Step-by-step explanation:
VERY EASY FOR ME
The real part (red) and imaginary part (blue) of the Riemann zeta function along the critical line Re(s) = 1/2. The first non-trivial zeros can be seen at Im(s) = ±14.135, ±21.022 and ±25.011. The Riemann h
ypothesis, a famous conjecture, says that all non-trivial zeros of the zeta function lie along the critical line.
SO 6+/7× and 78/+×
ANSWER
Write an equation of the line that is parallel to the given line and passes through the given point.
1. y=2x+1; (0,4)
2. y= -x-3; (0,7)
3. y=-8x +9; (0,-2)
A translation is shown on the grid below. Which are true statements about the translation?
The sides of the image and pre-image are congruent
Each point has moved the same number of units
can i get some help please
Answer:
X=
Step-by-step explanation:
x-1= 4x+3x+x-8
x-1 = 8x-8
shift places
8-1= 8x-x
7x = 7
X=7/7
X=1
I think so
please mark this answer as brainlist
Help asap struggling
Answer:
..D).... x = 8..
Step-by-step explanation:
..x = 8..
8 ÷ -2 · 42 + 9 i need help please
a store is offering a 20% discount on all sales over $50. If you purchase a shirt and a pair of leans for $62.50, what is the amount of the discount you would receive?
Answer:
you would receive 12.5% of the discount
Step-by-step explanation:
20% off of 62.50 is 50; so you would pay $50
hi! can i get some help with this question! :)
Hi there!
[tex]\large\boxed{log_b3b = 1.8397}[/tex]
Keep in mind the following log property:
logₓab = logₓa + logₓb
Thus:
[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]
We know the value of log_b3, and a log with the same values for the base equals 1. Thus:
[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]
Evaluate f-g+(-2) where f = -3.005 and g = 4.7
Answer:
-9.705
Step-by-step explanation:
f-g+(-2)
Let f = -3.005 and g = 4.7
-3.005 -4.7 -2
-9.705
Please hurry I will mark you brainliest
A sunflower plant is growing at a constant rate. It was 4cm tall after 1 month and 32 cm tall after
9 months.
a) Express the growth of the plant as a rate of change.
b) Write an equation to show this relationship
Answer:
a) 3.5 cm / month
b y = 3.5(x-1) + 4, x >= 1
Step-by-step explanation:
the plant grew 32-4 = 28 cm in 9-1 = 8 months.
so, the growth rate is 28 cm / 8 months = 7 cm / 2 months, or (to norm it to a typical 1 unit denominator) 3.5 cm per month.
x = months of growth
y = height of plant
so, considering the "start" of 4 cm after one month, the equation is
y = 3.5(x-1) + 4, x >= 1
since we don't know anything about anything that happened before the first month was over, we cannot validate this equation for anything x<1.
My homework is due soon, help!!
Answer:
50.24
Step-by-step explanation:
A = Area
Radius = 4 (The radius is half of the diameter
Diameter = 8
Pie = 3.14
A = (pie)r^2
A = (3.14)4^2
A = (3.14)16
A = 50.24
solve the equation: q²+2q-8=0
Answer:
q = -4 q=2
Step-by-step explanation:
q²+2q-8=0
Factor
What 2 numbers multiply to -8 and add to 2
4*-2 = -8
4-2 = 2
(q+4)(q-2) =0
Using the zero product property
q+4 = 0 q-2 =0
q = -4 q=2
more points for yal if u help <333
Can someone correct my work and answer/explain question C)
Marking Brainliest, 10 Points
Answer:
4 TOPPING WITH 5 CENTS LEFT
Step-by-step explanation:
A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so
3.5-0.75=2.75 (1 topping
2.75-0.75=2 (2 topping
2-0.75=1.25 (3 topping
1.25-0.75=0.5 (4 topping
there for you can get 4 toppings with 5 cents left over
the answers are
A) Yes
B) No
A fruits seller bought some lemon for Re 1 for 15 lemon. if he sold all lemons at 25% profit, how many lemons were sold for Rs 1.
Answer:
12 lemons
Step-by-step explanation:
CP of 15 lemon = ₹ 1
Profit = 25 %
SP of 15 lemons = [tex]\frac{100+profit}{100}*CP[/tex]
[tex]= \frac{125}{100}*1\\\\= \frac{5}{4}[/tex]
SP of 15 lemons = ₹ [tex]\frac{5}{4}[/tex]
Number of lemon for ₹ [tex]\frac{5}{4}[/tex] = 15
Number of lemons for ₹ 1 = 15 ÷ [tex]\frac{5}{4}[/tex]
[tex]= 15 *\frac{4}{5}\\\\= 3*4\\\\= 12[/tex]
Can someone please help me with my maths question
Answer:
[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
Step-by-step explanation:
The question relates with rules of indices
(a) The give expression is presented as follows;
[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]
By expanding the expression, we get;
[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]
Collecting like terms gives;
[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]
(b) The given expression is presented as follows;
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]
Therefore, we get;
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]
Collecting like terms gives;
[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]
[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]
Find the cos T. Round to the nearest 100th
Answer:
0.92 to nearest 100th.
Step-by-step explanation:
cos T = adjacent side / hypotenuse
= 12/13
= 0.9231
An airplane travels 3690 kilometers against the wind in 5 hours and 4490 kilometer with the wind in the Sam amount of time what is the rate of the plane
still air and what is the rate of the wind?
Step-by-step explanation:
Against the wind, the wind works against the speed. With the wind, the wind aids the speed.
4(p - w) = 2416
4(p + w) = 2896
p - w = 604
p + w = 724
2p = 1328
p = 664 mph
664 + w = 724
w = 60 mph
43. Para determinar la altura de un árbol nos apoyamos en los siguientes triángulos semejantes que se forman entre el árbol y
una lámpara
00
D
*ACB= 30°
3m
E
20 m
5 m
¿Cuál es la altura del árbol?
ООО
A. BA = 12 m
B. BA = 15 m
C. BA = 33.33 m
D. BA = 60 m
O
Respuesta:
A.) BA = 12 m
Explicación paso a paso:
Usando triángulos similares:
BA / AC = DE / EC
BA = x; AC = 20; DE = 3; EC = 5
POR ESO ; TENEMOS :
x / 20 = 3/5
Multiplicar en cruz:
5 * x = 20 * 3
5 veces = 60
5x / 5 = 60/5
x = 12
Can anyone explain this step-by-step?
4(10x - 20) = 2,000
Answer: x = 52
Step-by-step explanation:
You'd first deal with the 4 outside the parentheses, multiplying 10x-20 by 4. This would result in 40x - 80 = 200.
You'd then further isolate x, adding 80 on both sides, resulting in 40x = 2080. Divide by 40 on both sides and You'd get your answer of x = 52.
find the missing length indicated
Answer:
192
Step-by-step explanation:
According to Euclidian theorem
x^2 = 144*(400-144)
x^2 = 144*256
x^2 = 36864 find the root of both
x = 192
SIN TRIG PLEASE HELP 50 POINTS
If sin y° = s/8 and tan y° = s/t what is the value of sec y°
a. sec y° = 8s
b. sec y° = 8t
c. sec y° = 8/t
d. sec y° = t/8
Answer:
C
Step-by-step explanation:
We are given that:
[tex]\displaystyle \sin y^\circ = \frac{s}{8}\text{ and } \tan y^\circ = \frac{s}{t}[/tex]
And we want to find the value of:
[tex]\displaystyle \sec y^\circ[/tex]
Recall that tan(θ) = sin(θ) / cos(θ). Since sec(θ) = 1 / cos(θ), tan(θ) = sin(θ)sec(θ). Substitute:
[tex]\displaystyle \sin y^\circ \sec y^\circ = \frac{s}{t}[/tex]
Substitute:
[tex]\displaystyle \frac{s}{8}\sec y^\circ =\frac{s}{t}[/tex]
Solve for secant:
[tex]\displaystyle \sec y^\circ = \frac{8}{t}[/tex]
Hence, our answer is C.
Answer:
c. sec y° = 8/t
Step-by-step explanation:
I took the test
Which is the right answer?
Answer:
b the answer
Step-by-step explanation:
Which of the following should be the y-coordinate of left parenthesis (5,__) so that the ordered pair is a solution of 4x - y= -10
Answer:
y = 30
Step-by-step explanation:
Substitute x = 5 into the equation and solve for y
4(5) - y = - 10
20 - y = - 10 ( subtract 20 from both sides )
- y = - 30 ( multiply both sides by - 1 )
y = 30
Then (5, 30 ) is a solution of the equation
Who can help me ????.
instruction find the missing length.
Answer:
19 is the answer i think.
Chen I’d bringing fruit and veggies to serve at an afternoon meeting. He spends a total of $28.70 on 5 pints of cut veggies and 7 pints of cat fruit. The food cost is molded by the equation 5v + 7f = 28.70, where V represents the cost of 1 pint of cut veggies and F represents the cost of one pint of grapefruit. If the cost of each pint of fruit is $2.85, what is the approximate price of a pint of veggies? (round to the nearest cent, as needed)
Answer:
answer to that is A 1.75 per pint
Solid #1
SA= 539 cm?
V = 2058 cm
Solid #2
SA = 704 cm?
V?
Answer:
2688 cm³
Step-by-step explanation:
2058×704/539 = 2688 cm³
Rhonda walked diagonally across a rectangular playground with dimensions 60 m by 45 m. She started at point C. Determine the angle, to the
nearest degree, between her path and the longest side of the playground.
B
45m
D
60 m
Answer:
37degrees
Step-by-step explanation:
In order to get the required angle, we will use the SOH, CAH, TOA identity.
Let;
Adjacent = 60m
Opposite = 45m
According to TOA:
tan theta = opp/adj
tan theta = 45/60
tan theta = 0.75
theta = arctan 0.75
theta = 36.86
Hence the angle, to the nearest degree, between her path and the longest side of the playground is 37degrees
If f(x) = x/2 -2 and g(x) = 2x+ +x= 3, find (f + g)(x).
Answer:
.
.
.❥︎ᴀᴀɴᴋʜ ᴜᴛʜɪ ᴍᴏʜᴀʙʙᴀᴛ ɴᴇ ᴀɴɢᴅᴀɪ ʟɪ ,
.ᴅɪʟ ᴋᴀ sᴀᴜᴅᴀ ʜᴜᴀ ᴄʜᴀɴᴅɴɪ ʀᴀᴀᴛ ᴍᴇ ❣︎
.
.
Match each three-dimensional figure to its volume based on the given dimensions. (Assume π = 3.14.)
Answer/Step-by-step explanation:
✔️Volume of right cylinder = πr²h
Where,
π = 3.14
radius (r) = 4 cm
height (h) = 3 cm
Plug in the values into the formula
Volume of cylinder = 3.14*4²*3
= 150.72 cu cm
✔️Volume of cone = ⅓πr²h
Where,
π = 3.14
radius (r) = 5 cm
height (h) = 12 cm
Plug in the values into the formula
Volume of cylinder = ⅓*3.14*5²*12
= 314 cu cm
✔️Volume of pyramid = ⅓*Bh
Where,
Base area (B) = 16 cm²
height (h) = 30 cm
Substitute
Volume of pyramid = ⅓*16*30
= 160 cu cm
✔️Volume of square pyramid = ⅓*s²*h
Where,
Length of square base (s) = 3 cm
Height (h) = 16 cm
Substitute
Volume of square pyramid = ⅓*3²*16
= 48 cu cm
