Weiming, Farhan and Sam had some comic books.
Weiming and Farhan had 36 comic books altogether.
Weiming had 3 times as many comic books as Farhan.
Sam and Farhan had 60 comic books in total.
(a) How many comic books did Farhan have?
(b) How many comic books did Sam have?

Answer:

4294967296 Kilograms

Step-by-step explanation:

Great Pyramid has 2^21 blocks

2^21 = 2097152, so

2097152 blocks

Blocks weigh 2^11 each

2^11 - 2048, so

2048 kg per block

2097152(number of blocks) x 2048(weight in kilograms per block) = The Great Pyramid in Egypt weighs 4294967296 Kilograms

Step-by-step explanation:

More than 2,300,000 limestone and granite blocks were pushed, pulled, and dragged into place on the Great Pyramid. The average weight of a block is about 2.3 metric tons (2.5 tons).

How much is that? Well, you can think of it in terms of refrigerators. An average refrigerator weighs about 91 kg. If 1 metric ton = 1,000 kg, how many refrigerators equal a 2.3-metric ton block?

A 25 refrigerators

B 5 refrigerators

C 90 refrigerators

(hope this helps!)

YOUR INPUT:

[tex]T-Re^{x}[/tex]

FIRST DERIVATIVE:

 [tex]\frac{d}{dx} [T-Re^{x} ]\\=\frac{d}{dx} [T]-R*\frac{d}{dx} [e^{x} ]\\=0-Re^{x} \\=-Re^{x}[/tex]

Root/zero found at:

[tex]x=ln(\frac{T}{R} )[/tex]

Answer:

1. 2/5

2. 3/20

3. 6 1/9

4. 1/5

5. 11

6. 1

7. 3/13

8. 1 5/11

9. 2

10. 6 1/2

11. 20/27

12. 2 3/16

13. 4 13/18

14. 1 45/98

Hope this helps!

Step-by-step explanation:

Answer:

the answer should be 6 if i am not wrong

Step-by-step explanation:

Answer:

[tex]h = \frac{V}{\pi r^{2}}[/tex]

h = 4 cm

Step-by-step explanation:

Given the formula for the volume (V) of a cylinder: V = πr ²h, and the following values for volume and radius:

V = 36π cm³

r = 3 cm

First, solve for h:

V = πr ²h

Divide both sides by πr ²:

[tex]\frac{V}{\pi r^{2} } = \frac{\pi r^{2}h}{\pi r^{2} }[/tex]

[tex]h = \frac{V}{\pi r^{2}}[/tex]

Next, solve for the height of the cylinder by substituting the given values for volume and radius into the formula:

[tex]h = \frac{V}{\pi r^{2}}[/tex]

[tex]h = \frac{36\pi }{\pi (3^{2})}[/tex] → π cancels out.

[tex]h = \frac{36}{9}[/tex]

h = 4 cm

Answer:  $208,000

Step-by-step explanation:

Answer:

4 and 1/2 cups of flour

Step-by-step explanation:

First, you need to divide 2 by 1/3, which will give you 6. Then multiply 6 by 3/4, which gives you 4 1/2. Hope this helped!

Answer:

it is 9 centimeters

Step-by-step explanation:

it is a 1:1 ratio

Answer:

y = x + 3

Step-by-step explanation:

→ Rewrite y - x + 3 = 0 in y = mx + c format

y = x - 3

→ Find the gradient of L4

1

→ Rewrite into y = mx + c format

y = x + c

→ Substitute in ( 0 , 3 )

3 = 0 + c

→ Find c

c = 3

→ Rewrite into y = mx + c

y = x + 3

Answer:

18,14,9

Step-by-step explanation:

enjoy

The number of groups that can be chosen from the team of 17 depends on

the given conditions of the selection.

The correct responses are;

Reasons:

The combination of n objects taking r at a time is given as follows

[tex]_nC_r = \dbinom{n}{r}[/tex]

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = [tex]\dbinom{17}{9}[/tex] = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = [tex]\dbinom{9}{5} \times \dbinom{8}{4}[/tex]

[tex]\dbinom{9}{5} \times \dbinom{8}{4} = 126 \times 70 = 8,820[/tex]

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is [tex]\dbinom{17}{9} - \dbinom{9}{9}[/tex]

[tex]\dbinom{17}{9} - \dbinom{9}{9} = 24,310 - 1 = 24,309[/tex]

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

[tex]\dbinom{8}{8} \times \dbinom{9}{1} + \dbinom{8}{7} \times \dbinom{9}{2} + \dbinom{8}{6} \times \dbinom{9}{3} = 2,649[/tex]

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are [tex]\dbinom{15}{9} + 2 \times \dbinom{15}{8}[/tex]

[tex]\dbinom{15}{9} + 2 \times \dbinom{15}{8} = 5,005 + 2 \times 6,435 = 17,875[/tex]

(d) Two team members must work together or not at all is [tex]\dbinom{15}{7} - \dbinom{15}{9}[/tex]

[tex]\dbinom{15}{7} - \dbinom{15}{9} = 6,435 - 5,005 = 1,430[/tex]

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

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Answer:

2^2 * 3^2

Step-by-step explanation:

2 * 2 * 3 * 3

We are multiplying 2 twos and we are multiplying 2 threes 3^2

The base is the number and the exponent is the number of the times

2^2 * 3^2

Answer:

a)$62.2417

b)$65.9912

c)$39.7447

d)$47.2437

Step-by-step explanation:

a)100%-30%=70%

70%+13%=83%

83/100x74.99=62.2417

b)100%-25%=75%

75%+13%=88%

88/100x74.99=65.9912

c)100%-60%=40%

40+13=53

53/100x74.99=39.7447

d)100%-50%=50%

50+13=63%

63/100X74.99=47.2437

Hope this helps! Thanks.

Answer:

length: 601 1/3 area: 361601 7/9

Step-by-step explanation:

the maximum area would be a square, and we only need 3 sides, so we can divide the amount of fencing by 3

1804/3=601 1/3

the length is 601.(3)

square to find the area

(1804/3)^2

361601 7/9

area is 361601 7/9

Answer:

a. The real GDP increases by $200,000.

a. The real GDP increases by $150,000.

Step-by-step explanation:

a. What is the eventual effect on real GDP if the government increases its purchases of goods and services by $50,000?

Eventual effect on real GDP = Amount of increase in government spending * (1 /(1 - MPC)) = $50,000 * (1 / (1 – 0.75)) = $200,000

Therefore, the real GDP increases by $200,000.

a. What is the eventual effect on real GDP if the government, instead of changing its spending, increases transfers by $50,000?

Eventual effect on real GDP = (Amount of increase in government transfers * (1 /(1 - MPC))) - Amount of increase in government transfers = ($50,000 * (1 / (1 – 0.75))) - $50,000 = $150,000

Therefore, the real GDP increases by $150,000.

Step-by-step explanation:

hope this helps you dear sis.....

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

I would say 5 x= 8.5; x = 42.5 ounces that's my guess

Answer:

Step-by-step explanation:

A) 120 / 2 = 60°

B) 180 - 90  60 = 30°

C) 60° same as arc length GE in part A above

D) 9 units = Rsinθ = 18sin30

We want to find the work done by lifting a book a given distance.

The answer is 200 N*m

We know that the book weighs 100 Newtons and that we lift it a distance of 2 meters.

Remember that the work needed to lift an object of mass M to a height H is:

W = M*g*H

where g is the gravitational acceleration.

Knowing that:

weight = M*g

We can replace the things we know to get the work:

W = 100N*2m = 200 N*m

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Answer:

$106

Step-by-step explanation:

So, this is what we know:

$6 per vehicle (1 bus) + $2 per person (50 people)

Here is the solution:

= $6 + $100

= $106

Step-by-step explanation:

y=75+50(36 hours)=1875

give me brainliest

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Slope is 50x (50/1)

Explanation:

let m = slope

m = (y2-y1)/(x2-x)

m = (2,202,100-2,201,900)/(1994-1990)

m = 50/1

m = 50

Answer:

Step-by-step explanation:

5 1/3 x 1/6 = 8/9

5 1/3 + 1/6 = 5 2/6

5 1/3 - 1/6 = 31/6

5 1/3 / 1/6 = 32

Answer:

the correct answer for this problem is D: 5 and 1/3 divided by 1/6

Step-by-step explanation:

Answer:

Step-by-step explanation:

613 = 4x125 + 113 = 4x53 + 113

Hence the first digit (reading left to right) is a 4.

The remainder is 113 so how many 25's are there in 113?

113/25 = 4 with a remainder of 13

Thus

613 = 4x125 + 4x25 + 13 = 4x53 + 4x52 + 13

Hence the second digit (reading left to right) is also a 4.

The remainder is 13 so how many 5's are there in 13?

13/5 = 2 with a remainder of 3

Thus

613 = 4x125 + 4x25 + 2x5 + 3 = 4x53 + 4x52 + 2x5 + 3

Hence the third digit (reading left to right) is a 2 and the units digit is 3. Therefore

613 written in base 5 is 4423

example

Answer:

make a chart and it will be easy for you

Queremos encontrar y resolver un sistema de ecuaciones para encontrar el número de novillos comprados y el valor de cada uno.

Encontramos que las soluciones son:

La información que tenemos es:

El comerciante compro un dado número de novillos, digamos N.

El precio total fue de 1,440,000 colones.

Entonces si el precio de cada novillo es P, tenemos que:

N*P = 1,440,000

Sabemos que vendio 20 a 22,000 colones cada uno, es decir, obtuvo:

20*22,000 colones = 440,000 colones.

Es decir, de momento se tiene una perdida de:

1,440,000 - 440,000 = 1,000,000 colones.

Sí quiere obtener una ganancia de 200,000 colones, debe vender los (N - 20) novillos restantes a 2,000 colones más que P.

De esto planteamos la ecuación:

(N - 20)*(P + 2,000)= 1,000,000 colones + 200,000 colones = 1,200,000 colones.

Entonces tenemos el sistema de ecuaciones:

N*P = 1,440,000

(N - 20)*(P + 2,000) = 1,200,000

Para resolver esto comenzamos por aislar una de las variables en la primera ecuación, aislaremos N

N = (1,440,000)/P

Ahora reemplazamos esto en la otra ecuación:

(N - 20)*(P + 2,000) = 1,200,000

( (1,440,000)/P - 20)*(P + 2,000) = 1,200,000

Ahora debemos resolver esto para P.

1,440,000 - 20*P - 20*2,000 + 2,000*(1,440,000)/P = 1,200,000

- 20*P + 2,000*(1,440,000)/P = -180,000

Multiplicando ambos lados por P, obtenemos:

-20*P^2 + 2,880,000,000 = -180,000*P

Reescribimos esto como una ecuación cuadratica:

-20*P^2 +   2,880,000,000 + 180,000*P = 0

Y podemos resolver esto usando la formula de Bhaskara.

[tex]P = \frac{-180,000 \pm \sqrt{(180,000)^2 - 4*(-20)*(2,880,000,000)} }{2*-20} \\\\P = \frac{-180,000 \pm 512,640.22471 }{-40}[/tex]

Solo nos interesa la solución positiva, que es:

[tex]P = = \frac{-180,000 - 512,640.22471 }{-40} = 12,820.5[/tex]

Es decir, cada novillo le costó 12,820.5 colones.

y sabemos que:

N = 1,440,000/P = 1,440,000/12,820.5 = 112.3

Redondeamos al proximo numero entero, que es 112, donde ese 0.3 debe venir de algun error de redondeo (o más probablemente a un problema mal planteado).

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