Ruby is painting her house. She uses 2 2/7 gallons of paint in the living room. To paint the kitchen, Ruby uses 5/8 of the amount of paint she uses in the living room. Which expression can be used to find the number of gallons of paint Ruby uses to paint the kitchen?

Answer:

i put it in a calc and got 1 1/2 which simplifies to 2/3

Step-by-step explanation:

Answer: a?

Step-by-step explanation:

i did 3 dived by 5 then 2 diviided by 5, dived the awnsers and got 2/3

Answer:

-4 is your final answer in it

The answer is A. True.

Hope this helps

Answer:

True

Step-by-step explanation:

Two triangles are similar { ~ } only when they have same shape. And as these figures have same shape so they are similar. And their corresponding sides are equal too...

Answer:

30

Step-by-step explanation:

90 - 60 = 30

Answer:

370 inches

Step-by-step explanation:

To find the perimeter of a figure, you need to add all sides together.

60 + 60 + 125 + 125 = ?

60 + 60 = 120

125 + 125 = 250

120 + 250 = 370 inches

As Per Provided Information

Diameter of Circle is 27 units

Radius will be 27/2 units

Radius will be 13.5 units

Calculating Area of circle.

[tex] \boxed{ \qquad\huge\sf \:Area_{(Circle)} \: = \pi {r}^{2}}[/tex]

[tex] \qquad\longrightarrow\sf \:Area_{(Circle)} = 3.14 \times {13.5}^{2} \\ \\ \\ \qquad\longrightarrow\sf \:Area_{(Circle)} = 3.14 \times 182.25 \\ \\ \\ \qquad\longrightarrow\sf \:Area_{(Circle)} = 572.265 \\ \\ \\ \qquad\longrightarrow\sf \:Area_{(Circle)} \: = 572.3 \: square \: units[/tex]

Now finding the circumference of the circle.

[tex]\qquad\boxed{\huge\sf \: Circumference_{(Circle)} = 2 \pi \: r}\\\\\qquad\longrightarrow\sf \:Circumference_{(Circle)} = 2 \times 3.14 \times 13.5 \\ \\ \\ \qquad\longrightarrow\sf \:Circumference_{(Circle)} = 6.28 \times 13.5 \\ \\ \\ \qquad\longrightarrow\sf \:Circumference_{(Circle)} = 84.78 \\ \\ \\ \qquad\longrightarrow\sf \:Circumference_{(Circle)} = 85 \: units[/tex]

Step-by-step explanation:

Given :- Diameter of circle :- 27 units , radius :- 13.5 units

Area :- πr²

Area :- 3.14×13.5²

Area :- 572.265

rounding off to nearest hundredth = 572.3 sq. units

Circumference :- 2πr

= 2 ×3.14 × 13.5 units

= 84.78 units

rounding off to nearest hundredth = 85 units

Step-by-step explanation:

2(2x + 1) = 3(x - 4)

4x+2=3x-12

4x-3x=--12-2

x=14

Step-by-step explanation:

[tex] \frac{6}{7} \times ( \frac{11}{18} - \frac{5}{12} )[/tex]

[tex] \frac{6}{7} \times ( \frac{7}{36} )[/tex]

[tex] \frac{42}{252} [/tex]

Answer:

5x(squared)-4x+1

2x(squared)+11xy+14

7x(squared)+7xy+3x-17

Step-by-step explanation:

Answer:

2.3?

Step-by-step explanation:

i just divided it 14 ÷ 6

Answer:

12/4=3

Step-by-step explanation:

12/4

Answer:

3 batches

Step-by-step explanation:

Assuming that you are asking for how many batches she can make, we can divide 12 by 4 to find the number of batches.

Answer: add them

Step-by-step explanation: your welcome to get a tutor

Answer:

Circumference ≈ 50.27

Area ≈ 201.06

Step-by-step explanation:

The circumference of a circle is [tex]2\pi r[/tex] while the area of the circle [tex]\pi r^{2}[/tex]

Since the diameter is the radius multiplied by 2, the radius of the circle is 8. So substituting 8 for r, the circumference is 2 × [tex]\pi[/tex] × 8, which is approximately 50.27 (rounded to the nearest hundredth) and the area of the circle would be [tex]\pi[/tex] × 8². 8² is 64 so 64 times pi is approximately 201.06 (rounded to the nearest hundredth)

Answer:

Uncle=10, Grandpa=20, Bob=20

Step-by-step explanation:

Uncle: 50* 1/5 = 10

Grandpa: 50 * 2/5= 20

Bob: 50-(10+20)=20

Answer:

Uncle=10, Grandpa=20, Bob=20

Step-by-step explanation:

Uncle: 50* 1/5 = 10

Grandpa: 50 * 2/5= 20

Bob: 50-(10+20)=20

Step-by-step explanation:

Answer:

5 and -5

Step-by-step explanation:

3x² = 75

x² = 75/3

x² = √25

x = 5 and - 5

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$530000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=530000\left(1+\frac{0.04}{4}\right)^{4\cdot t}\implies A=530000(1.01)^{4t} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{after 12 years}}{t=12}\implies A=530000(1.01)^{4(12)}\implies A=530000(1.01)^{48} \\\\\\ A\approx 854479.82~\hfill \underset{\textit{interest in the account}}{\stackrel{854479.82~~ - ~~530000}{\approx 324479.82}}[/tex]

Answer:

look i don't have a paper,but

Answer:

x=30

angle ABC=100

angle DBC=80

Given Information :-

⠀⠀

⠀

To Find :-

⠀

⠀

Solution :-

⠀

To find the percentage of expenditure, we must know how much amount does he really spend, thus :

⠀

➥ Expenditure = Earnings - Savings

➥ Expenditure = Rs. 9600 - Rs. 2400

➥ Expenditure = Rs. 7200

⠀

Now, we can find the percentage,

⠀

[tex] \sf \hookrightarrow Percentage_{expenditure} = \dfrac{Expenditure}{Earnings} \times 100 \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{7200}{9600} \times 100 \qquad \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{72 \cancel{00}}{96 \cancel{00}} \times 100 \qquad \quad \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{ \cancel{72}}{ \cancel{96}} \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \cancel \frac{3}{4} \times 100 \qquad \qquad \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = 0.75 \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \underline{ \boxed{ \orange {\frak{75\%}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

Thus, the percentage of his expenditure is 75%.

⠀

[tex] \underline { \rule{227pt}{2pt}}[/tex]

⠀

Answer:

5%

Step-by-step explanation:

Earns= Rs 640

Spends= Rs 608

Saves= (Rs 640 - Rs 608) =Rs 32

therefore, 32/640x100

The equation of the graph G(x) is (x - 4)^2 + 1.

We have given the graph below have the same shape.

We have to find the equation of the graph g(x).

We have to find the equation of g(x) by using the phase shifting.

A shift is a rigid translation in that it does not change the shape or size of the graph of the function.

Here we can see that the vertex of the graph in f(x) is (0,0) and the

vertex of the graph is g(x) is (4,1)

Therefore [tex]x^2[/tex] is replaced by [tex](x-4)^2[/tex].

and  is shifted upward one unit therefore we get

[tex]G(x)=(x-4)^2+1[/tex]

Therefore we get the graph of g(x)= (x - 4)^2 + 1.

To learn more about the shift of graph visit:

https://brainly.com/question/24457739

#SPJ1

Answer: x= -2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Equation

Cost = 0.75 * x

The answer is Cost = 0.75 * x

Answer:

4

Step-by-step explanation:

4 sheets of plywood X 9$=36$

60$-36$=24$

24$ is left over to buy boxes of nails at 5$ each

24/5=4.8

Derek can buy 4 boxes of nails.

Check the picture below.

the assumption is that the graph keeps on going all the way to ±infinity.

Bear in mind that the interval notation is referring to the endpoints on the x-axis.

Answer:

20 Box.

The answer is B.

Step-by-step explanation:

Given information:

Each box is 60 cm^3.

Total Volumes boxes are 1200 cm^3.

Divide Total Box/Each Box.

[tex]1200/60=20 box[/tex]

Answer:

B

Step-by-step explanation:

Total volume 1200 divided by each box of 60 = 20 boxes

Option A has 16 boxes

Option B has 20 boxes

Option C has 30 boxes

Option D has 24 boxes

Therefore, the correct answer is B

Answer:

D and E

Step-by-step explanation:

Answer:

Draw two parallel chords AB and CD of lengths 5 cm and 11 cm. Let the center of the circle be O. Join one end of each chord to the center.

Draw two perpendiculars OM and ON to AB and CD, respectively, which bisects the chords.

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its center. If the distance between AB and CD is 6 cm, find the radius of the circle.

Thus, MB = 2.5 cm and ND = 5.5 cm [The perpendicular drawn from the center of the circle to the chords bisects it.]

Let OM = x and ON = 6 - x

Consider ΔOMB

By Pythagoras theorem,

OM2 + MB2 = OB2

x2 + 2.52 = OB2

x2 + 6.25 = OB2..................(1)

Consider ΔOND

By Pythagoras theorem,

ON2 + ND2 = OD2

(6 - x)² + 5.52 = OD2

36 + x2 - 12x + 30.25 = OD2

x2 - 12x + 66.25 = OD2............... (2)

OB and OD are the radii of the circle. Therefore OB = OD.

Thus, OB2 = OD2

Equating (1) and (2) we get,

x2 + 6.25 = x2 - 12x + 66.25

12x = 60

x = 5

Substituting the value of x in (1),

OB2 = x2 + 6.25

OB2 = 52 + 6.25

OB2 = 31.25

OB = 5.59 (approx.)

Thus, we get the radius of the circle = 5.59 cm.

Answer:

2

Step-by-step explanation:

because of your options

Answer:

3

Step-by-step explanation:

The mode is 3 because it is the most commonly repeating number in the data set.

The mode of the data represented in this line plot is 3

From the line plot, we have the following frequency table

Data   Frequency

1               2

2            3

3            4

4            3

In the above frequency table, the entry 3 has the highest frequency of 4

Hence. the mode of the data is 3

Read more about mode at:

https://brainly.com/question/14532771

#SPJ2