Answer:
Ex = k q / b2 [- ¾] , Ey = k q / b2 3
Explanation:
For this exercise we calculate the electric field created by each load on a test charge located at the origin
Field created by load q = + q
E₁ = k q / r²
r = b-0
E₁ = k q / b²
in the negative direction of the x axis
Field created by load q = -2q
E₂ = k (2q) / (2b-0)₂
E₂ = K q / 2b₂
The field is in the negative direction of the x-axis
Field created by charge q = + q / 3
this charge creates a field that has components on the x and y axes
X axis
E3x = K (q / 3) / (2b / 3) 2
E3x = K q 3 / 4b²
as the charge is on the negative side of the x axis. The field goes to the bright side
Axis y
E3y = k (q / 3) / (b / 3) 2
E3y = k q / b²
directed up
therefore the electric field is the sum of the field created by each charge
X axis
Ex = -E1 + E2 + E3x
Ex = -k q / b2 - k q / 2b2 + k q 3 / 4b2
Ex = k q / b2 [-1 -1/2 + ¾]
Ex = k q / b2 [- ¾]
Axis y
Ey = k q / b2 3
If a musician increases the wavelength of the sound waves
she produces without changing their speed, what must be happening to the frequency?
Explain your answer.
Answer:
The frequency decreases
Explanation:
The frequency will decrease as the wavelength continues to increase.
Wavelength is the distance between successive crests or troughs on a wave motion.
Frequency is the number of waves that passes through a point per unit of time.
it is expressed as;
f = [tex]\frac{speed }{wavelength}[/tex]
We can see that frequency is inversely proportional to wavelength.
As wavelength increases the frequency reduces.
Stokes’ law describes sedimentation of particles in liquids and can be used to measure viscosity. Particles in liquids achieve terminal velocity quickly. One can measure the time it takes for a particle to fall a certain distance and then use Stokes’ law to calculate the viscosity of the liquid. Suppose a steel ball bearing (density 7.8 \times 10^3~\text{kg/m}^37.8×10 3 kg/m 3 and diameter 3.0~\text{mm}3.0 mm) is dropped in a container of motor oil. It takes 12 s to fall a distance of 0.60 m. Calculate the viscosity of the oil.
Answer:
The viscosity is [tex]\eta = 0.76243 \ kg/ m \cdot s [/tex]
Explanation:
From the question we are told that
The density is [tex]\rho = 7.80 *10^{3} \ kg/m^3[/tex]
The diameter is [tex]d = 3.0 \ mm =0.003 \ m[/tex]
The time taken is [tex]t = 12 \ s[/tex]
The distance covered is [tex]d = 0.60 \ m[/tex]
Generally the velocity of the ball is
[tex]v = \frac{d}{t}[/tex]
=> [tex]v = \frac{0.60}{12}[/tex]
=> [tex]v = 0.05 \ m/s [/tex]
Generally the mass of the steel ball is
[tex]m = \rho * V[/tex]
Here V is the volume and this is mathematically represented as
[tex]V = \frac{4}{3} * \pi * [\frac{d}{2} ]^3[/tex]
=> [tex]V = \frac{4}{3} * 3.142 * [\frac{0.003}{2} ]^3[/tex]
=> [tex]V = 1.414 *10^{-8} \ m^3[/tex]
So
[tex]m = 7.80 *10^{3} * 1.414 *10^{-8}[/tex]
[tex]m = 0.00011 \ kg [/tex]
Generally the viscosity is mathematically represented as
[tex]\eta = \frac{m * g}{6\pi * r * v }[/tex]
Here r is the radius represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.003}{2}[/tex]
[tex]r = 0.0015 \ m [/tex]
So
[tex]\eta = \frac{0.00011 * 9.8}{6 * 3.142 * 0.0015 * 0.05 }[/tex]
=> [tex]\eta = 0.76243 \ kg/ m \cdot s [/tex]
10. when creating a cardiovascular fitness routine which program would be appropriate?
A Sprint a short distance
B Lift a heavy weights
C Run for a long time
D Use the entire range of motion
13. what would be an appropriate amount of time to hold a static stretch?
A 5 seconds
B 20 seconds
C 1 minute
D 5 minute
14. what activity may help prevent injury if it is performed prior to playing a sport?
A weight thing
B dynamic stretching
C high intensity interval training
D sprints
15. when your workout routines gets too easy what should you do?
A Increase the frequency
B Increase the intensity
C Increase the time
D All
PLEASE HELP
Answer:
10. B
13. It's actually 30 seconds but 20 comes closest so B
14. B, any type of stretching is good before you perform any type of physical activity because it loosens up the muscles
15. D, all of the above
Explanation:
I have done many sports in my life and am still very active, I grew to know most of these things through the years.
A force of 50 N acts upon a 10 kg block. Calculate the acceleration of the object.
An electron is accelerated from rest by a potential difference of 435 V. It then enters a uniform magnetic field of magnitude 167 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
Answer:
(a) the speed of the electron is 1.237 x 10⁷ m/s
(b) the radius of its path in the magnetic field is 4.21 x 10⁻⁴ m
Explanation:
Given;
potential difference, V = 435 V
magnetic field, B = 167 mT = 0.167 T
(a) the speed of the electron
eV = ¹/₂mv²
[tex]v = \sqrt{\frac{2eV}{m} }\\\\ v = \sqrt{\frac{2(1.6*10^{-19})(435)}{(9.1*10^{-31})}}\\\\v = 1.237*10^7 \ m/s[/tex]
(b) the radius of its path in the magnetic field
[tex]r = \frac{mv}{eB}\\\\r = \frac{(9.1*10^{-31})(1.237*10^7)}{(1.6*10^{-19})(0.167)}\\\\r = 4.21 *10^{-4} \ m[/tex]
Which statement is supported by Kepler's laws?
O The closer a planet is to the Sun, the faster it moves.
O The farther a planet is from the Sun, the faster it moves.
O As a planet moves away from the Sun, its gravitational force increases.
O As a planet moves away from the Sun, its gravitational force remains the same.
Answer:
A. The closer a planet is to the Sun, the faster it moves.
Explanation:
According to this law, planets move around the sun in elliptical orbits. An imaginary lines drawn from the center of Sun to center of planets will sweep equal area in equal time interval.
Answer option B,C&D is incorrect because planets that are far away from the Sun take more time to move all around the Sun and experience less gravitational force and move slower than those near the Sun.
Answer:
a
i am never wrong
ASAP PLEASE :)
How can we add kinetic energy to a baseball or football?
Answer:
Hitting it or throwing it with force.
Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Answer:
[tex]B=1.61\times 10^{-4}\ T[/tex]
Explanation:
The attached figure shows the path followed by an electron in the semicircular path from A to B.
Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]
It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].
The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be [tex]B=1.61\times 10^-{4]\ T[/tex]
What is magnetic field?The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.
The attached figure shows the path followed by an electron in the semicircular path from A to B.
The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]
It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}[/tex]
[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]
[tex]B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]B=1.61\times 10^-{4]\ T[/tex]
To know more about the magnetic field, follow
https://brainly.com/question/26257705
If the forces on an object are balanced, the object will do what?
Sheba is texting and driving. She does not see the baby chinchila
sitting in the road! If she was traveling at 35 m/s, and at best her
car can accelerate at -3.5 m/p/s, how far would it take her to stop?
Answer:
dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34
Explanation:
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true? Group of answer choices The potential energy of the electron is decreasing and it is moving to a region having a higher potential The potential energy of the electron is decreasing and it is moving to a region having a lower potential. The potential energy of the electron is increasing and it is moving to a region having a lower potential The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Complete Question
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?
Group of answer choices
a The potential energy of the electron is decreasing and it is moving to a region having a higher potential
b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.
c The potential energy of the electron is increasing and it is moving to a region having a lower potential
d The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Answer:
The correct option is C
Explanation:
From the question we are told that
An electron in between the plates is moving to the right
Generally the potential energy of the electron is mathematically represented as
[tex]PE = e * V[/tex]
Here e is the charge on the electron and V is the electric potential of the electron
Generally the left side with the positive charge has a higher potential than the right side with the negative charge
Now when the potential energy of the electron increases it will move toward the plate with the lower potential which is the left plate
Which is the correct answer?? Can you help please?
What was Bear B's average speed in m/min? (No units required for answer. Type your answer.)
Answer:
43
Explanation:
you divide 2600 by 60 and your answer is 43.3333333
I just took the quiz and got it right!
3. Pencils should not be used inside the computer to change the setting of switches or to
and
pry off jumpers because the tip contains lead which can act as a
may damage the computer Components.
Answer: True
Explanation:
Pencils indeed should not be used as tools when working inside a computer because it is made of Lead.
Lead is a conductor of electricity and as such if it is left inside the computer at even miniscule quantities, it can redirect electricity and damage components in the process.
If one wants to work inside a computer, it is best to use tools like tweezers and needle-nose pliers.
Due to the presence of graphite(A good conductor of electricity), Pencils should not be used inside the computer to change the setting of switches.
What is the meaning of conductors?The conductors are the materials that can allow electricity and heat to pass through them.
Since the pencils are made up of graphite which is a good conductor of electricity. When we use pencils to do something inside the computer circuits and if some portion of the graphite remains on the circuit board.
Now due to the good conducting property of the graphite, it will allow the current to flow and the short circuit of the circuit board can take place which will damage the computer.
Thus due to the presence of graphite(A good conductor of electricity). Pencils should not be used inside the computer to change the setting of switches.
To know more about Conducting materials follow.
https://brainly.com/question/771692
mechanical energy defintion
Answer: Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
(The energy acquired by the objects upon which work is done)
If you hold a piece of copper wire in an open flame, which of the following will most likely happen?
The heat will travel through the wire to your hand.
The light will change into electricity.
The flame will absorb heat from the wire.
The ſame will get brighter.
Answer:
The heat will travel through the wire to your hand.
Explanation:
Thats the one that makes the most sense.
What is the frequency of a short-wave radio transmission with a wavelength of 20. m?
Answer:
just do that
Explanation:
λ = C/f
Where,
λ (Lambda) = Wavelength in meters
c = Speed of Light (299,792,458 m/s)
f = Frequency
d2 = 20 m, d1= 50m
What is the magnitude of the resultant?
Answer:
53.85m
Explanation:
If we are assuming that d1 is one side of a triangle, and d2 is the other, and we are looking for the magnitude, which is essentially the hypotenuse, we use Pythagorean Theorem. a^2+b^2=c^2. 20^2 + 50^2 = 2900.
The square root of 2900 is 53.85164. Therefore, that is your hypotenuse.
8. According to the passage, in order for LeBron James to score a slam-dunk, what must he
exert?
Answer:
Kenetic Energy?
Explanation:
I need more context of what you are studying here...
The period of a pendulum is measured 16 times. The average value of the period over these 16 trials is calculated to be 1.50 seconds, whereas the standard deviation is found to be 0.24 seconds. The standard error (or standard deviation of the mean) therefore is 0.24 seconds divided by the square root of 16, yielding 0.06 seconds. Assuming that the uncertainty of this period arises solely from random error for these 16 trials, about how many additional trials would need to be completed to reduce the standard error to 0.03 seconds? ______________
Answer:
The additional trials needed is 48 trials
Explanation:
Given;
initial number of trials, n = 16 trials
the standard deviation, σ = 0.24 s
initial standard error, ε = 0.06 s
The standard error is given by;
[tex]\epsilon = \frac{\sigma}{\sqrt{n} }[/tex]
To reduce the standard error to 0.03 s, let the additional number of trials = x
[tex]0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials[/tex]
Therefore, the additional trials needed is 48 trials.
What is true about radioactive isotopes of an atom?
They are less stable.
They are more abundant.
They are more scarce.
They are more stable.
Answer:
they are less stable
Explanation:
i took the test
Explain why a golf ball that is hit on the moon travels much farther than a golf ball that is hit with the same force on Earth.
Answer:
the reason why is that if it is hit with the same force the moon has a lot less gravity than the earth dose so the golf ball will hit the ground on earth first before the golf ball on moon dose
is it better to walk or run in the rain?
Answer:
Not gonna lie. I actually had to think about this a lot XD
Running in the rain can cause you to slip and get hurt. Which I think isn't what you would want.
Walking in the rain (although it is sad), is actually a better idea than running.
Hope this helps!
Answer:
Walk
Explanation:
Running might stop you from being outside for as long, but running on wet ground will most likely result in a not-so-graceful faceplant.
A crate is pulled with a force of 165 N at an angle 30°
northwest. What is the resultant horizontal force on the crate?
Help asap?
Answer: 143 N
Explanation:
An electromagnet crane is carrying the electromagnet with the help of the three cables. But the electromagnet is not stable because of the wind. What is the reason behind the cause
Answer:
The reason behind the given instance is summarized below.
Explanation:
When another electromagnet shifts because of the wind, it induces a simulated area that acts on either the electromagnet as an effect or force, considered as the Lorentz force. This force thus renders the resultant force equivalent to a non-zero value mostly on the electromagnet. The balance is not protected by this power. When there is no breeze, just the three connectors sustain equilibrium.I’ve been stuck on this question, what’s the answer to this question?
Explanation:
[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]
Where [tex]\sf{H_2CO_3 }[/tex] is Carbonic AcidWhere [tex]\sf{ NaOH }[/tex] is Sodium HydroxideReaction gives out [tex]\sf{ NA_2CO_3 + H_2O}[/tex]Where [tex]\sf{ NA_2CO_3 }[/tex] is Sodium HydroxideAnd [tex]\sf{ H_2O}[/tex] is water.So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.
Hope it helps :)
What is the ostrich’s average acceleration from 9.0 to 18s
Answer:
Explanation:
10.00 5
The fuel is ignited in a model rocket sitting on a launch pad, which blasts the rocket upward. The rocket goes up because: Group of answer choices air friction pushes on the escaping fuel. the downward force of gravity is less than the downward momentum of the fuel. None of the above. the fuel pushes on the launch pad. the downward force of gravity is greater than the downward momentum of the fuel.
Answer: The fuel pushes on the launch pad.
Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.
Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.
What effect docs temperature have on the dissolution rate in sugar water?
A box weighing 52.4 N is sliding on a rough horizontal floor with a constant friction force of magnitude LaTeX: ff. The box's initial speed is 1.37 m/s and it stops after 2.8 s. Determine the magnitude of the friction force exerted on the box.A box weighing 52.4 N is sliding on a rough horizontal floor with a constant friction force of magnitude LaTeX: ff. The box's initial speed is 1.37 m/s and it stops after 2.8 s. Determine the magnitude of the friction force exerted on the box.
Answer:
The magnitude of the friction force exerted on the box is 2.614 newtons.
Explanation:
Since the box is sliding on a rough horizontal floor, then it is decelerated solely by friction force due to the contact of the box with floor. The free body diagram of the box is presented herein as attachment. The equation of equilbrium for the box is:
[tex]\Sigma F = -f = m\cdot a[/tex] (Eq. 1)
Where:
[tex]f[/tex] - Kinetic friction force, measured in newtons.
[tex]m[/tex] - Mass of the box, measured in kilograms.
[tex]a[/tex] - Acceleration experimented by the box, measured in meters per square second.
By applying definitions of weight ([tex]W = m\cdot g[/tex]) and uniform accelerated motion ([tex]v = v_{o}+a\cdot t[/tex]), we expand the previous expression:
[tex]-f = \left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex]
And the magnitude of the friction force exerted on the box is calculated by this formula:
[tex]f = -\left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex] (Eq. 1b)
Where:
[tex]W[/tex] - Weight, measured in newtons.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial speed, measured in meters per second.
[tex]v[/tex] - Final speed, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]W = 52.4\,N[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]v_{o} = 1.37\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]t = 2.8\,s[/tex], the magnitud of the kinetic friction force exerted on the box is:
[tex]f = -\left(\frac{52.4\,N}{9.807\,\frac{m}{s^{2}} } \right)\cdot \left(\frac{0\,\frac{m}{s}-1.37\,\frac{m}{s} }{2.8\,s} \right)[/tex]
[tex]f = 2.614\,N[/tex]
The magnitude of the friction force exerted on the box is 2.614 newtons.
