what are the domain and range of the function represented by the set of ordered pairs?. ​

Answer:

A) 400 + 72

Step-by-step explanation:

Let the certain number be denoted by x.

⇒ 5x = 40 [Equation 1]

⇒ 9x = 72 [Equation 2]

Multiply Equation 1 by 10 :

⇒ 10(5x) = 40(10)

⇒ 50x = 400 [Equation 3]

Finding the sum of Equation 2 and Equation 3 :

⇒ 50x + 9x = 400 + 72

⇒ 59x = 400 + 72

Hence, 59 times a certain number is represented by : 400 + 72

see the attached figure

A(4,8)  B(0,7)  C(4,3)

the line of reflection is x=5

the reflection is (x,y)-------------------> (10-x,y)

therefore

A(4,8)-----------------> A1(10-4,8)------> A1(6,8)

B(0,7)-----------------> B1(10-0,7)------> B1(10,7)

C(4,3)-----------------> C1(10-4,3)------> C1(6,3)

Answer:

Discus, Hurdles, Long jump, and 100m

Step-by-step explanation:

Answer:

32x^10y

Explanation -

You want to use distributive property. Take 2x^5 and the Exponent 2y^5

It should look like this

Answer:

8.382 cm

Step-by-step explanation:

1in = 2.54 cm

3.30 x 2.54 = 8.382 cm

Answer:

B

Step-by-step explanation:

answer is based on results from the Cartesian plane

Answer:

x = 27.19

Step-by-step explanation:

Sin(54) =22/x

0.81=22/x

x0.81= 22

x = 27.19

Answer:

0 ≤ y ≤ 8

Step-by-step explanation:

DOMAIN is x values of a function/graph

RANGE is the y-values that a function can have .....

     this one goes from 0 to 8 inclusive

Answer:

let M point x1, Y1 and f point X2,y2 then we know the formula of distance root (x2-x1)^2+(y2-y1)^2 then you will found the distance

The total amount collected over the life of the bond is $7,500.

A bond is a debt instrument that entitles its holder to regular interest payments. At the end of the life of the bond, the bondholder receives the amount invested back.

Total earnings = interest + amount invested

(20 x 0.025 x 5000) = $2500

Amount invested = $5000

= 2500 + 5000 = $7,500

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Answer:

4.19

Step-by-step explanation:

Find the mean:

[tex]\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}[/tex]

Find the standard deviation:

[tex]\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19[/tex]

Rewrite 1/4 to have 8 as the denominator: 1/4 = 2/8

Now add the two days together:

2/8 + 3/8 = 5/8

Answer: 5/8

Answer:

9.500+9.100+9.625+9.250=

18.600+18.875=

37.475

Hope this helps!

[tex] \frac{1}{x} + \frac{3}{x} = 16 \\ [/tex]

[tex] \frac{4}{x} = 16 \\ [/tex]

[tex]16x = 4[/tex]

[tex]x = \frac{4}{16} \\ [/tex]

[tex]x = \frac{1}{4} \\ [/tex]

[tex] \begin{gathered}\\ \large\implies\sf{ \frac{1}{x} + \frac{3}{x} = 16} \\ \end{gathered}[/tex]

[tex] \begin{gathered}\\ \large\implies\sf{ \frac{4}{x } = 16 } \\ \end{gathered}[/tex]

[tex] \begin{gathered}\\ \large\implies\sf{ x = 16 \times 4 } \\ \end{gathered}[/tex]

[tex] \begin{gathered}\\ \implies \orange{\underline{\boxed{\large\frak \pink{x = 64 }}}} \\ \end{gathered}[/tex]

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Answer:

4/5

Step-by-step explanation:

Answer:

=4/5 or 0.8 as decimal

Step-by-step explanation:

8/10

Factor the number: 8=2· 4

2x4

Factor the number: 10 = 2· 5

2x4/2×5

Cancel the common factor: 2

=4/5

or (decimal 0.8)

The slope of the cubic polynomial and it's y-intercept are respectively; f(1) = -4 and f(0) = -6

We are given the equation;

f(x) = 2x³ - 6

Now, because the highest power of x is 3, it means that this is a cubic polynomial and not linear because it has a degree of 3

Thus, let us differentiate to get the slope;

f'(x) = 6x² - 6

At f'(x) = 0; x = 1

Thus, slope is;

f(1) = 2(1)³ - 6

f(1) = -4

y-intercept is f(x) at x = 0. Thus;

f(0) = 2(0³) - 6

f(0) = -6

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Answer:

3260

Step-by-step explanation:

Answer:

Step-by-step explanation:

x + 3 = -x - 1

2x + 3 = -1

2x = -4

x = -2

y = -2 + 3

y = 1

(-2, 1)

answer is A

1/5 = 60/100 * x

1/5 * 100/60 = x

100/300 = x

1/3 = x

Answer:

[tex] \frac{1}{3} [/tex]

Step-by-step explanation:

According to what we know, one-fifth is 60% of a number. Let us call that unknown number x. Since

[tex] \frac{1}{5} = 60\% \: \\ then \\ x = 100\%[/tex]

60% as a fraction is 6/10 or 3/5, in that case 100% as a fraction would be 5/5.

Recall: 60% = 3/5 and 100% = 5/5

therefore:

1/5 = 3/5

x = 5/5

note in order to find the value of x we cross multiply*

[tex] \frac{1}{5} ( \frac{5}{5}) = \frac{3}{5} x[/tex]

[tex] \frac{1}{5} = \frac{3}{5} x \\ \\ \frac{ \frac{1}{5} }{ \frac{3}{5} } = \frac{ \frac{3}{5} }{ \frac{3}{5} } x \\ \\ \frac{1}{5} \times \frac{5}{3} = x[/tex]

[tex] \frac{1}{3} = x[/tex]

Let's start with the given arc and its angle.

The angle YWX is going to be half the arc length.

YWX = 1/2 (226) = 113

Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.

(15x - 8) + 113 = 180

15x + 105 = 180

15x = 75

x = 5

Hope this helps!

Answer:

m∠A = 49°

Step-by-step explanation:

According to Angle Sum Property,

m∠A

Answer:

No, it will not

Step-by-step explanation:

as square of 2 is 4

Answer:

Step-by-step explanation:

Equation

-6(1-4v) = 3v-8(-6-6v)                  Use the distributive property to get rid of the brackets.

Solution

-6 + 24v = 3v +48 +48v              Combine

-6 + 24v = 51v + 48                     Subtract 24v from both sides

-6 +24v-24v =51v-24v +48         Combine.

-6 = 27v + 48                              Subtract 48 from both sides.

-6-48 = 27v+48-48                     Combine

-54 = 27v                                    Divide by 27

-54/27=27v/27

-2 = v

Answer

v=-2

The proof of the given statements is shown below:

A line segment which touches a circle specified to only one point is called a tangent to that circle.

1. given

2. A line is a tangent to a circle if and only if the line is perpendicular to the radius drawn to the point of tangency.

3. Since the tangent is perpendicular to radius i.e., EFC is right angle then,

   angle EFC =90

4.  Sum of interior angles of a triangle is 180°.

5. proved above: angle EFC= 90

6. FEC + ECF= 180-90=90

7. As proved above

  FEC + ECF=90, its shows that angle FEC and ECF are complementary angle.

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Answer:

Step-by-step explanation:

[tex]sin^2({ \theta})+cos^2({ \theta})=1\\cos({ \theta})=-/+\sqrt{1-sin^2({ \theta})} \\cos({ \theta})=-\sqrt{1-sin^2({ \theta})} \\ --- > sin({ \theta})=\frac{1}{3} (known)\\cos({ \theta})=-\sqrt{1-sin^2({ \theta})} =-\sqrt{1-(-\frac{1}{3})} =-\sqrt{\frac{9-1}{9}} =-\frac{2x^{2} }{3}[/tex]

Answer:

500 km

Step-by-step explanation:

300 plus 200 is 500km this is how far it is

The distance between City A & City C is approximately 171.3km

Given that, city A is 300 km due east of city B.

City C is 200 km on a bearing of 123° from city B.

We need to find the distance between the cities A and C,

Here we will use the concept of Cosine rule,

{Refer to the figure attached}

From ∆ABC, to find |AC|,

The cosine rule will be used.

|AC|² = |BC|² + |AB|² - 2(|BC|)(|AB|)cosB

Let |AC| = x

x² = 200² + 300² - 2(200)(300)cos33

x² = 40000 + 90000 - 120000cos33

x² = 130000-100644

x² = 29356

x = √29356

x = 171.3359

x ≈ 171.3km

Therefore, the distance between City A & City C is approximately 171.3km

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Step-by-step explanation:

Given:
40 houses,

500 liters of waters everyday for common utilities

Unknown amount of water per house which we will call x.

4500 max liters for the gated community

Solve:

4500=40x+500

subtract 500 from both sides

4000=40x

divide by 40

100=x

Check:

40(100)+500=4500

4000+500=450

correct

Answer:

100 liters of water can be used by each house.

[tex]~~~~~37^x = 12\\\\\implies \ln\left( 37^x \right) = \ln(12)\\\\\implies x \ln (37) = \ln(12)\\\\\implies x = \dfrac{\ln(12)}{\ln(37)}\\\\\implies x \approx 0.689[/tex]