Answer:
295
Explanation:
Antibodies (also known as immunoglobulins) are immune system-related proteins that circulate in the bloodstream in order to recognize pathogenic harmful substances (antigens) and neutralize them. An antibody consists of two immunoglobulin heavy chains and two immunoglobulin light chains. There are two types of immunoglobulin light chains: 1-the kappa (κ) light chain, which is encoded by the immunoglobulin κ locus; and 2-the lambda (λ) light chain, which is encoded by the immunoglobulin λ locus. The immunoglobulin light chain is a multidomain protein composed of two domains: 1- the N-terminal variable (V) domain and 2-the C-terminal constant (C) domain. V(D)J recombination is a type of somatic rearrangement process by which T and B cells can assemble different gene segments, which are referred to as variable (V), diversity (D) and joining (J) gene segments. In the question above the number of possible genomic recombination events between immunoglobulin gene segments can be calculated as >> (5 x 35) + (4 x 30) = 295.
Abnormalities in the number of X chromosomes tends to have milder phenotypic effects than the same abnormalities in autosomes because of ___________.
Answer:
D. (X inactivation) I believe!
Hope this helps! Have a nice day :)
What is the use of hormones in humans
Answer:
Hormones are chemical messengers that use your bloodstream to travel throughout your body to your tissues and organs.
Explanation:
Answer:
Hormones are chemical messengers that move throughout your body via your bloodstream to your tissues and organs.
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Which of the following cycles does not involve living organisms?
a. carbon cycle
b. oxygen cycle
c. rock cycle
d. nitrogen cycle
Please select the best answer from the choices provided
PLS HELP ASAP
Answer:
rock cycle is the correct answer
If Sarah had skin vesicles on the anterolateral region of her neck, which peripheral nerve is infected by the virus? To which peripheral nerve plexus does this nerve belong?
Psychometric scores for anxiety, depression, negative self, somatization, and hostility were combined into a single Global Severity Index (GSI). Global Severity Index was compared for 80 adolescents who were seen in the outpatient clinic for 7 different physical complaints (short stature, obesity, lack of weight gain, breast problems, genital problems, menstrual problems, and hirsutism). Report the degrees of freedom for the relevant F statistic in the numerator and the denominator. (Round your answers to the nearest whole number.)
Answer:
The correct answer is -
Numerator = 6
Denominator = 73
Explanation:
In F static test or table there are two sets of degrees of freedom: one for the numerator and one for the denominator. The degrees of freedom are equal to the number of observations minus one. Thus, if the sample size were 7 then the degree of freedom would be 7 minus 1
Numerator df = 7 - 1 = 6
Thus, the numerato would be - 6.
Denominator is calculated by subtracting the observation or variables from the total number of sample size.
Denominator df = 80- 7 = 73
g In order to stimulate the renin-angtiotensin-aldosterone system (RAAS), _______________ cells in the kidney detect _______________blood pressure which causes ________________ to be released from the juxtaglomerular cells.
Answer:
Macula densa cells, lower and renin.
Explanation:
Macula densa cells in the kidney detect lowers blood pressure which causes renin to be released from the juxtaglomerular cells which is an enzyme. The arterial cells observe the drop in blood pressure, and the decrease in Na concentration is transfer to them by the macula densa cells. The juxtaglomerular cells then release an enzyme called renin. Renin converts angiotensinogen which is a peptide, or amino acid derivative into angiotensin-1.
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Answer:
Explanation:
C ạ
Question 1 of 10
Consider the following geometric solids.
A sphere with a ratio of surface area to volume equal to 0.3 m
A right circular cylinder with a ratio of surface area to volume equal to
2.1 m?
What results would you expect if these two models were compared in a
diffusion test?
A. The rate of diffusion would be slower for the right cylinder,
B. The rate of diffusion would be the same for the two models.
0
C. The rate of diffusion would be faster for the right cylinder.
D. The rate of diffusion would be faster for the sphere.
Answer:
the rate if diffusion will be faster in the right cylinder
Explanation:
The surface area to volume ratio of the cylinder is higher. This means that in the cylinder more reactants are exposed at the surface and the rate at which diffusion takes place increases
DNA and RNA are structurally similar in some ways but different in others. Identify whether each of the statements applies to DNA, RNA, both RNA and DNA, or neither DNA nor RNA.
QUESTION 6
Which one of the following substances is not a product of aerobic respiration?
A.
ATP
B.
Water
C.
Alcohol
D. Carbon dioxide
Answer:
C. alcahol
Explanation:
aerobic respiration equation
glucose+ oxygen -> carbob dioxide gas + water + energy
Answer:C
Explanation:
biology chapter 33 assessment 972
Answer:
Where is question
Explanation:
Please tell
What else is produced during the replacement reaction of silver nitrate and potassium sulfate?
2AgNO3 + K2SO4 Ag2SO4 + ________
KNO3
2KNO3
K2
2AgNO3
Answer:
2KNO3
Explanation:
Pls mark it brainliest
hope it helps u
Answer:
The answer is B.) 2KNO3
Explanation:
Neurons are classified functionally according to the direction the ____________ travels relative to the ____________ . Afferent neurons are the neurons of the sensory nervous system. They are responsible for conducting ____________ input from both somatic sensory and visceral sensory receptors. Most sensory neurons are ____________ . Efferent neurons are the neurons of the motor nervous system, conducting ____________ output from the CNS to the effectors. All motor neurons are ____________ . Interneurons (or ____________ neurons) lie entirely within the CNS. They receive stimulation from many other neurons and carry out the integrative function of the nervous system. The most numerous types of neurons are ____________ .
Answer:
Based on their roles, the neurons found in the human nervous system can be divided into three classes: sensory neurons, motor neurons, and interneurons.
Explanation:
Neurons are classified functionally according to their direction. The nerve impulse travels relative to the receiving neuron.
What do you mean by Neurons?Neurons may be defined as nerve cells that are responsible for the transmission of signals from the body to the brain.
Afferent neurons are the neurons of the sensory nervous system. They are responsible for conducting nerve impulse input from both somatic sensory and visceral sensory receptors. Most sensory neurons are afferent neurons.
Efferent neurons are the neurons of the motor nervous system, conducting nerve impulse output from the central nervous system to the effectors. All motor neurons are efferent neurons.
Interneurons or associated neurons lie entirely within the central nervous system. They receive stimulation from many other neurons and carry out the integrative function of the nervous system. The most numerous types of neurons are interneurons.
Therefore, it is well described above.
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Assuming that you observed similar patchy bacterial growth pattern in plates "B-Amp, phage" and "C-LB, phage". The T4 phages greatly affected the growth of E. coli strain CR63 in the LB plate ("C-LB, phage" plate), creating a patchy bacterial growth pattern similar to the expected result in the ampicillin plate of strain BE with phage ("B-Amp, phage" plate). Besides experimental errors, describe the possible reasons why the bacterial colonies were isolated in these two plates. "B-Amp, phage" Plate (strain BE)?
Answer:
Some bacterias show a great resistance power to fight against T4 phages That leads to great growth in the medium given that resistance power may be given by plasmids As plasmids show the resistant genes that great work in the medium.
T4 phage is a virus that shows a lytic cycle after affecting bacteria and going to kill the bacterial cells in bacterial strain So no growth in LB media. Some bacteria are sensitive due to the lack of resistant genes therefore, their growth may affect by many factors of the medium. If the bacteria are recombinant, they show greater growth in the medium.
* B-Amp, Phage plate (strain Be), there is ampicillin, so inhibits the growth of bacteria but still there is patchy growth of bacteria and they still show the growth but due to presence of phage T4, they show patchy growth.
The liver develops: as a ventral outgrowth of the embryonic foregut. incorporates both endodermal and mesodermal components. develops in the ventral mesentery. is connected to the stomach by the lesser omentum. All of the above.
Answer: All of the above.
Explanation:
The liver is simply the largest solid organ in the body and it can be found below the rib cage in the upper abdomen by the right. It's function is to maintain the blood sugar, regulate blood clotting and remove toxins from the blood.
It should be noted that the liver develops as a ventral outgrowth of the embryonic foregut. It also helps in the incorporation of both the endodermal and the mesodermal components. Furthermore, it's developed in the ventral mesentery and is connected to the stomach by the lesser omentum.
Therefore, all of the above options are correct.
ANOVA is a technique that permits the comparison of the equality of means for multiple populations. Thus, 3 means could be compared and a determination of whether or not one of the means is significantly different from others can be made. This technique is extremely useful, but, as is always the case, the application requires a firm understanding of models assumptions. Consider the following scenario. A meticulously determined random sample of 200 observations is taken from a very large population. This data divides into 4 groups or factor levels, and a numerical measure for each observation is recorded. The population distribution of the measure appears to be slightly skewed positive. The 4 groups have the following number of observations 30, 100, 15 and 55. Which of the following statements leads to the greatest concern in using ANOVA as an analytical technique.
a. Unequal sample sizes among groups can seriously affect the power of the test.
b. Slightly skewed positive distribution of population measures seriously affect the power of the test.
c. In this scenario, I should be concerned about whether the data has been gathered in a biased fashion.
d. Four is not a sufficient number of groups into which to divide the data.
Answer:
c. In this scenario, I should be concerned about whether the data has been gathered in a biased fashion.
Explanation:
ANOVA is a statistical method which separates observed variance data into different components to use. One way ANOVA is used for three or more groups of data. The greatest concern in ANOVA is that the data gathered should not be biased.
Which statement best describes a line graph?
A. It shows a line passing through scattered data points.
B. It shows a line that connects a series of data points.
C. It shows data as proportions of a whole.
D. It shows the locations of errors in data.
Answer:
B
Explanation:
I just did it
A line graph shows a line that connects a series of data points
what is line graph ?A line graph is a unique type of graph which is used in statistical application which represents the change in a quantity with respect to another quantity.
The price of different flavors of chocolates varies which can be represented, these variation is plotted in a two-dimensional XY plane.
If the relation include two measures can be presented by using a straight line in a graph called as linear graphs or a linear graph.
There are different types of the line graph, Simple Line Graph refers to Only one line is plotted on the graph, Multiple Line Graph where More than one line plotted on the same set of axes.
Compound Line Graph refers to the information can be divided into two or more types of data and this line graph is called a compound line graph which can be drawn to show the component.
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Eutrophication occurs when excess nutrients are supplied to a region, leading to an algae bloom and ultimately ______
A. Coral bleaching
B. Ocean deoxygenation
C. Ocean acidification
D. Overfishing
Answer:
The correct answer is - B. Ocean deoxygenation.
Explanation:
Eutrophication is the process in which a water body gets excessively rich in nutrients that leads to the algal growth or plankton growth in this region and covers the complete surface or most of the water body.
Due to this algal and plankton growth, there is a significant decrease in the concentration of the dissolved oxygen in water bodies that result in the incapability of supporting the lives found in it. The primary and main reason for this deoxygenation is eutrophication. Ocean deoxygenation is the reduction of the oxygen concentration of the oceans.
1) What is the function of the plasma membrane? (5pts)
2) How does high and low temperature affect a plasma membrane's fluidity? (5pts)
3) How does passive transport differ from active transport? (5pts)
4) What are the three main types of passive transport? Describe each of them. (5pts)
5) List the three types of tonic solutions and describe which way water moves in each one. (5pts)
Answer:
1.Plasma membrane is a semi permiable layer present in a plant cell.it allows only selected substances to pass in and out of the cell.
What is produced during the replacement reaction of Ba(NO3)2 and Na2SO4?
2BaNa + 2NO3SO4
2NaNO3 + BaSO4
NaNO3 + BaSO4
BaNa2 + (NO3)2SO4
Answer:
2NaNO3 + BaSO4
Explanation:
Answer:
2NaNO3 + BaSO4
Explanation:
Hydrocarbons are burned to produce water and carbon dioxide. Propane (C3H8) is a homologous series alkane that belongs to the hydrocarbon family. As a result, when propane is burned, three molecules of carbon dioxide and four molecules of water are produced.
Because there is an overabundance of oxygen, carbon dioxide is created when butane is completely burned.
Outline an experimental approach to determining the average chain growth rate for transcription in vivo. Chain growth rate is the number of nucleotides polymerized per minute per RNA chain. Fill in the blanks.
Label a growing bacterial or cell culture for a brief interval with a mixture of 14C-labeled nucleosides, which would be converted to nucleotides and incorporated into _____. Isolate total ______and subject it to hydrolysis with mild _____. Every _____-terminal nucleotide will be released as a nucleoside. Separate nucleosides from nucleotides, by ______. Total picomoles of nucleotide in the hydrolysate divided by total picomoles of nucleoside gives the number of nucleotides incorporated per _______chain-which, when divided by the labeling interval (minutes) gives the growth rate of individual chains (nucleotides incorporated per ______ chain per minute). An interesting variant of the experiment would be to carry it out with individual radiolabeled nucleosides and ask whether the chain ______is the same for each nucleotide.
Answer:
DNA
Protein
temperature
nerve
esterification of inorganic phosphate to C5 on aldose.
nucleic acid polymer
growth rate
Explanation:
Nucleosides have nitrogen base surrounded by 5 carbon carbohydrates which is called as ribose molecule. Nucleotides is simply a nucleoside with one or more phosphate group. There are 4 different types of nucleosides which are, adenosine, guanosine cytidine, and uridine. Nucleotides are formed from nucleosides by esterification of inorganic phosphate on aldose.
In butterflies, having red antennas (denoted by “R”) is dominant to having white antennas (denoted by “r”). If both parents are heterozygous for red antennas, what are the predicted Phenotypic outcomes of their offspring? (hint: a punnett square will help you determine this).
In butterflies, having red antennas (denoted by “R”) is dominant to having white antennas (denoted by “r”). If both parents are heterozygous for red antennas, what are the predicted Genotypic outcomes of their offspring? (hint: a punnett square will help you determine this).
All the offspring of a cross between a black-eyed mendelien and an orange-eyed mendelien have black eyes. What is the expected F2 phenotypic ratio of a cross between two F1 black-eyed mendeliens?
A) 1 black-eyed:1 orange-eyed
B) 3 black-eyed:1 orange-eyed
C) 1 black-eyed:3 orange-eyed
D) 1 black-eyed:0 orange-eyed
The phenotypic ratio of the cross is as follows: 3 red antennas: 1 white antenna
For question 2, the phenotypic ratio of the F2 generation is: 3 black-eyed: 1 orange-eyed
QUESTION 1
According to the first question, a gene coding for antenna color in butterflies is involved. Red antennas (“R”) is dominant to white antennas (“r”). Hence, a butterfly with genotype "Rr" will be phenotypically red.
According to this question, If both parents are heterozygous for red antennas i.e. Rr (red antenna) × Rr (red antenna), the following gametes will be produced: R and r. Using these gametes in a punnet square (see attached image), the following phenotypic ratio of offspring is produced:
3 RED ANTENNAS (RR, Rr, Rr) : 1 WHITE ANTENNA (rr)
2. In the second question, all the offspring of a cross between a black-eyed mendelien (BB) and an orange-eyed mendelien (bb) have black eyes (Bb). In a cross between two F1 black-eyed mendeliens i.e. Bb × Bb, the following proportion of offspring is produced:
BB, Bb, Bb, bb
Hence, a phenotypic ratio of 3 black-eyed: 1 orange-eyed
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A biologist discovered a new animal. Upon studying its embryonic development, she observed radial cleavage with the blastopore developing into an anus. This animal was categorized as a parazoan. pseudocoelomate. deuterostome. protostome. radiata.
Answer:
The correct answer is ''deuterostome''.
Explanation:
Deuterostomes are a superphylum of animals in which the anus is formed in or near the blastopore area in the developing embryo, and the mouth is secondarily formed elsewhere. The oral apparatus that these adult animals enjoy does not come from the embryo's blastopore. Instead it is a new formation. They enter the Bilateria classification, where species that enjoy bilateral symmetry are incorporated. In deuterostomes, the primary phases of division occur in parallel to the axis between the tips. That is, the segmentation they have is radial when the embryo is in state 1 with four cells.
b) The chemical equation below summarizes photosynthesis.
Energy (sunlight) + 6 H20 + 6 CO2 - C6H1206 + 6 02
Write a similar chemical equation for cellular respiration. Be sure to include a
description of the form of energy that results from cellular respiration. (3 points)
Pls help me
Answer:
The chemical equation for cellular respiration would be: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O.
Explanation:
C6H12O6 (1 Glucose molecule) + 6 O2 (6 Oxygen molecules) → 6 CO2 (6 Carbon dioxide molecules) + 6 H2O (6 Water molecules)
What variable did the experimenter change (independent variable), and what variable did the experimenter observe (dependent variable)?
Answer:
An independent variable can be controlled by the experimenter to observe it's affect on dependent variable which cannot be changed manually. Rather the dependent variable changes due to the effect of independent variable.
Answer:
The experimenter changed the carbon dioxide concentrations in the two flasks and observed the temperature change over time.
Explanation:
plato answer
Which of the following statements relating to leptin and the metabolism of lipids is correct. (Select all that apply.) Leptin acts mainly in the brain to stimulate appetite. High levels of leptin are interpreted as overfeeding. Insulin stimulates production of leptin in adipocytes. Leptin is a hormone involved in short-term control of eating behaviour. Higher leptin levels result in a decrease in appetite.
Answer:
High levels of leptin are interpreted as overfeeding.
Insulin stimulates production of leptin in adipocytes.
Higher leptin levels result in a decrease in appetite.
Explanation:
Leptin is a peptide hormone that helps to control body weight. This hormone (leptin) is synthesized by fat cells (i.e., adipocytes), then circulates in the blood and goes to the brain, in particular in a region of the brain called the hypothalamus, where it acts to alter food intake over the long term. Higher leptin levels trigger the hypothalamus to lower the appetite. Insulin is another peptide hormone that acts to regulate long-term leptin secretion of adipose cells through a posttranscriptional mechanism. In turn, leptin increases insulin sensitivity, thereby both hormones regulate each other. When body fat decreases as a consequence of decreased appetite, insulin and leptin concentrations in the bloodstream also decrease.
ATP is considered as nature dehydrating agent.what does it means?show with the help of examples
Answer:
that man is mental
WOmbats are what type of mammals?
Answer:
Los wombats son marsupiales que solo se encuentran en Australia, pero estos curiosos y simpáticos animales de piernas cortas y rechonchas rara vez son tenidos en cuenta como otros animales nativos como los koalas y los canguros, que parecen ser más mediáticos.
Explanation:
An enzyme, Pittpantherase, has a KM of 8mM. At a substrate concentration of 4mM, the velocity of the reaction was 2mM/min. What is Vmax for this enzyme
Answer: [Vmax]= 6mM/min.
Explanation:
Enzymes are proteins that produce a specific chemical change in a substance, called substrate, resulting in a product. By following the rate of product appearance (or disappearance of the substrate) as a function of time, the kinetics of the reaction is obtained. As the reaction proceeds, the rate of product formation decreases and the substrate is consumed.
The rate [V] indicates the amount of substrate that is converted into product per second. With increasing substrate concentrations [S], the enzyme approaches its maximum velocity [Vmax], but does not reach it. For this reason, there is no specific value of [S] for Vmax. However, a characteristic parameter of the enzyme can be defined using the substrate concentration at which half of the maximum velocity (Vmax/2) is reached. The initial velocity of the reaction is equal to the slope of the zero-time forward curve and is measured before 10% of the total substrate is consumed, so that the substrate concentration can be considered as essentially constant throughout the experiment. So, although it is impossible to measure exactly the substrate concentration that gives Vmax, enzymes can be characterized by the substrate concentration at which the reaction rate is half the maximum rate. This substrate concentration is known as the Michaelis-Menten constant (KM). For enzymes exhibiting simple Michaelis-Menten kinetics this constant represents the dissociation constant of the enzyme-substrate complex (or the inverse of the enzyme-substrate affinity). Thus, Km indicates the affinity of the enzyme for its substrate, since the higher the Km the lower the affinity. And the lower the Km the higher the affinity.
The formula for the calculation is as follows:
[tex]V_{0}= \frac{[Vmax] x [S]}{[S]+[KM]}[/tex]
So if we replace the numbers, we get:
[tex]2mM/min= \frac{[Vmax] x [4mM]}{[4mM]+[8mM]}[/tex]
If we clear the equation, we obtain that [Vmax]= 6mM/min.
what evidence shows that biological molecules on earth form naturally?
Explanation:
La siguiente entrada tiene como objetivo realizar una breve explicación sobre las moléculas biológicas lipídos y carbohidratos, las cuales son muy diversas ya que están formadas por carbono, lo cual hace que puedan formar muchos tipos de enlaces. Esta capacidad permite que las moléculas orgánicas adopten muchas formas complejas, como son las cadenas, las ramificaciones y los anillos.
Las moléculas biológicas son grandes polímeros que sintetizas para poder enlazarse con otras subunidades mucho mas pequeñas conocidos como monómeros. Las cadenas de subunidades estan unidas por enlaces covalentes los cuales se forman por deshidratación, estas cadenas pueden romperse por hidrólisis. La moléculas biologicas más importantes son los carbohidratos, lípidos, proteínas y ácidos nucleicos.
