Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?

(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.

Two Blocks Are Connected To Identical Ideal Springs And Are Oscillating On A Horizontal Frictionless

Answers

Answer 1

Hi there!

We can begin by identifying key characteristics of both graphs.

Graph A.

Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).

We also know that:
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]

We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.

Graph B.

The amplitude is 20 cm (0.2 m), and each period is 4 seconds.

We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.

For the other choices, we must look at forces and work.

Recall that:
Spring potential energy = [tex]\frac{1}{2}kx^2[/tex]

Kinetic energy = [tex]\frac{1}{2}mv^2[/tex]

Using the work-energy theorem:

[tex]\frac{1}{2}kx^2 = \frac{1}{2}mv^2[/tex]

Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.

Using Hooke's Law:
[tex]\Sigma F = -kx\\\\ma = -kx\\[/tex]

[tex]a = \frac{-kx}{m}[/tex]

If the mass is greater, the acceleration will be smaller. Choice D is correct.



Related Questions

According to Sigmund Freud, memories that easily surface into everyday thought are which part of the mind?

Answers

The conscious mind contains all of the thoughts, memories, feelings, and wishes of which we are aware at any given moment. This is the aspect of our mental processing that we can think and talk about rationally. This also includes our memory, which is not always part of consciousness but can be retrieved easily and brought into awareness.

hope it helps...!!!

According to Sigmund Freud, memories that easily surface into everyday thought are a conscious part of the mind.

What is conscious mind?

At any given time, the conscious mind contains all of our thoughts, memories, feelings, and wants.

This is the element of our brain functioning that we can reasonably think about and discuss. This includes our memories, which are not always conscious but can be readily recovered and brought into awareness.

Memories that easily emerge into everyday consciousness, according to Sigmund Freud, are a conscious element of the mind.

Hence, memories that easily surface into everyday thought are a conscious part of the mind.

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In a ______ wave, particles
the medium move perpendicular
to the direction of the wave.

Answers

Answer:

Transverse wave

Explanation:

I hope this helps you! :)

A steam engine is working. What is the transformation of energy?​

Answers

As its name suggests, the steam engine operates on the force of water vapor (steam) heated to high pressure. It is a technology that converts thermal energy (heat) to mechanical energy (work).

What role does your chosen reaction play in your life? Combustion

Answers

Answer:

When fuels burn in combustion reactions, they release useful thermal energy (heat). Combustion reactions are used to heat our homes, power most cars, and to generate a lot of our electricity.

Energy production from the reaction is what drives life and human greed. We stay alive by eating carbon-rich compounds, which are then burned in a spectacularly controlled and efficient manner to provide us with energy. It is the all-important energy term in the combustion equation that has made life on Earth possible

WILL GIVE BRAINLIEST no spamming
How are stationary waves formed on a string?

Answers

Answer:

hey, please open my account and see my question, please help me solve the task, I have to send it to the teacher soon.

Answer:

When waves are generated and they reflect off a fixed end, the reflected waves are completely out of phase. The reflected waves and the incident waves interfere with each other along the path and results in the formation of nodes and anti-nodes. Nodes are points of completely out of phase interference and anti-nodes are points of completely in phase interference.

Help please!

An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?

Answers

The correct expression for the maximum speed of the object during its motion is [tex]\frac{FT}{m}[/tex].

Maximum speed of the object

The maximum speed of the object is determined using the following formulas;

v(max) = Aω

where;

A is the amplitude of the motionω is angular speed

The maximum speed of the object can also be obtained from the maximum net force on the object,

F = ma

where;

F is the maximum net forcea is the accelerationm is mass of the object

F = m(v/t)

mv = Ft

v = Ft/m

Thus, the correct expression for the maximum speed of the object during its motion is [tex]\frac{FT}{m}[/tex].

Learn more about maximum speed here: https://brainly.com/question/4931057

Answer:

[tex]\frac{FT^{2} }{4\pi ^{2} }[/tex]

Explanation:

I just finished the AP Physics Exam and the other answer got the question wrong.

Find the Product or expression of: (4x-2)2​

Answers

Answer:

8x-4

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

[tex]\Longrightarrow: \boxed{\sf{8x-4}}[/tex]

Hence, the final answer is 8x-4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4

An audio compact disk (CD) has a playing time of 55 minutes. When the music starts, the CD is
rotating at an angular speed of 480 revolutions per minute (rpm) and during the playback the
rotation slows down. The average angular acceleration of the CD is a = -4.0 rev/min . Find the
angular speed at which the CD is rotating at the end of the music. Express your answer both in
rev/min and also in rad/s.

Select one:
27.2 rad/s
220 rad/s
120 rad/s
260 rad/s
22 rad/s

Answers

Answer:

See below

Explanation:

-4 rev / min^2 * 55 min =  - 220 rev/ min

480 - 220 = 260 rev/min at end

2pi radians /rev * 260 rev/min  = 1633.6 Radians/min

At the end of the music, the angular speed of the C.D. would be (d) 260 rev/minute and 1633.6 rad/minute

To calculate angular speed following information is given in the question:

The angular speed (ω) of the C.D. at starting = 480 revolutions/minuteThe playing time (t) of the C.D. is = 55 minutesThe angular acceleration (α) of the C.D. = -4 rev/[tex]min^{-2}[/tex] Angular speed of the C.D. at the end of the music will be = α*tAngular speed of the C.D. at the end of the music will be = 4 rev/[tex]min^{-2}[/tex] *55 min = -220 rev/minAt the end of the music angular speed = 480-220 rev/min = 260 rev/minValue of angular speed in rad/sec = 2π radians/rev*260 rev/min = 1633.6 Radians/min

Hence, option (d) is correct which states that the angular speed is 260 rev/min and 1633.6 radians/min.

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What is the magnetic flux going through a coil with 0.065 m2 area if the intensity of the magnetic field is 0.114 T.

Answers

Hi there!

[tex]\Phi _B = \int B \cdot dA[/tex]

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

[tex]\Phi _B = B A cos\theta[/tex]

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

[tex]\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}[/tex]

What is the magnitude of the electric field 3m away from the source if the electric potential is described by the function f(x)=2x+3, where x=2?

Answers

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

ture or false
A land breeze is when the cooler air over the ocean moves in toward land.

Answers

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

I’ve tried my hardest n just keep blowing my head please help!!

Answers

Answer:

Forces

Explanation:

1) A Force

2) Balanced

3) Unbalanced

4) Any object moving at a constant speed, Any object in 0 motion, A balanced see-saw (no net torque/forces)

5) Any object accelerating, Someone pushing a box

how many snow leopards live together in the wild (give a number or tell if they are solitary?)

Answers

Snow leopards are solitary... If you ever see a two or more snow leopards together, consider yourself extremely lucky! Fun fact: There is no term for a group of snow leopards because it is so rare to see them in a group!

Your welcome!

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

A man is pushing a large box with a force of 44 newtons. He slides over a floor that has a sliding frictional force of 12 Newtons. What is the acceleration?

Answers

I’m sorry I was not texting lol but 12 subduing and I got a phone call back to you later on for your birthday 17 wyd

A student uses a candle to model the process of an existing rock becoming an igneous rock. Which procedure best demonstrates the formation of an igneous rock?A) Melt the candle in a dish on a hotplate and keep it in liquid form.B) Break the candle into small pieces and crush the small pieces until they stick together.
C) Place books on top of the candle to apply pressure, and then heat it so its composition changes.D) Hold the lit candle over a small dish, and then let the melted candle wax that drops into the dish cool and harden.

Answers

Answer:

D) Hold the lit candle over a small dish, and then let the melted candle wax that drops into the dish cool and harden.

N:B-- IT MUSTN'T REMAIN IN LIQUID FORM; IT MUST COOL & SOLIDIFY.

Explanation:

Igneous rocks are formed when magma cools and solidifies in the earth's crust.

 Their characteristics are;Crystalline in nature.Are massive.Lack fossils

write about Archimedes principle​

Answers

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics.

Answer:

When a body is immersed fully or partially in a fluid, it experience is an upward force that is equal to the weight of the fluid displaced by it.

Applications:In designing ships and submarines.Lactometers used to determine the purity of sample of milk.Hydrometer is used to determine the density of liquids.

-What is the potential energy at point A?

-What is the kinetic energy at point A?

-What is the kinetic energy at point B?

-What is the potential energy at point D?

-What is the kinetic energy at point D?

Answers

Answer:

1560520156

Explanation:

Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.

Using the data from point C, we can find out that the total energy of the system is 156 because  [tex]E = K+Pe[/tex].

Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].

At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:

[tex]156=104+K\\52=K[/tex]

At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.

Problem 19: Oil with a density of 892 kg/m is flowing smoothly through a pipe, as
shown. In the lower portion, the oil is flowing at vi = 1.84 m/s, and the pressure gauge
indicates P, = 237 kPa. In the upper portion of the pipe, oil is flowing at V2 = 3.61 m/s at a
height that is 8.63 m above the lower portion.

Answers

The pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

Pressure in the upper portion of the pipe

The pressure in the upper portion of the pipe is calculated by applying Bernoulli's equation,

P₁ + ¹/₂ρv₁² + ρgh₁ = P₂ + ¹/₂ρv₂² + ρgh₂

Given;

P₁  = 237 kPav₁ = 1.84 m/sh₁ = 0v₂ = 3.61 m/sh₂ = 8.63 mρ = 892 kg/m³P₂  = ?

Susbtsitute the given parameters and solve the for the pressure in the upper portion of the pipe.

237,000 + ¹/₂(892)(1.84)² + (892)(9.8)(0) = P₂ + ¹/₂(892)(3.61)² + (892)(9.8)(8.63)

238,509.9776 = P₂ + 81,252.325

P₂ = 238,509.9776 - 81,252.325

P₂ = 157,257.65 Pa

P₂ ≅ 157 kPa

Thus, the pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

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solve ~
[tex]13x - 26 + 39 = 0[/tex]

ty! :)

Answers

Explanation:

13x - 26 + 39 = 0

13x=26-39

13x=-13

x= -1

[tex]13x-26+39=0\\\\\implies 13x +13 = 0\\\\\implies 13x = -13\\\\\implies x = -\dfrac{13}{13}\\\\\implies x = -1[/tex]

Fill in the blanks. If an object changes speed of __, its velocity also changes. Any change in ___results in acceleration.

Answers

If an object changes the speed of direction, its velocity also changes. Any change in velocity results in acceleration.

Hope that helps!

Mrs. dela Vega had 27 students in her class last year and this year she had 30 students in her math class. What is the percent of difference?

Answers

The class grew by (30-27) = 3 students.

3 is (3/27) = 1/9 of its original size.

The class grew by 1/9 or 11.1 % .

help me solve the following question below in the attachment

Answers

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

In a circuit, we are using conducting wires made from Manganese.
(i) If we assume there are 3 free electrons per an atom of manganese, what is its
electron density?
(ii) How much current flows through a cylindrical manganese wire of volume 27 cm3,
length 3cm if the circuit is switched on for 5 seconds?

Answers

i. The electron density of maganese is 2.44 × 10²⁸ electrons/m³

ii. The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

To solve the question, we need to know what electron density is.

What is electron density?

This is the number of free electrons per unit volume of material.

To find electron density, we need to find the atom density which is the number of atoms per unit volume, n.

Atom density of manganese

So, the atom density of manganese is n = Nρ/A where

N = avogadro's number = 6.022 × 10²³ atoms/mol, ρ = density of manganese = 7430 kg/m³ and A = atomic mass of manganese = 0.0594 kg/mol

So, n = Nρ/A

n = 6.022 × 10²³ atoms/mol × 7430 kg/m³/0.05494 kg/mol

n = 44743.46 × 10²³ atoms/mol × kg/m³/0.05494 kg/mol

n = 81440.59 × 10²³ atoms/m³

n = 8.144059 × 10²⁷ atoms/m³

n ≅ 8.14 × 10²⁷ atoms/m³

i. Electron density of manganese

The electron density of maganese is 2.44 × 10²⁸ electrons/m³

So, the electron density of manganese n' = n" × n where

n" = number of free electrons per atom = 3 and n = atom density = 8.14 × 10²⁷ atoms/m³

So, n' = n" × n

= 3 electrons per atom × 8.14 × 10²⁷ atoms/m³

= 24.42 × 10²⁷ electrons/m³

= 2.442 × 10²⁸ electrons/m³

≅ 2.44 × 10²⁸ electrons/m³

So, the electron density of maganese is 2.44 × 10²⁸ electrons/m³

ii. How much current flows through the cylindrical maganese wire?

The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

The current flowing through the wire is given by i = n'eV/t where

n = electron density = 2.44 × 10²⁸ electrons/m³, e = electron charge = 1.602 × 10⁻¹⁹ C, V = volume of wire = 27 cm³ = 27 × 10⁻⁶ m³ and t = time current flows = 5 s

So, substituting the values of the variables into the equation, we have

i = n'eV/t

i = 2.44 × 10²⁸ electrons/m³ × 1.602 × 10⁻¹⁹ C × 27 × 10⁻⁶ m³/5 s

i = 105.54 × 10³ C/5 s

i = 21.11 × 10³ C/s

i = 21.11 × 10³ A

i = 21.11 kA

So, the current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

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A box weighing 8 newtons requires a force of 2 newtons to push it along the floor. The coefficient or friction Berween the box and the floor is_?​

Answers

I believe the answer is 16.

 Have a blessed day!

4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of
kinetic friction is u - 0.3. If the crate is subjected to a 400-N towing force as shown,
determine the acceleration of the crate.
your
P = 400 N
490.5 N
400 N
too

30
30°
+
F-0.3 Nc
Nc
ΣΕ = max
Σ F, = may
A. a = 4. 185 m/s2
B. a = 5. 185 m/s2
C. a = 6. 185 m/s2
D. The entire above are false

Answers

Answer:

5.057 m/s^2

Explanation:

Force of kinetic friction = .3  = F /normal force

  .3 = F /(50* 9.81)     F of friction = 147.15

Net force =   400 - 147.5  =  252.85  N

F = m * a

252.85 = 50 * a       a = 5.057 m/s^2

can i get some help please

Answers

Answer:

B. They reproduce

Explanation:

Both arent made up of one cell, and both arent made up of mutliple cells. Only some unicellular and multicellular organisms are infectious.

Answer:

Your answer would be:
B.) They reproduce.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function. Multicellular organisms are composed of more than one cell, with groups of cells differentiating to take on specialized functions.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism. Multicellular organisms use many different cells to function.


Unicellular organisms are single-celled.

Multicellular organisms are multi-celled.
However, both reproduce.




Explanation:

Have a great rest of your day
#TheWizzer

A particle (q = +5.0 µC) is released from rest when it is 2.0 m from a charged particle which is held at
rest. After the positively charged particle has moved 1.0 m toward the fixed particle, it has a kinetic
energy of 50 mJ. What is the charge on the fixed particle?
a. –2.2 µC
b. +6.7 µC
c. –2.7 µC
d. +8.0 µC
e. –1.1 µC

Answers

The answer to your question is A. Have a great day

The kinetic energy of the charged particle is equal to the work done to bring it from the distance of 1 m. Hence, the total electric force here is 0.025 N. Therefore, the charge on the fixed particle is  approximately + 6.7 µC.

What is Coulomb's law ?

According Coulomb's law the electrostatic force between two charges is given by ,

F =  k q1 q2 /r²

Where q1 and q2 be the charges and r be the distance between them, k be the constant equal to 8 × 10⁹ N m²/C².

Given q1 = + 5  µC

r = 1 m.

the kinetic energy in bringing the charge of  5 µC from 2 m is given 50 mJ.

then F = 0.05 J/2 m = 0.025 N

Then q2 = F r²/ (q1 K)

q2  = 0.025 N / ( + 5  µC × 8 × 10⁹ N m²/C²)

      =  6 µC.

Therefore, option b is the approximate charge of the fixed particle.

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A 0.60- m -tall barrel is filled with water (with a weight density of 9800 N/m3 ). Find the water pressure on the bottom of the barrel. Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

P =  ρ g H       explains the pressure of a uniform column of density ρ

P = ρ H            where ρ is given as a weight density

P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2

Note N/m^2 = Force / Area      the definition of pressure

true or false
a)we should play inside our classroom..........
b)curd is made from milk........
c) wa.........t.............​

Answers

Answer:

a) we should play inside our classroom

Explanation:

Lactose intolerance does not mean a kid is allergic to milk, but they will probably feel bad after drinking milk or eating dairy products
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