Answer:
sin (a+b)= sina*cosb - sinb*cosa
cos (a+b) = cosa*cosb + sina*sinb
Answer:
sin (A + B) = sin A cos B + cos A sin B
cos (A + B) = cos A cos B - sin A sin B
on:
Help me! thank you so much
Answer:
Step-by-step explanation:
[tex]\frac{sinxcos^3x-cos xsin^3x}{cos^42x-sin^42x} \\=\frac{sin x cos x(cos^2x-sin ^2 x)}{(cis^2 2x+sin^2 2x)(cos^2 2x-sin ^22x)} \\=\frac{2sin x cos x cos 2x}{2(1)(cos 4x)} \\=\frac{sin 2x cos 2x}{2 cos 4x} \\=\frac{2 sin 2x cos 2x}{4 cos 4x} \\=\frac{sin 4x}{4 cos 4x} \\=\frac{1}{4} tan 4x[/tex]
58×62 without actual multiplication
Answer:
3596
Step-by-step explanation:
Use long multiplication to evaluate.
Answer:
3596
Step-by-step explanation:
(58*10) = 580
580*6 = 3480
58 * 2 = 116
3480 + 116 = 3596
Use Pythagoras to find the height and hence, the area of the triangle
below. Give height to 1 decimal place and area to the nearest whole. Write
answer in format: h= A= *
20 mm
Val
Answer:
h=17.3 A=173
Step-by-step explanation:
Calculator
Answer:
height = 17.3 mm
area = 173 mm²
Step-by-step explanation:
all three sides are of the same length (20 mm).
so, the height actually splits the baseline in half
(2 × 10 mm) while hitting it at a 90 degree angle.
so, we use Pythagoras, where the full side opposite of this 90 degree angle is c (Hypotenuse), the height of the main triangle is one side, and half of the baseline is the other side.
c² = a² + b²
20² = 10² + height²
400 = 100 + height²
300 = height²
height = 17.3 mm
the area of the main triangle is baseline (20) times height divided by 2.
so,
At = 20×17.3/2 = 10×17.3 = 173 mm²
A to B is 420 mile away, A travels 40 mph and B travels 80 mph. they toward to each other. how many hour will they meet ?
Answer:
Step-by-step explanation:
I hope these are people in vehicles travelling toward each other.
80 mh * t + 40 mph * t = 420 miles
The two vehicles are going to travel a total of 420 miles. B will cover a lot more ground than A, but together they will make 420 miles
80t + 40t = 420
120t = 420
t = 420/120
t = 3.5
So after driving 3.5 hours, the two cars will meet.
A student states that the translation of triangle ABC is A’B’C’. What measurements or properties of lines AA', BB', and CC' do you need to confirm that it is a translation? :D
If you can show that the following two items are true
AA' = BB' = CC'AA' || BB' || CC'then you have shown that triangle A'B'C' is a translated or shifted copy of triangle ABC. In other words, they are the same triangle.
write an equation of the function in the form y=a(b)^x -c that has a y intercept of -6, asymptote of y= -2 and goes through (2,-18)
Step-by-step explanation:
Asymptote: y = 2 y-intercept: (0,8)
Step-by-step explanation:
The given function is
f(x) = 6(0.5)^{x} + 2f(x)=6(0.5)
x
+2
This function is of the form:
f(x) = a {b}^{x} + cf(x)=ab
x
+c
where y=c is the horizontal asymptote.
By comparing , we have c=2 hence the horizontal asymptote is
y = 2y=2
To find the y-intercept, we put x=0 into the function to get:
f(0) = 6(0.5)^{0} + 2 = 6 + 2 = 8f(0)=6(0.5)
0
+2=6+2=8
Therefore the y-intercept is (0,8).
A hot air balloon is released into the air. During its straight ascent, the angle of elevation was 15° and, 3 minutes later, the angle of elevation increased 20°. How fast is the balloon traveling, in km/h, if the angle measurements were taken 300m away from the launch site?
Answer:
The speed of the balloon is 0.16 m/s.
Step-by-step explanation:
CD = 300 m
Let AD = x
AB = y
time, t = 3 min
Triangle, ADC
[tex]tan 15 = \frac{AD}{BC}\\\\0.27 \times 300 = x \\\\x = 80.4 m[/tex]
Triangle, BCD
[tex]tan 20 = \frac{BD}{BC}\\\\0.36 \times 300 = x + y \\\\x + y = 109.2 m[/tex]
So, y = 109.2 - 80.4 = 28.8 m
Speed = 28.8/180 = 0.16 m/s
Last month, Nate spent 12 % of his paycheck on
car repairs and 25 % of the remainder on food.
He gave $ 1,320 of the remaining money to his
parents and then bought a computer on sale. If
the usual price of the computer was $ 825 and
the discount was 20 %, how much money did
Nate have in the beginning?
Nate had $3000 at the beginning.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
Let the original amount of money is P
Nate spent 12 % of his paycheck on car repairs
⇒ 12% of P = 12P/100
And he spent 25 % of the remainder on food.
⇒ 0.25(88/100)P
He gave $ 1,320 of the remaining money to his parents
⇒ 1320
If the usual price of the computer was $ 825 and the discount was 20 %
⇒ 825 - 0.20(825) = 660
P = 12P/100 + 0.25(88/100)P + 1320 + 660
P - 34P/100 = 1980
100P - 66P = 198000
P = 3000
Hence, Nate had $3000 at the beginning.
Learn more about the percentages here:
brainly.com/question/24159063
#SPJ2
giving the funtions f(x)=2x-5 and g(x)=3x2=2 perform the indicated operation
Answer:3165
Step-by-step explanation:
Find the gcf for…………….
Chukwu, Abdul and kunle are to share $142, such that Abdul gets $11.00 less than Chukwu and $7.00 more than Kunle. How much is Chukwu's share?
Answer:
Chukwu's share is of $57.
Step-by-step explanation:
This question is solved by a system of equations.
I am going to say that:
Chukwu's share is x.
Abdul's share is y.
Kunle's share is z.
Chukwu, Abdul and kunle are to share $142
This means that [tex]x + y + z = 142[/tex]
Abdul gets $11.00 less than Chukwu
This means that:
[tex]y = x - 11[/tex]
$7.00 more than Kunle.
This means that:
[tex]y = z + 7[/tex]
So
[tex]z = y - 7[/tex]
[tex]z = x - 11 - 7[/tex]
[tex]z = x - 18[/tex]
How much is Chukwu's share?
We want to find x, so:
[tex]x + y + z = 142[/tex]
[tex]x + x - 11 + x - 18 = 142[/tex]
[tex]3x - 29 = 142[/tex]
[tex]3x = 171[/tex]
[tex]x = \frac{171}{3}[/tex]
[tex]x = 57[/tex]
Chukwu's share is of $57.
On Sunday Paul earns 20 cents for every newspaper he delivers if Paul receives $6.40 then how many newspapers did he deliver on Sunday
Answer:
32 newspapers
Step-by-step explanation:
6.4 / 0.2 = 32
Answer:
32 papers
Step-by-step explanation:
Take the total amount and divide by .20
6.40 / .20
Multiply the top and bottom by 10
64/2
32
a local community college has 860 students. Of these 860 students, 220 ride bicycles. Write the number of bike riders as a fraction of the number of students at the college in simplest form
Answer:
11/43
Step-by-step explanation:
A local community college has 860 students
Out of this 860 students, 220students ride bikes
Therefore the fraction of bike riders to the number of students can be calculated as follows
= 220/860
= 11/43
What is 2f+4f + 2-3 evaluated at f= 3?
|
Answer:
17
Step-by-step explanation:
2f + 4f + 2 - 3 when f = 3
1) first we multiply 3 wherever f is
2 x 3 + 4 x 3 + 2 - 3 (solve)
6 + 12 + 2 - 3
18 + 2 - 3
20 - 3
17
Answer:
6+12+2-3=17
Step-by-step explanation:
One of the legs of a right triangle measures 9 cm and the other leg measures 2 cm. Find the measure of the hypotenuse. If necessary, round to the nearest tenth.
Answer:
Approximately 9.2
Step-by-step explanation:
For right triangle, if you know 2 sides, you can find the third using pythagorean theorem, a^2 + b^2 = c^2. 'a' and 'b' are the lengths of the legs, while 'c' is the hypotenuse. You can plug in what you know into this formula:
9^2 + 2^2 = c^2
81+4 = c^2
c = √85, or approximately 9.2
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.
Answer:
380
Step-by-step explanation:
This is a bit nasty. It depends on how you read the 20 miles more and what you do with it. The best and most careful way to do it is do it a long way setting up the two equations carefully.
Second day
Let the time travelled = t
Let the speed travelled = 60 mph
d2 = 60*t
First Day
40*(t + 2) = d1
but d1 = d2 + 20 because he travelled 20 miles further on d1
40 * (t + 2) = d2 + 20
d2 however = 60*t
40*(t+2 ) = 60*t + 20 Remove the brackets
40t + 80 = 60t + 20 Subtract 20 from both sides
40t + 60 = 60t Subtract 40t from both sides
60 = 20*t Divide by 20
t = 60/20
t = 3 hours.
Day 2 = 60 + t = 180
Day 1 = 40*5 = 200
Total distance = 380
Where did that 20 miles go? It was just an observation about the difference in distance travelled between the 2 days.
The total distance the driver traveled in the two days is 260 miles
From the question, on the first day, the driver was going as a speed of 40 mph.
Let s be speed
∴ [tex]s_{1}= 40mph[/tex]
On the second day, he increased the speed to 60 mph
∴ [tex]s_{2}= 60mph[/tex]
From the statement- If he drove 2 more hours on the first day
Let time be t
Then
[tex]t_{1}= t_{2} + 2[/tex] hrs
and traveled 20 more miles
Let d be distance
Then,
[tex]d_{1}= d_{2} + 20[/tex] miles
From the formula
Distance = Speed × Time
Then,
[tex]d = s \times t[/tex]
∴ [tex]d_{1} = s_{1} \times t_{1}[/tex]
From above,
[tex]d_{1}= d_{2}+20[/tex] miles
[tex]s_{1}= 40mph[/tex]
[tex]t_{1}= t_{2} + 2[/tex] hrs
Putting these into
[tex]d_{1} = s_{1} \times t_{1}[/tex]
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex] ...... (1)
But,
[tex]Time = \frac{Distance}{Speed}[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{s_{2} }[/tex]
From above, [tex]s_{2}= 60mph[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{60}[/tex]
Put this into equation (1)
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex]
[tex]d_{2} + 20 = 40\times (\frac{d_{2}}{60} +2)[/tex]
[tex]d_{2} + 20 = \frac{2}{3}d_{2} +80\\d_{2} = \frac{2}{3}d_{2} +80-20\\d_{2} = \frac{2}{3}d_{2} +60[/tex]
Multiply through by 3
[tex]3\times d_{2} = 3\times \frac{2}{3}d_{2} +3 \times 60\\3d_{2} = 2d_{2} + 120\\3d_{2} -2d_{2} = 120[/tex]
∴ [tex]d_{2} = 120[/tex] miles
∴The distance traveled on the second day is 120 miles
For the distance traveled on the first day,
Substitute [tex]d_{2}[/tex] into the equation
[tex]d_{1}= d_{2}+20[/tex] miles
∴ [tex]d_{1}= 120+20[/tex]
[tex]d_{1}= 140[/tex] miles
∴ The distance traveled on the first day is 140 miles
The total distance traveled in the two days = [tex]d_{1} + d_{2}[/tex]
The total distance traveled in the two days = 120 miles + 140 miles
The total distance traveled in the two days = 260 miles
Hence, the total distance the driver traveled in the two days is 260 miles
Learn more here: https://brainly.com/question/23531710
What is the distance from the plane
Answer:
here's the answer to your question about
find the missing side lengths
Answer:
b = 2√3
a = 4
Step-by-step explanation:
Here taking 60 as reference angle
so
tan60 = p/b
[tex]\sqrt{3}[/tex] = p/2
so p = 2√3
so
b = 2√3
so
[tex]h^2 = p^2 + b^2\\h^2 = (2\sqrt{3})^2 + 2^2\\h^2 = 12 + 4\\h^2 = 16\\h = \sqrt{16} \\h = 4[/tex]
a = 4
A=E
BCE=90
BF=AC
AC=EC
==========================================================
Explanation:
HL stands for Hypotenuse Leg. This rule works only for right triangles.
So we must have two hypotenuses that are congruent, and we must have two legs that are congruent
The diagram shows that AB = DE are the congruent hypotenuses. So we have "H" taken care of. We just need the "L" portion.
We can see that only choice D works, which is AC = EC. If we knew that AC and EC were the congruent legs, then we have enough info to use HL.
please help! i have no idea
Answer:
θ = 51.7
SOH-CAH-TOA
CAH: COS = ADJ/HYP cos(θ) = 19.4/29.3
θ = 48.5
93.2 + 48.5 + x = 180
x = 38.3
90 + 38.3 + θ = 180
θ = 51.7
Step-by-step explanation:
Please help solve x and round all answers to the nearest tenth
4x+3=x+9
What is the number?
X=?
Answer:x=3
Step-by-step explanation:
4x+3=x+9
4x-x=(-3)+9
3x=6
x=6:3
x=2
Guys please help me solve this its so stressful
Answer:
Given:- [tex]y=-5x^3+10x+20[/tex]
A parabola attain maximum height at the vertex: formula to find x-coordinate of vertex is, [tex]x=-\frac{b}{2a}[/tex]
plug in a=-5 and b=10
so, [tex]x=-\frac{10}{2(-5)} =-\frac{10}{-10} =1[/tex]
Now plug in x=1 to get maximum height,
[tex]y=-5(-1)^2+10(1)+20[/tex]
[tex]=-5+10+20[/tex]
[tex]=+25[/tex]
so, maximum heigh reached by the rocket was 25 yards
Rocket will hit the ground when y=0
[tex]0=-5x^2+10x+20[/tex]
[tex]0=-5(x^2-2x-4)[/tex]
[tex]\frac{0}{-5} =\frac{-5}{-5} (x^2-2x-4)[/tex]
So, [tex]x^2-2x-4=0[/tex]
quadratic formula is,
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
plug in a=1, b=-2,and c=-4
[tex]x=-\frac{(-2)=-\sqrt{(-2)^2-4(1)(-4)} }{2(1)}[/tex]
[tex]=\frac{2=-\sqrt{4+16} }{2}[/tex]
[tex]=\frac{2+-\sqrt{20} }{2}[/tex]
[tex]=\frac{2+-2\sqrt{5} }{2}[/tex]
[tex]=1+-\sqrt{5}[/tex]
[tex]=1-\sqrt{5} ,1+\sqrt{5}[/tex]
[tex]=1-5.236,1+2.236[/tex]
[tex]=-1.236,3.236[/tex]
So, it takes 3.2 seconds to hit the ground.
OAmalOHopeO
Write an expression for the area of the square below.
4x + 2
A. 8x2 + 16x + 4
B. 16x2 + 16x + 4
C. 8x + 4
D. 16x2 + 6x + 4
Help
Area = Side^2
Area =( 4x + 2 )^2
Area = (4x)^2 + 2(4x)(2) + (2)^2
Area = 16x^2 + 16x + 4
Thus the correct answer is option B .
What is the answer of 2x5
pls help
#im really bad at math
Answer:
10
Step-by-step explanation:
ans is 10
because 2×5 is 10
Answer:
2x5= 10
Step-by-step explanation:
5, 10,15,20
five 2 times is 10
Hay 31 estudiantes en una clase. Ocho (8) estudiantes miden más de 6 pies de altura. Diecisiete (17) estudiantes miden 5-6 "a 6'-0" de altura. Seis (6) estudiantes miden menos de 5-2". ¿Cuál es la razón entre el número de estudiantes de menos de 5'-2" y el número de estudiantes de más de 6 'de altura?
Answer:
4/3
Step-by-step explanation:
The diameter of the circle above is 18 cm. What is the circumference of the circle? (Use = 3.14.)
Answer:
56.57
Step-by-step explanation:
See attached photo for steps
EDIT: I forgot to add 3.14, I am so sorry
Answer:
56.52
Step-by-step explanation:
Which answer shows 0.05 written in scientific notation?
Answer:
5x10^-2 option B
Step-by-step explanation:
Answer:
5x10^-2
the second one.
Indicate in standard form the equation of the line through the given points, writing the answer in the equation box below.
K(6, 4), L(-6, 4)
9514 1404 393
Answer:
y = 4
Step-by-step explanation:
The given points are on the horizontal line ...
y = 4
This is the standard-form equation of that line.
Graph the line that passes through (5, 5), and is perpendicular to a line whose slope is –2.
Answer:
y = 1/2x + 5/2
Step-by-step explanation:
y = 1/2x + b
5 = 1/2(5) + b
5 = 5/2 + b
5/2 = b
