What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 n at an angle of 35° above the horizontal? 0.23 m/s2 0.28 m/s2 2.52 m/s2 3.60 m/s2

The work done in moving the sled 35 feet when force is aligned from the horizontal is 1583.9 lb.ft

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

W = Fs cos θ

Given is the distance d =35 ft ,the force exerted F = 64lb and the angle of force from the horizontal direction is 45°.

Substituting the values, work done will be

W =64 x 35x cos 45°

W = 1583.9 lb.ft

Thus, the work done will be 1583.9 lb.ft

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The radius of the circle in which the plane is flying is 1887 m.

The aerodynamic lift is the force that keeps the aircraft flying in the air.

Let the  aerodynamic lift be F1 sinθ= mv^2/R ---- (1)

and F1 cosθ= mg --------- (2)

Equating (1) and (2) and eliminating the mass;

R = v^2/ g tanθ

Where v = 490 km/h or 136 m/s

R = (136)^2/9.8 * tan 45

R = 18496/ 9.8

R = 1887 m

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This question involves the concepts of current, power, and charge.

a) The power of taser is "2.75 watt".

b) The magnitude of charge flow per second "2.5 x 10⁻³ C/s".

c) Electrons flow per second is "1.56 x 10¹⁶ electrons/s".

The power of the taser can be given by the following formula:

P = IV

where,

Therefore,

P = (2.5 x 10⁻³ A)(1100 V)

P = 2.75 Watt

The charge flow per second is equal to the current passing through taser.

[tex]\frac{q}{t}=I[/tex]

where,

Therefore,

[tex]\frac{q}{t}=2.5\ x\ 10^{-3}\ C/s[/tex]

The electron flow per second is given by the following formula:

[tex]I = \frac{q}{t} = \frac{ne}{t}\\\\\frac{n}{t}=\frac{q}{te}[/tex]

where,

Therefore,

[tex]\frac{n}{t}=\frac{2.5\ x\ 10^{-3}\ C/s}{1.6\ x\ 10^{-19}\ C}\\\\\frac{n}{t}=1.56\ x\ 10^{16}\ electrons/s[/tex]

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The property of the ball that is constant is acceleration because the rate of it's distance is constant.

Constant acceleration refer to the rate of the velocity of the body that is moving at constant rate or when the rate of change of distance of an object with respect to time is constant.

Therefore, The property of the ball that is constant is acceleration because the rate of it's distance is constant.

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inelastic collision

75.3+60.5=(75+60)v'

225+300=135v'

v'=3.8 m/s

direction = positive = right

The statement 'research indicates that high serotonin levels may increase aggression' is FALSE.

Serotonin is a chemical messenger (i.e., a hormone) used to transmit messages through the body.

In conclusion, the statement 'research indicates that high serotonin levels may increase aggression' is FALSE.

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Answer:

V = f λ     speed of wave in terms of frequency and wavelength

t = S / V      time for wave to travel a distance S

t = 91.4 m / 344.5 m/s = .265 sec        time to travel 91.4 m

The planets of the solar system has the orbiting time.

Mercury-  88 days, Venus-225 days, Earth- 365 days, Mars-687 days, Jupiter- 12 years, Saturn- 29 years, Uranus-  84 years, Neptune- 165 years, Pluto- 248 years.

Solar system consists of all the planets and the most importantly the center of the solar system is Sun.

Sun is the main focus of the solar system. It emits high temperature light rays on the planets which in turn emit lights and be visible.

Outer planets take longer to orbit the sun because the gravitational pull is weaker as shown in the inverse square law.

The outer planets very far away from the Sun, means that they have more distance to cover in their orbit.

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Answer:

84 joules

Explanation:

potential energy = mgh

5.24×1.63×9.8

= 84 joules

Answer:

Ampere

Explanation:

The SI unit of electric current is Ampere (A) after French physicist Andre Ampere who discovered electrical current

Answer: 1 degree

Explanation:  I looked it up.

Answer:

I think it is Newton's law od gravity

Explanation:

Answer:

B. man with a beard

Explanation:

it is not a genetic mutation because it is completely natural and common unlike the other options.

The true statements are, the silver coin lost electrons and the wool cloth lost protons.

A positive charge is an ion with excess proton. In this process the atom deficient number of electron as compared to protons.

When a silver coin is rubbed vigorously against a wool cloth, the silver coin which is a metal will loss electron, having excess number of protons and becomes positively charged in the process.

Thus, the true statements are;

the silver coin lost electrons and the wool cloth lost protons.

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Answer:

The answer is C.

Explanation:

Answer:

[tex]\huge\boxed{\sf Option \ 3}[/tex]

Explanation:

[tex]\rule[225]{225}{2}[/tex]

Answer:

Approximately [tex]15\; {\rm m\cdot s^{-1}}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

Let [tex]m[/tex] denote the mass of this vehicle, and let [tex]g[/tex] denote the gravitational field strength.

Since the road is level, the normal force that the road exerts on the vehicle would be equal in magnitude to the weight [tex]m\, g[/tex] of this vehicle. That is: [tex]F_\text{normal} = m\, g[/tex].

Let [tex]\mu_{k}[/tex] denote the coefficient of (kinetic) friction between the tires of this vehicle and the road. The maximum friction that the road could exert on this vehicle would be:

[tex]\begin{aligned}& F_\text{max. friction} && (\text{max. friction}) \\ =\; &\mu_{k}\, F_\text{normal} && (\text{coefficient of friction}) \,(\text{normal force}) \\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].

Also because this road is level, the only unbalanced force on this vehicle would be friction. Thus, the net force on this vehicle would be equal to the friction that the road exerts on the vehicle, which is at most [tex]\mu_{k}\, m\, g[/tex]:

[tex]\begin{aligned}& F_\text{net} && (\text{net force}) \\ =\; & F_\text{friction} && (\text{friction}) \\ \le \; & F_\text{max. friction} && (\text{max. friction})&\\ =\; & \mu_{k}\, m\, g\, \end{aligned}[/tex].

In other words, [tex]F_\text{net} < \mu_{k}\, m\, g[/tex]. This inequality could provide an upper bound on the acceleration of this vehicle:

[tex]\begin{aligned}& a && (\text{acceleration}) \\ =\; & \frac{F_\text{net}}{m} && \genfrac{}{}{0em}{}{(\text{net force})}{(\text{mass})}\\ \le \; & \frac{\mu_{k}\, m\, g}{m} \\ =\; & \mu_{k}\, g\end{aligned}[/tex].

Thus, the maximum acceleration of this vehicle on this road would be [tex]a_\text{max} = \mu_{k}\, g[/tex].

Let [tex]r[/tex] denote the radius of this circle. When the vehicle is moving around this circle at a speed of [tex]v[/tex], the (centripetal) acceleration of this vehicle would continuously be [tex]a = (v^{2} / r)[/tex].

Since the upper bound of the acceleration of this vehicle is [tex]a_\text{max} = \mu_{k}\, g[/tex], rearrange the equation [tex]a = (v^{2} / r)[/tex] to find an upper bound on speed [tex]v[/tex]:

[tex]\begin{aligned}\frac{v^{2}}{r} &= a \\ & \le a_{\text{max}} \\ &= \mu_{k}\, g\end{aligned}[/tex].

[tex]v^{2} \le \mu_{k}\, g\, r[/tex].

[tex]v \le \sqrt{\mu_{k}\, g\, r}[/tex].

In other words, when the radius of the circle is [tex]r[/tex], the coefficient of friction between the tire and the ground is [tex]\mu_{k}[/tex], and the gravitational field strength is [tex]g[/tex], the maximum speed of the vehicle would be [tex]\sqrt{\mu_{k}\, g \, r}[/tex].

In this question, it is given that [tex]r = 40.0\; {\rm m}[/tex] whereas [tex]\mu_{k} = 0.60[/tex]. Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], the maximum speed of this vehicle would be:

[tex]\begin{aligned}v_\text{max} &= \sqrt{\mu_{k}\, g\, r} \\ &= \sqrt{0.60 \times 9.81\; {\rm m\cdot s^{-2}} \times 40.0\; {\rm m}} \\ &\approx 15\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Answer:

they carry a heavier load

Explanation:

Answer:

The wheels of buses and trucks are heavier than the wheels of car or scooters because the buses and trucks are heavy and require to exert less pressure. We know that when pressure decreases an area of contact increases, so the tires are broadened so that they exert less pressure on the road and move easily.  

Explanation:

Please mark me in the brainlist

Answer:

90 mAmps

Explanation:

V=IR

V/R = I

9 v / 100 ohm = .09 amps = 90 mAmps

Remember the formula

[tex]\\ \rm\Rrightarrow A(t)=A_o(0.5)^{\frac{t}{h}}[/tex]

[tex]\\ \rm\Rrightarrow A(7.82\times 10)=A(78.2)[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{\frac{78.2}{3.91\times 10^{5}}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{20\times 10^{-5}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{0.0002}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.998)[/tex]

[tex]\\ \rm\Rrightarrow 4.10178\times 10^{76}[/tex]

Why no options matched?

That time given in end i.e 7.82×10

The number of nuclei  of calcium-47 left after 7.82 x 10⁵s is 1.03 x 10¹⁶.

This can be found out using half life and laws of radioactive disintegration.

The Law of radioactive disintegration states  the number of  radioactive decay per unit time is proportional to the number of nuclei present in the sample initially.

So,  ΔN/Δt = λN

Where, ΔN = number of radioactive nuclei decayed

Δt = time taken for decay

N = No of nuclei present initially

λ= decay constant

Half life is the time taken for the radioactive nuclei to reach half of its initial value.

Half life is given by

 [tex]t_{1/2}[/tex] =  λ/t

Given here,  [tex]t_{1/2}[/tex] =  3/91 x 10.⁵s

N = 4.11 x 10¹⁶.

t = 7.82 x 10.⁵s

We see  here that  t = 2([tex]t_{1/2}[/tex])

Now, number of radioactive nuclei left undecayed in  one half life is N/2

So number of nuclei left undecayed in 2 half lives will be 1/2(N/2) = N/4

So number of nuclei left in the sample will be N/4 = (4.11 x 10¹⁶.)/4

So Number of nuclei left in the sample = 1.03 x 10¹⁶.

Hence 1.03 x 10¹⁶is the correct answer.

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Answer:

the answer is 2321 watts

Explanation:

power= energy/time

power= 441/0.19=2321.05watts

Answer:

Length of steel = 5.5 m

Increase in length = 0.0012 m

α of steel = 12 x 10-6/K

To find:

Temperature change needed ?

Calculation:

Let the required temperature change be ∆T. (in the photo)

So, temperature change of 18.1 Kelvin is required

I hope I have helped you and go to my profile to help me with my question, I really need It, thanks.

[tex]\\ \rm\Rrightarrow C=\dfrac{\epsilon_oA}{d}[/tex]

[tex]\\ \rm\Rrightarrow C=\dfrac{0.2(0.001)}{0.04}[/tex]

[tex]\\ \rm\Rrightarrow C=\dfrac{0.0002}{0.04}[/tex]

[tex]\\ \rm\Rrightarrow C=0.005F[/tex]

[tex]\\ \rm\Rrightarrow C=5mF[/tex]

Explanation:

Given data :

Given data :Plate area = 0.2m^2

Given data :Plate area = 0.2m^2Distance between plates=0.04m

Given data :Plate area = 0.2m^2Distance between plates=0.04mdielectric constant = 0.001 C/vm

Given data :Plate area = 0.2m^2Distance between plates=0.04mdielectric constant = 0.001 C/vmRTF=Capacitance.

Given data :Plate area = 0.2m^2Distance between plates=0.04mdielectric constant = 0.001 C/vmRTF=Capacitance. SolutionFirst formula for capacitance .

Answer:

The solar eclipse stopped years ago due to the moon, sun, and earth's alignment not being able to sync like it did before.

The statement a,d and e are correct. The chemical equation must be balanced.

One or more compounds, known as reactants, are transformed into one or more distinct substances, known as products. Such a process is known as a chemical reaction.

The given equation is;

[tex]\rm CH_4+2O_2 \arrow \rightarrow CO_2+2H_2O[/tex]

The statements that apply in order to complete the model is;

a) The products must equal the reactants.

d) One carbon atom and two oxygen atoms are needed to balance the equation.

e) One carbon dioxide molecule should be added to the product side of the equation.

Hence, statement a,d and e are correct.

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Answer:

Explanation:

answer: 4 velocity.

if nominal gdp is 1800 and the money supply is 450, then what is velocity?

4 velocity.

If the nominal GDP is 1800 and the money supply is 450, then the velocity of money would be 4.

The total value of goods and services generated in an economy during a given time period, usually a year, is referred to as nominal GDP and is not adjusted for inflation. It depicts what products and services are now selling on the market.

Given:

Nominal GDP, PQ = 1800

Money supply, M = 450

From equation of exchange:

MV = PQ

V = (PQ) ÷ M

V = (1800) ÷ (450)

V = 4

Hence, if the nominal GDP is 1800 and the money supply is 450, then the velocity of money would be 4.

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Answer:

$ .0248      or   2.48 cents

Explanation:

60 + 100 + 150 = 310 watts

  for one hour  =  310 watt- hr    or    .31 kw- hr

      .31 kw-hr   *  .08 / kw-hr  =  .0248

We are asked for the x coordinate of vertex

Here vertex is present somehow at 850-870nm

The most applicible answer should be 860nm

Option C is correct

Answer:

F = M a

F = 2350 kg * 2 m/s^2 = 4700 Newtons

That is in addition to the force of

F = 2350 * 9.8 m/s^2 = 23,030 N needed for a stopped elevator