Answer:
The weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].
Explanation:
First of all, we need to find the acceleration of gravity at 2R. Using the gravitational force equation
[tex]F=G\frac{mM}{R^{2}}[/tex]
Where:
M is the mass of the earth
m is the mass of the object
G is the gravitational constant
R is the radius of the earth
We can equal the gravitational force with the second Newton's law (F=ma)
[tex]F=G\frac{mM}{R^{2}}[/tex]
[tex]mg=G\frac{mM}{R^{2}}[/tex]
We know the weight at the earth surface is 90 N, which means:
[tex]90=G\frac{mM}{R^{2}}[/tex]
Now, we have the same equation in the case of 2R as a distance from the surface of the object. Let's remember we need to use the distance from the center of the mass of the earth, so in this case, will be 3R.
[tex]F'=G\frac{mM}{(3R)^{2}}[/tex]
[tex]F'=G\frac{mM}{9R^{2}}[/tex]
[tex]F'=\frac{1}{9}G\frac{mM}{R^{2}}[/tex]
Using the above equation we have:
[tex]F'=\frac{1}{9}90[/tex]
[tex]F'=\frac{90}{9}[/tex]
Therefore, the weight at a distance 2R from the surface of Earth will be [tex]F'=10 N[/tex].
I hope it helps you!
When Pluto was classified as a planet it was known as a oddball planet why? Why is it less if an oddball now?
Answer:
a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.
Explanation:
Explanation
What determines whether a real or a virtual image is formed from a concave mirror?
Answer:
The distance of the object from the concave mirror determines if it is a virtual or real image
Explanation:
Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.
can i eat air? im hungry
Answer:
Yes
Explanation:
If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
This question is incomplete, the complete question is;
1.80 kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small angle oscillations is 0.940 s.
a) what is the moment of inertia of the wrench about an axis through the pivot?
b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
Answer:
a) the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b) the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
Explanation:
Given that
mass m = 1.80 kg
L or d = 0.250 m
period T = 0.940 sec
g = 9.8
a)
we take a look at the expression for the moment of inertia
I = T²mgL / 4π²
we substitute
I = ((0.940)² × 1.80 × 9.8 × 0.250) / 4 × π²
I = 3.896676 / 4 × π²
I = 0.0987 Kg.m²
Therefore the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b)
If the wrench is initially displaced 0.400 rad from its equilibrium position,
the angular speed of the wrench as it passes through the equilibrium position = ?
Using conservation of energy;
mg × d × ( 1 - cos∅) = 1/2×I×w²
we substitute
1.80 × 9.8 × 0.250 × ( 1 - cos(0.400 rad)) = 1/2 × 0.0987 × w²
4.41 × ( 1 - 0.921060994 ) = 0.04935 × w²
0.000441 = 0.04935w²
w² = 0.3481 / 0.04935
w² = 7.0536
w = √7.0536
w = 2.6559 rad/s
Therefore, the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
You are sitting on the beach and notice that a seagull floating on the water moves up and down 5 times in I minute. What is the frequency of the water waves
Answer:
f = 0.0833 Hz
Explanation:
Frequency is defined as the no. of cycles per unit time. The frequency of water waves can be given by the following formula:
[tex]Frequency\ of\ waves = f = \frac{No.\ of\ Waves}{time}\\[/tex]
here,
No. of Waves = No. of times seagull moves up and down = 5
Time = 1 minute = 60 sec
Therefore, using these values in the formula, we get:
[tex]f = \frac{5}{60\ sec}[/tex]
f = 0.0833 Hz
A subway train is brought to a stop from a speed of 0.500 m/s in 0.400 m by a large spring bumper at the end of its track. What is the force constant of the s
Complete question is;
A 5 × 10^(5) kg subway train is brought to a stop from a speed of 0.5 m/s in 0.4 m by a large spring bumper at the end of its track. what is the force constant k of the spring
Answer:
781250 N/m
Explanation:
From conservation of energy, potential energy is equal to kinetic energy.
Thus;
½mv² = ½kx²
where;
m = mass of train
v = velocity of train
k = force constant of spring
x = the distance the train went while being stopped
We are given;
Mass; m = 5 × 10^(5) kg
Velocity; v = 0.5 m/s
Distance; x = 0.4 m
Thus, from ½mv² = ½kx²
Divide both sides by ½ to get;
mv² = kx²
k = mv²/x²
k = [(5 × 10^(5)) × 0.5²]/0.4²
k = 781250 N/m
I need help with science
Answer:
Ca = 2
Cl = 2
O = 6
Explanation:
Element given from the question above include = 2CaClO₃
NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.
Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:
Ca = 1 × 2 = 2
Cl = 1 × 2 = 2
O = 3 × 2 = 6
Thus,
Ca = 2
Cl = 2
O = 6
Henry is researching the efficacy of a new drug for treating agoraphobia (fear of public places). His assistant, who is unaware of the study’s purpose, randomly assigns half of his 200 subjects a 30 day supply of the drug (Fearnot) and the other half a 30 day supply of a placebo (i.e., sugar pill). A month later the subjects are given a questionnaire to rate their fear of being in public. Henry finds that there is no difference between the two groups in their level of fear. How many subjects participated in this study?
What is my name?:
I am a god
I am a guardian of the sun
I am used to measure heat.
Answer:
Apllo?
Explanation:
According to Coulomb's Law, how does distance affect the electric force?
A. The electric force only acts on objects that are in contact with
each other.
B. Only in charging by induction can the electric force act at a
distance.
C. Electric force gets stronger as charges get closer together and
gets weaker as charges move farther apart.
D. The electric force is zero if the objects are more than several
centimeters apart.
Answer:
C option is right.
Explanation:
According to columb's law
F ∝ 1/r²
so as r means distance between charges decrease force F increase and vice versa.
How much power does it take to lift a box with 350 newtons of force, 25 meters high, in 5 seconds? 70 watts 43,750 watts 2.8 watts 0 Points / 100
Answer:70 watts
Explanation: I took the test and got it correct
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s ‘blades’ (long studs) have a total area of 30 cm 2 . Only her blades are in contact with the floor.
Calculate the player’s pressure on the floor. Give the units.
Explanation:
Since Pressure = Force / Area,
We have 550N / (0.003m²) = 180k Pa. (2s.f.)
Plz help its due in in 15 mins
Answer:
Alpha radiation is a kinda massive type of radiation, this would mean that alpha radiation is weakly penetrating. Because of this:
a) When we have particles of smoke in the path of the alpha radiation, the smoke will "stop" a big part of the radiation, and when the detector stops detecting the radiation, it will let the alarm go off.
b) The radiation of alpha particles can be harmful, yes, but the smoke detector is shielded (Again, alpha radiation is weakly penetrating, then shielding the smoke detector is an easy task), this means that the radiation can not get out of the smoke detector, then it is not a problem for the people living near it.
Nancy walks 100 m west and then 60 m east. What is Nancy's displacement?
Answer:
40m to the East
Explanation:
Displacement is the distance moved in a specific direction. When writing the displacement value of a moving body, the direction must be put in the description.
Displacement takes into account the start and finish position of a body.
100m
Start -------------------------------------------------------------- →
60m
Final ←----------------------------------
Displacement = 100m - 60m = 40m
Therefore, the displacement is 40m due east
The electric field at a distance of 5cm from the center of a charged dome is 3 * 10 ^ 4 * N * C ^ - 1 . Calculate the charge (Q) on the dome.
Explanation:
Q is the charge, 9×10^9×3×10^4 is the magnitude ,d = 5 cm therefore q=3×10^4÷5^2=2.7×10^14÷25=1.08×10^13 c
Which of the following changes would lead to an increase in the efficiency of
a heat engine?
O A. Increasing the amount of work done while absorbing the same
amount of heat
B. Doing the same amount of work while increasing the amount of
heat released
C. Decreasing the amount of work done while absorbing the same
amount of heat
D. Doing the same amount of work while increasing the amount of
heat absorbed
Answer:
b
Explanation:
doing same amount of work while increase in amount of heat released
Suppose that a single guitar player makes noise at 70 dB. If two guitar players play at the same time, the noise level will be approximately 73 dB. How many guitar players will it take for the sound intensity level to be 100 dB
Answer: it will take 1000 guitar players for sound intensity level to be 100 dB
Explanation:
Given that;
noise level of a single player = 70 dB
Intensity of one guitar will be;
SL= 10 × log(I/I₀)
where I₀ is hum threshold intensity = 10⁻¹² W/m²
I is intensity of sound produced by 1 guitar
SL is intensity level of one guitar
so we substitute
70 = 10 × log(I/10⁻¹²)
70/10 = log (I/10⁻¹²)
I = 10⁻¹² × 10⁷
I = 10⁻⁵ W/m²
now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;
100 = 10 × log(In/10⁻¹²)
log(In/10⁻¹²) = 100/10
In = 10⁻¹² × 10¹⁰ = 10⁻² Wm²
we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²
so Intensity of n guitars will be;
n × I = In
n = In / I
we substitute
n = 10⁻² Wm² / 10⁻⁵ W/m²
n = 1000
Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB
A car is traveling due north at 23.6 m>s. Find the velocity of the car after 7.10 s if its acceleration is (a) 1.30 m>s2 due north, or (b) 1.15 m>s2 due south.
Answer:
a) v = 32.8 m/s
b) v= 15.4 m/s
Explanation:
a)
Applying the definition of acceleration (assumed to be constant), we can write the following expression for the velocity v:[tex]v = v_{o} + a*t (1)[/tex]
where v₀ is the initial velocity and a is the acceleration, being t the
time elapsed.
In the case a) the acceleration and the velocity vectors have both the same direction (due north), so both have the same sign, which means that the car is speeding up.Replacing by the givens v₀ and t in (1), we get:[tex]v = 23.6 m/s + (1.30 m/s2 * 7.10 s) = 32. 8 m/s (2)[/tex]
b)
In this case, the acceleration vector and the velocity vector have opposite directions, so the car slows down, due to both vectors have opposite signs.Replacing by the givens in (1) and taking into account the signs, we get:[tex]v = 23.6 m/s + ((-1.15 m/s2) * 7.10 s)) = 15. 4 m/s (3)[/tex]
Need help ASAPPPPP plssssss giving big points
Answer:
average
Explanation:
1. Each of four boys were given
some marbles.
have
day.
punc
exan
class
Joe: sixth multiple of eight
Khal: quarter of a gross
mar
Tate: 4 dozen
Tevin: one score plus a dozen
Which two boys r3eceived the same
number of marbles?
A. Joe and Tate
B. Joe and Khal
C. Tate and Tevin
D. Joe and Tevin
Answer:
the answer is A because
from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48
What is periodic motion?
Answer:
Periodic Motion :–
This is a type of motion where the object repeats its motion after a fixed interval of time.
Examples: pendulum of a clock, motion of child on a swing etc.
Answer:
Periodic motion is a type of motion that is being performed. You can take a rocking chair, bouncing ball, and a swing as an example of periodic motion.
Periodic motion is just another word for the motion because it describes any type of object performing movements even an object vibrating is another great example of periodic motion. If you want to talk about the motion of the universe take Earth and the moon orbiting around the sun it is an object performing.
Hope this helped :)
The potential difference between points A and B in an electric
field is 25.0 volts. How much work is required to transfer 10.0
coulombs of charge from A to B?
Answer:
Work = 250 Joules.
Explanation:
Given the following data;
Potential difference, V = 25V
Charge, C = 10 Coulombs
To find the work required;
Work = Charge * potential difference
Substituting into the equation, we have
Work = 10*25
Work = 250 Joules.
Therefore, the amount of work required to move the charge from A to B is 250 Joules.
Objects 1 and 2 attract each other with a gravitational force
of 72.0 units. If the distance separating Objects 1 and 2 is
changed to four times the original value (i.e., quadrupled),
then the new gravitational force will be units.
Answer:
The new gravitational force will be of 4.5 units
Explanation:
Recall that the formula for the gravitational force between two objects of masses m1 and m2 separated by a distance d is given by:
[tex]F_g=G\,\frac{m1*m2}{d^2}[/tex]
in our case, we are told that such gives 72 units of force:
[tex]F_g=G\,\frac{m1*m2}{d^2} =72[/tex]
Then we change the distance between the objects to 4 times the original (4 * d), such will produce a new gravitational force Fg':
[tex]F_g'=G\,\frac{m1*m2}{(4*d)^2} =G\,\frac{m1*m2}{16*d^2} = \frac{1}{16} *G\,\frac{m1*m2}{d^2}=\frac{1}{16} *\,72=4.5[/tex]
Therefore the new gravitational force would be of 4.5 units
PLEASE HELP PHYSICS QUIZ DUE TODAY!
WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
A block of mass 4kg is pushed up against a wall by a force (P) that makes the 50 degree angle with the horizontal.
A. Calculate the force P needed if the coefficient of static friction between the block and the wall is 0.
B. Calculate the the force or forces needed if the coefficient 0.25.
Please answer in Newton’s with two 2 significant figures.
I suppose you mean to say that the wall is frictionless in the first scenario? Also, I assume the block is to held in place. Construct a free body diagram for the block. There are 3 (in part A) or 4 (in part B) forces acting on it.
• its weight w, pulling it downward
• the normal force (magnitude n), pushing outward from the wall to the left
• the push as described, with magnitude p
• static friction (mag. f ), opposing the upward net force and thus pointing downward.
The static friction force has a magnitude proportional to that of the normal force. If the coefficient of static friction is µ, then
f = µ n
so if the wall is frictionless with µ = 0, then f = 0 and does not need to be considered.
(A) If µ = 0, then by Newton's second law we have
• net vertical force:
∑ F = p sin(50°) - w = 0
and we don't need to consider the net horizontal force to determine p from here. We get
p = w / sin(50°) = (4 kg) (9.8 m/s²) / sin(50°) ≈ 51 N
(B) If µ = 0.25, then Newton's second law gives
• net vertical force:
∑ F = p sin(50°) - w - f = 0
p sin(50°) - f = (4 kg) (9.8 m/s²)
p sin(50°) - f = 39.2 N
• net horizontal force:
∑ F = p cos(50°) - n = 0
p cos(50°) - f /0.25 = 0
[since f = 0.25 n]
p cos(50°) - 4f = 0
Multiply the first equation by -4, then add it to the second equation to eliminate f and solve for p :
-4(p sin(50°) - f ) + (p cos(50°) - 4f ) = -4 (39.2 N) + 0
p (cos(50°) - 4 sin(50°)) = -156.8 N
p = (156.8 N) / (4 sin(50°) - cos(50°)) ≈ 65 N
Find the distance between (-6, 1) and (2, 2). Round to the
nesest hundredth.
Answer:
d = 8.06 (units)
Explanation:
In this problem, we are given two points with X & y coordinates. therefore we must use the Pythagorean theorem with the respective coordinates of each point to determine the required distance.
[tex]A = (-6, 1)\\B = (2, 2)[/tex]
Now using the Pythagorean theorem.
[tex]d=\sqrt{(x_{1}-x_{0})^{2} +(y_{1}-y_{o})^{2} }\\d=\sqrt{(2-(-6))^{2} +(2-1)^{2} }\\d=\sqrt{64+1} \\d=8.06[/tex]
A spherical balloon with a 36cm diameter is being deflated. Its volume V is a function of its radius r according to
Question:
A spherical balloon with a 36 cm diameter is being deflated. Its volume V is a function of its radius r according to [tex]V(r) = \frac{4}{3}\pi r^3.[/tex]
As it's deflating, it is much easier to measure its radius than its volume. Suppose the radius of the balloon is [tex]r(t) = 18 - 18e^{-0.24t}[/tex] cm at t seconds.
Determine the value of V'(4) (accurate to 3 decimal places). Write a complete sentence including the units of both 4 and V'(4) in this context. Determine the value of r(4) (accurate to 3 decimal places). Write a complete sentence including the units of both 4 and r(4) in this context.Answer:
[tex]V'(4) = 201.143[/tex]
[tex]r(4) = 11.106[/tex]
Explanation:
Given
[tex]V(r) = \frac{4}{3}\pi r^3.[/tex]
[tex]r(t) = 18 - 18e^{-0.24}[/tex]
Solving (a): V'(4)
First, we determine V('r)
[tex]V(r) = \frac{4}{3}\pi r^3.[/tex]
Differentiate w.r.t r
[tex]V'(r) = 3 * \frac{4}{3}\pi r^{3-1}[/tex]
[tex]V'(r) = 3 * \frac{4}{3}\pi r^2[/tex]
[tex]V'(r) = 4\pi r^2[/tex]
Substitute 4 for r and take [tex]\pi = \frac{22}{7}[/tex]
[tex]V'(4) = 4 * \frac{22}{7} * 4^2[/tex]
[tex]V'(4) = 4 * \frac{22}{7} * 16[/tex]
[tex]V'(4) = \frac{4 * 22* 16}{7}[/tex]
[tex]V'(4) = \frac{1408}{7}[/tex]
[tex]V'(4) = 201.143[/tex]
This means that the volume of the balloon when the radius is deflated to 4 seconds is 201.143 cm^3
Solving (b): r(4)
Substitute 4 for t in [tex]r(t) = 18 - 18e^{-0.24t}[/tex]
[tex]r(4) = 18 - 18e^{-0.24*4}[/tex]
[tex]r(4) = 18 - 18e^{-0.96}[/tex]
[tex]r(4) = 18 - 18*0.383[/tex]
[tex]r(4) = 11.106[/tex]
This means that the radius of the balloon when at 4 seconds of deflation is 11.106 cm
which terms correctly represent a vector quantity and its respective unit
Answer:
Explanation:
The best terms that represent vector quantity are magnitude and direction. Magnitude and direction are both qualities in vector quantity. The basic measurement of vector quantity is the meter all others would best be described as scalars. So to best describe vector quantity use the meter uni
Different between rarer medium and denser medium at least 5 point each?? can anyone help me to solve this question
Answer:
A medium in which speed of light is more is known as optically rarer medium and a medium in which speed of light is less is said to be optically denser medium. For example in air and water, air is raer and water is a denser medium.
Explanation:
Answer:Rarer medium is less dense
Explanation:
Rarer medium is less dense than dense medium because rarer medium doesn't have a very high amount of particles packing it together. It's easier to see through a rarer medium, so you're able to get a clearer picture of what's on the other side of it. Denser medium is, simply put, more dense.
importance of choke coil?
Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.
Explanation:
Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of 55 km/hour, while car B travels at a constant speed of 12 km/hour. How long will it take care from t=0 for car A to meet car B?
Select one:
a. 24.5 s
b. 490 s
c. 245 s
d. 268 s
e. None of the above.
Answer:
d. 268 s
Explanation:
Constant Speed Motion
An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.
Expressed in a simple equation, we have:
[tex]\displaystyle v=\frac{d}{t}[/tex]
Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we can solve for d:
d = v . t
And we can also solve it for t:
[tex]\displaystyle t=\frac{d}{v}[/tex]
Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.
The time it will take for them to meet is:
[tex]\displaystyle t=\frac{5}{67}[/tex]
t = 0.0746 hours
Converting to seconds: 0.0746*3600 = 268.56
The closest answer is d. 268 s
