growth function?

0≤x≤8

Part B: What does the y-intercept of the graph of the function f(m) represent?

the length at the start of the study

Part C: What is the average rate of change of the function f(m) from m = 3 to m = 7, and what does it represent?

6.86−5.047−3=1.82

it represents the average growth in length of the fish from the 3rd month to the 7th month of the study

Step-by-step explanation:

Answer:

x >= 12

Step-by-step explanation:

2x + 7 <= 3x - 5

7 + 5 <= 3x - 2x

12 <= X

Queremos ver que fracción de la finca se ha destinado a plazas de aparcamiento.

La solución es:

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

Sabemos que originalmente se iba a destinar 3/14 del total de la finca a plazas de aparcamiento, pero finalmente se destino 3/4 de lo previsto a zonas ajardinadas.

Es decir, se destino 3/4 de los 3/14 del total de la finca a zonas ajardinadas, entonces el 1/4 restante se dedico a plazas de aparcamiento, esto da:

(1/4)*3/14  = 3/56

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

Sí quieres aprender más, puedes leer:

https://brainly.com/question/16649102

Answer:

522250

How to round to the nearest tenth:

Whenever you want to round a number to a particular digit, look only at the digit immediately to its right. For example, if you want to round to the nearest tenth, look to the right of the tenths place: This would be the hundredths place digit. Then, if it is 5 or higher, you get to add one to the tenths digit. If it is 4 or lower, the tenths digit remains the same.

For example, 3.58 can be rounded to 3.6 because the hundredths place digit, 8 is greater than or equal to 5.

3.32 would be rounded to 3.3, because the hundredths place digit, 2, is less than 5.

cihfoufiyfoffuutgjkao

The spider's movement is an illustration of a parabola.

(a) The equation

The spider passes through the origin.

So, we have:

[tex]\mathbf{(x,y) = (0,0)}[/tex]

The spider jumps to a maximum height of 20mm, midway 160mm.

So, the vertex is:

[tex]\mathbf{(h,k) = (80,20)}[/tex]

The equation of a parabola is:

[tex]\mathbf{y = a(x - h)^2 + k}[/tex]

So, we have:

[tex]\mathbf{0 = a(0 - 80)^2 + 20}[/tex]

[tex]\mathbf{0 = 6400a + 20}[/tex]

Subtract 20 from both sides

[tex]\mathbf{6400a =- 20}[/tex]

Solve for a

[tex]\mathbf{a =- \frac{1}{320}}[/tex]

Substitute [tex]\mathbf{a =- \frac{1}{320}}[/tex] and [tex]\mathbf{(h,k) = (80,20)}[/tex] in [tex]\mathbf{y = a(x - h)^2 + k}[/tex]

[tex]\mathbf{y = -\frac{1}{320}(x - 80)^2 + 20}[/tex]

(b) The focus, directrix and the axis of symmetry

The focus of a parabola is:

[tex]\mathbf{Focus = (h,k+p)}[/tex]

Where:

[tex]\mathbf{p = \frac{1}{4a}}[/tex]

So, we have:

[tex]\mathbf{p = \frac{1}{4\times -1/320}}[/tex]

[tex]\mathbf{p = -\frac{320}{4}}[/tex]

[tex]\mathbf{p = -80}[/tex]

So, we have:

[tex]\mathbf{Focus = (80 , 20-80)}[/tex]

[tex]\mathbf{Focus = (80 ,-60)}[/tex]

The axis of symmetry is:

[tex]\mathbf{x = h}[/tex]

So, we have:

[tex]\mathbf{x = 80}[/tex]

The directrix is:

[tex]\mathbf{y = k - p}\\[/tex]

So, we have:

[tex]\mathbf{y = 20+80}[/tex]

[tex]\mathbf{y = 100}[/tex]

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9514 1404 393

Answer:

  y = 2x +1

Step-by-step explanation:

The line rises 2 units for each 1 unit to the right, so its slope is ...

  m = rise/run = 2/1 = 2

The line crosses the y-axis at y = 1, so the y-intercept is ...

  b = 1

Then the slope-intercept form equation is ...

  y = mx + b . . . . . . . for slope m and y-intercept b

  y = 2x + 1 . . . . . . . . fill in the known values

Answer:

yes, since 513 has more than two factors

have a spook-tastic day

Step-by-step explanation:

Answer:

option D

Step-by-step explanation:

this trianle will be congurent by SSS method easily

Answer:

Option D.SSS These triangles congruent with SSS property

Hello Carousel!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex]

First, let's take I as ⇨ [tex]\tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex].

[tex]\tt \:I = \int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x +1}} \: dx \\\tt \: I =\int \: \frac{ x + 2 }{( {x}^{2} + 2x + 1 + x + 2) \sqrt{x + 1}} \: dx \\ \tt \:I =\int \: \frac{ x + 2 }{( ({x + 1}^{2}) + x + 2) \sqrt{x + 1}}[/tex]

Let, x + 1 = m² => dx = 2mdm.

[tex]\tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: m} 2mdm \\ \tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: \bcancel{ m}} 2 \bcancel{m}dm \\ \tt \: I = \: \int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 } 2dm[/tex]

Now, divide the numerator & denominator by m²....we'll get it as...

[tex]\tt \:I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{ {m}^{2} + 1 + \frac{1}{ {m}^{2} } } \: dm \\\tt \: I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{( {m}^{2} + \frac{1}{ {m}^{2} } - 2) + 3} \: dm \\\tt \: I =2\int \: \frac{ (1 + \frac{1}{ {m}^{2} }) \: dm }{ ({m} - \frac{1}{ m } ) ^{2} + 3} [/tex]

Now, let m - 1/m be t => (1 + 1/m²) dm = dt

[tex]\tt \:I =2\int \: \frac{ dt}{ {t}^{2} + 3 } \\ \tt \:I = 2\int \: \frac{ dt}{ {t}^{2} + ( \sqrt{3}) ^{2} }[/tex]

We know, [tex]\tt \:\int \: \frac{dx}{ {x}^{2} + a ^{2} } = \frac{1}{a} tan ^{ - 1} (\frac{x}{a} ) + c[/tex]...therefore...

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{t}{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 1}[/tex]

Now, substitute the value of 't' in eq. 1..we'll get..

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{m - \frac{1}{m} }{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 2}[/tex]

Now, substitute the value of 'm' in eq. 2...we'll get...

[tex] \tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}[/tex]

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