if the coefficient of friction between the block of mass 5 kg and ball is 0.5, then minimum force F required to hold the block with the wall is (g=10 m/s²)
Given parameters:
Mass of block = 5kg
Coefficient of friction = 0.5
g = 10m/s²
Unknown
Minimum force F required to hold the block =?
Solution:
Frictional force is a force that opposes motion.
The minimum force required to hold the block to the wall is the frictional force.
Frictional force = uN
Where u is coefficient of friction
N is the normal force
N = mg
where m is the mass of the body
g is the acceleration due to gravity
So,
Frictional force = umg
= 0.5 x 5 x 10
= 25N
The force required here is 25N
Which is formed by positive ions from a base and negative ions from an acid?
salt
vinegar
soap
carbonate
Answer:a
Explanation:
The formation of salt takes place by the sharing of positive ions from a base and negative ions from an acid. Hence, option (a) is correct.
The given problem is based on the concept and fundamentals of Neutralization. The process of neutralization is the name given to the chemical reaction between that takes place between the acid and base.
An acid is the chemical species having the negative ion, hence also known as anions.And the bases are the chemical species having the positive ions, hence they are also known as cationic species. During the chemical reaction between the acid and base, the positive ions from the base and negative ions from the an acid forms a neutral compound, known as Salt. Therefore, this reaction is also known as neutralization reaction.Thus, we can conclude that the formation of salt takes place by the sharing of positive ions from a base and negative ions from an acid. Hence, option (a) is correct.
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What volume is represented by each small tick mark ? Help need to turn in today !
Answer:
the beakers measure in milliliters (ml)
the skinny one measures 1 ml per tick mark
the wider one measures 25 ml per tick mark
An airplane has a maximum airspeed velocity of 140 mph South. If the wind is 60 mph West, what is the resultant velocity (groundspeed) and direction of the airplane?
Answer:
R∠ is 152,3 ∠ 246,8
Explanation:
We need to add (vectorially) these two velocities. We can choose the coordinates system just that speed of the airplane is the negative part of the y-axis, and negative region of the x-axis, for wind speed, according to
this, the module of the resultant velocity R is:
R =√ (60)² + (140)²
R = √( 3600) + ( 19600)
R =√ 23200
R = 152,315 mph
The tangent of the angle (α ) between R and the y-axis is:
tan α = 60/140
tan α = 0,4286
From tangent tables, we get arctan 0.4286
α = 23,2⁰
Then R∠ is 152,3 ∠ 246,8
Answer:
R∠ is 152,3 ∠ 246,8
PLEASE HELP ASAP
A golf ball is hit horizontally off the edge of a 30 m high cliff and lands
distance of 25 m from the edge of the cliff.
1. What is the initial vertical velocity of the golf ball?
2. At what time did the golf ball hit the ground?
3. What was the initial horizontal velocity of the golf ball?
4. What was the final horizontal velocity of the golf ball?
Answer:
1. Initial vertical velocity its 0m/s
2. 2.47 seconds
3. 10.12 m/s
4.10.12 m/s
Explanation:
Remember that we have here two parts of a problem, first we know that the ball made a free fall of 30 meters, since the ball was hit horizontally and doesn't state otherwise the vertical velocity is 0. To calculate the time we just use 30 m as our Height and use the formula for vertical distance on free fall:
[tex]H=\frac{g*t^{2} }{2} \\[/tex]
Now we just solve for time:
[tex]t=\sqrt{\frac{2H}{g} }[/tex]
With this we just insert the values we know:
[tex]t=\sqrt{\frac{2H}{g} }\\t=\sqrt{\frac{2*30}{9.81} }\\t=2.47[/tex]
Now we know that the ball was 2.47 seconds in the air, so the ball hti the ground at the second 2.47.
To calculate the velocity of the ball we just need to divide the horizontal distance covered by the time it spent on air:
[tex]v=\frac{d}{t} \\v=\frac{25}{2.47} \\v=10.12[/tex]
The final and initial horizontal velocity of the ball would be the same since nothing states otherwise, of course the hitting of the ground would decrease its velocity but since nothing is said in the problem it is not considered.
1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).
2. The time it took the golf ball to hit the ground is 2.47 seconds.
3. The initial-horizontal velocity of the golf ball is 10.12 m/s.
4. The final-horizontal velocity of the golf ball is 10.12 m/s.
Given the following data:
Maximum height = 30 meters.Horizontal distance = 25 meters.1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).
2. To determine the time it took the golf ball to hit the ground:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
g is the acceleration due to gravity.H is the maximum height.Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 30}{9.8} }\\\\Time = \sqrt{\frac{60}{9.8} }\\\\Time =\sqrt{6.12}[/tex]
Time = 2.47 seconds.
3. To determine the initial-horizontal velocity of the golf ball:
[tex]Horizontal\;velocity = \frac{Horizontal\;distance}{Time} \\\\Horizontal\;velocity = \frac{25}{2.47}[/tex]
Initial horizontal velocity = 10.12 m/s.
4. To determine the final-horizontal velocity of the golf ball:
The initial-horizontal velocity and final-horizontal velocity of the golf ball would be the same.
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The bodies of many cars are designed to compress or crumple during an accident. Why are cars built with a crumple zone?
please please please please
Answer:
....................
Answer:
20
Explanation:
40/2.0=20.......
hope it helps
a 50-kg object is acted upon by a net force of 360-N how much does it accelerate?
Answer:
it acceleration 7.2m/s²
Explanation:
mass of object = 50kg
force of object = 360N
acceleration = ?
Force= mass × acceleration
acceleration = force/mass
acceleration = 360N/50Kg
acceleration = 7.2m/s²
it accelerate 7.2 m/s²
If you push on an object that has a mass of 400 kg and it accelerates at 4 m/s2, what would the acceleration (a) be if the mass was reduced to 1/4 as much?
(Hint: Instead of plugging 400 kg into the equation, plug 100 kg into the equation as the mass but keep the force at 1,600 N.)
a
1/4 m/s2
b
16 m/s2
c
8 m/s2
d
4 m/s2
Answer:
b 16 m/s².
Explanation:
Hello.
In this case, the force exerted to the mass of 400 kg at an acceleration of 4 m/s² is:
[tex]F=400kg*4m/s^2=1600N[/tex]
Now, since the mass is decreased to 100 kg (1/4 of 400 kg), and the force remain the same, the new acceleration should be:
[tex]a=\frac{F}{m}=\frac{1600kg*m/s^2}{100kg}\\ \\a=16m/s^2[/tex]
Thus, the answer is b 16 m/s².
Best regards.
10 points
If a boat traveling East has a Net Force of 324 N, and the wind blowing
West has a Net Force of 789 N. What is the overall Net Force and which
side?
465 N, East
465 N, West
1113 N, West
1113 N, East
Answer:
465 N,East ............
John and Suzie are trying to improve the speed of their race car by adjusting the angle of the rear spoiler. Which choice is the controlled variable(s)?
the maximum speed and the angle of the rear spoiler
the type of tire and the type of fuel
only the maximum speed
only the angle of the rear spoiler
Answer:
the type of tire and the type of fuel
Explanation:
True or False: a projectile accelerates only in the y (vertical) direction. The "x," or
horizontal acceleration is equal to zero.
Answer:
True
Explanation:
Assuming no wind resistance, there will be no horizontal acceleration, because there will be no forces acting on it.
What is the example of stop moving
Answer:
Example:
A car applying brake.
A player catching a bowl.
Megan is eating a Snickers and decides not to finish the last it of it. She drops the snickers into a trashcan below. What happens to the speed of the piece of Snickers as it falls towards the trashcan?
Answer:
i like trains 45654
Explanation:
Suppose an octopus knows an enemy is nearby. Which two things would the octopus most likely do to escape?
A. Hide in a small space
B. Find something to eat
C. Attract a mate
D. Change its color
E. Show happiness or sadness
Answer:
A and D
Explanation:
The image below shows the processes of mitosis and meiosis.
How do the products of mitosis compare to the products of meiosis?
A.
The cells from mitosis are identical to each other and to the parent cell, but the cells from meiosis are not identical to each other or the parent cell.
B.
The cells from mitosis are a requirement of sexual reproduction, but the cells from meiosis are a requirement of asexual reproduction.
C.
Mitosis produces sperm and egg cells, but meiosis produces body cells, like skin and muscle.
D.
Mitosis produces cells with half the chromosomes of the parent cell, but meiosis produces cells with the same chromosomes as the parent cell.
Answer:
It’s D
Explanation:
The cells from mitosis are identical to each other and to the parent cell, but the cells from meiosis are not identical to each other or the parent cell. Hence, option (A) is correct.
What are mitosis and meiosis?Chromosome replication and equitable distribution between the two daughter cells occur during the cell division process known as mitosis. Each daughter cell has the same number of chromosomes as the parent cell, making them diploid. Thus, mitosis is sometimes referred to as equational division.
Meiosis is a type of cell division that describes how germ cells divide, resulting in the fission of two nuclei. The two nuclear fissions, known as meiosis 1 and meiosis 2, result in the formation of four sex cells known as gametes. The number of chromosomes in each sex cell is divided in half from that of the parent cell. This type of cell division happens during reproduction when one cell divides into four haploid daughter cells. The nucleus divides into four daughter cells, or nuclei.
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Which direction is the force of gravity on earth
Answer:
It is toward the center
Explanation:
Give reasons.
A stone thrown upward returns back to the earth surface.
Answer:
Gravity
Explanation:
Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.
Hope this helps!
Which best describes a neutralization reaction?
a reaction between an acid and a base
a reaction between two acids
a reaction between a base and a salt
a reaction between two salts
Answer:
a reaction between an acid and a base
Explanation:
Answer:
The answer is A. A reaction between an acid and a base
Explanation:
Consider the head-on collision between a nitrogen molecule, mass 28u and a water molecule mass 18u. Prior to the collision, the nitrogen molecule is moving with velocity 0.4390 km/s and the water molecule is moving with velocity -0.7690 km/s. Positive velocities indicate a molecule moving to the right and a negative velocities indicate a molecule moving to the left. Immediately after the collision, the velocity of the water molecule is v = 0.7016 km/s. The atomic mass unit (u) is commonly used to indicate the mass of atoms and molecules: 1u=1.66×10-27kg. What is the velocity of the nitrogen molecule immediately after the collision? (in km/s)
The velocity of the nitrogen molecule immediately after the collision (in km/s) is -0.5064 km/s.
What is conservation of linear momentum?When there is no external force acting on the system, the initial momentum before collision is equal to the final momentum after collision.
According to the momentum conservation principle,
m₁u₁ +m₂u₂ =m₁v₁ +m₂v₂
here, u represents the initial velocities, v represents final velocities and m represents the masses.
Given is the mass of nitrogen molecule, m₁ =28u =28 x 1.66×10⁻²⁷kg = 46.48 x 10⁻²⁷kg
the mass of water molecule, m₂ =18u =18 x 1.66×10⁻²⁷kg = 29.88 x 10⁻²⁷kg
initial velocity of nitrogen molecule u₁ = 0.4390 km/s
initial velocity of water molecule u₂ = -0.7690 km/s
final velocity of water molecule v₂ = 0.7016 km/s
Substituting the values into the above expression, we get the final velocity of the nitrogen molecule
46.48 x 10⁻²⁷kg x 0.4390 km/s + 29.88 x 10⁻²⁷kg x (-0.7690 km/s) = 46.48 x 10⁻²⁷kg x v₁ + 29.88 x 10⁻²⁷kg x 0.7016 km/s
v₁ = -0.5064 km/s
Thus, the final velocity of nitrogen molecule is -0.5064 km/s (to left).
Learn more about conservation of linear momentum.
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Q.3 There is two conductors A and B of same
material having lengths L and 2L and radii r and
r/2 respectively. What is the ratio of their
resistance?
Answer:
resistance = (resistivity.(l/A))
so for the 2 materials we get
r1 = resistivity.(l/r)
r2=resistivity.(2l/(r/2))
so ratio r1/r2=1/4
Explanation:
The resistance is proportional to the length and inversely proportional to the area (which is proportional to the square of the radius). Thus if we are just comparing the two (so the constants will cancel out).
r1 = l/r^2 (r squared).
r2 = (2l)/(1/2r)^2
r2 = 2l/(1/4)r^2
dividing by 1/4 is the same as multiplying to 4, so you are multiplying by 2 and then by 4, thus by 8.
Thus R2 is 8 times more than R1.
1. Define Inertia
2. Define Balenced force
3. Define Unbalenced force
Answer:
inertia:
a tendency to do nothing or to remain unchanged.
balanced force:
When two forces acting on an object are equal in size but act in opposite directions.
unbalanced force:
When two forces acting on an object are not equal in size.
A bar of gold has a temperature of 22 Celsius, and a bar of aluminum has a temperature of 27 Celsius. Which statement explains why the bar of aluminum as a higher temperature
Answer:Type of metal
Explanation:Basically certain types of metal may heat and get cold faster maybe the alumm may collect more sun and heat more and stay that way
Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.
What is meant by thermal conductivity ?The ability of a material to conduct or transport heat is referred to as thermal conductivity.
Here,
It is not the solid itself that moves in bulk as a result of thermal conductivity; rather, it is molecular agitation and contact.
A region of high temperature and high molecular energy is moved towards a region of lower temperature and lower molecular energy via a temperature gradient.
The density of aluminium is small. It is easily castable, machinable, and formable, and it has a high thermal conductivity and great corrosion resistance.
At 20 °C, gold has an electrical resistivity of 0.022 micro-ohm m and a thermal conductivity of 310 W m-1 K-1.
Aluminium conducts more heat than gold.
Hence,
Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.
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Why can concave mirror is used in cosmetic mirror
Answer:
"When face is placed between the concave mirror and its focus, it produces a magnified image. This enlarged image of face is helpful in makeup as even pores of skin are clearly visible."
Which of the following is man made and is used to store water for drinking or irrigation
Answer:
Reservoir.
Explanation:
Which two types of waves require matter in order to travel A:light waves B:sound waves C:electromagnetic waves D:Water waves
Answer:
Sound Waves
Light Waves
Explanation:
The effect wind has on an airplane can be modeled by using a wind tunnel. What is one limitation of this model
Answer:
The limitations of this this model is the amount of wind being blown to effect the airplane.
Answer: Highly skilled workers are necessary to run the wind tunnel.
Explanation: I took the quiz on A pex.
HURRY PLS 30 MINS LEFT
A ball is rolling across the floor so that it is traveling along the positive x axis at 5.00 m/s. Due to the bend of the carpet fibers it experiences an acceleration of 1.25 m/s2 at an angle of -125.0o from the x axis.
A. What is the x component of the acceleration?
B. What is the y component of the acceleration?
C. What is the x component of the balls displacement after 3.00s?
D. What is the y component of the balls displacement after 3.00s?
E. What is the displacement of the ball over 3.00s?
Answer:
A) aₓ = -0.717 m / s² , B) a_{y} = -1.024 m / s², C) x = 11.77 m , D) y = -4.6 m ,
E) d = 12.64 m
Explanation:
For this exercise we will use trigonometry to decompose the acceleration, we are told that
a = 1.25 m /s² with an angle tea = 125º in a clockwise direction
A) cos θ = aₓ / a
aₓ = a cos θ
aₓ = 1.25 cos (-125)
aₓ = -0.717 m / s²
B) sin θ = [tex]a_{y}[/tex] / a
a_{y} = a sin θ
a_{y} = 1.25 sin (-125)
a_{y} = -1.024 m / s²
C) The displacement component
x = v₀ₓ t + ½ aₓ t²
let's calculate
x = 5 3 + ½ (-0.717) 3²
x = 11.77 m
D) the y component of the displacement
y = [tex]v_{oy}[/tex] t + ½ [tex]a_{y}[/tex] t²
in this case the initial velocity is zero
y = 0 + ½ (-1,024) 3²
y = -4.6 m
E) Let's use the Pythagorean theorem
d =√ (x² + y²)
d = √ (11.77² + 4.6²)
d = 12.64 m
10 points
5). A car accelerates from rest to the speed of 9.6m/s over a distance of
40.5m. Determine the acceleration of the car.
Explanation:
u=0 m/s
v=9.6 m/s
s= 40.5 m
a=?
V^2=u^2 +2as
9.6^2=0+2×a×40.5
92.16=81a
a=92.16/81
a=1.14m/s^2
Define Transmission, reflection, refraction and diffraction
Answer:
transmission: the act or process by which something is spread or passed from one person or thing to another
reflection: when light from an object is reflected by a surface, it changes direction. It bounces off the surface at the same angle as it hits it. Smooth, shiny surfaces such as mirrors and polished metals reflect light well.
refraction: change in direction of a wave passing from one medium to another or from a gradual change in the medium
diffraction: various phenomena that occur when a wave encounters an obstacle or opening
