A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.
Starting from rest, a student pulls a 25.0 kg box a distance of 4.50 m across the floor using a 134 N force applied at 35.0 degrees above horizontal.
We can calculate the work (W) done by the pulling force using the following expression.
[tex]W = F \times d \times cos\theta = 134 N \times 4.50 m \times cos35.0\° = 4.9 \times 10^{2} J[/tex]
where,
F: puling forced: displacementθ: angle between F and dThe friction between the floor and the box. does not influence the work done by the pulling force.
A 25.0 kg box is moved 4.50 m by a force of 134 N applied at 35.0° above horizontal. The work done by the pulling force is 4.9 × 10² J.
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a place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 23.9 m/s at an angle of 51.5 degrees to the horizontal. (a) by how much does the ball clear or fall short of clearing the crossbar?
(b) does the ball approach the crossbar while still rising or while falling?
Explanation:
Let's calculate the components of the football's velocity:
[tex]v_{0x} = (23.9\:\text{m/s})\cos{51.5°} = 14.9\:\text{m/s}[/tex]
[tex]v_{0y} = (23.9\:\text{m/s})\sin{51.5°} = 18.7\:\text{m/s}[/tex]
a) The time it takes for the football to travel 36.0 m horizontally is
[tex]t = \dfrac{x}{v_{0x}} = \dfrac{36.0\:\text{m}}{14.9\:\text{m/s}} = 2.4\:\text{s}[/tex]
During this time, the y-displacement of the football is
[tex]y = v_{0x}t - \frac{1}{2}gt^2[/tex]
[tex]\:\:\:\:= (18.7\:\text{m/s})(2.4\:\text{s}) - \frac{1}{2}(9.8\:\text{m/s}^2)(2.4\:\text{s})^2[/tex]
[tex]\:\:\:\:= 16.7\:\text{m}[/tex]
This means that the football cleared the crossbar by 16.7 m - 3.05 m = 13.7 m
b) To determine whether the football was rising or falling while clearing the crossbar, let's look at the y-component of its velocity after 2.4 s:
[tex]v_y = v_{0y} - gt = 18.7\:\text{m/s} - (9.8\:\text{m/s}^2)(2.4\:\text{s})[/tex]
[tex]\:\:\:\:\:\:= -4.82\:\text{s}[/tex]
Since its sign is negative, this means that the football was already on its way down.
The displacement of an object in SHM is described by the equation
[tex] x = cos\binom{2\pi}{3}t[/tex]
where x is in meters and t in seconds. Determine the velocity of the object at t = 0.6 s.
Answer:
[tex]-1.99\:\mathrm{m/s}[/tex]
Explanation:
Assuming that the equation is intended to be [tex]\displaystyle x=\cos\left(\frac{2\pi}{3}t\right)[/tex], we can find the velocity vs. time equation by taking the first derivative with respect to [tex]t[/tex]:
[tex]\displaystyle \frac{dx}{dt}=\frac{d}{dt}\left(\cos\left(\frac{2\pi}{3}t\right)\right)[/tex]
Recall the chain rule:
[tex]\displaystyle f(g(x))'=f'(g(x))\cdot g'(x)[/tex]
Therefore,
[tex]\displaystyle \frac{d}{dt}\left(\cos\left(\frac{2\pi}{3}t\right)\right)=-\sin\left(\frac{2\pi}{3}t\right)\cdot \frac{2\pi}{3}[/tex]
Therefore, the velocity vs. time equation of the object is [tex]\displaystyle v=-\sin\left(\frac{2\pi}{3}t\right)\cdot \frac{2\pi}{3}[/tex].
Substitute [tex]t=0.6\text{ s}[/tex] into this equation to find the velocity at that given time:
[tex]\displaystyle v=-\sin\left(\frac{2\pi}{3}(0.6)\right)\cdot \frac{2\pi}{3}\approx \boxed{-1.99\text{ m/s}}[/tex]
Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
What is the maximum height of the cannonball?
Explanation:
The final velocity at the cannon ball's maximum height is zero ([tex]v_y = 0[/tex]). We can use the equation
[tex]v_y^2 = 0 = v_{0y}^2 - 2gy_{max}[/tex]
[tex]\Rightarrow y_{max} = \dfrac{v_{0y}^2}{2g}[/tex]
[tex]y_{max} = \dfrac{(25\:\text{m/s})^2}{2(9.8\:\text{m/s}^2)}[/tex]
[tex]\:\:\:\:\:\:\:=31.9\:\text{m}[/tex]
Please help with this question, it’s for physical science
Answer:
s times t
Explanation:
The equation for distance is D = st
Answer:
D is the correct answer (D=S*T)
This is an algebraic law; if you are to move the denominator or numerator to the other side of the equation, you must multiply it by the other side.
S=D/T is the same as D=S*T.
so distance=speed times time.
so if you are going 50 miles per hour, you multiply that times time, say one hour. you get your D distance which is 50 miles.
A............... pulley helps us by changing the direction of the applied effort
Answer/Explanation:
True
A fixed pulley changes the direction of the force you exert by pulling, so you can pull down to move an object up. In this fixed pulley system, you pull down on one side of the rope and the other side goes up. You use the same amount of force to pull down as you would to lift the toy yourself.
Help !!!
I solved Anthor one but didn’t understand this one ??
Answer:
Explanation:
It's a velocity•time chart. As distance = vt, the area under the curve between limits is the distance traveled.
Pic is fuzzy so I will ASSUME the horizontal axis is seconds and vertical is meters per second.
0 s ≤ t ≤ 5 s = ½(5 - 0)(30 - 0) = 75 m
5 s ≤ t ≤ 10 s = (10 - 5)(30 - 0) = 150 m
10 s ≤ t ≤ 15 s = ½(30 + 20)(15 - 10) = 75 m
0 s ≤ t ≤ 25 s = 75 + 150 + 75 + 20(20 - 15) + ½(20)(25 - 20) = 450 m
A toy car on a string is pulled across a table horizontally. The string is at an
angle of 30°. Which is the correct free-body diagram for this situation?
EN
w
w
w
w
А
B
с
D
A. A
ОВ. В
ОО Ο Ο
O C. C
D. D
(C)
...........................
Answer:
Hope this helps!
Explanation:
HELP PLEASE
What is the correct definition of amplitude?
A. the height of a wave
B. the distance between two crests or troughs
C. the number of complete waves that pass a point in a second
D. the time it takes for one complete wave to pass a given point
Answer:
correct answer is A) the height of a wave
Explanation:
i just did the test:)
The amplitude is used represent the height of the wave.
What is wave?A wave is a disturbance in a medium that carries energy without a net movement of particles. In general, waves are classified into two types as Longitudinal and Transverse
Given is the amplitude of a wave.
Amplitude of a wave is equal to measure of the length of crest or trough. Crest and trough are the points that represents the maximum and minimum displacement of the wave with respect to the reference axis. The crest and the trough points are both at a equal straight line distance from the reference axis. This distance is also called height of the wave. The amplitude is the distance between the centerline and the Crest or trough. The general equation representing the amplitude of wave is x = A sin (ωt + ϕ) or x = A cos (ωt + ϕ) is the formula.
Therefore, the amplitude represents the height of the wave.
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2. In these diagrams, the sunlight is coming from the left, as shown by the arrows. Which
diagram is accurate and why? (1)
a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the
other half is dark.
b) B is accurate because the whole Moon is bright as long as there are no shadows
covering parts of it.
c) C is accurate because the Moon is almost as close as it can be to the sun, and so the
Moon is almost fully lit by the sun.
d) All three diagrams are sometimes accurate because the Moon has some lighter-colored
rock and some darker-colored rock, and the half of the Moon with the lighter-colored
rock rotates to face different directions.
Answer:
Explanation:
a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.
The most accurate diagram of the Sun and Moon is: a. A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.
What is a Moon?A Moon can be defined as the natural satellite of planet Earth that shines due to the Sun's reflected light (sunlight), as it revolves around the Earth from west to east in 29½ days.
The phases of the Moon.Based on astronomical information, there are four (4) primary Moon phases and these are:
New MoonFirst QuarterFull MoonThird Quarter (Last Quarter)In conclusion, diagram A is the most accurate because half of the Moon that faced the Sun is lit by the Sun while the other half is dark.
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what force is represented by the vector
What is the net force on a cart being pushed with an applied force of 23 N with a frictional force of 23 N?
Answer:
1N
Explanation:
Pretty simple Divide 23 by 23 which gives you 1.
23N ÷ 23N = 1N
Answer:
[tex]\sf \longmapsto \: 1 \: N[/tex]
Explanation:
[tex]\sf \longmapsto \frac{23N}{23N} [/tex]
[tex]\sf \longmapsto1 \: N[/tex]
Bob is riding in a roller coaster, and is at the top of a vertical loop (shown below). The radius of the loop is 18 meters. If his apparent weight is just 28% of his actual weight, what is the speed of the roller coaster? Show all your steps.
Iron and nickel are examples of _______ materials
Content From May net
Answer:an iron-nickel alloy or nickel -iron alloy abbreviated FeNi or NiFe is a group of alloys consisting primarliy of the elemtns nickel and iron.
Explanation:
Answer:
Iron and nikel are example of "Metal" materials.
How long will it take to travel 200 000 m [North] traveling 10 m/s
Answer:
there are 1,000m in a km, so 200km is 200,000m
200,000m/10m/s = 20,000s
Explanation:
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While driving your car at a fast constant speed, you have to press down hard on your gas pedal than you do while driving at a slower constant speed.
In both cases, the net force on your car is zero. Explain why you have to apply a greater pressure to your gas pedal.
Answer:
You have to apply more pressure to the pedal so more gas runs through the car allowing it to reach higher speeds
To move, a car or any other object must be accelerated from rest to the desired speed; this necessitates that the engine force be greater than the friction force. The net force must be zero once the car is moving at constant velocity; otherwise, the car will accelerate (gain speed).
What forces act on a car at constant speed?All forces acting on a car moving at a constant speed (uniform motion) are balanced. In this case, the two opposing backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road.When we say constant speed, we mean that a body or object moves at a constant change in distance over time. For example, if we are walking in a straight line at 1 step per second, we can say we are moving at a constant speed. Our acceleration is equal to zero in this case.To learn more about : Speed
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Which statement describes friction?
Answer:
include the statements pls so i can choose wich one it is and tell you
Explanation:
10. The SI unit of the solid angle is
a) Degree
b) Steradian
c) Revolution
d) Radian
The S.I unit of solid angle is steradian, or square radian (symbol: sr).
A boy of mass 43.2 kg runs and jumps onto a stationary skateboard.The boy lands on the skateboard with a horizontal velocity of 4.10 m/s.The skateboard has a mass of 2.50 kg.
Using ideas about conservation of momentum, calculate the combined
velocity of the boy and skateboard just after the boy lands on it.
Answer:
= 3.87 m/s
Explanation:
Since momentum is conserved, momentum right before and after the boy jumps onto the skateboard should be the same.
Initial momentum = momentum of boy = 43.2 x 4.10 = 177 kg·m/s
Final momentum = momentum of boy and skateboard = (43.2 + 2.50) x v = 45.7v
177 = 45.7v
v = 177 / 45.7 = 3.87 m/s
(Hope this helps can I pls have brainlist (crown)☺️)
The combined velocity of the boy and the skateboard just after the boy lands on it will be equal to 3.87 m/s.
What is momentum?Momentum is the product of a particle's mass and velocity. Being a vector quantity, momentum possesses both direction and magnitude. According to Isaac Newton's second equation of motion, the force applied on a particle is equivalent to the temporal rate at which momentum changes.
According to Newton's second law, the product of the energy and the time interval is equal to the shift in momentum if a constant force acts on a molecule for a specified amount of time.
Momentum should be the same both before and after the boy gets onto the skateboard because it is preserved.
Initial momentum = momentum of boy
= 43.2 × 4.10 = 177 kg m/s
Final momentum = momentum of boy as well as skateboard
= (43.2 + 2.50) × v = 45.7 v
177 = 45.7 v
v = 177 / 45.7 = 3.87 m/s
Therefore, the combined velocity of boy and skateboard is 3.87 m/s.
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A normal atom is electronically ** (positive/negative/neutral) because the number of ** (protons/neutrons/electrons), each with a positive charge, equals the number of ** (protons/neutrons/electrons), each with a negative charge.
The answers to multiple choice questions are in parentheses
Answer:
(neutral)
(protons)
(electrons)
Explanation:
Electrons have a negative charge (-) while protons have a positive (+) charge.
Atoms will usually be neutral, which means that there will be no charge.
For an atom to have a neutral charge, protons and electrons must "cancel" each other out. For this to happen, you need to have the same amount of each.
Positive will "cancel" out the negative.
Give two examples of contact and non-contact forces and explain why they are contact and non-contact forces respectively.
The Two examples of contact forces are:
frictional force Contact force.The two examples of non contact forces are:
Gravitational forcemagnetic force.Contact forces happens due to the contact between two objects
Non Contact forces happens because there is no contact between two objects. There is no attraction.
What process makes this pattern on the ocean floor?
Two vectors P=40m/s and q=60mls are perpendicular to each other. Calculate the resultant force and the angle resultant make with either vectors
This question involves the concepts of the rectangular components of the vector and the resultant of the vectors.
The magnitude of the resultant force is "72.11 N", and it makes an angle of "33.7°" from one of the vectors.
The rectangular components of a vector are those components that have a right angle between them. The resultant of two rectangular components of a vector can be found using the following formula:
[tex]F = \sqrt{F_1^2+F_2^2}[/tex]
where,
F = resultant force = ?
F₁ = First component of force = 40 N
F₂ = Second component of force = 60 N
Correction: The unit in question is given as m/s, while the unit of force is N. Hence, N is taken here.
Therefore,
[tex]F = \sqrt{(40\ N)^2+(60\ N)^2}[/tex]
F = 72.11 N
The following formula can be used to find the angle of resultant from 60N vector:
[tex]\theta = tan^{-1}(\frac{40\ N}{60\ N})\\\\[/tex]
θ = 33.7°
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The attached picture shows the resultant calculation for the rectangular components of a vector.
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
Starting at 9a.m., you ride your hover board for 3hrs at an average speed of 6 mph. Out of breath, you stop for tea from noon until 2p.m. What is your average speed over the interval from 9a.m. to 2p.m.?
what is an electrostatic phenomenon?
Answer:
Electrostatic phenomenon is a from the forces that electric charges exert on each other.
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What is the value of the force measured by the spring balance?
help with this question please.
Answer: Yes Because it matches with the mass and the amount of force Hope this helps :>
Explanation:
Un péndulo de 4 m de longitud tiene una frecuencia de 5Hz. Calcular la longitud de otro péndulo que en el mismo lugar tiene una frecuencia de 4Hz
Conociendo la longitud y frecuencia de un péndulo, queremos encontrar la longitud de otro pendulo de tal forma que tenga otra frecuencia.
Veremos que la longitud del nuevo péndulo debe ser 6.25m
Sabemos que un péndulo de 4m de longitud tiene una frecuencia de 5Hz.
La frecuencia de un péndulo está dada por:
[tex]f = \frac{1}{2*\pi} *\frac{g}{l}[/tex]
Donde g es la aceleración gravitatoria y l es la longitud del péndulo, remplazando los datos que tenemos en esa ecuación obtenemos:
[tex]5 Hz = \frac{1}{2*3.14} *\sqrt{\frac{g}{4m} } \\\\(5Hz*2*3.14)^2*4m = g = 3,943.8 m/s^2[/tex]
Ahora debemos encontra la longitud de tal forma que la frecuencia sea 4Hz, entonces debemos resolver:
[tex]4Hz = \frac{1}{2*3.14} *\sqrt{ \frac{3943.8m/s^2}{l} }\\\\4hz*2*3.14 = \sqrt{ \frac{3943.8m/s^2}{l} }\\\\l =\frac{3943.8m/s^2}{ (4hz*2*3.14)^2} = 6.25m[/tex]
La longitud del nuevo péndulo deve ser 6.25m
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A machine whose efficiency is 75% is used to lift a load of 100m.calculate the effort put into the machine if it has a velocity ratio of 4.
Explanation:
M.A = load / Effort
efficiency = M.A/V.R X 100
75 = M.A / 4 X 100
75 = 25 X M.A
M.A = 75/25 = 3
M.A = load / effort
3 = 100/E
E = 100/3 = 33.333
A machine whose efficiency is 75% is used to lift a load of 100m. the effort needed to put into the machine is 33.33 meters if the velocity ratio is 4.
What is the mechanical advantage?Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = output force(load) /input force (effort)
Simple machines like static pulleys, as well as a movable pulleys, provide a great amount of mechanical advantage.
A machine whose efficiency is 75% is used to lift a load of 100m.calc if it has a velocity ratio of 4.
As we know that the mechanical advantage of a machine is equal to the product of its efficiency and velocity ratio.
mechanical advantage = velocity ratio ×Efficiency
=4 × 0.75
= 3
The mechanical advantage is 3 , which means the ratio of load to effort is 3
load / effort = 3
100 m/effort =3
effort = 33.33 m
Thus, the effort put into the machine comes out to be 33.33 m.
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why do the star constellations seem to move across the sky
Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.
Explanation: why do the star constellations seem to move across the sky
Answer:
because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.
Explanation:
