Round 82585 to the nearest ten thousand. Enter your answer in the box
below.

Step-by-step explanation:

[tex] \frac{a}{b} c = \frac{a}{ \frac{b}{c} } [/tex]

[tex] \frac{a}{b} c = a \times \frac{c}{b} [/tex]

Answer:

Step-by-step explanation: change A/B/C to A÷B/C then change the division sign into a multiplicmultiplication sign so that you will have A×C/Bwhich will make your left equation = to your right equation

Answer:

1440 cubic inches

V = [tex]l[/tex] × [tex]w[/tex] × [tex]h[/tex]

V = 12 × 10 × 12 = 1,440 cubic inches

The cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

Given the cost of operating the marketing Department for March is $19,000. The total area of operation is,

Total Area = Department A + Department B + Department C + Department D

Total Area = 1400 m² + 820 m² + 560 m² + 390 m² = 3,170 m²

Now, the cost of operating a unit area can be determined as,

Cost of operating = $19,000/3,170m² = $5.99369 per m²

Further the cost of operating the different departments are,

Department A = 1400m²×$5.99 = $8,391.17

Department B = 820m²×$5.99 = $4,914.83

Department C = 560m²×$5.99 = $3,356.47

Department D = 390m² × $5.99 = $2,337.53

Hence, the cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

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Answer:

each notebook costs $2

Step-by-step explanation:

21-5=16/8=$2

Answer:

Lateral surface area = [tex]18\sqrt{91}[/tex] units²

                                 = 171.71 units²

Step-by-step explanation:

Lateral area:  total surface area excluding its base

Find the radius (circumradius) of the regular hexagonal base.  Use this to find the slant edge of the pyramid, then use the slant edge to find the slant height and thus the area of each face.

Radius of a regular polygon: distance from its center to its vertices.

[tex]\textsf{Radius of a regular polygon}=\dfrac{s}{2 \sin \left(\dfrac{180^{\circ}}{n}\right)}[/tex]

where:

Given:

[tex]\implies \textsf{Radius}=\dfrac{6}{2 \sin \left(\dfrac{180^{\circ}}{6}\right)}=6\:\sf units[/tex]

Use Pythagoras' Theorem to find the slant edge:

[tex]\begin{aligned}\textsf{Slant edge} & =\sf \sqrt{r^2+h^2}\\& = \sqrt{6^2+8^2}\\ & = 10\:\sf units\end{aligned}[/tex]

Use Pythagoras' Theorem to find the slant height:

[tex]\begin{aligned}\textsf{Slant height} & = \sqrt{\textsf{slant edge}^2-\left(\dfrac{s}{2}\right)^2}\\& =\sqrt{10^2-3^2}\\ & =\sqrt{91}\: \sf units\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Area of one face} & = \dfrac{1}{2} \times s \times \textsf{slant height}\\\\ & = \dfrac{1}{2} \cdot 6 \cdot \sqrt{91}\\\\ & = 3\sqrt{91}\: \sf units^2\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Lateral Surface Area}& = 6 \times \textsf{area of one face}\\ & = 6 \cdot 3\sqrt{91}\\ & = 18\sqrt{91}\\ & =171.71\: \sf units^2\:(nearest\:hundredth)\end{aligned}[/tex]

Answer:

then

x2-4x+3=x-5

or,x2-4x-x= -5-3

or,x2-5x+8=0

The equation of the ellipse will be (x - 5)² / 16 + (y + 7)² / 64 = 1 and the equation of the hyperbola will be (x + 1)² / 4 - (y)² / 64 = 1.

Ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called foci adds up to a constant. It is taken from the cone by cutting it at an angle.

The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.

Conic sections provide a format that makes them fairly uncomplicated to draw manually.

Then the equation of the ellipse will be

(x - 5)² / 16 + (y + 7)² / 64 = 1

Then the equation of the hyperbola will be

(x + 1)² / 4 - (y)² / 64 = 1

The graphs are given below.

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Answer:

4

Step-by-step explanation:

It is 4 because the point rises 4 units up from the graph and runs 1 unit to the right which is 4/1 = 4.

Answer:

its b actually jack had 5 numbers for each button

Answer:

B

Step-by-step explanation:

2.

what is the middle between 2 numbers (any numbers, really) ?

you add both numbers and divide the result by 2.

the same here :

(-3 + 24) / 2 = 21/2 = 10 1/2

proof :

what is the distance from -3 to 10 1/2 ? it is 10 1/2 from 0 to 10 1/2 plus 3 from -3 to 0 = 10 1/2 + 3 = 13 1/2.

what is the distance from 10 1/2 to 24 ? it is 13 from 11 to 24, and another half from 10 1/2 to 11. so, in total 13 1/2.

both distances are equal, so it is proven for 10 1/2 to be the midpoint.

The radius of the circular garden whose circumference is 122.46 feet is: 19.5 feet.

Circumference = 2πr, where r is the radius of the circle.

Given the following:

122.46 = 2(3.14)(r)

122.46/2(3.14) = r

r = 19.5 feet.

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Given 3x and 5x --------------- (i)

(3x+10)/(5x+10) = 5/7

21x + 70 = 25x + 50

4x = 20

x = 5

Answer:

I'd say the order from youngest to oldest, would be B A C.

Step-by-step explanation:

My reason is that, A is younger than C or in other words C is older than A. Also B is NOT older than A, so therefore B must be younger than A.

So from youngest to oldest, B is younger than A, A is younger than C, and that means C is the absolute oldest out of the three children.

Hope this helps you :)

Sorry if it didn't though.

The two coterminal angles in radian measure (one positive and one negative) for each angle for figure 1 and 2 are,[(13π/4),(-π/4) and [(7π/4),(-17π/4) rad] respectively.

Angles having the same terminal side at standard position are called coterminal angles.

Although the magnitudes of coterminal angles varies, they all have the same sides and vertices.

Positive or negative coterminal angles are possible. The positive coterminal is obtained by adding 2 rad or 360° to the negative coterminal, while the negative coterminal is obtained by removing 2 rad or 360°.

For figure 1;

The positive coterminal angle is found as;

[tex]\rm \rightarrow \theta + 2 \pi \\\\ \rightarrow \frac{5 \pi}{4} + 2 \pi \\\\ \rightarrow\frac{13 \pi}{4} \ rad[/tex]

The negative coterminal angle is found as;

[tex]\rm \rightarrow \theta - 2 \pi \\\\ \rightarrow \frac{5 \pi}{4} - 2 \pi \\\\ \rightarrow\frac{-3 \pi}{4} \ rad[/tex]

For figure 2;

The positive coterminal angle is found as;

[tex]\rm \rightarrow \theta + 2 \pi \\\\ \rightarrow \frac{-9\pi}{4} + 2 \pi \\\\ \rightarrow\frac{7 \pi}{4} \ rad[/tex]

The negative coterminal angle is found as;

[tex]\rm \rightarrow \theta - 2 \pi \\\\ \rightarrow \frac{-9 \pi}{4} - 2 \pi \\\\ \rightarrow\frac{-17 \pi}{4} \ rad[/tex]

Hence,the two coterminal angles in radian measure (one positive and one negative) for each angle for figure 1 and 2 are,[(13π/4),(-π/4) and [(7π/4),(-17π/4)] respectively.

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Answer:

5.9 C

Step-by-step explanation:

Plug in 16°C for the initial amount, 0.06 for the rate of decrease, and 16 minutes for the time elapsed.

y= a(1–r)t

y= 16(1–0.06)16 Plug in values

y= 16(0.94)16 Subtract

y= 16(0.37157…) Simplify

y= 5.94518… Multiply

Round to the nearest tenth.

5.94518… → 5.9

To the nearest tenth, the difference in temperature will be 5.9°C.

Answer:

20

Step-by-step explanation:

85% of 24 is 20

Since the isotope is initially 154 mg, the amount of radioactive isotope left after 64 hours is 9.625 mg

To answer the question, we need to know what radioactive decay is.

Radioactive decay is the spontaneous disintegration of a larger atom to a smaller one

Half-life of a radioactive isotope is the time it takes for the isotope to decay to half its initial value.

The amount left after n half lives is N = (1/2)ⁿN₀ where N₀ = initial mass of isotope.

Given that the half-life of the isotope is 16 hours, and we desire the amount present after 64 hours.

The number of half-lives after 64 hours is n = time/half-life

= 64 h/16 h

= 4

Since we have 154 mg of isotope present, N₀ = 154 mg

Given that

Substituting the values of the variables into N, we have

N = (1/2)ⁿN₀

N = (1/2)⁴ × 154 mg

N = 154 mg/16

N = 9.625 mg

So, the amount of radioactive isotope left after 64 hours is 9.625 mg

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The width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a×b

Here, (a)is the length of the rectangle and (b) is the width of the rectangle

The length of the outer rectangle is 26+2x and width of it is 18+2x. The area of this rectangle is 884² m. Thus,

A=a×b

884=(26+2x)×(18+2x)

884=468+52x+36x+4x²

4x²+88x-416=0

Divide both side with 4,

x²+22x-104=0

x²+26x-4x-104=0

x(x+26)-4(x+26)=0

(x+26)(x-4)=0

x=-26,4

Take the positive value 4. The width of the path is equal to x which is 4 meters.

Hence, the width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

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Answer:

sorrry i forget you man ..... or bro .....

Answer:

The answer is Graph C.

Step-by-step explanation:

Both the equation of each other are the same in Graph C..

Answer:

B. Graph C

The lines are together, so every point they pass is a solution

Answer:

y = 1/3 x + 4

Step-by-step explanation:

y = 1/3 x + 4

The y intercept is 4 (when x = 0 from the graph) and the slope is rise (1) and run (3).

There are a total of  180 seats in the theater

The theatre illustrates an arithmetic sequence, with the following parameters:

Number of rows = 18

Let the number of seats per row be n.

So, we have:

Total = 18n

When there are 3 fewer rows, the total number of seats is:

Total = (18 - 3) * (n + 6)

This gives

Total = 15* (n + 6)

Substitute Total = 18n in Total = 15* (n + 6)

18n = 15* (n + 6)

Open the bracket

18n = 15n + 90

Subtract 15n from both sides

3n = 30

Divide both sides by 3

n = 10

Substitute n = 10 in Total = 18n

Total = 18 *10

This gives

Total = 180

Hence, there are 180 seats in the theater

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Answer:

Minimum: 0

Quartile Q1: 22.5

Median: 50

Quartile Q3: 77.5

Maximum: 100

Step-by-step explanation:

Answer:

hope it helps you

Step-by-step explanation:

To make such a frequency distribution table, first, write the class intervals in one column. Next, tally the numbers in each category based on the number of times it appears. Finally, write the frequency in the final column. A frequency distribution table drawn above is called a grouped frequency distribution table.

Answer:

the length of the line is 7

Step-by-step explanation:

it is b. 7

Based on the longitudes of Quito and Singapore, the shortest distance between the two areas is 19,702.5 km .

Because both cities are close to the equator, you use the longitudinal difference method to find the shortest distance.

First find the difference in longitudes:

= Singapore - Quito

= 104 - (-78.5) because Quito is west

= 104 + 78.5

= 182.5°

Then subtract this from 360°:
= 360 - 182.5

= 177.5°

Every 1° longitude along the Equator is 111 km so the shortest distance is:

= 177.5 x 111

= 19,702.5 km

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