What is the answer to this math problem?

Answer:

33 Is your answer :)

Step-by-step explanation:

Always do P.E.M.D.A.S ( always go in order it gives you) parenthesis, exponets, multiply/divide, and add/subtract

5^3+6*3=

15+18= 33

Answer:

8 squared units

Sorry if this answer is not correct, if it is or is not, please tell me in the comments!

Step-by-step explanation:

Rectangle:

To find the area of the rectangle, we need to mutiply the base and the height. 3 units(base) x 2 units(height) = 6 squared units

Triangle:

To find the area of the triangle is very similar to finding the area of the rectangle. We need to multiply the base and the height and divide it by 2.

Base= 2 units(since it is a rectangle, the opposite side is the same length)

Height = 2 units

Next, we plug it in to this formula: 1/2 bh (b = base and h = height)

multiplying by one half is the same as dividing by 2

The area of the triangle is 2 x 2 = 4

4 divided by 2 = 2 squared units

For the final step, we add the areas together. (6+2 = 8) the label is very important (squared units)

Answer: C

Step-by-step explanation:

This is a Pythagorean triple.

Answer:

i. 31/25

ii. 1/5

Step-by-step explanation:

you know that tanx = 3/4, so you can also find that sinx = 3/5 and cosx = 4/5. Then you can use the double angle identities to find cos2x and sin2x: cos^2(x) - sin^2(x) + 2sinxcosx and substitute the givens to get 31/25. Then, cosx - sinx is obviously 1/5.

Answer:

state the problem

ask relevant questions

perform an experiment to collect data

compare with the baseline value of the control group

arrive at a logical conclusion

make a hypothesis

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: - 10 + 5(78 + 8) < - 4s + 3 - 8[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 10 + 5(86) < - 4s - 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 10 +430 < - 4s - 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: 420 + 5 < - 4s [/tex]

[tex]\qquad \sf  \dashrightarrow \: 42 5 < - 4s [/tex]

[tex]\qquad \sf  \dashrightarrow \: 42 5 \div 4 < - s [/tex]

[tex]\qquad \sf  \dashrightarrow \: 106.25 < - s [/tex]

Inequalities change when it is multiplied by -ve number

[tex]\qquad \sf  \dashrightarrow \: - 106.25 > s [/tex]

Answer:

There's no real roots

Answer:

No.

Step-by-step explanation:

The graph will not cut the x-axis.

Using an arithmetic sequence, it is found that the clock chimes 132 times in a 24-h period.

In an arithmetic sequence, the difference between consecutive terms is always the same, called common difference d.

The nth term of an arithmetic sequence is given by:

[tex]a_n = a_1 + (n - 1)d[/tex]

In which [tex]a_1[/tex] is the first term.

The sum of the first n terms is given by:

[tex]S_n = \frac{n(a_1 + a_n)}{2}[/tex]

In this problem, as the day is divided in two 12-hours period, the total will be twice the sum of the 12 elements of the following sequence:

{0, 1, 2, 3, ..., 11}

In which [tex]a_1 = 0, a_11 = 11, n = 12[/tex].

Then:

[tex]T = 2\frac{12(0 + 11)}{2} = 12 \times 11 = 132[/tex]

The clock chimes 132 times in a 24-h period.

More can be learned about arithmetic sequences at https://brainly.com/question/6561461

Answer:

y = 4

Step-by-step explanation:

Use slope intercpet form: y = mx + b

Answer:

its Y (bottom left graph)

Step-by-step explanation:

i graphed the function on desmos and matched it

Answer:

Yes

Step-by-step explanation:

Anything muliplied by zero end up equalling zero. So with this in mind we can put 0 in for x and find out what each eqautian equals.

2(0) + 6(0) = 0; Once we multiply both sides we end up adding 0 and 0, so it equals 0

9(0) = 0

Since, 0 = 0 they are both equal.

Hope this helps!

Answer:

x = -16

Step-by-step explanation:

[tex]\frac{1}{4}x-6=-10 < ==add\ 6\ to\ both\ sides\\ \ \ \ \ \ \ \ \ +6 \ \ \ \ \ \ \ \ +6\\\\\frac{1}{4}x=-4 < ==multiply\ both\ sides\ by\ 4\\4(\frac{1}{4}x=-4)\\\\x=-16 < ==final\ answer[/tex]

Hope this helps!

Answer:

1. Acute, because it is less than 90 degrees or less than a right angle.

2. that is obtuse because it is bigger than 90 degrees

3. acute, because it is less than 90 degrees.

Answer:

1. Acute 2. Obtuse 3. Acute

Step-by-step explanation:

1 and 3's angles are smaller than 90 degrees. 2 is obtuse because its angle is larger than 90 degrees.

Ariana paid a 3.6% interest rate on the loan.

Simple interest is defined as interest paid on the original principal and calculated with the following formula:

S.I. = P × R × T, where P = Principal, R = Rate of Interest in % per annum, and T = Time, usually calculated as the number of years. The rate of interest is in percentage r% and is to be written as r/100.

We have been given data as:

Principal (P) = $2000

Simple interest = $144

Time (T) = 2 years

⇒ Simple interest  = P × R × T

Substitute the value of P and T in the above formula,

⇒ 144  = 2000 × R × 2

⇒ 144  = 4000 × R

⇒ R = 144/4000

Apply the division operation, and we get

⇒ R = 0.036

⇒ R = 3.6 %

Therefore, Ariana paid a 3.6% interest rate on the loan.

Learn more about the simple interest here:

brainly.com/question/22621039

#SPJ2

Answer:

6. $62.74 7.$331

Step-by-step explanation:

6. The original cost= $119.5

After 30% of discount = (70/100)× 119.5

= $83.65

After 25% discount = (75/100)× 83.65

= $62.74

7. Original cost= 679

Price after 35% discount = (65/100)×679=$441.35

Price after 25% discount = (75/100)× 441.35

=$331

So the final price will be = $331

Answer:

First one.

Step-by-step explanation:

Quantity is usually the best way to know people's preference, that's why Family Feud asks 100 people for their question's answers. This answer may be wrong, since this question is a bit due to opinion. Hope this helps! <3

Answer:

0.6

Step-by-step explanation:

apply the volume of cylinder and equal both of them because both contain same amount of water.

see the picture for full solution

Answer:

  A.  50°

Step-by-step explanation:

The external angle ACB created by tangents CA and CB is the supplement of arc AB it intercepts.

  ∠ACB = 180° -AB

  ∠ACB = 180° -130°

  ∠ACB = 50°

[tex]\large{\mathcal{QUESTION:}}[/tex]

An elliptical mirror has an eccentricity of 0.8. The mirror is surrounded by a 2-inch wide golden frame and is 34 inches tall including the frame. If a replacement mirror is being cut from a rectangular sheet of glass, what is the minimum dimensions needed for the sheet of glass?

[tex]\large{\mathcal{ANSWER:}}[/tex]

B. 17 inches by 8 inches

The minimum dimensions needed for the sheet of glass are B. 17 inches by 8 inches

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

We are given that elliptical mirror has an eccentricity of 0.8.

Since the mirror is surrounded by a 2-inch wide golden frame and is 34 inches tall including the frame. If a replacement mirror is being cut from a rectangular sheet of glass,

We can conclude that the minimum dimensions needed for the sheet of glass could be;

17 inches by 8 inches

Learn more about the area;

https://brainly.com/question/1658516

#SPJ2

Answer:

The Answer is 1 cup and 4 oz, I'm sorry if incorrect..>~<

Answer:

The Answer is 1 cup and 4 oz.

Step-by-step explanation:

2qts + 1cup equals 72 oz. 6oz x 10=60oz.

72 oz - 60 oz = 12 oz. 1 cup and 4 oz.

Answer:

x = -4, y = 3

Step-by-step explanation:

1. Substitute 2x + 11 for y:

5x + 2(2x + 11) = -14

2. Simplify:

2(2x) = 4x
4x + 5x = 9x, 2(11) = 22
so,

9x + 22 = -14

3. Isolate x:

9x + 22-22 = -14-22 = 9x -36

9x/9 = -36/9

x = -4

4. Plug in the value of x in to solve for y:

y = 2(-4) + 11

y = 3

hope this helps!

Answer:

a is when you need to go from 12 to 5 so is this flvs?

Step-by-step explanation:

Answer:

a)

first you need to find the missing lengths the first one would be

12-7=5
and the second one you will need to find the circumference
π*4*2=8π
and now you add

12+7+5+5+3+8π=32+8π
so the perimeter is 32+8π

b)

so lets make some sections

one of the sections will be a rectangle that is 8 in length and 7 in width
8*7=56units^2
and another reactangle that is 3 in length and 5 in width

3*5=15units^2
and then we need to find the area for the semicircle with a raidius of 4
π*4^2=16πunits^2
them divide by 2
(16π)/2=8pi
so the area would be 71+8π

Step-by-step explanation:

Answer:

The answer would be y=3.5x+7

Step-by-step explanation:

This is because there is a one-time fee of $7, meaning there is no x attached with it. 3.5 has an x with it because it is 3.5 per hour, and not just one time. Hope this helps! :)

4374

Step-by-step explanation:

We are multiplying by 3 each time

2*3 = 6

6*3 =18

18*3 = 54

The formula is

an = 2 * 3^(n-1)  where n is the term number

a8 = 2 * 3^(8-1)

a8 = 2 * 3^7

a8 = 2*2187

a8 = 4374

Answer:

4374

Step-by-step explanation:

First term, a =2

Common ratio, r = 3

nth term = a.r^(n-1)

where , n is the number of terms

8th term = 2.(3)^(8–1)

=2(2187)

=4374

⇒ A geometric progression, sometimes termed a geometric sequence, is a series of integers in which each term after the first is determined by multiplying the preceding one by a fixed, non-zero value known as the common ratio.

Answer:

the #1 one is about 307.88 & the #2 on is 100.53

Step-by-step explanation:

Answer:

308 in³, 101 in³ (from left to right)

Step-by-step explanation:

Volume of cylinder= πr²h, where r is the radius and h is the height.

Cylinder on left

radius= 7 in

height= 2 in

Volume

= π(7²)(2)

= 98π

= 308 in³ (3 s.f.)

Cylinder of right

radius= 4 in

height= 2 in

Volume

= π(4²)(2)

= 32π

= 101 in³ (3 s.f.)

Let first consider the equations one by one and will be solving one by one ;

[tex]{:\implies \quad \sf x+\dfrac{1}{y}=4}[/tex]

Multiplying both sides by y will lead ;

[tex]{:\implies \quad \sf xy+1=4y}[/tex]

[tex]{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}[/tex]

Now, consider the second equation which is ;

[tex]{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}[/tex]

Multiplying both sides by x will yield

[tex]{:\implies \quad \sf xy+1=\dfrac{x}{4}}[/tex]

[tex]{:\implies \quad \sf xy=\dfrac{x}{4}-1}[/tex]

[tex]{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}[/tex]

As LHS of both equations (i) and (ii) are same, so equating both will yield;

[tex]{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}[/tex]

Multiplying both sides by 4 will yield

[tex]{:\implies \quad \sf 16y-4=x-4}[/tex]

[tex]{:\implies \quad \sf 16y=x}[/tex]

Dividing both sides by y will yield :

[tex]{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}[/tex]

Hence, the required answer is 16

Answer:

30 pages

Step-by-step explanation:

https://brainly.com/question/17253194

Speed is the change in distance of a body with respect to time.

Speed = Distance/Time

If the library made a copy of leslie's 3 page essay in just 1/10 of a minute, this means that she made 3 pages in (1/10 * 60)secs i.e 6secs

To get the speed, we need to calculate the amount of page of essay that are produced in a minute (60secs).

If 3 page essay = 6secs

x page essay = 60 secs

cross multiply

3*60 = 6x

180 = 6x

x = 180/6

x = 30

This shows that 30 page essays are produced in just a minute. Hence the speed of the copy machine is 30page essay/min.

first off let's change the mixed fractions to improper fractions, and let's Hailey's account first.

[tex]\stackrel{mixed}{9\frac{1}{4}}\implies \cfrac{9\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{37}{4}} ~\hfill \stackrel{mixed}{8\frac{7}{8}}\implies \cfrac{8\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{71}{8}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &\stackrel{43000(2)}{\$86000}\\ P=\textit{original amount deposited}\dotfill & \$43000\\ r=rate\to \frac{71}{8}\%\to \frac{~~ \frac{71}{8}~~}{100}\dotfill &0.08875\\ t=years \end{cases} \\\\\\ 86000=43000e^{0.08875\cdot t}\implies \cfrac{86000}{43000}=e^{0.08875t}\implies 2=e^{0.08875t}[/tex]

[tex]\ln(2)=\ln(e^{0.08875t})\implies \log_e(2)=\log_e(e^{0.08875t})\implies \ln(2)=0.08875t \\\\\\ \cfrac{\ln(2)}{0.08875}=t\implies 7.81\approx t[/tex]

ok, now we know how long it takes for Hailey's money to double, how much money does Aiden have by then?

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$43000\\ r=rate\to \frac{37}{4}\%\to \frac{~~ \frac{37}{4}~~}{100}\dotfill &0.0925\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &\frac{\ln(2)}{0.08875} \end{cases}[/tex]

[tex]A=43000\left(1+\frac{0.0925}{12}\right)^{12\cdot \frac{\ln(2)}{0.08875}}\implies A=43000\left( \frac{4837}{4800} \right)^{\frac{12\ln(2)}{0.08875}}\implies \boxed{A\approx 88311}[/tex]

notice, in Hailey's amount we used the logarithmic value for "t", just to avoid any rounding issues.