The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the improper integral L{f(t)}(s) = infinity 0 e-st.f(t)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant)
1. Find L{t}. (hint: remember integration by parts)
A. 1
B. -1/s2
C. 0
D. 1/s2
E. -s2
F. None of these
2. Find L{1}.
a.1/s
b. 1
c. 0
d. -s
e. -1/s
f. none of these

Answers

Answer 1

(1) D

[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]

Integrate by parts, taking

[tex]u = t \implies \mathrm du=\mathrm dt[/tex]

[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]

Then

[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]

[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]

(2) A

[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]

[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]


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y=-2/3x+6

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y= -2/3 x + 6

Step-by-step explanation:

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Solve the equation by graphing. If integral roots cannot be found, estimate the roots by stating the consecutive integers between which the roots lie. -2p2=12p+15

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9514 1404 393

Answer:

  roots are between -5 and -4, and between -1 and -2.

Step-by-step explanation:

The graph shows the roots are approximately ...

  -4.2 — between -5 and -4

  -1.8 — between -2 and -1

p(X)=x²+50 then p(2)=
a) 6
b)7
c)8
d)9​

Answers

Answer:

54

Step-by-step explanation:

p(x)=x^2+50, p(2)=2^2+50=54

P(x) = x² + 50

P(2) = 2² + 50

= 54

P(6) = 6²+50

= 86

P(7) = 7²+ 50

= 99

P(8) = 8²+50

= 114

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= 131

Answered by Gauthmath must click thanks and mark brainliest

50T Q12 A man wants to buy bags of gravel to cover his driveway. He decides to work out the area of his driveway. 1 bag of gravel covers 14m2 3m Sketch of driveway Not to scale 3m 8m 6m What is the area of his driveway? How many bags of gravel must he buy?​

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Find the length of the arc.
A. 21/π4 in
B. 18π in
C. 45/π8 in
D. 1890π in

Answers

Answer:

we know that all Lenght of circle is 2πr so 2*π*7=14π

Step-by-step explanation:

14π equal to 360°

but we need just 135° so we should write it kind of radian(π)

if 14π=360°

x=135°

14π*135=360°*x 14π*27=72*x ........= 14π*3=8*x

7π*3=4*x ....... X=21π/4

The length of the arc is 21/π4 in

An answer is an option A. 21/π4 in

What is the arc of the circle?

The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.

⇒angle= arc/radius

 ⇒  135°=arc/7

⇒ arc =135°*7

  ⇒arc=135°*π/180° *7in

⇒arc = 21/π4 in

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the art club held a show for 2 days a total 269 people attended the show. On the second day, 15 more people attended than had come to the show the first day how many people attended on the first day?

Answers

Answer:

127 people

Step-by-step explanation:

Number of attendees the first day = x.

Solve the following equation for x:

x + (x + 15) = 2692x = 269 - 152x = 254x = 254/2x = 127

Tìm diện tích của mặt. Phần mặt x2+y2+z2=9 nằm bên trên mặt phẳng z=1.

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If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,

r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).

Then the area of the surface (I denote it by S) is

[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]

What is the domain of the following function?

Answers

Answer:

the domain is all real numbers except  x=3

Step-by-step explanation:

The domain is the values that x can take

X can be all real number except when the denominators equal zero

x-3 ≠ 0

x≠3

the domain is all real numbers except 3

can someone help me pls

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Answer:

D NO IS THE WRITE ANSWER .

Answer:

D)

Step-by-step explanation:

A lottery ticket has a grand prize of $30.1 million. The probity of winning the grand prize is .000000038
Deteman the expected value of the lottery ticket

Answers

Answer:

$30.1 million * .000000038

$1.14

did the question say how much the ticket cost?

if it was $1 then you would have to subtract $1 so the expected value would be 14 cents

Step-by-step explanation:

If 10 wholes are divided into pieces that are one half of a whole each how many pieces are there?

Answers

9514 1404 393

Answer:

  20

Step-by-step explanation:

A whole can be divided into two pieces that are each 1/2 of the whole.

 (10 wholes) × (2 pieces per whole) = 20 pieces

What is the distance from point Yto wx in the figure below?
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30
X
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The length of YZ in the similar triangle given is calculated using Pythagoras theorem which gave us 16√3

What are Similar Triangle

Similar triangles are two or more triangles that have the same shape but may be different sizes. They have the same angles and corresponding sides that are proportional.

In this problem, we need to use the concept of ratio and proportions to find the length of YZ

However, we can simply use Pythagoras theorem to determine the length.

According to Pythagoras' Theorem, the square of the hypotenuse, or side opposite the right angle, in a right-angled triangle, is equal to the sum of the squares of the other two sides.

It is expressed as the equation a² + b² = c².

This is because the triangles forms a right angled triangle and we can easily apply that here.

YZ² = 16² + (16√2)²

YZ² = 768

YZ = √768

YZ = 16√3

The length or distance from point Y to WX which is the same as the length of YZ is calculated as 16√3.

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Answer:

C. 16

Step-by-step explanation:

I hope this helps :)

A store spends $10 for each pair of Brand X jeans and adds a 120% markup to the cost. What is the selling price of the jeans? (circle one)

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Step-by-step explanation:

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3 lawns in 9 hours.what was the rate of mowing in hours per lawn

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Answer:

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Step-by-step explanation:

3 = 9 \:th \\ 1 = 3 \\ 3 \times 3 = 9 \\ 9 \div 3 = 3 \\ so \: that \: answer \: is \: 3

3 because 3x3 = 9 and that just makes more sense then to put anything other unless I’m missing something it’s 3

If only the height of a pyramid is doubled its volume is Also doubled true or false

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Step-by-step explanation:

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35/37

Step-by-step explanation:

sin(B)=(AC)/(AB) = 35/37

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− 8 a ^7

Step-by-step explanation:

See picture for steps :)

a woman has two boards one is two times as long as the other together the two boards equal 9 ft what is the length of the shortest board​

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Answer:

3 feet

Step-by-step explanation:

Let x represent the length of the shortest board.

Since the other is two times as long, its length can be represented by 2x.

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Step-by-step explanation:

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Answer:

No, they are not.

Step-by-step explanation:

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The BBQ club meets every Thursday. The meetings last 2 1/2 hours. There were 5 Thursdays in
September. How many hours did the BBQ club meet in September?


A.2 1/2 hours
B.5 hours
C.12 1/2 hours
D.10 hours

Answers

Answer:

12 1/2

Step-by-step explanation:

2 x 5 = 10

1/2 x 5 = 2 1/2

10 + 2 1/2 = 12 1/2

Which equation has the same solution as 10(x) - x + 5 = 41

Answers

Step-by-step explanation:

if that is truly the full problem description, then we have

10x - x + 5 = 41

=>

9x = 36

our simply

x = 4

so, I am not sure, what your teacher wants to see as result.

there is an infinite number of equations I could find, all with the solution x = 4.

Change to cylindrical coordinates. 3∫−3 9-x^2∫0 9−x^2-y^2∫x^2+y^2 dz dy dx

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I think the given integral reads

[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

In cylindrical coordinates, we take

x ² + y ² = r ²

x = r cos(θ)

y = r sin(θ)

and leave z alone. The volume element becomes

dV = dx dy dz = r dr dθ dz

Then the integral in cylindrical coordinates is

[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]

To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set

{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}

which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.

Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to

r sin(θ) = 9 - (r cos(θ))²

You can solve this explicitly for r as a function of θ :

r sin(θ) = 9 - r ² cos²(θ)

r ² cos²(θ) + r sin(θ) = 9

r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)

(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))

(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))

r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]

r  = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))

Then r ranges from 0 to this upper limit.

Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.

The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

or

[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

or

[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

Which inequality is true?
O A. 1 2 > 2
OB. 8 - T > 5
O C. 1071 > 30
O D. 1+4<7

Answers

Answer:

true

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

A

[tex]\frac{12}{2\pi }[/tex]  ≈ 1.91 < 2

B

8 - π 8 - 3.14 = 4.86 < 5

C

10π ≈ 31.42 > 30 ← True

D

π + 4 = 3.14 + 4 = 7.14 > 7

Option C is a true inequality

What is |1-8i|?

A.
B.
C
D

Answers

9514 1404 393

Answer:

  (b) √65

Step-by-step explanation:

The modulus of a complex number is the root of the sum of the squares of the real and imaginary parts.

  |1 -8i| = √(1² +(-8)²) = √(1+64) = √65

find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!

Answers

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

[tex]\frac{a}{sin78}[/tex] = [tex]\frac{18}{sin53}[/tex] ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = [tex]\frac{18sin78}{sin53}[/tex] ≈ 22.0 ( to the nearest tenth )

(3)

[tex]\frac{c}{sinC}[/tex] = [tex]\frac{a}{sinA}[/tex] , substitute values

[tex]\frac{35}{sinC}[/tex] = [tex]\frac{45}{sin134}[/tex] ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = [tex]\frac{35sin134}{45}[/tex] , then

∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{35sin134}{45}[/tex] ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values

[tex]\frac{BC}{sin38}[/tex] = [tex]\frac{10}{sin50}[/tex] ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = [tex]\frac{10sin38}{sin50}[/tex] ≈ 8.0 ( to the nearest tenth )

Help me please --------------------

Answers

9514 1404 393

Answer:

  139.39 in

Step-by-step explanation:

The length of a semicircle of diameter D is ...

  C = (1/2)πD

For the given diameter of 27 inches, the length of the curved edge of the figure is ...

  C = 1/2(3.14)(27 in) = 42.39 in

__

The perimeter of the figure is the sum of the side lengths. Clockwise from left, that sum is ...

  P = 27 + 35 + 42.39 + 35 = 139.39 . . . inches

The perimeter of the figure is 139.39 inches.

What is the image of (3, -12) after a dilation by a scale factor of į centered
at the origin?

Answers

Answer:

9 is. ................m.m..mk

Question for the kids orrr?

Answers

Answer:

B. 18 sq in.

Step-by-step explanation:

Surface area of the triangular pyramid excluding the base = area of the three triangular faces = 3(½ × base × height)

Where,

base = 3 inches

height = ED = 4 inches

Plug in the known values into the equation

Surface area of the triangular pyramid excluding the base = 3(½ × 3 × 4)

= 3(3 × 2)

= 3(6)

= 18 sq in.

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