Simplify the problem below and write in standard
form:
–725 + 8x3 – 6x2 – 10x3 – 9
-7x5

Answer:

64.7 when rounded up to one decimal place

Step-by-step explanation:

Answer: y = x + 5

Step-by-step explanation:

Answer:

t = 2.4n

Step-by-step explanation:

y = mx + c

t = mn + c

c = y-intercept (where the graph line crosses the cost line)

c = 0

mx/mn= gradient ( rise/run, up/across)

mn= 12/5 ( you could have picked any point in the graph )

mn= 2.4

the m is unnecessary now so we discard it

t = 2.4n + 0

Answer: x = 2

Step-by-step explanation:

And thats how you get the answer!

the domain is

[tex]x \geqslant - 6[/tex]

Answer:

637

Step-by-step explanation:

rectangle =

12*16*2 = 384

triangle = 12*16/2

= 96

semi circle = pie*hyp^2/2

= pie * (sqrt(12^2+16^2))^2/2

=157

Answer:

Top right (one what has 16cm^2 and 9cm^2)

Step-by-step explanation:

The one in the top right and even though I cannot see what the area is of the biggest square, I can tell what it should be the two smaller squares combined

Hope this helps :)

Answer:

962

Step-by-step explanation:

MMM for step by step its kinda just plug and check

962/3 = 320 R2

962/6 = 160 R2

962/8 = 120 R2

962/10 = 96 R2

962/12 = 80 R2

and finally 962/13 = 74

have a government

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Step-by-step explanation:

yan napo lahat answer

Answer:

18+3b-2b-1

b+17

Step-by-step explanation:

[tex]\mathrm{Using\:the\:distributive\:law}:\quad \:-\left(a+b\right)=-a-b[/tex]

[tex]-\left(2b+1\right)=-2b-1[/tex]

[tex]=3\left(6+b\right)-2b-1[/tex]

[tex]=18+3b-2b-1[/tex]

[tex]\mathrm{Group\:like\:terms}[/tex]

[tex]=3b-2b+18-1[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:18-1=17[/tex]

[tex]=3b-2b+17[/tex]

[tex]\mathrm{Add\:similar\:terms:}\:3b-2b=b[/tex]

[tex]=b+17[/tex]

[RevyBreeze]

Answer:

second option is correct onee

Step-by-step explanation:

mark me brainliest

Answer:

2y² + 12y + 18

Step-by-step explanation:

2(y + 3)²

First use formula (a + b)² = a² + 2ab + b² to expand (y + 3)²:

(a + b)²

(y + 3)²

y² + 2*y*3 + 3²

y² + 6y + 9

Dont forget the 2:

2(y² + 6y + 9) <== distribute and multiply

2y² + 12y + 18

Hope this helps!

Answer:

6) 152.6

7) 348.4

Step-by-step explanation:

For question number 6, calculate the surface area of the two triangles first. And then, calculate each of the surface area for the rectangles. Finally, total up the area of the two triangles and the rectangles.

[tex](6.6 \times 9) + (4 \times 9) + (5.2 \times 9) \times (\frac{1}{2} \times 5.2 \times 4) = 152.6[/tex]

For question number 7, given that the area of a triangle is 28.4. Hence calculate the area of the three rectangles. Lastly, total up the area of two triangles and three rectangles.

[tex]28.4 + 28.4 + 3(12 \times 8.1) = 348.4[/tex]

Hope this helps =)

Answer:

Step-by-step explanation:

Complementary angles add to 90 degrees, so the measure of its complement is 90-88=2 degrees.

Supplementary angles add to 180 degrees, so the measure of its supplement is 180-88=92 degrees.

[tex]\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\ \\\\~~~~~~~=\dfrac{3}{\sqrt{3^2 +2^2}}~~~~~~~;[\text{Pythagorean theorem.}]\\\\\\~~~~~~~=\dfrac{3}{\sqrt{9+4}}\\\\\\~~~~~~~=\dfrac{3}{\sqrt{13}}[/tex]

Circular equations are often organized in the following form:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

To find the equation of a circle given its center and a point:

We're given:

Plug the center into the general equation:

[tex](x-(-7))^2+(y-7)^2=r^2\\(x+7)^2+(y-7)^2=r^2[/tex]

Plug in the given point (-2,-5) and find r²:

[tex]((-2)+7)^2+((-5)-7)^2=r^2\\(5)^2+(-12)^2=r^2\\25+144=r^2\\r^2=169[/tex]

Plug the center and radius back into the original equation:

[tex](x-h)^2+(y-k)^2=169\\(x+7)^2+(y-7)^2=169[/tex]

[tex](x+7)^2+(y-7)^2=169[/tex]

Answer: 300 cents and/or pennies

Step-by-step explanation:

Answer:

a. 0.8727rad

b. 5.585rad

that should be correct, if not, i apologize T_T

Answer:

10.48 miles.

Step-by-step explanation:

That is 4/5 * 13.1

= 10.48 miles.

Answer:

1. Not statistical

2. Statistical

3. Not statistical

Answer:

lol cant belive he could lie like that- anyways here is half the test since you can only post 5 pictures

Step-by-step explanation:

Answer: C

Step-by-step explanation:

[tex]\left(2x+3\right)\left(x+5\right)[/tex]

[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]

[tex]=2xx+2x\cdot \:5+3x+3\cdot \:5[/tex]

[tex]$$Simplify[/tex]

[tex]=2x^2+13x+15[/tex]

Answer:

C. No, because the sides aren't congruent

Step-by-step explanation:

Here is your Answer:

3/4

Answer:

Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own. But these things will change direction of the inequality: Multiplying or dividing both sides by a negative number. Swapping left and right hand.JUST FOLLOW THE TEXT TO GET THE ANSWER OF THE INEQUALITY ×>5

There are three values of x where the instantaneous rate of change of f(x) are equal in the open and closed intervals

The function is given as:

[tex]f(x) = \frac 14x^4 - \frac 23x^3 + \frac 12x^2 - \frac 12x[/tex]

Calculate f(0)

[tex]f(0) = \frac 14 * 0^4 - \frac 23 * 0^3 + \frac 12 *0^2 - \frac 12 * 0[/tex]

[tex]f(0) = 0[/tex]

Calculate f(1.565)

[tex]f(1.565) = \frac 14 * 1.565^4 - \frac 23 * 1.565^3 + \frac 12 *1.565^2 - \frac 12 * 1.565[/tex]

[tex]f(1.565) = -0.613[/tex]

The average rate of change is then calculated using:

[tex]m = \frac{f(1.565) - f(0)}{1.565 - 0}[/tex]

This gives

[tex]m = \frac{-0.613 - 0}{1.565 - 0}[/tex]

[tex]m = -0.392[/tex]

Differentiate the function f(x)

[tex]f'(x) = x^3 - 2x^2 + x - \frac 12[/tex]

Set f'(x) to [tex]m = -0.392[/tex]

[tex]x^3 - 2x^2 + x - \frac 12 = -0.392[/tex]

From the graph of the above equation (see attachment), we have three values of x at:

x = 0.1492, x = 0.5614 and x = 1.2894

Hence, there are three values of x in the open interval (0,1.565)

Read more about instantaneous rate at:

https://brainly.com/question/24592593

Answer:

Multiply both sides by 3

Step-by-step explanation:

x/3 = 5

x/3 × 3 = 5×3

x = 15

Answer:

multipy both sides  by 3

Step-by-step explanation:

let's firstly convert the mixed fractio to improper fraction.

[tex]\stackrel{mixed}{3\frac{1}{6}}\implies \cfrac{3\cdot 6+1}{6}\implies \stackrel{improper}{\cfrac{19}{6}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{ccll} Km s&Hour\\ \cline{1-2} \frac{19}{6}&\frac{1}{4}\\[1em] x&1 \end{array}\implies \cfrac{~~ \frac{19}{6}~~}{x}~~ = ~~\cfrac{~~ \frac{1}{4}~~}{1}\implies \cfrac{~~ \frac{19}{6}~~}{\frac{x}{1}}=\cfrac{1}{4}\implies \cfrac{19}{6}\cdot \cfrac{1}{x}=\cfrac{1}{4} \\\\\\ \cfrac{19}{6x}=\cfrac{1}{4}\implies 76=6x\implies \cfrac{76}{6}=x\implies \cfrac{38}{3}=x\implies 12\frac{2}{3}=x[/tex]