Select the correct answer.
As part of a class project, a university student surveyed the students in the cafeteria lunch line to look for a relationship between eye color and hair color among students. The table below contains the results of the survey.

Select The Correct Answer.As Part Of A Class Project, A University Student Surveyed The Students In The

Answers

Answer 1

Answer: Choice B)  0.27

=========================================================

Explanation:

There are a lot of data values here, and it's possible to easily get lost in them. However, we're asked only about students with blond hair. So we only focus on the first row. Ignore everything else.

We see that there are 78 of these students total. Of this total, 21 have green eyes.

Therefore, the relative frequency of blonds with green eyes is 21/78 = 0.2692 which rounds to 0.27; so that's why the answer is choice B.


Related Questions

For Coronado Industries, sales is $500000, variable expenses are $335000, and fixed expenses are $140000. Coronado’s contribution margin ratio is

a) 67%.
b) 33%.
c) 28%.
d) 5%.

Answers

the right answer would be C

g(x) = f(x+1) using f(x)= x to the power of 2

Answers

Answer:

g(x) = x² + 2x + 1

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding

Functions

Function Notation

Step-by-step explanation:

Step 1: Define

Identify

g(x) = f(x + 1)

f(x) = x²

Step 2: Find

Substitute in x [Function f(x)]:                                                                           f(x + 1) = (x + 1)²Expand:                                                                                                             f(x + 1) = x² + 2x + 1Redefine:                                                                                                           g(x) = x² + 2x + 1

Can someone help me find the answer?

Answers

Answer: B. This function has no intercept. I think B is the correct answer.

A company that manufactures and bottles apple juice uses a machine that automatically fills 32-ounce bottles. There is some variation, however, in the amount of liquid dispensed into the bottles. The amount dispensed has been observed to be approximately normally distributed with mean 32 ounces and standard deviation 1 ounce. Determine the proportion of bottles that will have more than 30 ounces dispensed into them. (Round your answer to four decimal places.)

Answers

Answer:

The proportion of bottles that will have more than 30 ounces dispensed into them is 0.9772 = 97.72%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The amount dispensed has been observed to be approximately normally distributed with mean 32 ounces and standard deviation 1 ounce.

This means that [tex]\mu = 32, \sigma = 1[/tex]

Determine the proportion of bottles that will have more than 30 ounces dispensed into them.

This is 1 subtracted by the p-value of Z when X = 30, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 32}{1}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228.

1 - 0.0228 = 0.9772

The proportion of bottles that will have more than 30 ounces dispensed into them is 0.9772 = 97.72%.

A car travels 630 miles in 14 hours. At this rate, how far will it travel in 42 hours?

Answers

Assuming the car's speed [tex]\frac{630}{14}=45\mathrm{mph}[/tex] does not change, the car will travel [tex]45\cdot42=\boxed{1890}[/tex] miles.

Hope this helps :)

help with q25 please. Thanks.​

Answers

First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

Let's apply the first derivative of this f(x) function.

[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]

Now apply the derivative to that to get the second derivative

[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]

We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.

Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.

-----------------------------------

Let's compute dy/dx. We'll use f(x) as defined earlier.

[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]

Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

Now use the quotient rule to find the second derivative of y

[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]

If you need a refresher on the quotient rule, then

[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]

where P and Q are functions of x.

-----------------------------------

This then means

[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]

Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

------------------------------------

Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]

So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]

Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 83 months with a variance of 81. If the claim is true, what is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors? Round your answer to four decimal places.

Answers

Answer:

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The production manager claims they have a mean life of 83 months with a variance of 81.

This means that [tex]\mu = 83, \sigma = \sqrt{81} = 9[/tex]

Sample of 146:

This means that [tex]n = 146, s = \frac{9}{\sqrt{146}}[/tex]

What is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors?

This is 1 subtracted by the p-value of Z when X = 81.2. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{81.2 - 83}{\frac{9}{\sqrt{146}}}[/tex]

[tex]Z = -2.42[/tex]

[tex]Z = -2.42[/tex] has a p-value of 0.0078.

1 - 0.0078 = 0.9922.

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

An F test for the two coefficients of promotional expenditures and district potential is performed. The hypotheses are H0: 1 = 4 = 0 versus Ha: at least one of the j is not 0. The F statistic for this test is 1.482 with 2 and 21 degrees of freedom. What can we say about the P-value for this test?

Answers

Answer:

Pvalue > 0.10

Step-by-step explanation:

Given the hypothesis :

H0 : β1 = β4 = 0

H1 : Atleast one of βj is not 0

F statistic = 1.482 ;

Degree of freedom = 2 and 21 ;

DFnumerator = 2

DFdenominator = 21

Using the Pvalue calculator from Fstatistic ;

Pvalue(1.482, 2, 21) = 0.24999 = 0.25

Hence, Pvalue for the test is 0.25

Pvalue > 0.10

Out of a total of 10 college textbooks estimate the standard deviation of their ages if the oldest textbook is known to be 7.9 years old and the newest textbook is 1.3 years old.

Answers

Answer:

Given that the maximum age of the textbook is 7.9 years and the minimum age of the textbook is 1.3 years.

Using the range rule, the standard deviation is estimated as,

S≈maximum−minimum/4

=7.9−1.3/4

=1.65

The required value of the approximate standard deviation is 1.65.

The standard deviation of the data is 1.65.

What is Standard Deviation?

Standard deviation is the measure of the deviation of the data from the mean.

The total college textbooks is 10

The oldest book is 7.9 years old

The newest book is 1.3 years old

The standard deviation of range is equal to one fourth of the difference of maximum to minimum.

The standard deviation = ( 7.9 - 1.3 ) /4 = 1.65

To know more about Standard Deviation

https://brainly.com/question/14747159

#SPJ5


Write 6/7 as a decimal rounded to the nearest hundredth

Answers

Answer:

0.01

Step-by-step explanation:

6/7% = 6÷7÷100 = 0.0085714286 round to the nearest hundredth = 0.01

a) __m=10km 25m =___km

b) __m=__km__m=1.5 km

Example :
a) 7250m= 7km 250m = 7.250km


Please help me

Answers

Answer:

a) 10,025 m = 10km 25m = 10.025 km

b) 1,500 m = 1 km 500 m = 1.5 km

Answer:

a) 10025m = 10km 25m = 10.025km

b) 1500m = 1km 500m = 1.5km

Step-by-step explanation:

Concept:

Here, we need to know the idea of unit conversion.

Unit conversion is the conversion between different units of measurement for the same quantity.

1 km = 1000 m

Solve:

a)

10km 25m = 10×1000 + 25 = 10025 m10km 25m = 10 + 25/1000 = 10.025 km

b)

1.5km = 1 + 0.5 × 1000 = 1km 500m1.5km = 1.5 × 1000 = 1500m

Hope this helps!! :)

Please let me know if you have any questions

A boat travels 400 kilometers in 9.6 hours (with a constant speed). How much time will it take to travel 138 kilometers? (round to the nearest tenth of an hour)

Answers

Step-by-step explanation:

here's the answer to your question

Find the length of the arc round your answer to the nearest 10th

Answers

Answer:

45

Step-by-step explanation:

The length of the arc is equal to the central angle it sees.

You pay $1.25 per pound for x pounds of apples?

Answers

Answer:

$1.25x

Step-by-step explanation:

Given :

Cost per pound = $1.25

Number of pounds of apple = x

The total cost of apple = (cost per pound * number of apple in pounds)

Hence,

Total cost of x pounds of apple is :

($1.25 * x)

= $1.25x

In the Data Analysis portion of the article the authors report that they completed a power analysis to determine the power of their study with the sample size utilized. They report a power of 90%. What does this mean

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

The power of a test simply gives the probability of Rejecting the Null hypothesis, H0 in a statistical analysis given that the the alternative hypothesis, H1 for the study is true. Hence, the power of a test can be referred to as the probability of a true positive outcome in an experiment.

Using this definition, a power of 90% simply means that ; there is a 90% probability that the a Pvalue less Than the α - value of an experiment is obtained if there is truly a significant difference. Hence, a 90% chance of Rejecting the Null hypothesis if truly the alternative hypothesis is true.

Find the value of x.

Answers

Answer:

x=3

Step-by-step explanation:

Find the radius and use Pythagoras on the right side

Ray’s weight increased by 11% in the last two years. If he gained 16.5 pounds, what was his weight two years ago?

Answers

2 years ago he weighed 119.5 pounds

Graph the linear equation by find
2 = 4x + y

Answers

2=4x+y

y=2-4x

Александр Мазепов

Step-by-step explanation:

Step 1:  Solve for y

[tex]2 = 4x + y[/tex]

[tex]2 - 4x = 4x + y - 4x[/tex]

[tex]y = 2 - 4x[/tex]

Step 2:  Solve for x

[tex]2 - 2 - 4x = 0 - 2[/tex]

[tex]-4x / -4 = -2 / -4[/tex]

[tex]x = 1/2[/tex]

Step 3:  Solve for y

[tex]y = 2 - 4(0)[/tex]

[tex]y = 2[/tex]

Step 4:  Graph the equation

Graph the x-intercept, (1/2, 0), the y-intercept, (0, 2) and draw a line between them.  Look at the attached picture for the graph:

I need help with that, if you can, plz. I ty it I think is a not sure

Answers

Answer:

-5≤x <1

Step-by-step explanation:

sqrt( x+5) / sqrt(1-x)

The numerator must be greater than zero since it is a square root

sqrt(x+5) ≥0

Square each side

x+5≥0

x≥-5

The denominator must be greater than zero (the denominator cannot be zero)

sqrt(1-x)> 0

Square each side

1-x > 0

1>x

Putting these together

-5≤x <1

A rectangular floor is 20 feet long and 16 feet broad. if it is to be paved with squared marbles of same size,find the greatest length of each squared marbles.​

Answers

Answer:

4 ft

Step-by-step explanation:

I guess, the meaning is the largest marbles, so that we can pave the whole floor without cutting any marbles and leaving empty spots.

so, 20×16 ft²

we can have marbles 1/2 ft long. and it all fits well : 40×32 marbles.

we can have them 1 ft long, and it all fits well : 20×16 marbles.

we can have them 2ft long, and it still fits well : 10×8 marbles.

and so on.

so, actually, we are looking for the greatest common divisor (GCD) of 20 and 16. and that gives us the maximum length of a single marble to fulfill the requirement.

let's go for the prime factors starting with 2

20/2 = 10

10/2 = 5

5/3 fits not work

5/5 = 1 done

so, 20 = 2²×3⁰×5¹

16/2 = 8

8/2 = 4

4/2 = 2

2/2 = 1 done

16 = 2⁴

so, for the GCD I can only use powers of 2 (the only prime factors both numbers have in common).

and we have to use the smaller power of 2, which is 2, so, the GCD is 2² = 4

=>

the maximum length of the squared marbles is 4 ft.

that would pave the floor with 5×4 marbles completely.

I want to know how to solve this equation

Answers

Answer:

your answer will be Option D

Step-by-step explanation:

log 10

Two numbers total 31 and have a difference of 11. Find the two numbers

Answers

Answer:

let 2 no. be x and y

x+y=31 ..... (1)

x-y=11 .........(2)

from (1)

x=31-y ..........(3)

putting (3) in (2)

31-y-y=11

-2y=11-31

-2y=-20

2y=20

y=10

31 -11 = 20
20 + 11 = 31
The Two numbers are 20 & 11

21. SCALE FACTOR A regular nonagon has an area of 90 square feet. A similar
nonagon has an area of 25 square feet. What is the ratio of the perimeters of
the first nonagon to the second?

Answers

Answer:

The ratio of the perimeters of the first nonagon to the second is 3.6 to 1.

Step-by-step explanation:

Given that a regular nonagon has an area of 90 square feet, and a similar nonagon has an area of 25 square feet, to determine what is the ratio of the perimeters of the first nonagon to the second, the following calculation must be performed:

25 = 1

90 = X

90/25 = X

3.6 = X

Therefore, the ratio of the perimeters of the first nonagon to the second is 3.6 to 1.

According to Fidelity Investment Vision Magazine, the average weekly allowance of children varies directly as their grade level. In a recent year, the average allowance of a 9th-grade student was 9.66 dollars per week. What was the average weekly allowance of a 5 th-grade student?​

Answers

The average weekly allowance of a 5th grade student as calculated using direct variation with the information provided by Fidelity Investment Vision Magazine is 5.367 dollars per week.

The question given is a direct variation problem:

Let:

Average weekly allowance = [tex]a[/tex]

• Grade level = [tex]g[/tex]

If Average weekly allowance varies directly as grade level , then , then the direct variation between the variables can be expressed as :

[tex]a = k * g[/tex]

Where ,  [tex]k[/tex] = constant of proportionality

We can obtain the value of k from the given values of a and g

[tex]9.66 = k * 9\\9.66 = 9k\\k = 9.66/9[/tex]

Our equation becomes:

[tex]a = (9.66/9) * g[/tex]

[tex]a = (9.66/9) * 5\\a = 5.367[/tex] (rounded to 3 decimal places)

Hence, using proportional relationship, the average weekly allowance for a 5th grade student is [tex]5.367[/tex] per week

Learn more about direct variation here:

https://brainly.com/question/17257139

What is the value of the capacitance of a capacitor that stores 40
μ
C on each plate, when a potential difference of 10 V is applied to it?

Answers

Charge=Q=40uCPotential difference=V=10VCapacitance=C=?

We know

[tex]\boxed{\sf Q=CV}[/tex]

[tex]\\ \large\sf\longmapsto C=\dfrac{Q}{V}[/tex]

[tex]\\ \large\sf\longmapsto C=\dfrac{40}{10}[/tex]

[tex]\\ \large\sf\longmapsto C=4\mu F[/tex]

The manager of a juice bottling factory is considering installing a new juice bottling machine which she hopes will reduce the amount of variation in the volumes of juice dispensed into 8-fluid-ounce bottles. Random samples of 10 bottles filled by the old machine and 9 bottles filled by the new machine yielded the following volumes of juice (in fluid ounces).

Old machine: 8.2, 8.0, 7.9, 7.9, 8.5, 7.9, 8.1,8.1, 8.2, 7.9
New machine: 8.0, 8.1, 8.0, 8.1, 7.9, 8.0, 7.9, 8.0, 8.1

Required:
Use a 0.05 significance level to test the claim that the volumes of juice filled by the old machine vary more than the volumes of juice filled by the new machine

Answers

Answer:

Reject H0 and conclude that volume filled by old machine varies more than volume filled by new machine

Step-by-step explanation:

Given the data:

Old machine: 8.2, 8.0, 7.9, 7.9, 8.5, 7.9, 8.1,8.1, 8.2, 7.9

New machine: 8.0, 8.1, 8.0, 8.1, 7.9, 8.0, 7.9, 8.0, 8.1

To test if volume filled by old machine varies more than volume filled by new machine :

Hypothesis :

H0 : s1² = s2²

H1 : s1² > s2²

Using calculator :

Sample size, n and variance of each machine is :

Old machine :

s1² = 0.37889

n = 10

New machine :

s2² = 0.006111

n = 9

Using the Ftest :

Ftest statistic = larger sample variance / smaller sample variance

Ftest statistic = 0.37889 / 0.006111

Ftest statistic = 62.001

Decision region :

Reject H0 ; If Test statistic > Critical value

The FCritical value at 0.05

DFnumerator = 10 - 1 = 9

DFdenominator = 9 - 1 = 8

Fcritical(0.05, 9, 8) = 3.388

Since 62 > 3.388 ; Reject H0 and conclude that volume filled by old machine varies more than volume filled by new machine

I NEED HELP ASAP, I DON'T UNDERSTAND THIS PROBLEM!!!!!

Answers

Answer:

1

Step-by-step explanation:

Cosine is a trigonometric function that is represented by adjacent divided by the hypotenuse. The side adjacent to angle A is AC and the hypotenuse is AB, so we can say cos(A) = [tex]\frac{AC}{AB}[/tex]. We can do the same for angle B. The side adjacent to it is BC, and the hypotenuse is again AB. So, we can say

cos(B) = [tex]\frac{BC}{AB}[/tex]. We are solving for [tex]\frac{cosA}{cosB}[/tex], so we can substitute the value of those two and solve:

[tex]\frac{\frac{AC}{AB}}{\frac{BC}{AB} }[/tex]

[tex]\frac{AC}{AB} * \frac{AB}{BC} = \frac{AC}{BC}[/tex]

AC is given to be 3 and BC is also 3, so [tex]\frac{AC}{BC}[/tex] is [tex]\frac{3}{3}[/tex] which is just 1.

If p is true and ~ q is false, then p ~ q is _____ false.
a. sometimes
b. always
c. never

Answers

Vas happenin
Hope you having a good day
I think it’s A
Hope this help *smiles*

can anybody help with this ?

Answers

Answer:(

fx).(gx)=D. -40x^3+25x^2+45

Step-by-step explanation:

How many women must be randomly selected to estimate the mean weight of women in one age group? We want 90% confidence that the sample mean is within 3.7 lbs of the populations mean, and population standard deviation is known to be 28 lbs.

Answers

Answer:

155 women must be randomly selected.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The population standard deviation is known to be 28 lbs.

This means that [tex]\sigma = 28[/tex]

We want 90% confidence that the sample mean is within 3.7 lbs of the populations mean. How many women must be sampled?

This is n for which M = 3.7. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]3.7 = 1.645\frac{28}{\sqrt{n}}[/tex]

[tex]3.7\sqrt{n} = 1.645*28[/tex]

[tex]\sqrt{n} = \frac{1.645*28}{3.7}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645*28}{3.7})^2[/tex]

[tex]n = 154.97[/tex]

Rounding up:

155 women must be randomly selected.

Other Questions
What is 4 times the sum of g and p A monkey is swinging from a tree. On the first swing, she passes through an arc of 10 m. With each swing, she passes through an arc 9/10 the length of the previous swing.What is the total distance the monkey has traveled when she completes her 25th swing? Round your final answer to the nearest meter. Variable costs as a percentage of sales for Lemon Inc. are 71%, current sales are $551,000, and fixed costs are $207,000. How much will operating income change if sales increase by $37,600? a.$10,904 increase b.$26,696 decrease c.$26,696 increase d.$10,904 decrease As water is cooled from 4 C to 0 C, its densityA. stays the sameB. decreases and increasesC. increasesD. decreases Concrete is made by mixing screenings cement and sand in the ratio 3:1:15. How much sand would be needed to make 125 tonnes of concrete? The development of the modern computer system has been evolutionary. Discuss this phenomenon and further discuss how current trends in computing would impact future computer systems development. 11. The coordinates of AABC are A(-1,1), B(3,3),and C(4, -2). Find the coordinates of points A', B',and C' under the translations that takea. P(0,0) to Q(1,3)b. P(0, -1) to Q(4,-2) c. P(-1,-2) to Q(-2,2) given: ray FEH bisects what is the level of development not the same everywhere? Women in the United States typically need to consume more of which of the following nutrients? why should we developed good character write any five points suggest three ways in which the physical environment of the city can be adapted to reduce temperatures during the late afternoon 1. Wait a minute, please. The concert ______________ soon.2. When ______________ humans ______________ on the Red Planet?3. OK. At 5 oclock we ______________ you outside the shopping centre.4. They probably ______________me the job. I had a terrible interview.5. Im sorry about losing that book. I ______________ you another one next week.6. ________ you ________ me when you get the news?7. If it doesnt rain tomorrow, we ______________ our umbrellas.8. Turn on your laptop tonight. We ______________ a little bit.9. I______________ them here again, whatever you say.10. I think people ______________ CDs in 20 years time. MC Qu. 149 Trago Company manufactures... Trago Company manufactures a single product and has a JIT policy that ending inventory must equal 30% of the next month's sales. It estimates that May's ending inventory will consist of 85,500 units. June and July sales are estimated to be 285,000 and 295,000 units, respectively. Trago assigns variable overhead at a rate of $2.30 per unit of production. Fixed overhead equals $405,000 per month. Compute the number of units to be produced and use this amount to compute the total budgeted overhead that would appear on the factory overhead budget for the month of June. what quantities will you need to measure to determine the specific heat of one of these liquids? (pivot) According to the Federal Election Commission, 53.6% of all registered voters in 2012 voted in the US presidential elections in 2012. A political study conducted in January 2016 surveyed 1,251 eligible voters and found that 86% said they planned to vote in the 2016 presidential election. Based on this information, match each term to its value.1. 1,251 2. 53.6% 3. 86%a. statistic b. sample size c. parameter discuss any five barries of integrating ict tools in education Four times an angle is equal to half of its supplement. Find the measures of both angles. Your firm is considering a project with a discount rate of 9%. If you start the projecttoday, your firm will incur an initial cost of $490 and will receive cash inflows of$365 per year for 3 years. If you instead wait one year to start the project, the initial cost will rise to $530 and the cash flows will increase to $405 a year for the following 3 years. Would your firm be better off starting the project now or waiting to start the project in a year? Explain clearly including an estimate of the value of the option to wait. How did the kansas- Nebraska act affect the future of kansas