Answer:
One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.
Explanation:
The magnetic field lines of a bar magnet spread out from the
A. north end to the south end.
B. south end to the north end.
C. edges to the center.
D. center to the edges.
Answer:
I think the letter B. But I'm not sure pero I try mo Lang po baka Yan po ang tamang sagot kac Yan po Yung nilagay na sagot saakin e Kaya try mo Lang po
what is the gravitation potential energy of a 57 kg sightseer standing at the top of the empire state building which is 381m above ground level
GPE = mgh
GPE = 57 x 9.8 x 381 = 2.12 x 10⁵ J
. True or False: A bystander intervention is the term used to define when an individual actively moves in and changes the outcome of a situation.
Answer:
true
Explanation:
a toy car needs a source of energy to move. how could you give gravitational potential energy to a toy car so that it will move when you let it go?
Answer:
wait one second im about to go get some milk im thirsty
Explanation:
do you want any chicken on your salad
How much kinetic energy does a 0.30-kg stone have if it is thrown at44
Answer:
290.4 joules
Explanation:
As the formula to find kinetic energy is 1/2 mv^2.
So if we put the given data in it,the answer comes 290.4 joules
What is specific heat capacity??
Specific heat capacity is the unit mass of a substance is defined as the amount of heat absorbed (kg) (J), when its temperature rises 1 K (or 1 ° C), and its units J / ( kg K) or J / happen. (Kg ° C).Hope it helps u
Stay safe, stay healthy and blessed.Have a good day !Thank you
#Jennifer
Answer:
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
-10m/s² and vertical height of 0.6m.How will we use this information to find the velocity of the falling object?
Why are current and resistance kept very low?
A. To prevent excess heat.
B. Because the voltage is also quite low.
C. Both A. and B.
D. None of the above.
Answer:
I think the answer is B.
Explanation:
If the resistance is too high, the current will be low even if the voltage is enough.Derive the Schrödinger's Time independent wave equation using kinetic energy and momentum.
Consider,
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]
Multiply both sides by ih and simplification will yield
[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]
Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]
Integrating by parts and knowing the same fact by some simplification will yield:
[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]
The momentum is thus contained within the wave function, so we can then deduce that:
[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]
[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]
[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
Now the kinetic energy
[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]
The classical formula for the total energy
[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]
Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having
[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]
This is the Famous Time-Independent Schrödinger wave equation
Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer
Why the range of a clinical thermometer kept between 35°C and 42°C?
Answer:
Because it is the standard operational range for measuring the body temperature of a living individual.
Explanation:
When making a measuring equipment like a thermometer, you attempt to keep the reading range (Span) as small as possible so that the reading is as accurate as feasible. Because sensors are often rated in percent of span (in this example, span = 45 C–32 C = 13 degrees Celsius), One percent of 13 equals 0.13 degrees Celsius, thus if your sensor has a usual accuracy of 1%, your temperature reading is accurate to roughly 0.1 degrees Celsius.
Your precision would be 0.2 degrees Celsius if you doubled the span. The reading accuracy is now becoming unsatisfactory. Readability is another advantage of analog and mercury clinical thermometers. The markings for 0.1 deg C would be ten times closer together if a mercury thermometer had ten times the range (span). There is a limit to the device's readability.
1. The sketch shows two 4 kg blocks on a horizontal surface, joined by a string S. They are attached to a 2 kg mass by another string which passes over a frictionless pulley, allowing the 2 kg mass to hang freely. Each of the blocks experiences 6 N of friction.
a) Show that the system accelerates to the right at 0.8 m/s². Calculate the tension in string S.
b) 4 kg S 4 kg 2 kg [4] [4]
Answer:
M g - T = M a acceleration of hanging block (M = 2)
2 g - T = 2 a where M = 2
T = 2 g - 2 a
T = 8 * a + 12 N acceleration of blocks on table
2 g - 2 a = 8 a + 12
10 a = 2 g - 12
a = .8 m/s^2 (assuming g = 10 m/s^2)
T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N
Check: For blocks on table
a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2
A small object with a mass of 1 kg moves in a circular path with a constant speed of 5 m/s. What is the change in momentum during 1⁄2 of period; one period?
The change in momentum of the object during the half period is -10 kgm/s.
The change in momentum of the object during the one period is 0.
Change in momentum of the object during ¹/₂ period
The change in momentum of the object during the half period is calculated as follows;
ΔP(¹/₂) = Pf - Pi
where;
Pf is final momentumPi is the initial momentumΔP(¹/₂) = (-5 x ) - (5 x 1)
ΔP(¹/₂) = -10 kgm/s
Change in momentum of the object during 1 periodΔP(1) = Pf - Pi
ΔP(1) = (5 x 1) - (5 x 1) = 0
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Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is
1. The object or point from which movement is determined is called a
of
Answer: reference point
Explanation: A reference point could be a put or question utilized for comparison to decide in case something is in movement.
what is the main function of a diode
Answer:
acts as a one-way switch for current
What arguments can you think of for staying single
Answer:
Staying single makes it a whole lot easier to focus on yourself, gain self love, and work on yourself!
Explanation:
What kind of object are the light rays interacting with in the model below?
Convex mirror
Convex lens
Concave mirror
Concave lens
Answer:
Concave lens
.............
An empty hot air balloon weighs 1000 newtons (N). As the balloon is released in the air, the atmosphere provides a lift force of 3300 N. What is the magnitude and direction of the net force?
2300 N upward
4300 N upward
2300 N downward
4300 N downward
[tex]\Large{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}[/tex]
2300 N upward
Explanation:
The force by weight of balloon = 1000 N
The atmospheric force experienced by balloon = 3300 N
While weight of balloon is attracted by gravity so the force of weight will act downward
And the atmospheric force gives upward lifting force to the balloon
Net force = atmospheric force - weight of balloon
= 3300 - 1000
= 2300 N
As the atmospheric force is more dominating the balloon will goes upward with 2300 N force
A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?
Answer:
0.315C
Explanation:
Force/Electric field
7520N/23900C
Air is a good medium for sound waves because it is
Answer:
air does not have a modulus of rigidity.
Explanation:
Since air is completely elastic medium, that is, it does not have a modulus of rigidity, therefore sound waves in air are longitudinal.
calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high
Answer:
529.2 joules
Explanation:
Work done = force x distance = mass x gravity x distance
= 36x9.8 x1.5 =529.2 joules
!!!
MULTIPLE CHOICE QUESTION
If a simple machine has a MA of 5 and you lift an object UP 2 m, how far must you push the
object along the ramp's surface?
0.5 m
10 m
0.2 m
1 m
Answer:
0.5
Explanation:
I think it is this beacause if u have the answer you have that
4) The specific heat of aluminum is 0.88 J/g °C. How much heat is released when a 10 g piece of aluminum foil is taken out of the oven and cools from 100° to 50°?
4.40 J
568 J
440 J
Answer:
See below
Explanation:
The units of the specific heat hint at how to solve these types of problems
.88 J/(g-C) * 10 g * (100- 50 C) = 440 J
( see how the g and the C 'cancel out' ?)
Monitoring cash flow and keeping track of the bottom line of a business are responsibilities for whom?
What do you like MOST about your chosen learning modality
86. What is the average velocity if the initial velocity is at rest and the final velocity of 16 m/s? a) 16 m/s b) 12 m/s c) 8 m/s d) 4 m/s
Answer:
8 m/s
Explanation:
(16-0)/2 = 8 m/s
A tourist, who weighs 805 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops one-fourth of the way along the bridge. Assume that the board of the bridge has negligible weight. What is the magnitude of the vertical force that a concrete support exerts on the bridge at the far end?
The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
What is force?The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
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1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.
2. A sound wave has a time period of 0.01 seconds. What is its frequency?
3. A radio wave has a time period of 0.0000002 seconds. What is its frequency?
1)The period of these ripples will be 0.2 sec.
2)The time period of sound wave will be 100 Hz.
3)The frequency of the sound wave will be 5×10⁶ Hz.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
Frequency of ripples (f₁)=5 Hz
The period of these ripples will be;
T₁=1/f₁
T₁=1/5
T₁=0.2 sec
The time period of sound wave (T)=0.01 seconds
The time period of sound wave;
f=1/T
f=1/0.01
f=100 Hz
Time period of A radio wave = 0.0000002 seconds
The frequency of the sound wave is;
f=1/T
f=1/0.0000002
f=5×10⁶ Hz
Hence,the period of these ripples will be 0.2 sec.
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7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.
The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.
What is centrifugal force?when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.
It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.
The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.
To simulate gravity for the inhabitants, the concept of the centrifugal force is used.
Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.
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A body of mass 200gram is executing SHM with amplitude of 20mm. The magnitude of maximum force which acts upon it is 0.6N. Calculate its maximum velocity?
Given ,
Mass of the body (m) = 200g
Amplitude (A) = 20mm
Maximum force (F) = 0.6 N
Maximum velocity (vmax) =?
We know that
Fmax = mv2max/A
or , 0.6 = 200×10-3xv2max/20×10-3
or , 0.6×20/200= v2max
or , vmax = 0.24 m/s
∴ Maximum velocity = 0.24 m/s2
The value of maximum velocity will be 0.3464 m/s². Energy or work is equal to the product of force and displacement.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
Mass of the body is,(m= 200g)
Amplitude is,(A =20 mm)
Maximum force is,F= 0.6 N
To find;
Maximum velocity
Energy or work is equal to the product of force and displacement.
[tex]\rm KE = \frac{1}{2} mV_{max}^2 \\\\ \rm F_{max} \times A = \frac{1}{2} mV_{max}^2 \\\\ F_{max}= \frac{1}{2}\frac{ mV_{max}^2}{A} \\\\ 0.6= \frac{1}{2}\times \frac{ 0.2 \times V_{max}^2}{20 \times 10^{-3}} \\\\ V_{max}=0.3464 \ m/sec^2[/tex]
Hence,the value of maximum velocity will be 0.3464 m/s².
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