The magnetic material is distributed this way because magnets
A
have magnetic fields that repel magnetic materials and push the shavings away.
B
have multiple magnetic fields that attract the shavings with different strengths.
C
have uneven magnetic fields that attract the shavings in random patterns.
D
have magnetic fields that flow from one pole of the magnet to the other.

Answer:

(a) the speed of the electron is 1.237 x 10⁷ m/s

(b) the radius of its path in the magnetic field is 4.21 x 10⁻⁴ m

Explanation:

Given;

potential difference, V = 435 V

magnetic field, B = 167 mT = 0.167 T

(a) the speed of the electron

eV = ¹/₂mv²

[tex]v = \sqrt{\frac{2eV}{m} }\\\\ v = \sqrt{\frac{2(1.6*10^{-19})(435)}{(9.1*10^{-31})}}\\\\v = 1.237*10^7 \ m/s[/tex]

(b) the radius of its path in the magnetic field

[tex]r = \frac{mv}{eB}\\\\r = \frac{(9.1*10^{-31})(1.237*10^7)}{(1.6*10^{-19})(0.167)}\\\\r = 4.21 *10^{-4} \ m[/tex]

Answer:

53.85m

Explanation:

If we are assuming that d1 is one side of a triangle, and d2 is the other, and we are looking for the magnitude, which is essentially the hypotenuse, we use Pythagorean Theorem. a^2+b^2=c^2. 20^2 + 50^2 = 2900.

The square root of 2900 is 53.85164. Therefore, that is your hypotenuse.

Answer:

A. The closer a planet is to the Sun, the faster it moves.

Explanation:

According to this law, planets move around the sun in elliptical orbits. An imaginary lines drawn from the center of Sun to center of planets will sweep  equal area in equal time interval.

Answer option B,C&D  is incorrect because planets that are far away from the Sun take more time to move all around the Sun and experience less gravitational force and move slower than those near the Sun.

Answer:

a

i am never wrong

Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

Answer: The fuel pushes on the launch pad.

Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.

Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.

Answer:

Hitting it or throwing it with force.

Answer: 143 N

Explanation:

Answer:

Not gonna lie. I actually had to think about this a lot XD

Running in the rain can cause you to slip and get hurt. Which I think isn't what you would want.

Walking in the rain (although it is sad), is actually a better idea than running.

Hope this helps!

Answer:

Walk

Explanation:

Running might stop you from being outside for as long, but running on wet ground will most likely result in a not-so-graceful faceplant.

Answer:

The magnitude of the friction force exerted on the box is 2.614 newtons.

Explanation:

Since the box is sliding on a rough horizontal floor, then it is decelerated solely by friction force due to the contact of the box with floor. The free body diagram of the box is presented herein as attachment. The equation of equilbrium for the box is:

[tex]\Sigma F = -f = m\cdot a[/tex] (Eq. 1)

Where:

[tex]f[/tex] - Kinetic friction force, measured in newtons.

[tex]m[/tex] - Mass of the box, measured in kilograms.

[tex]a[/tex] - Acceleration experimented by the box, measured in meters per square second.

By applying definitions of weight ([tex]W = m\cdot g[/tex]) and uniform accelerated motion ([tex]v = v_{o}+a\cdot t[/tex]), we expand the previous expression:

[tex]-f = \left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex]

And the magnitude of the friction force exerted on the box is calculated by this formula:

[tex]f = -\left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex] (Eq. 1b)

Where:

[tex]W[/tex] - Weight, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial speed, measured in meters per second.

[tex]v[/tex] - Final speed, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]W = 52.4\,N[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]v_{o} = 1.37\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]t = 2.8\,s[/tex], the magnitud of the kinetic friction force exerted on the box is:

[tex]f = -\left(\frac{52.4\,N}{9.807\,\frac{m}{s^{2}} } \right)\cdot \left(\frac{0\,\frac{m}{s}-1.37\,\frac{m}{s} }{2.8\,s} \right)[/tex]

[tex]f = 2.614\,N[/tex]

The magnitude of the friction force exerted on the box is 2.614 newtons.

Answer:

The frequency decreases

Explanation:

The frequency will decrease as the wavelength continues to increase.

Wavelength is the distance between successive crests or troughs on a wave motion.

Frequency is the number of waves that passes through a point per unit of time.

    it is expressed as;

                  f  = [tex]\frac{speed }{wavelength}[/tex]

We can see that frequency is inversely proportional to wavelength.

As wavelength increases the frequency reduces.

Explanation:

[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]

So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.

Hope it helps :)

Answer:

The additional trials needed is 48 trials

Explanation:

Given;

initial number of trials, n = 16 trials

the standard deviation, σ = 0.24 s

initial standard error, ε = 0.06 s

The standard error is given by;

[tex]\epsilon = \frac{\sigma}{\sqrt{n} }[/tex]

To reduce the standard error to 0.03 s, let the additional number of trials = x

[tex]0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials[/tex]

Therefore, the additional trials needed is 48 trials.

Answer:

The heat will travel through the wire to your hand.

Explanation:

Thats the one that makes the most sense.

Answer:

the reason why is that if it is hit with the same force the moon has a lot less gravity than the earth dose so the golf ball will hit the ground on earth first before the golf ball on moon dose

Answer:

43

Explanation:

you divide 2600 by 60 and your answer is 43.3333333

I just took the quiz and got it right!

Answer:

they are less stable

Explanation:

i took the test

Complete Question

A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?

Group of answer choices

a The potential energy of the electron is decreasing and it is moving to a region having a higher potential

b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.

c The potential energy of the electron is increasing and it is moving to a region having a lower potential

d  The potential energy of the electron is increasing and it is moving to a region having a higher potential.  

Answer:

The correct option is  C

Explanation:

From the question we are told that

  An electron in between the plates is moving to the right

Generally the potential energy of the electron is mathematically represented as  

          [tex]PE  =  e *  V[/tex]

Here  e is the charge on the electron and  V  is the electric potential of the electron

Generally the left side with the positive charge has a higher potential than the right side with the negative  charge

Now when the potential energy of the electron increases it will move toward the plate with the lower potential  which is the left plate

Answer:

just do that

Explanation:

λ = C/f

 Where,

λ (Lambda) = Wavelength in meters

c = Speed of Light (299,792,458 m/s)

f = Frequency

Answer:

The reason behind the given instance is summarized below.

Explanation:

Answer:

dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34

Explanation:

Answer: True

Explanation:

Pencils indeed should not be used as tools when working inside a computer because it is made of Lead.

Lead is a conductor of electricity and as such if it is left inside the computer at even miniscule quantities, it can redirect electricity and damage components in the process.

If one wants to work inside a computer, it is best to use tools like tweezers and needle-nose pliers.

Due to the presence of graphite(A good conductor of electricity), Pencils should not be used inside the computer to change the setting of switches.

The conductors are the materials that can allow electricity and heat to pass through them.

Since the pencils are made up of graphite which is a good conductor of electricity. When we use pencils to do something inside the computer circuits and if some portion of the graphite remains on the circuit board.

Now due to the good conducting property of the graphite, it will allow the current to flow and the short circuit of the circuit board can take place which will damage the computer.

Thus due to the presence of graphite(A good conductor of electricity). Pencils should not be used inside the computer to change the setting of switches.

To know more about Conducting materials follow.

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Answer:

Explanation:

10.00 5

Answer:

10. B

13. It's actually 30 seconds but 20 comes closest so B

14. B, any type of stretching is good before you perform any type of physical activity because it loosens up the muscles

15. D, all of the above

Explanation:

I have done many sports in my life and am still very active, I grew to know most of these things through the years.

Answer:

The viscosity is  [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]  

Explanation:

From the question we are told that

  The  density is  [tex]\rho  =  7.80 *10^{3} \  kg/m^3[/tex]

  The diameter is  [tex]d =  3.0 \  mm =0.003 \ m[/tex]

    The  time taken is  [tex]t  =  12 \ s[/tex]

   The  distance covered is  [tex]d =  0.60 \ m[/tex]

Generally the velocity of the ball is  

      [tex]v  =  \frac{d}{t}[/tex]

=>    [tex]v  =  \frac{0.60}{12}[/tex]

=>    [tex]v  =  0.05 \ m/s [/tex]

Generally the mass of the steel ball is  

    [tex]m  =  \rho  *  V[/tex]

Here  V  is the volume and this is mathematically represented as

     [tex]V  =  \frac{4}{3} *  \pi  * [\frac{d}{2}  ]^3[/tex]

=>    [tex]V  =  \frac{4}{3} *  3.142  * [\frac{0.003}{2}  ]^3[/tex]

=>      [tex]V  = 1.414 *10^{-8} \  m^3[/tex]

So

     [tex]m  = 7.80 *10^{3}  *   1.414 *10^{-8}[/tex]

     [tex]m  = 0.00011 \  kg [/tex]

Generally the viscosity is mathematically represented as  

     [tex]\eta  =  \frac{m  *  g}{6\pi  *  r  *  v }[/tex]

Here  r is the radius represented as

      [tex]r =  \frac{d}{2}[/tex]

=>   [tex]r =  \frac{0.003}{2}[/tex]

[tex]r =  0.0015  \  m [/tex]

So

  [tex]\eta  =  \frac{0.00011  *  9.8}{6 *  3.142   * 0.0015  * 0.05 }[/tex]    

=> [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]

Answer:

Kenetic Energy?

Explanation:

I need more context of what you are studying here...

Answer:

[tex]B=1.61\times 10^{-4}\ T[/tex]

Explanation:

The attached figure shows the path followed by an electron in the semicircular path from A to B.

Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]

It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be  [tex]B=1.61\times 10^-{4]\ T[/tex]

The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.

The attached figure shows the path followed by an electron in the semicircular path from A to B.

The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]

It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}[/tex]

[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]

[tex]B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is  [tex]B=1.61\times 10^-{4]\ T[/tex]

To know more about the magnetic field, follow

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