A bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. The average resistance offered by the target is:
[tex]\huge{\boxed{{\colorbox{red}{1 N}}}}[/tex]
that's my answer
vf²=vi²-2ad (vf=0, stop)
vi²=2ad
200²=2.a.5
a = 200² : 10
F = ma
F = 25 x 200² : 10
F = 1 x 10⁵ dyne = 1 N
A foul ball is hit straight up into the air with a speed of 25 m/s.
how long is it in the air?
Answer:
31.25 m
Explanation:
The foul ball experiences upward linear motion thus:
initial velocity(u) - 25m/s
final velocity(v) - 0m/s
velocity due to gravity - -10m/s2 (since the ball moves upwards)
Hence:
v2=u2+2(gs)
0=625+2(-10*s)
0=625-20s
-625=-20s
s=31.25m
What happens to the force applied by the person pushing the crate (Fapplied
) as the frictional force increases? What can they do to change this force?
The force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
What is friction?Friction is defined as the force resisting the relative motion of an object when moving on the surface of another object. This force slow down the speed of a moving object.
So we can conclude that the force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
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what is the speed of light in air ?
[tex] \\ [/tex]
ty! ~
Answer:
the speed of light in air is about 299,000,000 and 3×10⁸ m/s
A roller coaster is moving at 10 m/s at the top of a hill and 22 m/s at the bottom of the hill two seconds later. What is the acceleration of the roller coaster?
Answer:
The acceleration is
Explanation:
Acceleration = final velocity - initial velocity
---------------------------------------
speed
Initial velocity = 10m/s
final velocity = 22m/s
speed = 2 secs
acceleration = 22 - 10
-----------
2
= 12/2
6 m/s^2
How many kg of ice at 0°C must be added to 0.6kg of water at 100°C in an insulated 0.1kg copper container and its contents to 30°C? The specific heats of water and copper are 4.2 and 0.39 kJ/kgK, respectively; the heat of fusion of ice is 335 kJ/kg.
Answer:
.389 kg of ice required
Explanation:
The heat absorbed by melting the ice and warming it to 30 C
must be equal to the heat lost by cooling the existing water and the copper from 100 to 30 C
First, melt the ice (this occurs at a constant temperature)
x * 335 kj/kg and warm this water x * 4.2 kj/kg-k * 30 k
(x = kg of ice required)
then cool the copper and the .6 kg water from 100 to 30 C (70 degrees)
.1 kg * .39 * 70 K + .6kg * 4.2 kj/kg-K * 70 K
then equate the two amounts of heat
x ( 335 + 4.2 *30) = .1 * .39 * 70 + .6 * 4.2 * 70
solve for x = .389 kg
How much kinetic energy does a 0.30-kg stone have if it is thrown at44
Answer:
290.4 joules
Explanation:
As the formula to find kinetic energy is 1/2 mv^2.
So if we put the given data in it,the answer comes 290.4 joules
(100 POINTS AND BRAINLIEST)
1. What are the four groups of carbon compounds found in living things?
2. Classify each substance as either sugar, starch, protein, or nucleic acid.
a. the major compound that makes up the skin
b. glucose
c. the major compound in potatoes
d. DNA
3. What is the difference between saturated and unsaturated fat? Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat?
1. carbohydrates, lipids, proteins, and nucleic acids.
2. a is protein b is sugar c is starch and d is nuclear acid
3. What is the difference between saturated and unsaturated fat? it's that Saturated fats have the maximum number of hydrogens possible, while unsaturated fats have a double bond between two of the carbons. part 2. Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat? I was not able to find a different answer for it than part 1.
Air is a good medium for sound waves because it is
Answer:
air does not have a modulus of rigidity.
Explanation:
Since air is completely elastic medium, that is, it does not have a modulus of rigidity, therefore sound waves in air are longitudinal.
A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?
Answer:
0.315C
Explanation:
Force/Electric field
7520N/23900C
5. How far can a car travel in 14 hours while going at a speed of 75 miles per hour?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Here we go ~
Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~
[tex]\qquad \sf \dashrightarrow \: d = v \sdot t[/tex]
[tex]\qquad \sf \dashrightarrow \: d = 75 \times 14[/tex]
[tex]\qquad \sf \dashrightarrow \: d = 1050 \: \: miles[/tex]
so, it can travel 1050 miles in 14 hours
Answer:
1050 miles
Explanation:
Simply:
d = 75 m/hr * 14 hr =1050 miles
( see how the 'hr' cancels and you are left with miles ?)
A dog barking at the sound of the postal carrier delivering mail is reacting to what type of cue?
A. External
B. Internal
Answer:
A. External
Explanation:
External stimulus includes touch/pain, vision, smell, taste, and sound.
(100 POINTS AND BRAINLIEST)
1. When elements form a molecule, what is true about the oxidation numbers of the atoms in the molecule?
a. The sum of the oxidation numbers must equal zero.
b. All oxidation numbers from the same molecule must be positive.
2. True or False: All oxidation numbers from the same molecule must be negative.
a. True
b. False
3. Which of the following elements will bond with oxygen resulting in a 1:1 ratio of oxygen and the element?
a. lithium
b. boron
c. beryllium
d. nitrogen
Answer:
1. a
2. b (FALSE)
3. c (beryllium)
Explanation:
Answer:
the answer for number one is A. number 2 is B. and number 3 is C.
Explanation:
theys a Quizlet made on these three questions already so I just got it from there. they should be correct pls let me know if they are.
Water flowing through a garden hose of diameter 2.74 cm fills a 25.0-liter bucket in 2.50 min. What is the volumetric flow rate?
A copper wire of length 25 cm is in a magnetic field of 0.20 T. If it has a mass of 10 g, what is the minimum current through the wire that would cause a magnetic force
equal to its weight?
Select one:
1.3 A
1.5 A
2.0 A
4.9 A
Hi there!
Recall the equation for magnetic force on a wire:
[tex]F_B = B \times iL[/tex]
[tex]F_B[/tex] = Magnetic force (N)
B = Magnetic field strength (0.2 T)
i = Current in wire (? A)
L = Length of wire (0.25 m)
This is a cross-product, but we can assume the field is perpendicular to the current since it is not explicitly stated otherwise.
The equation for the weight of an object (Force due to gravity) is given by:
[tex]F_g = mg[/tex]
m = mass of object (0.01 kg)
g = acceleration due to gravity (9.81 m/s²)
Set the two equations equal to each other and solve for 'i'.
[tex]F_B = F_g\\\\BiL = mg\\\\i = \frac{mg}{BL} = \frac{0.01 * 9.81}{0.2 * 0.25} = \boxed{1.962A \approx 2.0 A}[/tex].
How does the image make the message in the "Mummy, what happens to us if the bomb drops?" poster more clear?
A. The poster shows a clear picture of a girl having a serious talk with her parents.
B. The poster shows all the supplies needed to survive in picture format.
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
D. The poster shows the actual bomb attack.
Answer:
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
Explanation:
The girl looks quite worried in the poster. Attached is the image:
An empty hot air balloon weighs 1000 newtons (N). As the balloon is released in the air, the atmosphere provides a lift force of 3300 N. What is the magnitude and direction of the net force?
2300 N upward
4300 N upward
2300 N downward
4300 N downward
[tex]\Large{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}[/tex]
2300 N upward
Explanation:
The force by weight of balloon = 1000 N
The atmospheric force experienced by balloon = 3300 N
While weight of balloon is attracted by gravity so the force of weight will act downward
And the atmospheric force gives upward lifting force to the balloon
Net force = atmospheric force - weight of balloon
= 3300 - 1000
= 2300 N
As the atmospheric force is more dominating the balloon will goes upward with 2300 N force
The electrostatic force of attraction between two spheres that are one meter apart is 10 newtons (N). If the charge on each sphere is doubled, what is the new electrostatic force between the two spheres?
20 N
30 N
40 N
80 N
Answer:
its 20 n because of the temeture
Explanation:
because
A tourist, who weighs 805 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops one-fourth of the way along the bridge. Assume that the board of the bridge has negligible weight. What is the magnitude of the vertical force that a concrete support exerts on the bridge at the far end?
The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
What is force?The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
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What do you like MOST about your chosen learning modality
How many hydrogen atoms can bond with this oxygen atom?
Answer:
2
Explanation:
there are two lonely pairs
2 hydrogens
Explanation:
oxygen has 3 lone pairs of electrons which do not take part in the bonding leaving two electrons in the outermost shell to be part of it, hydrogen has only one electron in it's outermost shell it needs one electron to be stable so two atoms of hydrogen bonds with one oxygen atom to to share there electrons to be stable.
Consider an object of mass 2kg on a ramp with βs=0.5 and βk=0.4.
If we keep increasing the ramp angle, what is the angle() that the object starts to move downward? Give your answer in degree with 1 decimal place.
Answer:
bs angle will move in 1.5
Monitoring cash flow and keeping track of the bottom line of a business are responsibilities for whom?
What energy is produced by a 150 w lightbulb lit for 4.6 hours
W = Pt
W = 150 x (4.6 x 3600) = 2.484 x 10⁶ J
Light nulbs do not "produce" energy.
When YOU bring electrical energy from somewhere and pour it through the light bulb, the bulb turns some of it into light energy and the rest into heat energy .
(150 W) x (4.6 hr) =690 watt-hrs
or 0.69
calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high
Answer:
529.2 joules
Explanation:
Work done = force x distance = mass x gravity x distance
= 36x9.8 x1.5 =529.2 joules
when a tractor trailer and a smart car collide head on, who hits who with greater force? explain your reasoning
Answer:
The smart car hit with the greater force
Explanation:
Despite the trailers weight, the smart car moves with more speed and momentum than that of the trailer...
I don't even understand what I'm typing
Both will exert equal and opposite force on each other.
When a tractor-trailer and a smart car collide head-on, we can determine the relative forces experienced by each vehicle using Newton's second law of motion.
According to this law, the force acting on an object is equal to the rate of change of its momentum.
Let's consider the tractor-trailer as object 1 with mass [tex]\(M_1\)[/tex] and velocity [tex]\(V_1\)[/tex], and the smart car as object 2 with mass [tex]\(M_2\)[/tex] and velocity [tex]\(V_2\)[/tex].
The force exerted on object 1 due to object 2 [tex](\(F_{12}\))[/tex] can be calculated as:
[tex]\[F_{12} = M_1 \cdot \frac{{dV_1}}{{dt}}\][/tex]
Similarly, the force exerted on object 2 due to object 1 [tex](\(F_{21}\))[/tex] can be calculated as:
[tex]\[F_{21} = M_2 \cdot \frac{{dV_2}}{{dt}}\][/tex]
Since the collision is head-on, the direction of the forces will be opposite for the two objects.
To determine which object experiences a greater force, we need to compare the magnitudes of [tex]\(F_{12}\) and \(F_{21}\)[/tex] = 0 by Newton's third law.
Thus, both will exert equal and opposite force on each other.
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The most effective way to reduce waste is to not create it in the first place.
True
False
Answer:
True
Explanation:
If there isnt any waste it would reduce the quantity however the waste that is present needs to be dealt with so......
An 845–g bar of ice is initially at –25 °C. The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2050 J/(kg·°C), and the specific heat of water is 4180 J/(kg·°C). Determine how much energy is required if the final temperature of the system is to reach 39 °C.
Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.
Calorimetry, sensible heat and latent heatCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
Energy required in this case-25°C to 0 °CIn firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.
So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c(ice)= 2050 [tex]\frac{J}{kgC}[/tex] m= 845 g= 0.845 kgΔT= Tfinal - Tinitial= 0 °C - (-25) °C= 25 °CReplacing:
Q1= 2050 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 25 °C
Solving:
Q1= 43,306.25 = 43.3 kJ
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 0.845 kgΔHfus= 334 [tex]\frac{kJ}{kg}[/tex]Replacing:
Q2= 0.845 kg× 334[tex]\frac{kJ}{kg}[/tex]
Solving:
Q2= 282.23 KJ
0 °C to 39 °CSimilar to sensible heat previously calculated, you know:
c(liquid)= 4180[tex]\frac{J}{kgC}[/tex]m= 0.845 kgΔT= Tfinal - Tinitial= 39 °C - 0 °C= 39 °CReplacing:
Q3= 4180 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 39 °C
Solving:
Q3= 137,751.9 J= 137.75 kJ
Total heat requiredThe total heat required is calculated as:
Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ
Total heat required= 463.28 kJ
In summary, the amount of heat required is 463.28 kJ.
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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J
How to determine the heat required change the temperature from –25 °C to 0 °C Mass (M) = 845 g = 845 / 1000 = 0.845 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–25) = 25 °C Specific heat capacity (C) = 2050 J/(kg·°C) Heat (Q₁) =?Q = MCΔT
Q₁ = 0.845 × 2050 × 25
Q₁ = 43306.25 J
How to determine the heat required to melt the ice at 0 °Mass (m) = 0.845 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?Q = mL
Q₂ = 0.845 × 334000
Q₂ = 282230 J
How to determine the heat required to change the temperature from 0 °C to 39 °C Mass (M) = 0.845 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 39 °Change in temperature (ΔT) = 39 – 0 = 39 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?Q = MCΔT
Q₃ = 0.845 × 4180 × 39
Q₃ = 137751.9 J
How to determine the heat required to change the temperature from –25 °C to 39 °CHeat for –25 °C to 0°C (Q₁) = 43306.25 JHeat for melting (Q₂) = 282230 JHeat for 0 °C to 39 °C (Q₃) = 137751.9 JHeat for –25 °C to 39 °C (Qₜ) =?Qₜ = Q₁ + Q₂ + Q₃
Qₜ = 43306.25 + 282230 + 137751.9
Qₜ = 463288.15 J
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According to Clark Hull, our behavior is based on the need to reduce unwanted arousal
caused by physiological needs like hunger, thirst, and fatigue. He called these physiological
needs...
urges
drives. Desires. None of these.
Answer:
Clark Hull put the emphasis of his work on experimentation, an organized theory of learning, and the nature of habits, which he argued were associations between a stimulus and a response
Explanation:
Why are current and resistance kept very low?
A. To prevent excess heat.
B. Because the voltage is also quite low.
C. Both A. and B.
D. None of the above.
Answer:
I think the answer is B.
Explanation:
If the resistance is too high, the current will be low even if the voltage is enough.