Answer:
[tex]x=\frac{ab+a+b-c}{a+b}[/tex]
Step-by-step explanation:
a(x−b)+bx+c=a+b
Step 1: Add ab to both sides.
−ab+ax+bx+c+ab=a+b+ab
ax+bx+c=ab+a+b
Step 2: Add -c to both sides.
ax+bx+c+−c=ab+a+b+−c
ax+bx=ab+a+b−c
Step 3: Factor out variable x.
x(a+b)=ab+a+b−c
Step 4: Divide both sides by a+b.
[tex]\frac{x(a+b)}{a+b} =\frac{ab+a+b-c}{a+b}[/tex]
[tex]x=\frac{ab+a+b-c}{a+b}[/tex]
Hope this helped! :)
The measure of angle tis 60 degrees.
What is the x-coordinate of the point where the
terminal side intersects the unit circle?
1
2
O
O
Isla Isla
2
DONE
Answer:
Step-by-step explanation:
Not a clear list of options and/or reference frame
Probably 0.5 if angle t is measured from the positive x axis.
Which expression is equivalent to 15 n=10 (n+3/n)?
Answer:
±√6
Step-by-step explanation:
[tex]15n=10(n+\frac{3}{n} )[/tex] is your expression first muiltiply out the 10 to get 15n= 10n+10 3/n next subtract 10 n from both sides to get 5n=10+3/n multiply both sides by n to get 5n^2=13 combine both sides and use the quadratic equation to solve to get your solution of ±√6
Which is equivalent to 10’6
Answer:
35/5 (if you mean 10.6)
1000000 (if you mean 10 to the sixth power)
0.000001 (if you mean 10/6)
Answer:
There are 126 inches in 10'6
Step-by-step explanation:
take our feet and multiply the value by 12
Team A scored 30 points less than four times the number of points that Team B scored. Team C scored 61 points more than half of the number of points that Team B scored. If Team A and Team C shared in the victory, having earned the same number of points, how many more points did each team have than Team B?
Answer:
team a and team c scored 74 points which is 48 points more than team b, scoring 26 points.
Step-by-step explanation:
Given that f(x) = logo x, write a function that translates f(x) down 4 units and then
reflects it across the x axis.
Answer:
Answer 2/B
Step-by-step explanation:
The one with Parentheses
-(log6 x-4)
evaluate
(3^-1+4^-1)^-2
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{= (3^{-1}+4^{-1})^{-2}}\\\\\\\mathsf{3^{-1} = \bf {\dfrac{1}{3}}}\\\\\\\mathsf{4^{-1} = \bf \dfrac{1}{4}}\\\\\\\mathsf{= (\dfrac{1}{3}+\dfrac{1}{4})^{-2}}\\\\\\\mathsf{\dfrac{1}{3} + \dfrac{1}{4} = \bf \dfrac{7}{12}}\\\\\\\mathsf{= (\dfrac{7}{12})^{-2}}\\\\\large\text{Simplify above and you have your overall answer...}\\\\\\\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{144}{49}}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}\\\\\\\\\frak{Amphitrite1040:)}[/tex]
According to an independent research, a point estimate of the proportion of U.S. consumers of black tea is p = 0.76. Calculate the sample size needed to be 95% confident that the error in estimating the true value of p is less than 0.015? Use the z-value rounded to two decimal places to obtain the answer. 4072.69
Answer:
The sample size needed is 3115.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
Point estimate:
[tex]\pi = 0.76[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
Calculate the sample size needed to be 95% confident that the error in estimating the true value of p is less than 0.015?
This is n for which M = 0.015. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.015 = 1.96\sqrt{\frac{0.76*0.24}{n}}[/tex]
[tex]0.015\sqrt{n} = 1.96\sqrt{0.76*0.24}[/tex]
[tex]\sqrt{n} = \frac{1.96\sqrt{0.76*0.24}}{0.015}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96\sqrt{0.76*0.24}}{0.015})^2[/tex]
[tex]n = 3114.26[/tex]
Rounding up:
The sample size needed is 3115.
Does the graph represent a function and if so, why?
A.Yes, no two ordered pairs on this graph have the same second element.
B.Yes, there is more than one ordered pair on this graph.
C.Yes, no two ordered pairs on this graph have the same first element.
D.No, there is a limited number of ordered pairs on this graph.
Answer:
A. yes
Step-by-step explanation:
After running a mile a day over a period of two weeks, the average amount of weight loss is 2.5 pounds. A dietitian, who publishes health articles in a newspaper, states their new diet program helps with additional weight loss when combining their special diet with running a mile a day over a period of two weeks. Interested in studying the dietitian's article further, you ask friends who have tried the dietitian's new program and you determine their weight loss to be 3.0 pounds in a two week period, on average. As you set up a hypothesis test to determine if the dietitian's article is correct, what is the dietitian's claim?
a. Adults should run every day to lose weight.
b. The average amount of weight loss is less than 2.52.5 pounds.
c. The average amount of weight loss is greater than 3.03.0 pounds.
d. The average amount of weight loss is greater than 2.52.5 pounds.
Answer:
d. The average amount of weight loss is greater than 2.5 pounds.
Step-by-step explanation:
After running a mile a day over a period of two weeks, the average amount of weight loss is 2.5 pounds.
At the null hypothesis, we test if this mean is of 2.5, that is:
[tex]H_0: \mu = 2.5[/tex]
A dietitian, who publishes health articles in a newspaper, states their new diet program helps with additional weight loss.
With the additional weight loss, the dietitian claims that the mean is more than the value presented at the null hypothesis, that is, more than 2.5, and thus, the correct answer is:
[tex]H_1: \mu > 2.5[/tex]
And thus, the correct option is given by option d.
A data set includes data from student evaluations of courses. The summary statistics are n=89, x=3.44, s=0.67. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative hypotheses?
A.
H0: μ=3.50
H1: μ>3.50
B.
H0: μ=3.50
H1: μ<3.50
C.
H0: μ≠3.50
H1: μ=3.50
D.
H0: μ=3.50
H1: μ≠
(I also need the test statistic and p-value) thank you so much in advance :)
We're told that "the claim that the population of student course evaluations has a mean equal to 3.50". So this means μ=3.50 makes up the null H0
The alternative would be H1: μ ≠ 3.50 since it's the opposite of the claim made in the null.
We go with answer choice D to form the null and alternative hypotheses.
The sign ≠ in the alternative hypothesis tell us that we have a two tail test.
---------------------------------------
Let's compute the test statistic
z = (xbar - mu)/(s/sqrt(n))
z = (3.44 - 3.50)/(0.67/sqrt(89))
z = -0.84483413122896
z = -0.84
The test statistic is roughly -0.84
---------------------------------------
Despite not knowing what sigma is (aka the population standard deviation), we can see that n > 30 is the case. So we can use the Z distribution. This is the standard normal distribution. When n > 30, the T distribution is fairly approximately the same as the Z distribution.
Use a calculator or a Z table to determine that
P(Z < -0.84) = 0.2005
which is approximate
Because we're doing a two-tail test, this means we double that result to get 2*0.2005 = 0.401
The p-value is roughly 0.401
-----------------------------------------
Since the p-value is larger than alpha = 0.05, we don't have enough evidence to reject the null. So you can say that we fail to reject the null, or we accept the null.
The conclusion based on that means that μ=3.50 must be true (unless other evidence comes along to disprove this). In other words, the mean evaluation score from students appears to be 3.50
find the amount of time to the nearest day it would take a deposit of $2500 to grow to $1 million at 2% compounded continuously. find how many days & years
Answer:
Years = natural log (Total / Principal) / Rate
Years = natural log (1,000,000 / 2,500) / .02
Years = natural log (400) / .02
Years = 5.9914645471 / .02
It would take 299.573227355 Years
Source: http://www.1728.org/rate2.htm
Step-by-step explanation:
Consider a political discussion group consisting of 6 Democrats, 6 Republicans, and 4 Independents. Suppose that two group members are randomly selected, in succession, to attend a political convention. Find the probability of selecting an Independent and then a Republican.
___.
(Type an integer or a simplified fraction.)
Answer:
10/16=5/8
6+6+4=16
The probability is 5/8
Write a quadratic equation in standard form that has two solutions, 9 and -2
(the leading coefficient must be 1.)
A pie is cut into 9 equal pieces. If all but 2 pieces are eaten, how much of the pie remains?
Answer:
is 7 pieces are remian
Step-by-step explanation:
9: total
2: eaten
so, 9-2 = 7 pieces?
In a survey of 938 U.S. adults, 235 say the phrase "you know" is the most annoying conversational phrase. Let p be the proportion of the population who respond yes. Use the given information to Construct a 90% confidence interval for p.
Answer:
CI 90% = ( 0.227 ; 0.273)
Step-by-step explanation:
Information from the survey:
sample size n = 938
number of people with yes answer x = 235
proportion of people p = 235/938
p = 0.25 then q = 1 - 0.25 q = 0.75
Confidence Interval 90 % .
CI 90% = ( p ± SE )
CI 90% = ( p ± z(c)*√(p*q)/n)
CI 90 % then significance level is α = 10 % α/2 = 5%
α/2 = 0.05 we find in z-table z (c) = 1.64
√(p*q)/n = √0.25*0.75/938
√(p*q)/n = √0.000199
√(p*q)/n = 0.014
CI 90% = ( p ± z(c)*√(p*q)/n)
CI 90% = ( 0.25 ± 1.64*0.014)
CI 90% = ( 0.25 ± 0.023 )
CI 90% = ( 0.227 ; 0.273)
Help please …………………..
9514 1404 393
Answer:
T = s + dd = 5,011 for FridayStep-by-step explanation:
(a) As you might imagine, the disposition of apples in inventory will be one of "sold" or "discarded". (They could also be "stolen", but we'll call that "discarded", since they're not sold.) Then the inventory turnover T is the sum of numbers sold and discarded:
T = s + d
__
(b) The value of d for Friday will be ...
d = T -s = 34848 -29837 = 5,011 . . . value of d for Friday
find two ordered pairs for x-4y=2
Answer:
x-4y=2 can be written as y=(x-2)/4
(2,0) when x=2, y=0 and (6,1) when x=6, y=1
Identify the terminal point for a 45° angle in a unit circle.
O A (231)
O B.
O c.
V2 72
Answer:
D
Step-by-step explanation:
x- coordinate = cos45° = [tex]\frac{1}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]
y- coordinate = sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]
That is ( [tex]\frac{\sqrt{2} }{2}[/tex] , [tex]\frac{\sqrt{2} }{2}[/tex] ) → D
I will give brainliest if you answer properly.
Answer:
See below
Step-by-step explanation:
a)
[tex]2\sin(x) +\sqrt{3} =0 \implies 2\sin(x)=-\sqrt{3} \implies \boxed{\sin(x)=-\dfrac{\sqrt{3}}{2} }[/tex]
[tex]\therefore x=\dfrac{4\pi }{3}[/tex]
But note, as sine does represent the [tex]y[/tex] value, [tex]\dfrac{5\pi }{3}[/tex] is also solution
Therefore,
[tex]x=\dfrac{4\pi }{3} \text{ and } x=\dfrac{5\pi }{3}[/tex]
This is the solution for [tex]x\in[0, 2\pi ][/tex], recall the unit circle.
Note: [tex]\sin(x)=-\dfrac{\sqrt{3}}{2} \implies \sin(x)=\sin \left(\pi +\dfrac{\pi }{3} \right)[/tex]
b)
[tex]\sqrt{3} \tan(x) + 1 =0 \implies \tan(x) = -\dfrac{1}{\sqrt{3} } \implies \boxed{ \tan(x) = -\dfrac{\sqrt{3} }{3} }[/tex]
Once
[tex]\tan(x) = -\dfrac{\sqrt{3} }{3} \implies \sin(x) = -\dfrac{1}{2} \text{ and } \cos(x) = \dfrac{\sqrt{3} }{2}[/tex]
As [tex]\tan(x) = \dfrac{\sin(x)}{\cos(x)}[/tex]
[tex]\therefore x=-\dfrac{\pi }{6}[/tex]
c)
[tex]4\sin^2(x) - 1 = 0 \implies \sin^2(x) = \dfrac{1}{4} \implies \boxed{\sin(x) = \pm \dfrac{\sqrt{1} }{\sqrt{4} } = \pm \dfrac{1}{2}}[/tex]
Therefore,
[tex]\sin(x)=\dfrac{1}{2} \implies x=\dfrac{\pi }{6} \text{ and } x=\dfrac{5\pi }{6}[/tex]
[tex]\sin(x)=-\dfrac{1}{2} \implies x=\dfrac{7\pi }{6} \text{ and } x=\dfrac{11\pi }{6}[/tex]
The solutions are
[tex]x=\dfrac{\pi }{6} \text{ and } x=\dfrac{5\pi }{6} \text{ and }x=\dfrac{7\pi }{6} \text{ and } x=\dfrac{11\pi }{6}[/tex]
help with math it would help with summer school
Answer:
[tex]A). \ \ \frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
Step-by-step explanation:
Given;
radius of the circle, r = 9 inches
the part of the circle cut out = one-forth of the complete circle
the angle of the sector cut out θ= ¹/₄ x 360 = 90⁰
Area of the complete circle = πr² = π x 9² = 81π in²
Area of the sector cut out = [tex]= \frac{\theta }{360} \pi r^2 = \frac{90}{360} \pi (9^2) = \frac{1}{4} \times 81\pi = \frac{81 \pi}{4} = \frac{(72\pi + 9\pi)}{4} \ in^2[/tex]
Therefore, the only correct option is A. [tex]\frac{(72\pi + 9\pi )}{4} \ in^2[/tex]
Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36
9514 1404 393
Answer:
asymptotes: x = ±6
zero: x = 0
Step-by-step explanation:
The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...
x^2 -36 = 0
x^2 = 36
x = ±√36 = ±6
The vertical asymptotes of the function are x = -6 and x = +6.
__
The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...
6x = 0
x = 0 . . . . . divide by 6
The zero of the function is x=0.
__
As a check on this work, we have had a graphing calculator graph the function and identify the zero.
verify cos(a+b)/cos(a) cos(b) =1-tan(a) tan(b)
The identity as been verified/proved as:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Given that:
[tex]\frac{\cos(a + b)}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Apply cosine identity to the numerator
[tex]\frac{\cos\ a\ cos\ b - \sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Split the fraction:
[tex]\frac{\cos\ a\ cos\ b}{\cos\ a\cos b} - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Cancel out common terms
[tex]1 - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
In trigonometry, we have:
[tex]\frac{\sin \theta}{\cos \theta} = \tan \theta[/tex]
So, the equation becomes:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Hence, the identity has been verified
Read more about trigonometry identities at:
https://brainly.com/question/21055284
how to work this fraction 4/11+5/22+3/44
Answer:
29/44
Step-by-step explanation:
[tex]\frac{4}{11} +\frac{5}{22} +\frac{3}{44} =\\[/tex]
-find the common denominator
[tex]\frac{4*4}{4*11} + \frac{2*5}{2*22} +\frac{3}{44} =[/tex]
[tex]\frac{16}{44} +\frac{10}{44} +\frac{3}{44} =[/tex]
-add the fractions and solve
[tex]\frac{16+10+3}{44} =[/tex]
[tex]\frac{29}{44}[/tex]
Most linear graphs are direct variation, unless they go through the origin.
True
False
Find the cash value of the lottery jackpot (to the nearest dollar). Yearly jackpot payments begin immediately (26 for Mega Millions and 30 for Powerball). Assume the lottery can invest at the given interest rate. Powerball: $360 million; 5.4% interest
a. $188,347,953
b. $282,573,702
c. $185,870,742
d. $298,386,685
Answer:
The right response is Option c ($185,870,742).
Step-by-step explanation:
Given:
n = 30
r = 5.4%
or,
= 0.054
Periodic payment will be:
[tex]R = \frac{360000000}{30}[/tex]
[tex]=12000000[/tex] ($)
Now,
The present value will be:
= [tex]R+R(\frac{1-(1+r)^{-n+1}}{r} )[/tex]
By substituting the values, we get
= [tex]12000000+12000000(\frac{1-(1+0.054)^{-30 + 1}}{0.054} )[/tex]
= [tex]12000000+12000000\times 14.4892[/tex]
= [tex]185,870,742[/tex] ($)
Working at home: According to the U.S Census Bureau, 41% of men who worked at home were college graduates. In a sample of 506 women who worked at home, 166 were college graduates. Part: 0 / 30 of 3 Parts Complete Part 1 of 3 (a) Find a point estimate for the proportion of college graduates among women who work at home. Round the answer to at least three decimal places. The point estimate for the proportion of college graduates among women who work at home is .
Solution :
a). The point estimate of proportion of college graduates among women who work at home,
[tex]$\hat p =\frac{166}{506}$[/tex]
= 0.3281
99.5% confidence interval
[tex]$=\left( \hat p \pm Z_{0.005/2} \sqrt{\frac{\hat p (1- \hat p)}{n}} \right)$[/tex]
[tex]$=\left( 0.3281 \pm 2.81 \sqrt{\frac{0.3281 \times (1- 0.3281)}{506}} \right)$[/tex]
[tex]$=(0.3281 \pm 0.0586)$[/tex]
[tex]$=(0.2695, 0.3867)$[/tex]
Find the length of the missing sides
Answer:
f = 10
g = 2 sqrt(3)
h = 20
Step-by-step explanation:
The short leg is opposite the smaller angle so it is f
The longer leg is opposite the larger angle so it is g
The hypotenuse is opposite the right angle so it is 20
We know f = x
g = x sqrt(3)
h = 2x = 20
2x = 20 so x = 10
f = 10
g = 2 sqrt(3)
h = 20
Which of the following statements correctly explains the meaning of the term "95% confidence" in the confidence statement? The interval 52% to 58% is based on a procedure that includes a sample representing 95% of population. The interval 52% to 58% is based on a procedure that includes the true population value 95% of the time. The interval 52% to 58% is based on a procedure that produces a margin of error (of ±3) 95% of the time.
Answer:
The interval 52% to 58% is based on a procedure that includes the true population value 95% of the time.
Step-by-step explanation:
x% confidence interval:
A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.
95% confidence
We are 95% sure that the interval contains the true mean/proportion, and thus, the correct option is:
The interval 52% to 58% is based on a procedure that includes the true population value 95% of the time.
The critical value of F for an upper tail test at a 0.05 significance level when there is a sample size of 21 for the sample with the smaller variance and there is a sample size of 9 for the sample with the larger sample variance is _____. a. 2.94 b. 2.45 c. 2.10 d. 2.37
Answer:
2.45
Step-by-step explanation:
Given that :
α = 0.05
Larger sample variance= numerator, sample size = 9
Smaller sample variance = denominator, sample size = 21
Hence,
DFnumerator = n - 1 = 9 - 1 = 8
DFdenominator = n - 1 = 21 - 1 = 20
Critical value for upper tail test using the F distribution table at α = 0.05 ; DFnumerator on horizontal ; Df denominator as vertical ;
F critical = 2.447
F critical = 2.45
The sample size needed to estimate the difference between two population proportions to within a margin of error E with a significance level of ? can be found as follows. In the expression
E=z?p1(1?p1)n1+p2(1?p2)n2?????????????????????????
we replace both n1 and n2 by n (assuming that both samples have the same size) and replace each of p1, and p2, by 0.5 (because their values are not known). Then we solve for n, and get
n=(z?)22E2.
Finally, increase the value of n to the next larger integer number.
Use the above formula and Table C to find the size of each sample needed to estimate the difference between the proportions of boys and girls under 10 years old who are afraid of spiders. Assume that we want a 99% confidence level and that the error is smaller than 0.07.
n=______.
Answer:
n= (z)22E2
n=10× 99%÷ 0.07
