The points L, M, N and O all lie on the same line segment, in that order, such that the ratio of LM : MN : NO is equal to 3 : 1 : 5. If LO=36, find NO.

NO = ( )

Answer:

Step-by-step explanation:

what percent of 7 is 3.5

3.5 is half of 7, so 100%: 2 = 50%

Answer: 50%

I have shown two methods, both work well and can be used to solve other scenarios as well.

[Method One]

     We will set up a proportion and solve.

-> A percent divided by 100 is a decimal. This means 100% = 1 in our proportion

[tex]\frac{1}{7} =\frac{x}{3.5}[/tex]

7x = 3.5

x = 0.5

0.5 * 100 = 50%

[Method Two]  

     We will put the whole value in the denominator, and the "what percent of" value is the numerator.

[tex]\displaystyle \frac{3.5}{7}[/tex]

0.5

0.5 * 100 = 50%

Answer:

A = $14,745.544

Step-by-step explanation:

The equation for compound interest is 

A = P (1+i)t 

A = final value

P = amount invested (principal) (10000)

i = interest rate, expressed as a decimal (.05)

t = number of years invested (8)

This formula assumes annual compounding.

Plugging in what we know.

A = 10000(1.05)^8

A = 10000 (1.47745544)

A = $14,745.544

Usual gradation standards

So inorder to make her wrong we need something less than B+ I e <70

Smallest score is 0 largest score is 70 .

Answer:

42

Step-by-step explanation:

well , here we can find the unknown variable which is X

127 = 3X+2 ( vertically opposite angles are equal)

127 = 3X+2

3x+2= 127

collecting like terms

3x = 127-2

3x = 125

dividing bothsides by 3

3x/3 = 125/3

x = 41.66

x = 42 (approximately)

Answer:

  FH = 108

Step-by-step explanation:

The given figure requires we use the Pythagorean theorem to write two relations involving right triangle side lengths. The Pythagorean theorem tells us the square of the hypotenuse is the sum of the squares of the other two sides.

__

  EG² = GH² +HE²

  GH² = EG² -HE² = 53² -28² = 2025 . . . . . solve for GH², use given values

  FG² = GH² +FH²

  FH² = FG² -GH² = 117² -2025 = 11664 . . . . solve for FH², use known values

  FH = √11664 = 108 . . . . . take the square root

The length FH is 108.

Answer:

x = 67 *272    = 364.48 = 364 (rounded as requested).  

Step-by-step explanation:

Use the proportion

   50 = 272  

    67      x

Answer:

  (x, y) = (17/31, 1/31)

Step-by-step explanation:

Simplify the given equation, then equate real parts and equate imaginary parts. This will give you two equations in the two unknowns.

__

  (5 -3i)(x -yi) = 3(x +2yi) +1 -2i

 5x -5yi -3xi +3yi² = 3x +6yi +1 -2i

  (5x -3y) +i(-5y -3x) = (3x +1) +i(6y -2)

This resolves to the two equations ...

Putting these equations into general form gives ...

  2x -3y -1 = 0

  3x +11y -2 = 0

Using the "cross multiplication method" to solve these equations, we get ...

  x = ((-3)(-2) -(11)(-1))/(2(11) -3(-3)) = 17/31

  y = ((-1)(3) -(-2)(2))/31 = 1/31

The values of x and y that satisfy this equation are ...

  (x, y) = (17/31, 1/31)

_____

You can read more about the cross multiplication method here.

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Figure a: The area of the triangle is 13.3 sq. km.

Figure b: The area of the rectangle is 57.4 sq. cm.

Figure c: The area of the parallelogram is 45.5 sq. km.

Figure d: The area of the trapezoid is 24.36 sq. m.

The area of a two-dimensional closed figure is the total space within its boundary.

In the question, we are asked to find the area of the given shapes.

Figure a:-

It is showing a triangle.

The area of a triangle is calculated using the formula:

Area = (1/2)*Base*Height.

Thus, the area of the triangle

= (1/2)*7*3.8 sq. km

= 13.3 sq. km.

Figure b:-

It is showing a rectangle.

The area of a rectangle is calculated using the formula:

Area = Length*Width.

Thus, the area of the rectangle

= 8.2*7 sq. cm

= 57.4 sq. cm.

Figure c:-

It is showing a parallelogram.

The area of a parallelogram is calculated using the formula:

Area = Base*Height.

Thus, the area of the parallelogram

= 9.1 * 5 sq. km

= 45.5 sq. km.

Figure d:-

It is showing a trapezoid.

The area of a trapezoid is calculated using the formula:

Area = (1/2)*(Sum of parallel sides)*(height).

Thus, the area of the trapezoid

= (1/2)*(2.7 + 8.9)*4.2 sq. m.

= 11.6 * 2.1 sq. m.

= 24.36 sq. m.

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Answer:

25%

Step-by-step explanation:

4 days of 16 days is 25% or 1/4

Hope this helps! ;-)

Step-by-step explanation:

[tex] {x}^{2} + 2x - 2 = 0[/tex]

Now Adding three on both sides we get

[tex]{x}^{2} + 2x - 2 + 3 = 0 + 3[/tex]

[tex] {x}^{2} + 2x + 1 = 3[/tex]

[tex] {(x + 1)}^{2} = 3[/tex]

Answer:

I believe it is B

Step-by-step explanation:

Answer:

Ricky had 1201 hits and

Pedro hade 1481 hits

Step-by-step explanation:

Let Ricky be 'y'.

Since, Pedro hit 280 mroe than Ricky.

Pedro is 'y+ 280'

Thus,

y + y+ 280 = 2682

2y = 2402

y = 1201

Ricky had 1201 hits and

Pedro hade 1201 + 280 = 1481 hits

Answer:

See below ~

Step-by-step explanation:

Let :

Solving :

Solution :

Answer:

B and D

Step-by-step explanation:

hope it helps in some way possible

Answer:

1 day = 1440min

so 36min of a day = 36/1440 = 1/40

Answer:

The answer would be B

Step-by-step explanation:

The missing step is to subtract 12 from both sides of the equation.

The step would be:

3x = -9

Answer:

I think the answer is 12 and 19

A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

Given that Farhan bought a bag and a wallet at a discount from a store, and he was given a discount of 30% for the bag, and for the wallet, a discount was also given, and he saved a total of $66.60, and he paid a total of $121.40 for the 2 items and paid $46.60 more for the bag than the wallet, to determine A) what was the price of the bag without discount, and B) what was the percentage discount given for the wallet, the following calculations must be performed:

Therefore, A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

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Answer:A) the price of the bag without discount was $120, and B) the discount on the wallet was 45%.

Step-by-step explanation:

Answer:

[tex]\bullet \ \large\text{The mean in period 2 is higher than the mean in period 1.}[/tex]

Step-by-step explanation:

the mean in period 1 :

(2.3+2.1+2.2+2.2+2.2+2.1+2.4+2.5+2.2+2.0+1.9+1.9+2.1+2.2+2.3)÷15=21.733...

the mean in period 2 :

(2.3+2.1+3.3+1.5+3.6+1.6+3.0+1.1+4.7+2.1+2.4+1.9+2.8+0.5+2.3)÷15=23.466...

Since 23.466 > 21.733 then “The mean in period 2 is higher than the mean in period 1”.

Answer:

I think it is 15. if I am wrong sorry, but if I am right mark brainliest!!

Answer:

1. False

2. True

3. True

4. True

Step-by-step explanation:

A rational number is a number that can be written as a fraction of two integers. An irrational number can not be written as a fraction of two integers.

(Remember that an integer and a whole number are the same).

This means that...

All whole numbers/integers are rational.

3 is true for reasons mentioned above.

4 is just asking the same as 3.

Answer:

[tex](f \cdot g)(x)=2x^5+x^4-x^3+6x^2+3x-3[/tex]

Step-by-step explanation:

Given functions:

[tex]f(x)=x^3+3[/tex]

[tex]g(x)=2x^2+x-1[/tex]

Therefore:

[tex]\begin{aligned}(f \cdot g)(x) & =f(x) \cdot g(x)\\& = (x^3+3)(2x^2+x-1)\\& = x^3(2x^2)+x^3(x)+x^3(-1)+3(2x^2)+3(x)+3(-1)\\& = 2x^5+x^4-x^3+6x^2+3x-3\end{aligned}[/tex]

Answer:

Area = 1250cm²

Step-by-step explanation:

Area of a kite = pq/2

where p and q are diagonals

p = 25+25 = 50

q = 30+ 20 = 50

Area of a kite = pq/2

Area = (50*50 ) / 2

Area = 1250cm²

Answer:

 x = 7

 y = -49

Step-by-step explanation:

           y = -6x - 7 ---------------(I)

           y = -7x -------------------(II)

Substitute y = -7x  in equation (I)

          -7x = -6x  - 7

   -7x + 6x = -7

            -x   = -7    

Multiply both sides by (-1)

           [tex]\sf \boxed{\bf x = 7}[/tex]

Substitute x =7 in equation (II)

       y = -7*7

       [tex]\sf \boxed{\bf y = -49}[/tex]

Answer:

X = 7 Y = -49

Step-by-step explanation:

Y= -6 X -7---------(1)

Y= -7 X ------------(2)

-7 X = -6X -7

-7 X+6X = -7

- X = -7

cancelling the - sign on bothsides

X = 7

put X = 7 into equation (2)

Y = -7(7)

Y = -49

therefore, X = 7 Y= -49

Done

[tex] \pink{\underline{\boxed{8a²+a-7}}}[/tex]

Solution :-

[tex]\Longrightarrow\sf{(3a ^2 + 2a) + (5a^2 -a-7)}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{3a^2+ 2a + 5a^2-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+2a-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \Longrightarrow\sf{8a^2+1a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+a-7}[/tex]

[tex]\red{━━━━━━━━━━━━━━━━━━━━━━}[/tex]

The  Indication of the position of port Q on the drawing is shown by using the example of the image attached.

To Indicate the position of port Q on the drawing (use the x tool).

12 * 5  = 60km

Note that S=  VT

Because 1cm represent 3km

1/3 =x/60

3x = 60

x= 60/3

x= 20

So therefore, 60km needs 20cm.

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Answer:

Step-by-step explanation:

[tex]\mathrm{Critical\:Points\:of}\:45\frac{x^4}{5}+\frac{x^9}{5}:[/tex] [tex]x=-\sqrt[5]{20},\:x=0[/tex]

Critical Point Definition:

Find where [tex]f'(x)[/tex] is equal to zero or undefined

[tex]x=-\sqrt[5]{20},\:x=0[/tex]

Identify critical points not in [tex]f(x)[/tex] domain

Domain of [tex]45\frac{x^4}{5}+ \frac{x^9}{5}: -{ \infty} < x < { \infty}[/tex]

All critical points are in domain

[tex]x=-\sqrt[5]{20},\:x=0[/tex]