The half-life of Calcium-47 is 3.91 x 105 seconds. A sample contains 4.11 x 1076 nuclei. How much of the sample is left after 7.82 x 10 seconds?
2.57 x 1015 nuclei
5.14 x 1015 nuclei
1.03 x 1016 nuclei
2.06 x 1016 nuclei

Answers

Answer 1

Remember the formula

[tex]\\ \rm\Rrightarrow A(t)=A_o(0.5)^{\frac{t}{h}}[/tex]

h is half life

[tex]\\ \rm\Rrightarrow A(7.82\times 10)=A(78.2)[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{\frac{78.2}{3.91\times 10^{5}}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{20\times 10^{-5}}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{0.0002}[/tex]

[tex]\\ \rm\Rrightarrow 4.11\times 10^{76}(0.998)[/tex]

[tex]\\ \rm\Rrightarrow 4.10178\times 10^{76}[/tex]

Why no options matched?

That time given in end i.e 7.82×10

10 should contain some power to match our options .

Answer 2

The number of nuclei  of calcium-47 left after 7.82 x 10⁵s is 1.03 x 10¹⁶.

This can be found out using half life and laws of radioactive disintegration.

What are the laws of radioactive disintegration?

The Law of radioactive disintegration states  the number of  radioactive decay per unit time is proportional to the number of nuclei present in the sample initially.

So,  ΔN/Δt = λN

Where, ΔN = number of radioactive nuclei decayed

Δt = time taken for decay

N = No of nuclei present initially

λ= decay constant

What is Half life?

Half life is the time taken for the radioactive nuclei to reach half of its initial value.

Half life is given by

 [tex]t_{1/2}[/tex] =  λ/t

Given here,  [tex]t_{1/2}[/tex] =  3/91 x 10.⁵s

N = 4.11 x 10¹⁶.

t = 7.82 x 10.⁵s

We see  here that  t = 2([tex]t_{1/2}[/tex])

Now, number of radioactive nuclei left undecayed in  one half life is N/2

So number of nuclei left undecayed in 2 half lives will be 1/2(N/2) = N/4

So number of nuclei left in the sample will be N/4 = (4.11 x 10¹⁶.)/4

So Number of nuclei left in the sample = 1.03 x 10¹⁶.

Hence 1.03 x 10¹⁶is the correct answer.

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A 20 kg rock sits on the edge of a cliff that is 100 m high.
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Answers

The potential energy of the rock is 19600 J. Then, the kinetic energy when it hits the ground will be 19600 J. The velocity before it hits the ground will be 44.2 m/s.

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The potential energy of an object is the energy by virtue of its position. It is related to the mass, m ,height h and acceleration due to gravity g as follows:

p = mgh.

Given m =20 kg

height = 100 m

g = 9.8 m/s²

then  p = 20 kg × 100 m ×  9.8 m/s² = 19600 J.

When the rock falls down as it approaches the ground, the potential energy converts to kinetic energy. Hence, the kinetic energy before it strike the ground will be 19600 J.

Ke = 1/2 mv² = 19600 J

then v = √ (2 Ke/m)

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Question 12 (True/Faise Worth 5 points)
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Answers

Answer:

D

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A generator is operating with 5% droop primary control. The generator is rated for 100 kW. Its secondary power command at this point in time (in other words, the power commanded to produce at 60 Hz) is 67 kW. The grid frequency is currently 59.9 Hz. What is the generator power

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Answers

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Explanation:i had this question on my test

100 % verified!

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Answer:

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