Answer:
0.0174 m
Explanation:
Given that:
mass of carbon 12 [tex]m_{c \ 12} = 1.993 \times 10^{-26} \ kg[/tex]
mass of carbon 13 [tex]m_{c \ 13} = 2.159 \times 10^{-26} \ kg[/tex]
Speed V = [tex]7.50 \times 10^ 5 \ m/s[/tex]
[tex]q = 1.6 \times 10^{-19 } \ C[/tex]
B = 0.9000 T
[tex]R_1 = \dfrac{ m_{c \ 12} \ v}{ qB}[/tex]
[tex]R_1 = \dfrac{ 1.993 \times 10^{-26} \ 7.50 \times 10^5}{ 1.6 \times 10^{-19} \times 0.90000}[/tex]
[tex]R_1 =0.1038 \ m[/tex]
[tex]R_2 = \dfrac{ m_{c \ 13} \ v}{ qB}[/tex]
[tex]R_2= \dfrac{2.159 \times 10^{-26} \ 7.50 \times 10^5}{ 1.6 \times 10^{-19} \times 0.90000}[/tex]
[tex]R_2 = 0.1125 \ m[/tex]
The spatial separation (D) = [tex]2R_2 - 2R_1[/tex]
[tex]D = 2(0.1125 \ m) - 2(0.1038 \ m)[/tex]
D = 0.0174 m
If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
This question is incomplete, the complete question is;
1.80 kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small angle oscillations is 0.940 s.
a) what is the moment of inertia of the wrench about an axis through the pivot?
b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
Answer:
a) the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b) the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
Explanation:
Given that
mass m = 1.80 kg
L or d = 0.250 m
period T = 0.940 sec
g = 9.8
a)
we take a look at the expression for the moment of inertia
I = T²mgL / 4π²
we substitute
I = ((0.940)² × 1.80 × 9.8 × 0.250) / 4 × π²
I = 3.896676 / 4 × π²
I = 0.0987 Kg.m²
Therefore the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b)
If the wrench is initially displaced 0.400 rad from its equilibrium position,
the angular speed of the wrench as it passes through the equilibrium position = ?
Using conservation of energy;
mg × d × ( 1 - cos∅) = 1/2×I×w²
we substitute
1.80 × 9.8 × 0.250 × ( 1 - cos(0.400 rad)) = 1/2 × 0.0987 × w²
4.41 × ( 1 - 0.921060994 ) = 0.04935 × w²
0.000441 = 0.04935w²
w² = 0.3481 / 0.04935
w² = 7.0536
w = √7.0536
w = 2.6559 rad/s
Therefore, the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
Which observation is the best evidence that some colors of visible light are
being absorbed in this photo?
A. The man's head is distorted under the water.
B. The top of the man's head appears disconnected.
C. The shape of the man's arm is clearly seen underwater.
D. The snorkel in the man's mouth appears yellow.
Answer:
D-The snorkel in the mans mouth appears yellow
Explanation:
Answer D is the only example related visible light being absorbed.
When Pluto was classified as a planet it was known as a oddball planet why? Why is it less if an oddball now?
Answer:
a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.
Explanation:
Explanation
A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead
Given :
Charge on glass bead, Q = 8 nC .
To Find :
The magnitude of the electric field 2.0 m from the center of the bead.
Solution :
Electric field at position r is given by :
[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]
Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .
A soccer has been kicked as far as it can get with an initial momentum of 153 kg*m/s and the
ball weights 1.8 kg. What is the velocity of the ball?
Answer:
85 m/s
Explanation:
The formula for momentum is product of weight and velocity
p=mv where m is mass and v is velocity
Given that;
Momentum = 153 kg*m/s
Weight = 1.8 kg
Velocity = ?
p=mv
153 = 1.8 * v
153/1.8 = v
85 m/s
Henry is researching the efficacy of a new drug for treating agoraphobia (fear of public places). His assistant, who is unaware of the study’s purpose, randomly assigns half of his 200 subjects a 30 day supply of the drug (Fearnot) and the other half a 30 day supply of a placebo (i.e., sugar pill). A month later the subjects are given a questionnaire to rate their fear of being in public. Henry finds that there is no difference between the two groups in their level of fear. How many subjects participated in this study?
1. Each of four boys were given
some marbles.
have
day.
punc
exan
class
Joe: sixth multiple of eight
Khal: quarter of a gross
mar
Tate: 4 dozen
Tevin: one score plus a dozen
Which two boys r3eceived the same
number of marbles?
A. Joe and Tate
B. Joe and Khal
C. Tate and Tevin
D. Joe and Tevin
Answer:
the answer is A because
from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48
Jane climbs the stairs to the first floor all by herself in a certain time. If the next time she rides the elevator to the first floor then which of the following statements is true?
The work done in both cases are different
the time taken in both cases is the same
the power in both cases is the same.
the work done in both cases is the same.
Answer:
the power in both cases is the same.
Explanation:
hope helps you
thanksss
Which hormone is released by the pancreas to reduce blood glucose levels?
Glucagon
Insulin
Glycogen
Answer:
Insulin.
Explanation:
The most important hormone that the pancreas produces is insulin. Insulin is released by the 'beta cells' in the islets of Langerhans in response to food. Its role is to lower glucose levels in the bloodstream and promote the storage of glucose in fat, muscle, liver and other body tissues.
John is conducting an experiment that involves melting ice cubes. Which of the following is most important for John to collect reliable data?
A.The outcome needs to be controlled.
B.An unbiased observer must witness the experiment.
C.Technology needs to be used to determine the results.
D.Only one variable should be tested during the experiment.
Answer:
Hmmmm
Explanation:
Answer:
B
Explanation:
Please help with a simple Physics question!
Regions of compression and rarefaction help define ______.
a. electromagnetic waves
b. longitudinal waves, but not transverse waves
c. transverse waves, but not longitudinal waves
d. all mechanical waves
SERIOUS ANSWERS PLEASE, THANK YOU AND GOD BLESS
Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart. Wave motion and particles.
Answer is B.
Once again, move the balloon to the right and let it go. Note how fast the balloon moves. Next, brush the balloon against the entire sweater. Allow all the electrons to transfer. Again, move the balloon all the way to the right, let it go, and note how fast it moves. Is there a difference in how fast the balloon moves when the balloon has more electrons and the sweater has fewer electrons?
Answer:
Yes. The balloon moves faster when it has more electrons and the sweater has fewer electrons
Explanation:
From Plato. Hope this helps!
Answer:
Yes. The balloon moves faster when it has more electrons and the sweater has fewer electrons
Explanation:
Edmentum
A 845kg dragster (very fast car) accelerates from 2m/s to 30m/s in 0.9s. Determine the average force exerted on the dragster.
Plis I need help
Answer:
Explanation:
Just use the Force formula.
F = M . A
Acceleration Formula
A = V - Vo / Time
So...
F = 845 . (30 - 2 / 0.9)
F = 845 . 20
F = 16900 N
look at the diagram below
Which statement is correct about Ray 1?
A 3.50-g bullet has a muzzle velocity of 250 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed of the rifle. m/s (b) If a marksman with a weight of 650 N holds the rifle firmly against his shoulder, determine the recoil speed of the shooter and rifle.
Answer:
(a) 0.343 m/s
(b) 0.012 m/s
Explanation:
(a) From the question above,
MV = mv............................... Equation 1
Where M = mass of the rifle, V = recoiling speed of the rifle, m = mass of the bullet, v = velocity of the bullet.
make V the subject of the equation
V = mv/M........................... Equation 2
Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg.
Substitute into equation 2
V = (0.0035×250)/2.55
V = 0.343 m/s.
(b) Similarly,
(M'+M)V' = mv....................... Equation 3
Where M' = mass of the marksman, V' = recoiling speed of the shooter and rifle
make V' the subject of the equation
V' = mv/(M'+M)................... Equation 4
Given: m = 3.5 g = 0.0035 kg, v = 250 m/s, M = 25 N = 25/9.8 = 2.55 kg, M' = 650 N = 650/9.8 = 66.33 N
Substitute into equation 4
V' = (0.0035×250)/(66.33+2.55)
V' = 0.8125/68.88
V' = 0.012 m/s
The recoil velocity can be obtained using the principle of conservation of linear momentum.
Using the principle of conservation of linear momentum;
momentum before collision = momentum after collision
Mass of the bullet = 3.50-g or 0.0035 Kg
Mass of the rifle = 2.5 Kg
Where;
M1 = mass of rifle
M2 = mass of bullet
u1 =initial velocity of rife
u2 = initial velocity of the bullet
(2.5 × 0) + (0.0035 × 250) = (0.0035 × 0) + (2.5 × v)
0.875 = 2.5 v
v = 0.35 m/s
For the shooter and the rifle;
(67.5 × 0) + (0.0035 × 250) = (0.0035 × 0) + (67.5 × v)
0.875 = 67.5 × v
v = 0.013 m/s
Learn more about momentum: https://brainly.com/question/904448
According to Coulomb's Law, how does distance affect the electric force?
A. The electric force only acts on objects that are in contact with
each other.
B. Only in charging by induction can the electric force act at a
distance.
C. Electric force gets stronger as charges get closer together and
gets weaker as charges move farther apart.
D. The electric force is zero if the objects are more than several
centimeters apart.
Answer:
C option is right.
Explanation:
According to columb's law
F ∝ 1/r²
so as r means distance between charges decrease force F increase and vice versa.
The student wants to collect data to determine the work done by the force due to gravity on the object as it falls. Which of the following lists contains the fewest number of measuring devices, in addition to the motion detector, that the student can use?
A - spring scale
B - spring scale and meterstick
C - stopwatch and meterstick
D - spring scale, meterstick, and stopwatch
Answer:
B - spring scale and meterstick
Explanation:
The work done by the force of gravity as the object falls is equal to the potential energy of the object.
We know that the gravitational potential energy(PE) of an object is obtained by;
PE =mgΔh
Where;
m = mass of the object
g = acceleration due to gravity
h= height of the object
The spring scale is needed to measure the mass of the object while the meterstick measures the Δh in meters.
Answer:
B
Explanation:
w= fd
f: spring scale
d: meterstick
Drop a comment if you have any questions! :)
The asteroid Icarus orbits the sun like other planets. Its period is about 410 days. What is its mean distance from the sun
Answer:
Mean distance = 1.61 x 10^8 km
Explanation:
Given the following data;
Orbital period for Icarus, T2 = 410 days
To find the mean distance of Icarus, we would use Kepler's third law of motion.
According to Kepler's third law of planetary motion, the square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.
Mathematically, it is given by the formula;
[tex] (\frac {T_{1}}{T_{2}})^2 = (\frac {r_{1}}{r_{2}})^3 [/tex]
Where;
T1 & T2 is the orbital period of a planetary object.
r1 & r2 is the mean distance of a planetary object.
Also, we know that the orbital period for earth, T1 = 365 days
Mean distance of earth = 1.49x10^8 km
Substituting into the equation, we have;
[tex] (\frac {365}{410})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]
[tex] (\frac {365}{410}})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]
[tex] (0.8902)^2 = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]
[tex] (0.7925) = (\frac {1.49x10^{8}}{r_{2}})^3 [/tex]
Cross-multiplying, we have;
[tex] (r_{2})^3 = \frac {1.49x10^{8}}{0.7925} [/tex]
Taking the cube root of both sides;
[tex] r_{2} = 1.61 * 10^8 km[/tex]
A child pulls a wagon at a constant velocity of 4.0 m/s for 4.0 minutes along a level sidewalk. The child does this applying a 22 N force to the wagon handle, which is inclined at 35 ° to the sidewalk as shown below. How much work does the child do on the wagon ?
288 k J
8.7 kJ
17.3 kJ
2.3 kJ
Answer:
288kj
Explanation:
An object on the end of a spring with spring constant k moves in simple harmonic motion with amplitude A and frequency f. Which of the following is a possible expression for the kinetic energy of the object as a function of time t?
a. kA^2sin^(2πft)
b. 1/2kA^2cos^2(2πft)
c. 1/2kA sin(2πft)
d. kAcos(2πft)
e. 1/2kAsin(2πft)
The expression for the kinetic energy of the object as a function of time, t is [tex]K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex].
The general wave equation is given as;
[tex]x = A \ cso(\omega t)\\\\x = A \ cos(2 \pi ft)[/tex]
Apply the principle of conservation of energy, the kinetic energy of a particle in such motion is given as;
[tex]K.E = U_x\\\\K.E = \frac{1}{2} kx^2[/tex]
Substitute the value of x into the kinetic energy equation
[tex]K.E = \frac{1}{2} kx^2\\\\K.E = \frac{1}{2} k ( A \ cos (2\pi ft)^2\\\\K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex]
Thus, the expression for the kinetic energy of the object as a function of time, t is [tex]K.E = \frac{1}{2} k A^2 \ cos^2 \ (2\pi ft)[/tex].
Learn more here:https://brainly.com/question/13736293
A man walks 10 km north, turns around and walks 5 km south. What displacement did the man walk?
A. 10km S
B. 5km N
C. 15km N
D. 5km S
Answer:
The total displacement is 5 km North (answer B)
Explanation:
Recall that displacement is defined by the vector formula:
Displacement = Final position - initial position
Which corresponds to a vector with its tail at the starting point, and the arrow at the final position. This gives a vector pointing North, and of length 5 km.
This agrees with answer labeled B.
58) Two balls, A and B are simultaneously projected from the top
of a building at 10 mis upwards & 20 m/s downwards respectively. Find
out the separation btwn them 3 sec after projection.
Answer:
90 m
Explanation:
For ball A::
The equation of a ball moving upwards is given by the formula:
s = ut - (1/2)gt²
where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) - (1/2) * 10 * 3²
s = 30 - 45
s = -15 m
The negative sign means the object travels in the opposite direction. Hence s = 15 m
For ball B::
The equation of a ball falling downwards is given by the formula:
s = ut + (1/2)gt²
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) + (1/2) * 10 * 3²
s = 30 + 45
s = 75 m
Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m
When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place 125 g of aluminum ina calorimeter with 1,000 g of water. The water changes temperature by 2 °C andthe aluminum changes temperature by â74.95 °C.
Required:
a. Water has a known specific heat capacity of 4.184 J/g °C. Usethe specific heat equation to find out how much heat energy the watergained (q).
b. Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)
Answer:
A) 8,368 J
B) 0.893 J/gºC
Explanation:
A)
The heat gained by the water can be obtained solving the following equation:[tex]q_{g} = c_{w} * m * \Delta T (1)[/tex]
where cw = specific heat of water = 4.184 J/gºCm= mass of water = 1,000 gΔT = 2ºC Replacing these values in (1) we get:[tex]q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)[/tex]
B)
Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:[tex]q_{l} = c_{Al} * m_{Al} * \Delta T (3)[/tex]
⇒ [tex]-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)[/tex]
[tex]c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)[/tex]
Answer:
A: the heat gained is 8368 J (8.368 KJ)
B: 0.893 J/g°C
Explanation:
A:
q = ?
m = 1000 g
C = 4.184 J/g°C
△T = 2°C
q = mc△T
q = (1000g) (4.184 J/g °C) (2 °C)
q = 8368 J
B:
q = mc△T
---------------
△T △T
c = q / m△T
c = - 8368 J / (125 g) (-74.95 °C)
c = 0.893 J/g°C
a uniform rod is hung at onen end and is partially submerged in water. If the density of the rod is 5/9 than of wter, find the fraction of the legth tof the rod above water
Answer:
[tex]\frac{h_{liquid} }{ h_{body} }[/tex] = 5/9
Explanation:
This is an exercise that we can solve using Archimedes' principle which states that the thrust is equal to the weight of the desalted liquid.
B = ρ_liquid g V_liquid
let's write the translational equilibrium condition
B - W = 0
let's use the definition of density
ρ_body = m / V_body
m = ρ_body V_body
W = ρ_body V_body g
we substitute
ρ_liquid g V_liquid = ρ_body g V_body
[tex]\frac{\rho_{body} }{\rho_{liquid} } } = \frac{V_{liquid} }{V_{body} } }[/tex]
In the problem they indicate that the ratio of densities is 5/9, we write the volume of the bar
V = A h_bogy
Thus
[tex]\frac{V_{liquid} }{V_{1body} } = \frac{ h_{liquid} }{h_{body} }[/tex]
we substitute
5/9 = [tex]\frac{h_{liquid} }{ h_{body} }[/tex]
Which property of a solid measures how resistant the material is to deformation?
A. Elasticity
B. Hardness
C. Plasticity
D. resilience
Answer: the answer is a
Explanation:
Does the mass of an object make it need more force to move, and to stop?
Answer:
Yea
Explanation:
Let's compare a brick to a small table, does it take more force and strength to push a car or a small table? A car, because it's heavier and has more mass.
Answer:
Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.
Explanation:
☝️
importance of choke coil?
Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.
Explanation:
When Coach Kwan notices that a player is getting tired, she takes out the tired player and substitutes a fresh player.
Which type of chemical reaction does this best model?
Answer:
is replacement
Explanation:
What is my name?:
I am a god
I am a guardian of the sun
I am used to measure heat.
Answer:
Apllo?
Explanation:
I need help with science
Answer:
Ca = 2
Cl = 2
O = 6
Explanation:
Element given from the question above include = 2CaClO₃
NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.
Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:
Ca = 1 × 2 = 2
Cl = 1 × 2 = 2
O = 3 × 2 = 6
Thus,
Ca = 2
Cl = 2
O = 6
