Answer:
The coefficient of x is 2.
Step-by-step explanation:
1) Add the numbers
7y + 4x + 4 - 2x + 8
7y + 4x + 12 - 2x
2) Combine like terms
7y + 4x + 12 - 2x
7y + 2x + 12
3) Rearrange items
7y + 2x + 12
2x + 7y + 12
y = 3
3y + 78 + 6y + 13
Step-by-step explanation:
the thing you need to do here is put the value of x and just simply the expression.....
= 3y + 78 + 6y + 13
= 3 × 3 + 78 + 6 × 3 + 13
= 9 + 78 + 18 + 13
= 118
[tex]....[/tex]
Answer:
3×3+78+6×3÷13
9+78+18÷13
88.38
Step-by-step explanation:
i m not sure if it's correct since i didn't follow tye bodmas rule properly and it was bit tricky and it comes in decimal so not sure if it's correct
Problem 6.1
Which number is larger?
12x10^9
4x10^9
Answer:
7 7^10
1 5^9
yan po yung sagot
sana makatulong
URGENT MATH QUESTION MIDDLE SCHOOL
Answer:
A
Step-by-step explanation:
There is an even number of values.
Hope it helps
Sorry if I’m wrong
13 of 15
L
Find the x-intercepts of the parabola with
vertex (-1,-17) and y-intercept (0,-13).
Write your answer in this form: (*1,91),(X2,42).
Answer:
(√30 - 1, 0)(-√30 - 1, 0)Step-by-step explanation:
Making the equation of the parabola :
⇒ y = a(x - h)² + k
⇒ y = (x + 1)² - 17 - 13
⇒ y = (x + 1)² - 30
x-intercepts have y = 0 :
0 = (x + 1)² - 30(x + 1)² = 30Taking the square root on each side :
√(x + 1)² = √30x + 1 = ±√30x = ±√30 - 1The x-intercepts are :
(√30 - 1, 0)(-√30 - 1, 0)How to solve this problem???
[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \underset{\textit{we'll use this one}}{log_a a^x = x}\qquad \qquad a^{log_a x}=x \end{array} \\\\[-0.35em] ~\dotfill\\\\ 2.7e^x-5 ~~ = ~~33.6\implies 2.7e^x~~ = ~~38.6\implies e^x=\cfrac{38.6}{2.7} \\\\\\ \log_e(e^x)=\log_e\left( \cfrac{38.6}{2.7} \right)\implies x=\ln\left( \cfrac{38.6}{2.7} \right)\implies x\approx 2.66[/tex]
If you use mobile payment and lose your phone, you should NOT:
OA. Cancel your card.
OB. Get a new phone and keep using the same card in the app.
OC. Remotely lock your device.
OD. If possible, clear the data off of your device.
Reason:
Yes you should get a new phone, but you should not keep using the same card. Whoever has your phone (assuming anyone found it or stole it) may be able to gain access to the phone, and use the card fraudulently. You should call the credit card company and cancel that card, and get a new card. This is why choice A is eliminated. Choices C and D are eliminated as well so that you protect your privacy from any potential thieves.
Find the different angle measures
The different angle measures are
1. [tex]m\angle EBD = 34^\circ[/tex]
2. [tex]m\angle ACE = 52^{\circ}[/tex]
3. [tex]m \overset{\LARGE\frown}{GB} = 76^\circ[/tex]
4. [tex]m \overset{\LARGE\frown}{GBD} = 256^\circ[/tex]
5. [tex]m \angle DBA= 90^\circ[/tex]
6. [tex]m \overset{\LARGE\frown}{GD} = 104^\circ[/tex]
7. [tex]m\angle DFC= 56^\circ[/tex]
Calculating measures of anglesFrom the question, we are to determine the measures of the different angles
1.
From the given information,
[tex]m \overset{\LARGE\frown}{HD} = 68^\circ[/tex]
This implies that the measure of the central angle is 68°
Then,
[tex]m\angle EBD = \frac{1}{2} \times 68^\circ[/tex] (Angle at the center is twice the angle at the circumference)
∴ [tex]m\angle EBD = 34^\circ[/tex]
2.
From the diagram
[tex]m\angle ACE + m\angle BED + 90^\circ = 180^\circ[/tex]
From the given information
[tex]m\angle BED = 38^\circ[/tex]
Then,
[tex]m\angle ACE + 38^\circ + 90^\circ = 180^\circ[/tex]
[tex]m\angle ACE + 128^{\circ} = 180^\circ[/tex]
[tex]m\angle ACE = 180^\circ-128^{\circ}[/tex]
[tex]m\angle ACE = 52^{\circ}[/tex]
3.
First, we will determine [tex]m \overset{\LARGE\frown}{GD}[/tex]
[tex]m \overset{\LARGE\frown}{GD} = 2 \times m\angle ACE[/tex] (Angle at the center is twice the angle at the circumference)
[tex]m \overset{\LARGE\frown}{GD} = 2 \times 52^\circ[/tex]
[tex]m \overset{\LARGE\frown}{GD} = 104^\circ[/tex]
But,
[tex]m \overset{\LARGE\frown}{GD} + m \overset{\LARGE\frown}{GB} = 180^\circ[/tex]
[tex]m \overset{\LARGE\frown}{GB} = 180^\circ - m \overset{\LARGE\frown}{GD}[/tex]
[tex]m \overset{\LARGE\frown}{GB} = 180^\circ - 104^\circ[/tex]
[tex]m \overset{\LARGE\frown}{GB} = 76^\circ[/tex]
4.
[tex]m \overset{\LARGE\frown}{GBD} = m \overset{\LARGE\frown}{GB} + 180^\circ[/tex]
[tex]m \overset{\LARGE\frown}{GBD} = 76^\circ +180^\circ[/tex]
[tex]m \overset{\LARGE\frown}{GBD} = 256^\circ[/tex]
5.
[tex]m \angle DBA= 90^\circ[/tex] (Tangent and diameter/ radius theorem)
If a tangent and a diameter meet at the point of tangency, then they are perpendicular to one another
6.
[tex]m \overset{\LARGE\frown}{GD} = 104^\circ[/tex] (As determined above)
7.
First, we will determine [tex]m\angle GFB[/tex]
[tex]m\angle GFB + m\angle EBD + 90^\circ = 180^\circ[/tex]
[tex]m\angle GFB = 180^\circ -(m\angle EBD + 90^\circ)[/tex]
[tex]m\angle GFB = 180^\circ - (34^\circ+90^\circ)[/tex]
[tex]m\angle GFB = 180^\circ - 124^\circ[/tex]
[tex]m\angle GFB = 56^\circ[/tex]
[tex]m\angle GFB = m\angle DFC[/tex] (Vertically opposite angles)
[tex]m\angle DFC= 56^\circ[/tex]
Hence, the different angle measures are
1. [tex]m\angle EBD = 34^\circ[/tex]
2. [tex]m\angle ACE = 52^{\circ}[/tex]
3. [tex]m \overset{\LARGE\frown}{GB} = 76^\circ[/tex]
4. [tex]m \overset{\LARGE\frown}{GBD} = 256^\circ[/tex]
5. [tex]m \angle DBA= 90^\circ[/tex]
6. [tex]m \overset{\LARGE\frown}{GD} = 104^\circ[/tex]
7. [tex]m\angle DFC= 56^\circ[/tex]
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Which expression is equivalent to 6^4 • 6^3?
(6•6•6•6)+(6•6•6)
(6+6+6+6)•(6+6+6)
(6•6•6•6)•(6•6•6)
(6•6•6•6•6)•(6•6•6•6)
Answer: C)
Step-by-step explanation:
11.4 Conversions of Polar and Rectangular Coordinates
What are the approximate coordinates in the rectangular plane that represent the polar coordinates (6,- pi/6)
? Round values to the nearest thousandth.
Answer: A - (5.196, -3)
Step-by-step explanation: correct on ed
In Detroit the high temperatures in degrees Fahrenheit for
five days in January were -12°, -8°, -3°, 6°, -15°. What was the
average temperature for these five days?
Answer:
-6.4 degrees.
Step-by-step explanation:
The average temperature
= (-12 -8 -3 + 6 - 15) / 5
= -32/5
= -6.4 degrees.
What is the slope of the line that passes through the points (-2, 2), and (-4, -2)?
• -1/2
• 2
• -2
• 1/2
Answer:
-2
Step-by-step explanation:
Slope of a line, given two points : formatslope=y2−y1x2−x1=4−2−2−(−1)=2−1=−2
A triangle has vertices T(3, 7), U(6, -6), and V(5, -9).
The image of the triangle has vertices T'(8, 1), U'(-5,
4), and V'(-8, 3).
Which transformations could have produced the
image?
OT(1.-2) ° Ty=x
Ory=x0 T(1, -2)
O Ta. -2) o Ro, 180°
O
O Ro. 180
Ta. -2)
Step-by-step explanation:
y=2x find the value of y and x
Which is the graph of x≤2?
Answer:
Graph 2
Step-by-step explanation:
We are given the inequality x≤2
First off, with the inequality sign being ≤ rather than <, we know that 2 is also included. This means that x can be equal to 2 or less than 2.
Since 2 is included, we know we are looking for a solid line.
That said, we can eliminate the 1st and 4th graphs because there is a dotted line at 2, meaning that 2 is not included.
Next, based on the inequality sign, we know that values less than 2 satisfy it. So judging by the shaded region on each graph, we see that Graph 2 is the one that satisfies it.
For clarity's sake, one trick you can use is thinking of the inequality sign as an arrow. If it points left, values toward the left should be shaded and vice versa.
Lastly, I'll give you the inequality for each graph.
Graph 1: x<2
Graph 2: x≤2
Graph 3: x≥2
Graph 4: x>2
Hope that helps, let me know if you have any questions!
What is the slope of the line that
passes through these two points?
(2, 3)
(2,9)
Answer:
Slope = undefined.
Step-by-step explanation:
Given two points:
(2,3) & (2,9)To Find:
The slopeSolution:
Using slope's formulae,
[m denotes slope]
[tex] \boxed{ \rm{m = \cfrac{y_2 -y_1 }{x_2 - x_1} }}[/tex]
According to the question,here:
(y_2,y_1) = (9,3)(x_2,x_1) = (2,2)Substitute them onto the formulae:
[tex] \rm \: m = \cfrac{9 - 3}{2 - 2} [/tex]
Simplify.
[tex] \rm \: m = \cfrac{6}{2 - 2} [/tex]
[tex]\rm \: m = \cfrac{6}{0} = \boxed{ \rm \: undefined}[/tex]
if an expression contains division by 0 , then It's undefined.
So, slope(m) = undefined.
I don't understand. Help please.
Answer:
the H stands for hours. the E stands for money. because it says 10h that means she gets $10 per hour. that answers the first question. I don't understand the second part though. hope you get it!
Please show work and thank you
Answer: [tex]4\sqrt{7}[/tex]
Step-by-step explanation:
If [tex]AC=16, DC=7[/tex], then this means [tex]AD=9[/tex].
So, by the geometric mean theorem, [tex]DB=\sqrt{(9)(7)}=\sqrt{63}[/tex].
This means that by the Pythagorean theorem, [tex]BC=\sqrt{\left(\sqrt{63} \right)^{2}+7^{2}}=\boxed{4\sqrt{7}}[/tex]
HELP! PLEASE! I will mark you brainalist!!!!!
Answer:
Step-by-step explanation:
Problem a
a is an isosceles triangle. It has 2 sides marked as equal. Therefore the two angles marked in red are also equal.
The top angle = x
x + 70.5 + 70.5 = 180 All triangles have 180 degrees.
x + 141 = 180 Subtract 141 from both sides
x + 141-141 =180 - 141 Combine
x = 39
c + 39 + 87.2 =180 Combine the left
c + 126.2 = 180 Subtract 126.2 from both sides
c+126.2-126.2 = 180-126.2
c = 53.45
Answer: 53.45
Problem B
Comment
Problem b can only be found by taking the supplements of the two given angles. After that is done, the vertically opposite angle to d can be found because d is opposite the third angle.
Supplement of 115.6
Call the supplement = y
y + 115.6 = 180 Supplementary angles = 180 degrees
y +115.6-115.6 = 180 - 115.6 Combine
y = 64.2
Now we need the supplement of 99.9
Call the supplement = z
z + 99.9 = 180 Supplementary angles = 180
z+99.9-99.9 = 180-99.9
z = 80.1
Now subtract y + z from 180
180 - 64.2 - 80.1 = x
x = 35.7
x is opposite d
d = x
d = 35.7 degrees.
Answer
d = 35.7
Which is a property of polygons?
A polygon has a maximum of 100 sides
A polygon is a solid figure
A polygon is a open figure
A polygon is a plane figure
Answer:
A polygon is a plane figure.
Step-by-step explanation:
This means it is a 2 dimensional shape that lies flat, it has length and width, it has area but no thickness.
There is no max number of sides, so the first answer is not right.
In math, saying it is solid means its 3-d, so that is not right (it's only 2-d)
Saying its open, means that somewhere on the shape, the sides don't meet up at a corner, like an animal corral with the gate left open. So that's not right. Part of the definition of a polygon is that it is closed.
It is a 2-d shape with straight sides and closed, it lies flat in a plane. The last answer is correct.
Answer:
A polygon is a plane figure.
please answer this question
Answer:
[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx = \boxed{ - \frac{\sqrt{x^4 + 1} (8x^8 - 4x^4 + 3)}{30x^{10}} + C }[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Rule [Basic Power Rule]:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integration
IntegralsIntegration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration Methods: U-Substitution, U-Solve, Trigonometric Substitution
Step-by-step explanation:
*Note:
The problem is too big to fit all work. I will assume that you know how to do basic calculus.
Step 1: Define
Identify given.
[tex]\displaystyle \int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integrand] Rewrite:Step 3: Integrate Pt. 2
Identify variables for u-substitution/u-solve.
Set u:Step 4: Integrate Pt. 3
Start solving the integral using u-solve:
[tex]\displaystyle \begin{aligned}\int {x^{-11}(1 + x^4)^\Big{- \frac{1}{2}}} \, dx & = \int {\frac{1}{x^{11}\sqrt{x^4 + 1}}} \, dx \\& = \int {\frac{1}{2u^6 \sqrt{u^2 + 1}}} \, du \\& = \frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du \\\end{aligned}[/tex]
Step 5: Integrate Pt. 4
Identify variables for trigonometric substitution.
Set u:Step 6: Integrate Pt. 5
Let's focus on just the integral itself. Apply the Trigonometric Substitution Integration Method and other basic integration techniques listed under "Calculus":
[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\\end{aligned}[/tex]
Step 7: Integrate Pt. 6
Identify variables for u-substitution/u-solve again.
Use another variable besides u to avoid confusion with earlier substitutions:
Set w:Step 8: Integrate Pt. 7
Reduce the integral using the U-Solve Integration Method and other basic integration techniques listed under "Calculus":
[tex]\displaystyle \begin{aligned}\int {\frac{1}{u^6 \sqrt{u^2 + 1} }} \, du & = \int {\frac{\sec^2 v}{\tan^6 v \sqrt{\tan^2 v + 1} }} \, dv \\& = \int {\frac{\sec v}{\tan^6 v}} \, dv \\& = \int {\cot v \csc v (\csc^2 v - 1)^2} \, dv \\& = \int {-(w^2 - 1)^2} \, dw \\& = - \int {(w^2 - 1)^2} \, dw \\& = - \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw \\\end{aligned}[/tex]
Step 9: Integrate Pt. 8
Solve the integral using basic integration techniques listed under "Calculus":
[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \Bigg[ \int {w^4} \, dx - \int {2w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \int {w^4} \, dx - 2 \int {w^2} \, dx + \int {} \, dx \Bigg] \\& = - \Bigg[ \frac{w^5}{5} - \frac{2w^3}{3} + w + C \Bigg] \\& = - \frac{w^5}{5} + \frac{2w^3}{3} - w + C \\& = - \frac{\csc^5 v}{5} + \frac{2\csc^3 v}{3} - \csc v + C \\\end{aligned}[/tex]
[tex]\displaystyle\begin{aligned}- \int {\bigg( w^4 - 2w^2 + 1 \bigg)} \, dw & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{5u^5} + \frac{2(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{u} + C \\\end{aligned}[/tex]
Step 10: Integrate Pt. 9
Let's substitute our integral value into our integral from "Step 4":
[tex]\displaystyle\begin{aligned}\frac{1}{2} \int {\frac{1}{u^6 \sqrt{u^2 + 1}}} \, du & = - \frac{(u^2 + 1)^\Big{\frac{5}{2}}}{10u^5} + \frac{(u^2 + 1)^\Big{\frac{3}{2}}}{3u^3} - \frac{\sqrt{u^2 + 1}}{2u} + C \\& = - \frac{(x^4 + 1)^\Big{\frac{5}{2}}}{10x^{10}} + \frac{(x^4 + 1)^\Big{\frac{3}{2}}}{3x^6} - \frac{\sqrt{x^4 + 1}}{2x^2} + C \\& = \boxed{ - \frac{\sqrt{x^4 + 1}(8x^8 - 4x^4 + 3)}{30x^{10}} + C } \\\end{aligned}[/tex]
∴ we have found the indefinite integral.
___
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Topic: Calculus
Part A: Which polynomial below is a fourth-degree polynomial in standard form? Explain how you know it is a fourth-degree polynomial and how do you know it’s in standard form.
(Image Below)
Part B: Explain the closure property as it relates to polynomials and give an example.
In the given question, all the equations are fourth degree polynomial because they all have the highest power of 4
What is degree of polynomial?A polynomial's degree is the highest or the greatest power of a variable in a polynomial equation.
In the given question, all the equation are fourth degree polynomial
2x^3 -3x^2 + 1 + 5x^45x^4 + 2x^3 -3x^2 + 1-3x^2 + 1 + 5x^4 + 2x^31 - 3x^2 + 2x^3 + 5x^4What closure property relates here is that when we add two different polynomial, the result will definitely be a polynomial.
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This is frying my brain, can anyone help and explain?
Answer:
1) Answer is D
2) Answer is C
3) Answer is D
Step-by-step explanation:
Problem 1
Since we are given 12 numbers to choose from, there's a 2/12 chance of selecting a 2. Additionally, there's a 3/11 chance of selecting a number divisible by 4 AFTER selecting a 2. Thus, since the two events are independent, their probabilities are multiplied, so the probability of selecting a 2 and then a number divisible by 4 is (2/12)(3/11) = 6/132 = 1/22, so option D is correct.
Problem 2
There's a 4/12 chance of selecting an odd number and a 6/11 chance of selecting an even number AFTER selecting an odd number (remember that 0 is neither even nor odd). Multiplying the probabilities, the probability of drawing an odd number and then drawing an even number is (4/12)(6/11) = 24/132 = 2/11, so option C is correct.
Problem 3
There's a 2/12 chance of selecting a zero and a 1/11 chance of selecting a second zero. Thus, multiplying their probabilities, the probability of drawing 2 zeroes is (2/12)(1/11) = 2/132 = 1/66, so option D is correct.
PLS HELP ASAP WILL GIVE BRAINLIEST
Answer:
C
Step-by-step explanation:
None of the others are vertical angles
a is supplementary angles
b is supplementary angles
d is alternate interior angles
Ivan bought a suit on sale for $152. This price was 60% less than the original price.
What was the original price?
Work Shown:
x = original price in dollars
x - 60% of x = x - 0.60x = 0.40x = sale price in dollars
0.40x = 152
x = 152/0.40
x = 380
find the local maximum and minimum values using the Second Derivative Test.
Answer:
Find the first and second derivatives:
[tex]\begin{aligned}f(x) & =-x-\dfrac{9}{x}\\& =-x-9x^{-1}\\\\\implies f'(x) & =-1-(-1)9x^{(-1-1)}\\ & =-1+9x^{-2}\\ & = -1+\dfrac{9}{x^2}\\\\\implies f''(x) & = 0+(-2)9x^{(-2-1)}\\& = -18x^{-3}\\& = -\dfrac{18}{x^3}\end{aligned}[/tex]
To find the stationary points (local minimum and maximum) set the first derivative to zero and solve for x:
[tex]\begin{aligned}f'(x) & = 0 \\\\\implies -1+\dfrac{9}{x^2} & = 0 \\\\\dfrac{9}{x^2} & = 1 \\\\9 & =x^2\\\\\implies x & = \pm 3\end{aligned}[/tex]
To determine the type of stationary points, input the found values of x into the second derivative.
[tex]f''(3)=-\dfrac{18}{3^3}=-\dfrac{2}{3} < 0 \implies \textsf{maximum}[/tex]
[tex]f''(-3)=-\dfrac{18}{(-3)^3}=\dfrac{2}{3} > 0 \implies \textsf{minimum}[/tex]
Finally, to find the y-values of the stationary points, input the found values of x into the original function:
[tex]f(3)=-3-\dfrac{9}{3}=-6 \implies (3,-6)[/tex]
[tex]f(-3)=-(-3)-\dfrac{9}{-3}=6 \implies (-3,6)[/tex]
Therefore:
[tex]\large \begin{array}{ r | r | c | c }\textsf{At} \: x= & \textsf{and} \: y= & \textsf{sign of} \: f''(x) & \textsf{conclusion}\\ \cline{1-4} -3 & 6 & + & \textsf{minimum} \\ \cline{1-4} 3 & -6 & - & \textsf{maximum}\end{array}[/tex]
Suppose the figure above is translated 2 units left and 4 units up. The translated figure is then dilated with a scale factor of 3, centered at the origin. Which is the ordered pair for the image of C?
Which is the value of the 4 in 5,138.204?
Answer:
thousandths
Step-by-step explanation:
John has 9 boxes of apples. Each box holds 10 apples. If 7 of the boxes are full, and 2 of the boxes are half full, how many apples does John have?
A. 29
B. 90
C.80
D. 45
Answer:
80
Step-by-step explanation:
10x7=70
2x5=10
70+10=80
Find the slope and the -intercept of the line. y=x+8
Answer:
slope = 1
y intercept = (0,8)
Step-by-step explanation:
the equation y = x + 8 is put in y = mx + b form
where m = slope and b = y intercept
in the equation y = x + 8 , the value of "m" is 1 meaning the slope is 1 and the value of "b" is 8 so the y intercept is (0,8)
Answer:
m = 1 and b = 8
Step-by-step explanation:
y = x + 8
Here the slope is 1, since y = mx+ b. m is the slope so m = 1. b is the
y-intercept so b=8
Tanner bought 6 chocolates. Maggie bought c times as many chocolates as Tanner. Write an expression that shows how many chocolates Maggie bought.
Answer:
The equation that we most use to find how many chocolates Maggie bought would be:
6 x c = how many chocolates Maggie bought
Maggie bought c times as many chocolates as Tanner. This means to find how many chocolates Maggie bought we would multiply the c (Being how many times more chocolates Maggie bought) by 6 to find the number of chocolates Maggie bought`.
For example:
If the question stated Maggie bought 4 times as many chocolates as Tanner, the equation would be; 6 x 4 = how many chocolates Maggie bought. Which would be 24 chocolates.
Step-by-step explanation:
Have a great rest of your day
#TheWizzer
3/4 : 6/x = 3/8 : 4/5 : 6/7
The value of x will be equal to 3 for the given expression.
What is a fraction?The fraction is defined as the division of the whole part into an equal number of parts.
Given expression is solved as:-
[tex]\dfrac{\dfrac{3}{4} }{\dfrac{6}{x}} = \dfrac{3}{8}[/tex]
[tex]\dfrac{3}{4}\times \dfrac{x}{6}=\dfrac{3}{8}[/tex]
[tex]\dfrac{x}{8}=\dfrac{3}{8}[/tex]
x = 3
The value of x will be equal to 3 for the given expression.
Therefore the value of x will be equal to 3 for the given expression.
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