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Answer:

a) 20r + 20w = 500, 10r + 35w = 500

b) r = 15, w = 10

c) 900 calories

Explanation:

Let running time be r, walking time be w

a) Hence, make equation's:

20r + 20w = 500... equation 1

10r + 35w = 500... equation 2

b) Determine the value of the variables by solving simultaneously.

⇒ (500 - 20w)/20 = (500 - 35w)/10

cross multiply

⇒ 10(500 - 20w) = 20(500 - 35w)

multiply

⇒ 5000 - 200w = 10000 - 700w

shift sides

⇒ -200w + 700w = 10000 - 5000

simplify

⇒ 500w = 5000

divide both sides by 500

⇒ w = 10

Now find the value of variable r,

⇒ r = (500 - 20w)/20

insert w = 10

⇒ r = (500 - 20(10))/20

simplify

⇒ r = 15

Hence the value of r is 15 and w is 10

c) Find calories burnt after one hours of running:  [1 hours = 60 minutes]

calories = 60r = 60(15) = 900 calories

Hence, he can burn 900 calories after one hours of running.

a) standard deviation of the scores of the monthly home run totals in the player’s rookie season will be 1.29

b) The standard deviation of the scores of the monthly home run totals in this season will be 2.738

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

a)The standard deviation of the scores of the monthly home run totals in the player’s rookie season:-

The data from the graph will be

1,0,6,2,0,2

Standard deviation is calculated as:-

[tex]\sigma = \dfrac{\sqrt{\sum(x-\mu)^2}}{N}}[/tex]

[tex]\mu = \dfrac{1+0+6+2+0+3}{6}=2[/tex]

Putting the values we get

[tex]\sigma = \dfrac{\sqrt{(1-2)^2+(0-2)^2+(2-2)^2+(0-2)^2+(3-2)^2}}{6}}=1.29[/tex]

Hence standard deviation is 1.29

b)The standard deviation of the scores of the monthly home run totals in this season

The data from the graph will be

4,6,4,8,7,13

Standard deviation is calculated as:-

[tex]\sigma = \dfrac{\sqrt{\sum(x-\mu)^2}}{N}}[/tex]

[tex]\mu = \dfrac{4+6+4+8+7+13}{6}=7[/tex]

Putting the values we get

[tex]\sigma = \dfrac{\sqrt{(4-7)^2+(6-7)^2+(4-7)^2+(8-7)^2+(7-7)^2+(7-13)^2}}{6}}=2.738[/tex]

Hence standard deviation is 2.738

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Let's solve this problem step by step:

 ⇒ on one side, I solve the equaiton

    ⇒ on the other side, I give you the property that I use to solve the

        equation

         ⇒ you don't need to write down those properties if your teachers

             didn't ask you for it

  [tex]4(5x-2)=2(9x+3)\\[/tex]      |   Given equation

  [tex]20x-8=19x+6[/tex]           |    Distributive Multiplication over subtract/add

  [tex]x=14[/tex]                             |    Subtraction Property of Equality

Answer: x = 14

Definition of Properties:

Answer:

[tex]a^{4}-2a^{2} -24[/tex]

Step-by-step explanation:

We do FOIL to solve this

Answer:

a=b-44y

Step-by-step explanation:

a=b-44y

Answer:

A parameter is a numerical description of a population characteristic

Step-by-step explanation:

A parameter is a numerical description of a population characteristic

The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3

n³ / (2n - 6) ÷ n³ / (3n - 9)

= n³ / (2n - 6) × 1 / n³ / (3n - 9)

= 2n - 6 / 3n - 9

= 2(n - 3) / 3(n - 3)

= 2/3

Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3

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Answer:

2/3

Step-by-step explanation:

Answer:

[tex] d = sin(39) \times 30[/tex]

Answer:

273

Step-by-step explanation:

Answer: 273

Step-by-step explanation: when you divide 16.38 by 0.06 you get 273.

a) a= 2×40 = 160°

b) b = 60/2 = 30°

c) c = 40°

d) d = 115°

Answer:

4.1 units

Step-by-step explanation:

A( -2,3)

B( 2,5)

C( 8.6)

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve for x and y ~

Since the given triangle is a right angled triangle, we can use Trigonometric ratios here to get the required values

[tex]\qquad \sf  \dashrightarrow \: \tan(45 \degree) = \dfrac{y}{2 \sqrt{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: 1= \dfrac{y}{2 \sqrt{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 2 \sqrt{2} \: \: units[/tex]

Now, let's get to x ~

[tex]\qquad \sf  \dashrightarrow \: \sin(45 \degree) = \dfrac{y}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{ \sqrt{2} } = \dfrac{2 \sqrt{2} }{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \sqrt{2}{} \times \sqrt{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \times 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 4 \: \: units[/tex]

I hope you understood the whole procedure ~

The percent of change in the number of points she scored between the first and second tests  = 4.878 %

If the data is decreasing,

Decrease = Original Number - New Number.

Then: divide the decrease by the original number and multiply the answer by 100.

% Decrease = Decrease ÷ Original Number × 100.

Given that:

The score of first Math test = 82

The score of second Math test = 78

Changes occurs in marks by=78-82

                                               =-4

So, there is decrease in marks.

We have to find the decrease percentage:

Decrease%= [tex]\frac{change \;in \;value}{Original\; value} *100[/tex]

                   = [tex]\frac{4}{82} *100[/tex]

                   = 0.04878 * 100

                  = 4.878 %

There is 4.88% decrease in Olivia's score.

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The values of x given the following expression are ∛243/7 and 7^1/4

Given the following expression

7x³ =243
x³ = 243/7

x = ∛243/7

For the expression

5x⁴ + 7 = 42
5x⁴  = 42 - 7

5x⁴ = 35

x⁴ = 7

x = 7^1/4

Hence the values of x given the following expression are ∛243/7 and 7^1/4

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20f - 4 (5f + 4) + 16

= 20f - 20f - 16 + 16

= 0

Answer:

0

Step-by-step explanation:

Distribute terms in the parentheses

Answer:

radius = 72.00 in (nearest hundredth)

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substituting the given values into the formula and solving for r:

[tex]\implies \sf 1481276.16=3.14 \cdot r^2 \cdot 91[/tex]

[tex]\implies \sf 1481276.16=285.74r^2[/tex]

[tex]\implies \sf r^2=\dfrac{1481276.16}{285.74}[/tex]

[tex]\implies \sf r^2=5184[/tex]

[tex]\implies \sf r=\sqrt{5184}[/tex]

[tex]\implies \sf r=72\:in[/tex]

Answer: radius : 72.00 inch

The following is a cylinder.

Volume of Cylinder: πr²h

Given following:

Solve for radius:

[tex]\rightarrow \sf \pi r^2h =V[/tex]

[tex]\rightarrow \sf (3.14) r^2(91) =1,481,276.16[/tex]

[tex]\rightarrow \sf r^2 =\dfrac{1,481,276.16 }{91(3.14)}[/tex]

[tex]\rightarrow \sf r^2 =5184[/tex]

[tex]\rightarrow \sf r=\sqrt{5184}[/tex]

[tex]\rightarrow \sf r=72[/tex]

The special ticket cost to cover the expected value of the refunds would be $2.60

Probability of A winning = 80%

Probability of B winning = 20%

We have to solve for the rebate of the bet.

80% = 0.8, 20% = 0.2

0.8 x 2 = 1.6

0.2 x 5 = 1

The extra minimal cost of the special ticket would be calculated as: 1 + 1.6

= $2.6

Therefore the answer to the question is $2.6

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Part A

y-intercept: 3

It represents that after 0 months practice, the number of matches won is 3.

Part B

slope intercept form: y = mx + b

Here to find slope,

take two points: (5, 12), (0, 3)

[tex]\sf slope: \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{rise}{run}[/tex]

[tex]\rightarrow \sf slope = \dfrac{3-12}{0-5} = 1.8[/tex]

Equation:

y - y1 = m(x- x1)

y - 12 = 1.8(x - 5)

y = 1.8x - 9 + 12

y = 1.8x + 3

To find Matches won after 13 months

insert x = 13

y = 1.8(13) + 3

y = 26.4 ≈ 26 matches

The team could have won 26 matches after 13 months practice.

Answer:

See below ~

Step-by-step explanation:

Part A :

Part B :

Forming the equation :

Predicting how many matches can be won with 13 months of practice :

Answer:

(8w + 7)(7w + 9)

Step-by-step explanation:

56w² + 121w + 63

consider the factors of the product of the coefficient of the w² term and the constant term which sum to give the coefficient of the w- term

product = 56 × 63 = 3528 and sum = 121

After much trial and error the factors are + 49 and + 72

use these factors to split the w- term

56w² + 49w + 72w + 63 ( factor first/second and third/fourth terms )

= 7w(8w + 7) + 9(8w + 7) ← factor out (8w + 7) from each term

= (8w + 7)(7w + 9) ← in factored form

Problem 16

Work Shown:

[tex]2ax - 5x = 2\\\\x(2a - 5) = 2\\\\x = \frac{2}{2a-5}\\\\[/tex]

I factored out x, then divided both sides by (2a-5)

=========================================================

Problem 17

Work Shown:

1 yard = 3 feet

1/3 yard = 1 foot

x/3 yards = x feet

In the second step, I divided both sides by 3. Afterward, I multiplied both sides by x.

#16

Option C

#17

So

Answer:

volume = 14,137

Step-by-step explanation:

radius is the diameter divided by 2

30÷2=15

radius = 15 then square

15^2 = 225

formula of volume of a cone is 1/3*pi*raduis^2*the height

1/3(3.14)(225)(60)= 14,137

The volume of a cone with a diameter of 30 feet and a height of 60 feet is 14130.

The volume of the cone is given by;

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\Where;\ r = radius \ and \ h = height[/tex]

The volume of a cone with a diameter of 30 feet and a height of 60 feet.

The radius of the cone is;

[tex]\rm Radius =\dfrac{Diameter}{2}\\\\Radius=\dfrac{30}{2}\\\\Radius=15[/tex]

Substitute all the values in the formula

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\ Volume \ of \ cone=\dfrac{1}{3}\times 3.14 \times 15^2 \times 60\\\\Volume \ of \ cone=14130[/tex]

Hence, the volume of a cone with a diameter of 30 feet and height of 60 feet is 14130.

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Answer: number of kids(k)=200

sand the number of adults(a)=300, visited the carnival.

The tool I used is called simultaneous equation and I used elimation method as the method.

Answer:

Jorge needs 1/2 apple to make the snack.

Answer:

See below ~

Step-by-step explanation:

1. The average grade of Brenda :

2. During the second quarter, Brenda scored her lowest grade, which was an 82.

Answer:

908

Step-by-step explanation:

879+29=908

Answer: y=108

Step-by-step explanation:

Answer:

k = 4.5

y = 4.5x

Step-by-step explanation:

Finding the variation constant, k :

Equation of variation :

Answer:

The rule is "add 5, add 10, add 20" and the rule keeps doubling.