University administrators have developed a Markov model to simulate graduation rates at their school. Students might drop out, repeat a year, or move on to the next year. Students have a 3% chance of repeating the year. First-years and sophomores have a 6% chance of dropping out. For juniors and seniors, the drop-out rate is 4%. Compute the probability that a student who starts as a 1st-year eventually graduates the university.

Answer:

m_added = 2 kg

Explanation:

From the question, we are told that the cylinder is allowed to fall 800 m in height. Thus, the potential energy will be converted into heat energy which will increase the temperature of water .

Now, let the mass of the falling cylinder be denoted by "m1" and let h be the height of fall.

Thus;

Formula for potential energy = mgh

Thus, as said earlier it's converted to heat generated. So heat generated = m1gh

Now let's calculate the heat absorbed;

heat absorbed = (m2)cΔt

Where;

ΔT is change in temperature

c is specific heat of water .

m2 is mass of water

Heat absorbed = heat generated

Thus;

(m2)cΔt = m1gh

Δt = m1gh/(m2•c)

Now, in both cases of the water and cylinder, m1, g , h and c are constant

Thus, we have;

Δt = (m1gh/m2) × 1/c

Where;

(m1gh/m2) is denoted as a constant k.

Thus;

Δt = K/m

For the first experiment, we have;

m = 2 kg

Δt = 2.4

Thus;

2.4 = K/2

Multiply both sides by 2 to get;

K = 4.8

For the second experiment, we have;

Δt = 1.2

Also,we have seen that K = 4.8

Thus;

Δt = K/m

Thus;

1.2 = 4.8/m

m = 1.2

m = 4 kg

Thus,mass added is;

m_added = 4 - 2

m_added = 2 kg

Answer:

tapping, horizontal dusting, slash drilling

Explanation:

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

Answer:

Q ≅ 1.53 m³/s

Explanation:

From the given information:

The flow rate of the orifice is:

[tex]v = c_v \sqrt{2gh}[/tex]

[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]

where;

[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &

[tex]c_d = c_c \times c_v[/tex]

∴

[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]

[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]

[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]

Q ≅ 1.53 m³/s

Answer:

A motion sensor uses one or multiple technologies to detect movement in an area. When a sensor detects motion, it sends a signal to your security systems control panel, which connects to your monitoring panel system. This alerts you and the monitoring center to a potential threat in your home.

Hope It Helps You................

Answer:protection circuit overload as usual

circuit overload

Explanation:

it is ery easy for wverone

Answer:

550kN

Explanation:

We are required to find the maximum allowable load that will satisfy geotechnical ULS requirements

P' = pu/FOS ---1

Pu = design load

FOS = factor of safety

We get the design of safety

Pu = 0.75p

= 0.75 x 2200

= 1650kN

Factor of safety = 3

Design load = 1650

P' = 1650/3

= 550kN

So we have the maximum allowable load to be 550kN

Solution :

1. PL [tex]$= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$[/tex]

       = 17.36 %

2. Liquid limit at 25 number of blows,

  [tex]$LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$[/tex]

       [tex]$= 47.75 $[/tex] %

Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%

Therefore, the Plasticity index, PI  [tex]$=47.75 - 17.36 = 30.39$[/tex] %

Equation of A-line [tex]$= 0.73 \times [47.75 - 20]$[/tex]

                             [tex]$=20.25 $[/tex] %

Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI

Answer: There are no major convergent boundaries in the Atlantic, which is where these events are more likely to occur

Explanation:

Explanation:

current- amperes

resistance- ohms

voltage- volts

electrical energy- kilowatt hours

electrical power- watts

hope it helps!

Answer and Explanation: A fluid flow is steady when its properties (velocity, pressure and others) do not change over time: P = P(x,y,z), with P being any of the properties.

So, an unsteady flow does depend upon time: P = P(x,y,z,t).

1. V = [[tex]ay2e^{-bt}[/tex]]i : This velocity field is one-dimension, because there is only the component in the x-direction and unsteady, because it is dependent upon the variable time (t);

2. V = [tex]ax^{2}i+bxj+ck[/tex] : is a three-dimensional field, because there is one component for each direction (x, y and z) and is steady, since it's independent of time;

3. V = axyi - bytj : is a 2-dimensional field, and since it changes with time, it is unsteady;

4. V = axi - byj + ctk : is a 3-dimensional field and the flow is unsteady;

Answer: Gasoline cars are bad because

Explanation: They give off carbon emissions and pollute the ozone layer causing the greenhouse effect which leads to global warming

Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load = [tex]\frac{wL}{2}[/tex]

w = maximum intensity of load , L = span of varying load

since AC = 6m( L )  then

Total load due to linearly varying load  = 3w  ------ ( 1 )

attached below is the detailed solution of the given problem

Answer:

the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

Given that;

depth 1 = 71 ft

depth 2 = 10 ft

pressure p = 17 psi = 2448 lb/ft²

depth h = 71 ft - 10 ft = 61 ft

we know that;

p = P_air + yh

where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )

so we substitute;

p = 2448 + ( 49.3 × 61 )

= 2448 + 3007.3

= 5455.3 lb/ft³

= 37.88 psi

Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

I won't answer each of these, but will give you an explaination of how to solve for each.

You'll need to use Ohm's Law and Kirchhoff's Voltage Law.

Remember Ohm's Law as [tex]V = IR[/tex].

Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.

[tex]E_T = E_1 + E_2 + E_3[/tex]

A couple of other helpful notes:

These three resistors are in series which means that the current flowing through them is equal.

So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]

Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).

Answer: A leak in the system

Explanation:

Answer:

decreases too

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

decreases

Explanation:

Since the gravitational force is directly proportional to the mass of interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases (decreases), the force of gravitational attraction between them also increases (decreases).

Answer:

Hello the circuit related to this question is missing attached below is the missing circuit

answer : 1.5 V

Explanation:

attached below is the detailed solution to the question

Applying Thevenin equivalent Circuit Theorem

First we perform Nodal analysis at Vth and draw the equivalent Thevenin circuits

Hence for a maximum power triangle

[tex]V_{RL} = \frac{V_{th} }{2} = \frac{-3}{2}[/tex]  = -1.5

therefore the value of v that maximizes the power dissipated in the voltage source

V = [tex]-V_{RL}[/tex] = 1.5 V

Answer:Referencing is a standardised method of acknowledging the sources of information and ideas you have used.

Explanation:Depending on the way in which they record sources, scholarly reference styles can be divided into three main categories: documentary notes styles, parenthetical (or author-date) styles, and numbered styles. Within each category there are several, slightly different reference styles.

Referencing allows you to acknowledge the contribution of other writers and researchers in your work. Any university assignments that draw on the ideas, words or research of other writers must contain citations. Referencing is also a way to give credit to the writers from whom you have borrowed words and ideas.