Water flows through this orifice meter by gravity. The orifice diameter is 50 cm and water height difference is 10 m. If the contraction coefficient is 0.62 and velocity coefficient is 0.90, the flow rate through the orifice is most nearly:

Answers

Answer 1

Answer:

Q ≅ 1.53 m³/s

Explanation:

From the given information:

The flow rate of the orifice is:

[tex]v = c_v \sqrt{2gh}[/tex]

[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]

where;

[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &

[tex]c_d = c_c \times c_v[/tex]

[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]

[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]

[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]

Q ≅ 1.53 m³/s


Related Questions

The device shown below contains 2 kg of water. The cylinder is allowed to fall 800 m during which the temperature of the water increases by 2.4°C. Some amount of water is added to the container and the experiment is repeated. All other values remain constant. This time the temperature of the water increases by 1.2°C. How much water was added to the container?

Answers

Answer:

m_added = 2 kg

Explanation:

From the question, we are told that the cylinder is allowed to fall 800 m in height. Thus, the potential energy will be converted into heat energy which will increase the temperature of water .

Now, let the mass of the falling cylinder be denoted by "m1" and let h be the height of fall.

Thus;

Formula for potential energy = mgh

Thus, as said earlier it's converted to heat generated. So heat generated = m1gh

Now let's calculate the heat absorbed;

heat absorbed = (m2)cΔt

Where;

ΔT is change in temperature

c is specific heat of water .

m2 is mass of water

Heat absorbed = heat generated

Thus;

(m2)cΔt = m1gh

Δt = m1gh/(m2•c)

Now, in both cases of the water and cylinder, m1, g , h and c are constant

Thus, we have;

Δt = (m1gh/m2) × 1/c

Where;

(m1gh/m2) is denoted as a constant k.

Thus;

Δt = K/m

For the first experiment, we have;

m = 2 kg

Δt = 2.4

Thus;

2.4 = K/2

Multiply both sides by 2 to get;

K = 4.8

For the second experiment, we have;

Δt = 1.2

Also,we have seen that K = 4.8

Thus;

Δt = K/m

Thus;

1.2 = 4.8/m

m = 1.2

m = 4 kg

Thus,mass added is;

m_added = 4 - 2

m_added = 2 kg

Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.

Answers

Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load = [tex]\frac{wL}{2}[/tex]

w = maximum intensity of load , L = span of varying load

since AC = 6m( L )  then

Total load due to linearly varying load  = 3w  ------ ( 1 )

attached below is the detailed solution of the given problem

List 3 specific things you can do with a drill press (not just cut holes in wood)

Answers

Answer:

tapping, horizontal dusting, slash drilling

Explanation:

Find the value of v [v] that maximizes the power dissipated in the voltage source. You may use the Thevenin Equivalent Circuit Theorem. {Answer Format: answer in voltage (V) }

Answers

Answer:

Hello the circuit related to this question is missing attached below is the missing circuit

answer : 1.5 V

Explanation:

attached below is the detailed solution to the question

Applying Thevenin equivalent Circuit Theorem

First we perform Nodal analysis at Vth and draw the equivalent Thevenin circuits

Hence for a maximum power triangle

[tex]V_{RL} = \frac{V_{th} }{2} = \frac{-3}{2}[/tex]  = -1.5

therefore the value of v that maximizes the power dissipated in the voltage source

V = [tex]-V_{RL}[/tex] = 1.5 V

University administrators have developed a Markov model to simulate graduation rates at their school. Students might drop out, repeat a year, or move on to the next year. Students have a 3% chance of repeating the year. First-years and sophomores have a 6% chance of dropping out. For juniors and seniors, the drop-out rate is 4%. Compute the probability that a student who starts as a 1st-year eventually graduates the university.

Answers

Solution :

The percentage of the students who have a chance of repeating their current year = 3%

The drop out students for the first year and the sophomores = 6%

Drop out rate of first year and the seniors = 4%

Now for the state space :

S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }

Therefore

the first year students are indicated as '1'

Sophomores are indicated as '2'

Juniors are indicated as '3'

Seniors are indicated as '4

Graduates are indicated as 'G'

Dropouts are indicated as 'D'

The transition diagram is attached below.

The probability of the students who have the chance of repeating their current year = 3/100 = 0.03

Probability of first year dropouts and sophomores = 6/100 = 0.06

Probability of dropout rate of juniors and seniors = 4/100 = 0.04

Therefore, the probability matrix can be made as :

              1        2        3        4       G        D

    [tex]\begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}[/tex]      [tex]\begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\ 0& 0.03 & 0.91 & 0 & 0 & 0.06\\ 0& 0 & 0.03 & 0.93 & 0 & 0.04\\ 0& 0 & 0 & 0.03 & 0.93 & 0.04\\ 0& 0 & 0 & 0 & 1 & 0\\ 0& 0 & 0 & 0 & 0 & 1\end{bmatrix}[/tex]  

Here, G represents 'graduates' and D represents 'Dropouts.'

What is the normal balance side of an asset?

Answers

The normal balance for asset and expense accounts is the debit side, while for income, equity, and liability accounts it is the credit side. An account's assigned normal balance is on the side where increases go because the increases in any account are usually greater than the decreases

In a certain chemical plant, a closed tank contains ethyl alcohol to a depth of 71 ft. Air at a pressure of 17 psi fills the gap at the top of the tank. Determine the pressure at a closed valve attached to the tank 10 ft above its bottom.

Answers

Answer:

the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

Given that;

depth 1 = 71 ft

depth 2 = 10 ft

pressure p = 17 psi = 2448 lb/ft²

depth h = 71 ft - 10 ft = 61 ft

we know that;

p = P_air + yh

where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )

so we substitute;

p = 2448 + ( 49.3 × 61 )

= 2448 + 3007.3

= 5455.3 lb/ft³

= 37.88 psi

Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Create a simulation on multisim of over-voltage & under-voltage protection circuit.

Answers

Answer:protection circuit overload as usual

circuit overload

Explanation:

it is ery easy for wverone

What is a height gage?

What is true about gaging?

How often do frequently used instruments need calibration?

What is a machinist rule?

Answers

The answer would be -62 because 62 x 1 equals 62 so that would be the answer.

if a current of 5 amps flows through a resistance of 40 ohms, what is the voltage across that resistor

Answers

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

CAN I GET ANSWERS PLEASE, I TRY THE FORMULA AND MY TEACHER HAS A FAMILY EMERGENCY SO HE CANT RESPOND BACK SO PLEASE HELP ME

Answers

Explanation:

I won't answer each of these, but will give you an explaination of how to solve for each.

You'll need to use Ohm's Law and Kirchhoff's Voltage Law.

Remember Ohm's Law as [tex]V = IR[/tex].

Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.

[tex]E_T = E_1 + E_2 + E_3[/tex]

A couple of other helpful notes:

These three resistors are in series which means that the current flowing through them is equal.

So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]

Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).

For the velocity fields given below, determine:
a) whether the flow field is one-, two-, or three-dimensional,
b) whether the flow is steady or unsteady, and why. (The quantities a and b are constants.)
1. V = [ay2e−bt]i
2. V = ax^2i + bxj + ck
3. V = axyi - bytj
4. V = axi - byj + ctk

Answers

Answer and Explanation: A fluid flow is steady when its properties (velocity, pressure and others) do not change over time: P = P(x,y,z), with P being any of the properties.

So, an unsteady flow does depend upon time: P = P(x,y,z,t).

1. V = [[tex]ay2e^{-bt}[/tex]]i : This velocity field is one-dimension, because there is only the component in the x-direction and unsteady, because it is dependent upon the variable time (t);

2. V = [tex]ax^{2}i+bxj+ck[/tex] : is a three-dimensional field, because there is one component for each direction (x, y and z) and is steady, since it's independent of time;

3. V = axyi - bytj : is a 2-dimensional field, and since it changes with time, it is unsteady;

4. V = axi - byj + ctk : is a 3-dimensional field and the flow is unsteady;

The production of carbon dioxide makes it unwise and unsafe to operate a tractor or any motor vehicle inside enclosed spaces such as a barn.

True
False

Answers

I believe the answer is true

When the mass of an object decreases, the force of gravity does what?

Answers

Answer:

decreases too

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

decreases

Explanation:

Since the gravitational force is directly proportional to the mass of interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases (decreases), the force of gravitational attraction between them also increases (decreases).

Why are Gas cars Bad?(cons) give me reasons why gasoline cars are bad

Thx if u help ​

Answers

Answer: Gasoline cars are bad because

Explanation: They give off carbon emissions and pollute the ozone layer causing the greenhouse effect which leads to global warming

discuss referencing techniques​

Answers

Referencing is a standardised method of acknowledging the sources of information and ideas you have used. Usually you will identify these sources in the text (either with the author's surname and date in brackets, or with a number) and then include the full references as footnotes and/or as a list at the end of the work.

Answer:Referencing is a standardised method of acknowledging the sources of information and ideas you have used.

Explanation:Depending on the way in which they record sources, scholarly reference styles can be divided into three main categories: documentary notes styles, parenthetical (or author-date) styles, and numbered styles. Within each category there are several, slightly different reference styles.

Parenthetical citations give a short reference in parentheses directly in the text.Numerical citations give only a number that corresponds to a footnote, endnote, or reference list entry.

Referencing allows you to acknowledge the contribution of other writers and researchers in your work. Any university assignments that draw on the ideas, words or research of other writers must contain citations. Referencing is also a way to give credit to the writers from whom you have borrowed words and ideas.

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