Sadie earns $11.25 per hour. Do her earnings vary inversely or directly with
her number of hours worked? Determine how many hours she worked in a
week if her earnings were $146.25.

The trigonometric function gives the ratio of different sides of a right-angle triangle. The length of the side KL is 30.81 units.

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

The measure of ∠J can be written as,

Cos(∠J) = JK/JL

Cos(∠J) = 7/31.6

∠J = 77.2°

Similarly the length of side KL can be written as,

Tan(∠J) = KL/JK

Tan(77.2°) = KL/7

KL = 30.81 units

Hence, the length of the side KL is 30.81 units.

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The solution to the function [tex]f(x) = 2\sqrt{x - 2}[/tex] when x = 2 is 0

The equation of the function is given as:

[tex]f(x) = 2\sqrt{x - 2}[/tex]

When x = 2, we have:

[tex]f(x) = 2\sqrt{2 - 2}[/tex]

Evaluate the difference

[tex]f(x) = 2\sqrt{0}[/tex]

Evaluate the exponent of 0

f(x) = 2 * 0

Evaluate the product

f(x) = 0

Hence, the solution to the function when x = 2 is 0

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The probability that the spinner will land on a number greater than 4 or on a shaded section is 2/3

The given parameters are:

Using the above parameters, we have the following probabilities

P(Greater than 4) = 2/6

P(Shaded) = 3/6

P(Shaded section and greater than 4) = 1/6

The required probability is then calculated using:

P = 2/6 + 3/6 - 1/6

Evaluate

P = 4/6

Simplify

P = 2/3

Hence, the probability that the spinner will land on a number greater than 4 or on a shaded section is 2/3

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Answer:

Jenny has worked out the area of the whole circle using the formula π × r² where r is the radius length. She has assumed π is 3.14 which leads to her working of 3.14 × 10² = 314 units². She has to divide the total area by 4 to calculate the sector area.

Let's check

Area of sector

Using it's concept, it is found that there is a 0.1087 = 10.87% probability Sung chose a milk chocolate then a white chocolate.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Thus, the probability of milk then white is given by:

[tex]p = \frac{5}{12} \times \frac{6}{23} = \frac{30}{12 \times 23} = 0.1087[/tex]

0.1087 = 10.87% probability Sung chose a milk chocolate then a white chocolate.

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Answer:

$977.20

Step-by-step explanation:

We will use the compound interest formula to solve this: A = P(1 + R) ^ T

Using this formula we plug-in the values that we already have:

A = 880(1 + .0525) ^ 2

Now if we solve this, we end up with 977.20. That is your answer.

Answer:

1 m^2

Step-by-step explanation:

A = W * L

1 * 1 = 1

Answer:

$ 471.78

Step-by-step explanation:

This describes an 'ordinary annuity' ====>   FORMULA:

PV= C [  1-(1+i)^-n / i ]    Looking for C    i = .05/12   n =60   PV = 25000

 plug in the numbers and calculate   C = 471.78

Answer:

126 yellow crayons

Step-by-step explanation:

Finding the number of each of the crayons :

Number of yellow crayons :

Answer:

[tex]\huge{\red{\angle ABC = \boxed{30}\degree}}[/tex]

Step-by-step explanation:

Answer:

  (6x² +4x -20)/(x² +x -3) cm

Step-by-step explanation:

The perimeter of a rectangle is twice the sum of its length and width. Here, length and width are rational functions. The same relation to perimeter applies.

__

  [tex]P = 2(L+W)\\\\P=2\left(\dfrac{2x^2 +3x-5}{x^2+x-3}+\dfrac{x^2-x-5}{x^2+x-3}\right)\qquad\text{use given values for $L$ and $W$}\\\\P=2\left(\dfrac{2x^2+3x-5+x^2-x-5}{x^2+x-3}\right)=\dfrac{2(3x^2 +2x-10)}{x^2+x-3}\\\\P=\dfrac{6x^2+4x-20}{x^2+x-3}\\\\\underline{\ \qquad}\\\\\textsf{It would take $\dfrac{6x^2+4x-20}{x^2+x-3}$ cm of ribbon to go around the package.}[/tex]

Answer:

[tex](x+1)^{2} +4[/tex]

a = 1

b = 4

Step-by-step explanation:

hope this helps!! p.s. i really need brainliest :)

Answer:

4-20(6x-5x)^2+11

(6-5x)^2=11+(-16)

6^2-10x+25=-5

6^2-10x+20

The probability of drawing a head card of diamonds and then a head card of hearts is:

P = 0.003

Here we assume that we have a deck of 52 cards, and we want to find:

P(Head, Diamond AND Head, Heart)

This is the probability of drawing a head of diamonds and then a head of hearts.

Remember that for each suit has 3 head cards, J, Q, and K.

Then for the first card, the probability of getting a head of diamonds is equal to the quotient between the number of cards with these properties (3) and the total number of cards (52).

P = 3/52

Then we need to draw a head of hearts, the probability is computed in the same way, but before we drew a card, so now the total number of cards is 51, so we get:

Q = 3/51

Then the joint probability is:

p = (3/52)*(3/51) = 0.003

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Step-by-step explanation:

We can use long division to solve this

First place a 5 in the tens place, this means we are multiplying 5 by 50. This will subtract 250 from 280, leaving us with 30.

Next place a 6 in the ones place, this means we are multiplying 5 by 6. This will subtract 30 from 30, leaving us with 0.

This means we have found our answer of 56.

Answer:

See explanation

Step-by-step explanation:

Basically, division is just saying "how many numbers would go into this number this many times?" We can break this problem down into 200/5 and 80/5. 200/5 is 40, and 80/5 is 16. 40+16 is 56, so the answer is 56.

(I can elaborate further if needed)

Hope this helps!

Answer:

D is not true.

Step-by-step explanation:

[tex] |4.5| = 4.5[/tex]

[tex] | - 45| = 45[/tex]

[tex]4.5 \leqslant 45[/tex]

Answer:

C neither

the coordinates shows that only the x intercepts are moving not y the line of the graph will be horizontal and straight . it is not a function

Answer:

Yes

Step-by-step explanation:

Euler's Formula for Polyhedrons :

Faces + Vertices = Edges + 2

Given :

Verifying using Euler's Formula :

The given shape is a polyhedron using the Euler's formula.

Polyhedron is defined as the three dimensional shape which consists of flat shapes which are polygons.

Cubes, pyramids are all polyhedrons.

Euler's formula for polyhedron states that,

V - E + F = 2

where V, E and F are the number of vertices, number of edges and the number of faces respectively.

For the given polyhedron,

Number of vertices, V = 6 + 6 = 12

Number of edges, E = 6 + 6 + 6 = 18

Number of faces, F = 1 + 6 + 1 = 8

So, V - E + F = 12 - 18 + 8 = -6 + 8 = 2

Hence the given shape is a polyhedron.

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y=3x+3

Step-by-step explanation:

The m is 3 because it is rise over run. For every 3 up it goes one over (3/1) or just 3. The b is 3 because b is where x equals 0 and it is at 3.

Answer:

10y - 70z + 10.

Step-by-step explanation:

10(y-7z+1)    Multiply each term in the brackets by 10:

= 10y - 70z + 10

The measure of angle DAB in the circle shown with the given arc length is: 2.23 radians.

Arc length = θ × r, where r is the radius of the circle, and θ is the central angle in radians.

Given the following:

Length of arc = 6.47 cm

Radius (r) = 2.9 cm

θ = m∠DAB

Plug in the values into the arc length formula:

6.47 = θ × 2.9

6.47/2.9 = θ

θ = 2.23 radians

m∠DAB = 2.23 radians

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Answer:

DAB = 2.23 radians

Hope this helps!

Step-by-step explanation:

Answer:

A. $115; $72/hour

B. c = 72h + 115

C. $8

Step-by-step explanation:

Part A.

1 hour: $187

2 hours: $259

2 hours - 1 hour = 1 hour

$259 - $187 = $72

$72/hour

The hourly rate is $72/hour.

Since for the first hour he charges $187, and only $72 comes from the hourly rate, then the initial cost is $187 - $72 = $115.

The initial cost is $115.

Part B.

c = 72h + 115

Part C.

Carpenter L for 6 hours:

c = 72(6) + 115 = 547

$547

Carpenter N for 6 hours:

60(6) + 195 = 555

$555

Difference: $555 - $547 = $8

Recall that for all [tex]z\in\Bbb C[/tex],

[tex]\sin(z) = \dfrac{e^{iz} - e^{-iz}}{2i}[/tex]

so that

[tex]\sin(z) = a \iff e^{iz} - e^{-iz} = 2ia[/tex]

Multiply both sides by [tex]e^{iz}[/tex] to get a quadratic equation,

[tex]e^{2iz} - 2iae^{iz} - 1 = 0[/tex]

Solve for [tex]e^{iz}[/tex]. By completing the square,

[tex]e^{2iz} - 2ia e^{iz} + i^2a^2 = 1 + i^2a^2[/tex]

[tex]\left(e^{iz} - ia\right)^2 = 1 - a^2[/tex]

[tex]e^{iz} - ia = \pm \sqrt{1-a^2}[/tex]

[tex]e^{iz} = ia \pm \sqrt{1-a^2}[/tex]

[tex]iz = \log\left(ia \pm \sqrt{1-a^2}\right)[/tex]

[tex]iz = \ln\left|ia \pm \sqrt{1-a^2}\right| + i \left(\arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n\right)[/tex]

[tex]\boxed{z = -i \ln\left|ia \pm \sqrt{1-a^2}\right| + \arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n}[/tex]

where n is any integer.

We are given with:

[tex]{\quad \qquad \longrightarrow \sin (z)={\sf a}\:,\:z\in \mathbb{C}}[/tex]

Recall the identity what we have for the sine function of complex numbers

Put the values to thus obtain:

[tex]{:\implies \quad \sf \dfrac{e^{\iota z}-e^{-\iota z}}{2\iota}=a}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}-e^{-\iota z}=2a\iota}[/tex]

Multiply both sides by [tex]{\sf e^{\iota z}}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}\cdot e^{\iota z}-e^{-\iota z}\cdot e^{\iota z}=2a\iota e^{\iota z}}[/tex]

[tex]{:\implies \quad \sf (e^{\iota z})^{2}-2a\iota e^{\iota z}-1=0}[/tex]

Put x = [tex]{\sf e^{\iota z}}[/tex]:

[tex]{:\implies \quad \sf x^{2}-2a\iota x-1=0}[/tex]

Find the discriminant, here D will be, D = (-2ai)² - 4 × 1 × (-1) = 4 - 4a² = 4(1-a²)

Now, By quadratic formula:

[tex]{:\implies \quad \sf x=\dfrac{-(-2a\iota)\pm \sqrt{4(1-a^{2})}}{2}}[/tex]

[tex]{:\implies \quad \sf x=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}[/tex]

[tex]{:\implies \quad \sf e^{\iota z}=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}[/tex]

[tex]{:\implies \quad \sf \iota z=log\bigg(\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}\bigg)}[/tex]

Using the formula for logarithms, we have:

[tex]{:\implies \quad \sf \iota z=log(a\iota \pm \sqrt{1-a^{2}})-log(2)}[/tex]

[tex]{:\implies \quad \sf z=\dfrac{1}{\iota}log(a\iota \pm \sqrt{1-a^{2}})-\dfrac{1}{\iota}log(2)}[/tex]

The sine function is periodic on 2πn and zero on (π/2), and the logarithmic expression becomes undefined for all ia±√(1-a²) < 0, so we will take modulus of it

[tex]{:\implies \quad \boxed{\bf{z=\dfrac{1}{\iota}log\bigg|a\iota \pm \sqrt{1-a^{2}}\bigg|-\dfrac{1}{\iota}log(2)+\dfrac{\pi}{2}+2\pi n\:\:\forall \:n\in \mathbb{Z}}}}[/tex]

Answer:

x=3, Aly is correct.

Step-by-step explanation:

a. angle YWZ

b. ZY = 9

c. the triangles are congruent so 7x-20=2x-5, 5x=15, and x=3

Yes

Step-by-step explanation:

[tex] \cos( \alpha ) = \frac{base}{hypoteneuse} [/tex]

Its just correct..

Answer:

Answer In this Picture.

Answer:

$10.64

Step-by-step explanation:

20% out of $53.18 is $10.636 rounded to $10.64