What did hegel and kant have in common? they both were determined to disprove marxist theory. they both thought that only history could reveal universal truths. they both refused to completely abandon the role of religion in their work. they both believed that perception was an important element in understanding reality.

Answer:

Velocity towards east = 20m/s

Distance in 2 min(120 sec) = 20 x 120= 2400m = 2km

Velocity towards west = 15m/s

Distance in 2 min(120 sec) = 15 x 120 = 1800m = 1.8km

Separation= 2+1.8 = 3.8km

Explanation:

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Answer:

Answer:

Conservation of energy still holds - so somewhere in traversing some of the potential energy was converted into something other than kinetic energy.

The loss of energy can be attributed to several things - friction on  the ramp, air resistance, friction within the item descending the ramp; in general one would say that some of the initial PE was lost during the descent of the ramp. and did not show up as KE.

The ideal location for the exhaust fan on your Kitchen wall should be 12m above the floor.

Exhaust fan is defined as the device that is used to remove excess moisture, odors, and stale air usually from the kitchen.

When being installed in the kitchen, it should be above the kitchen stove and high enough to be able to remove the steam from the cooking activities.

Therefore, the ideal location for the exhaust fan on your Kitchen wall should be 12m above the floor.

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The length the student should record as correct is ​18.55 centimeters (cm) because it is the average value.

The average value is a number associated with the middle amount for a given number of measured samples.

In this case, the median value results less useful to describe a set of data when compared to the average.

In conclusion, the length the student should record as correct is ​18.55 centimeters (cm) because it is the average value.

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The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.

The average daily temperature of the different days is calculated as follows;

Monday = (4 + 18 + 22)/3 = 14.67 ⁰C

Tuesday = (6 + 19 + 24)/3 = 16.3 ⁰C

Wednesday = (10 + 20 + 25)/3 = 18.3 ⁰C

The average daily temperature of Wednesday is the greatest.

The balloon will rise the most on Wednesday due to high temperature that will increase the thermal energy of the balloon and cause it to rise higher.

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Answer:

A child holds the bar of a set of weights without moving I think

The source of nutrition that Andrew should consume prior to the match to get the boost of energy he desires is carbohydrate.

Nutrition refers to the organic process by which an organism assimilates food and uses it for growth and maintenance.

There are 6 major classes of nutrients and they are as follows:

Among these classes of nutrients, carbohydrates provide the fastest source of energy in the body and hence, can be recommended for an athlete like Andrew who is preparing for a weight lifting endeavor.

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Answer:

Mass of Earth (M1) = 6×10^24 kg

Mass of Puppy (M2) = 3.6 kg

Radius (R) = 6371000 m

Universal Gravitational Constant (G) = 6.67 × 10^11

Now,

Gravitational Force = G×M1×M2 / R^2

GF = 6.67 × 10^11 × 6 × 10^24 × 3.6 / (6371000)^2

GF = 144.072 × 10^35 / 40,589,641,000,000

GF = 3549.477 × 10^20

F = G M.m/r²

F = force, N

G = gravitational constant,  6.67 x 10⁻¹¹ Nm²/kg²

m,M = mass of object,  kg

r = distance, m

F = 6.67 x 10⁻¹¹ x 69.3 x 52/1.2²

F = 1.669 x 10⁻⁷

Answer:

by obtaining the total mass of the dimes present:

d = 27.22 g / dozen       the density of dimes

M = n * d = 5 dozen * 27.22 g / dozen = 126.1 g

The true statements about the two congruent, shaded figures are:

This refers to the name that is given if two figures or objects have the same shape and size.

Hence, we can see from the complete text that four parallel lines are drawn in a rectangular sign and painted using two colors in an alternating pattern, then they are parallelograms because their opposites are parallel.

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Answer:

electromagnetic waves

After one half-life, 8 g of radioactive isotope will remain in the sample.

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

The following formula is used to compute the number of half lives elapsed:

[tex]\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram[/tex]

Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.

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Answer:

Answer is below

Explanation:

8 g

Answer:

eV to Joules just multiply by 1.602 × 10^-19

Hence, 1.5eV = 1.5 × 1.602 × 10^-19 J

= 3.04 × 10^-19 J

∑F=m.a

18 - 6 = 40 x a

12 = 40a

a = 0.3 m/s²

The vibrational period of the rope, when a student shakes it is 0.25 s.

Frequency is the number of oscillations per second.

Given is the number of vibrations =36 in time t = 9s, then frequency will be

f = 36/9 =4Hz

The time period is the reciprocal of the frequency.

T = 1/f

Plug the frequency value, we get

T = 1/4 Hz = 0.25 seconds

Thus, the vibrational time period is 0.25s.

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Answer:

When the car crashes, there is no unbalanced force acting on the person, so they continue forward (Newton's First Law). The person moves against the seat belt, exerting a force on it.

Answer:

Static Electricity.

Explanation:

The rubbing of hair (object) onto the balloon creates a negative charge that is carried by electrons, the electrons will soon build higher to create static electricity, thus keeping it onto the ceiling.

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Answer:

It passes another car that travels southward at 60 km/h. Do both cars have the same speed? Do they have the same velocity? Answer: Both cars have the same speed, but they have opposite velocities because they are moving in opposite directions.

Explanation:

Answer:

See below ~

Explanation:

As the magnitude (absolute numerical value) of both cars are equal, they both have the same speed.

But, as they are travelling in opposite ways, they have different directions. Hence, they have different velocities.

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}[/tex]

[tex]\\ \rm\Rrightarrow u=\dfrac{190}{-14}[/tex]

[tex]\\ \rm\Rrightarrow u=13.6cm[/tex]

Real

Answer:

A) P = W / t = 6000 / 60 = 100 J/s == 100 watts

B) P = I V = .05 * 240 = 12 watts

C)  Bulb B) uses much less power

Answer:

gears - answer

Explanation:

Hope it helps

As the volume of the container increases the pressure inside will decrease because the atoms have more room to move around in.

Answer:

 In a container of the same volume, a greater number of molecules results in greater pressure. Gas pressure increases as container volume decreases.

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[tex] \bold{\underline{\underline{\underbrace{Answer}}}} [/tex]

5 images

Explanation:

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What is reflection of light?

The reflection of light is the phenomenon in which the rays of light falls on the object and change it's path.

⠀

How image is formed in plane mirror?

When you look at the mirror the image is formed behind the mirror and it is virtual. The light from the object which reaches the mirror gets reflected back.

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⠀

The formula to find the no. of images between the 2 plane mirror at any angle θ.

[tex] \sf No. \: of \: images = \frac{360 \degree}{ \theta} - 1[/tex]

According to the question the plane mirror is inclined at 60° angle.

Substituting the required values.

[tex] \sf \large \frac{ \cancel{360} \small \: \: 6}{ \cancel{60}} - 1 \\ \\ \sf \large 6 - 1 \\ \\ \boxed{ \frak{ \implies 5} }[/tex]

The 2 plane mirror will form 5 images inclined at 60° angle.

Answer:

Sorry if im late

The answer is Electric field (D)

Explanation:

The electric field is thought of as the force per unit positive charge that can be exerted before the field is disturbed by the presence of a test charge.

hope this still helped :)

~rere

Answer:D

Explanation:

I have answer key

Answer:

[tex]f_n_e_t=0[/tex]

Explanation:

[tex]f_1+f_2=f_n_e_t[/tex]

because there are two different forces in different directions (left: negative, right: positive, down: negative, up: positive) so 60N left will be negative, and 60N right will be positive:

[tex]60+(-60)=0[/tex]

when two same forces apllied then the net force is zero.

Answer:

4 m/s

Explanation:

v=u+ at  and  v^2=u^2+2as.

It is given that  v=0,t=5  s    and  s=10  m.

⇒0=u+5a  and  0=u^2+20a.

⇒a=−u/5  and  a=−u^2/20.

⇒u/5 = u^2/20⇒u=4  m/s.

⇒  The initial velocity is  4  m/s.

Answer:

[tex]64\; {\rm m}[/tex], assuming that the rollercoaster is not attached to the track.

Explanation:

Let [tex]r[/tex] denote the radius of the loop. The height of the top of the loop would be [tex]2\, r[/tex].

Let [tex]a[/tex] denote the acceleration of the rollercoaster. At any position in the loop, if the speed of the rollercoaster is [tex]v[/tex], the (centripetal) acceleration of the rollercoaster would be:

[tex]\displaystyle a = \frac{v^{2}}{r}[/tex].

Let [tex]m[/tex] denote the mass of the rollercoaster. The net force on the rollercoaster would then be:

[tex]\displaystyle F_\text{net} = m\, a = \frac{m\, v^{2}}{r}[/tex].

The rollercoaster would stay on the track (and goes around the loop without falling off) only if the normal force [tex]F_\text{normal}[/tex] between the track and the rollercoaster is non-negative. In other words: it is necessary that [tex]F_\text{normal} > 0[/tex] for the rollercoaster to stay on the track.

At the top of the loop, [tex]F_\text{normal}[/tex] and the weight of the rollercoaster [tex]m\, g[/tex] are in the same direction as the centripetal acceleration (downwards towards the center of the loop.) Hence:

[tex]F_\text{net} = F_\text{normal} + m\, g[/tex].

Let [tex]v_\text{top}[/tex] denote the speed of the rollercoaster at the top of the loop.

[tex]\begin{aligned} F_\text{normal} &= F_\text{net} - m\, g \\ &= \frac{m\, v_\text{top}^{2}}{r} - m\, g\end{aligned}[/tex].

If [tex]F_\text{normal} > 0[/tex] at the top of the loop, then:

[tex]\displaystyle \frac{m\, v_\text{top}^{2}}{r} - m\, g > 0[/tex].

[tex]\displaystyle v_{\text{top}}^{2} > g\, r[/tex].

At the same time, by the conservation of energy, the sum of the kinetic energy [tex]\text{KE}[/tex] and gravitational potential energy [tex]\text{GPE}[/tex] of the rollercoaster should stay the same during the entire ride. Assuming that [tex]\text{GPE}\![/tex] is [tex]0[/tex] at the bottom of the loop:

[tex]\begin{aligned}& \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top}\end{aligned}[/tex].

Let [tex]v_{0}[/tex] denote the speed of the rollercoaster at the bottom of the loop.

[tex]\begin{aligned}\text{KE at the bottom} = \frac{1}{2}\, m\, {v_{0}}^{2}\end{aligned}[/tex].

The speed of the rollercoaster at the top of the loop [tex]v_\text{top}[/tex] is at least [tex](g/r)[/tex]. Therefore:

[tex]\begin{aligned}& \text{KE at the top}= \frac{1}{2}\, m\, {v_{\text{top}}}^{2} > \frac{1}{2} \, m\, g\, r\end{aligned}[/tex].

Since the height of the loop is [tex]2\, r[/tex], the [tex]\text{GPE}[/tex] of the rollercoaster at the top of the loop would be:

[tex]\text{GPE at the top} = m\, g\, h = 2\, m\, g\, r[/tex].

Thus:

[tex]\begin{aligned} \frac{1}{2}\, m\, {v_{0}}^{2} &= \text{KE at the bottom}\\ &= \text{KE at the top} + \text{GPE at the top} \\ & > \frac{1}{2}\, m\, g\, r + \text{GPE at the top}\\ & = \frac{1}{2}\, m\, g\, r+ 2\, m\, g\, r \\ &= \frac{5}{2}\, m\, g\, r\end{aligned}[/tex].

In other words:

[tex]\displaystyle \frac{1}{2}\, m\, {v_{0}}^{2} > \frac{5}{2}\, m\, g\, r[/tex].

Rearrange and simplify to obtain a bound on [tex]r[/tex]:

[tex]\begin{aligned} r < \frac{(1/2)\, m\, {v_{0}}^{2}}{(5/2)\, m\, g}\end{aligned}[/tex].

[tex]\begin{aligned} r < \frac{{v_{0}}^{2}}{5\, g}\end{aligned}[/tex].

Given that [tex]v_{0} = 40\; {\rm m\cdot s^{-1}[/tex] and [tex]g = 10\; {\rm N \cdot kg^{-1}} = 10\; {\rm m\cdot s^{-2}[/tex]:

[tex]\begin{aligned} r & < \frac{{v_{0}}^{2}}{5\, g} \\ &= \frac{(40\; {\rm m\cdot s^{-1}})^{2}}{5 \times (10\; {\rm m\cdot s^{-2}})} \\ &= 32\; {\rm m}\end{aligned}[/tex].

Hence, the radius of this loop is at most [tex]32\; {\rm m}[/tex], such that the height of the top of this loop is at most [tex]2 \times 32\; {\rm m} = 64\; {\rm m}[/tex].