PLZZZ HELP
This is due in 15 mins
I need 5
But I already have 4
So one more

Answer:

4/5

Step-by-step explanation:

y varies as x

y=kx

k=x/y

Answer:

12.6

Step-by-step explanation:

Length of arc=(2*pi*r)*(theta/360)

Length of arc=(2*12*pi)*(1/6)=12.6

Answer:

The answer is "18".

Step-by-step explanation:

Amount of different methods a resident could get an advertisement:

[tex]=2\times 3 \times 3\\\\= 18[/tex]

Answer:

The Answer is 18

Step-by-step explanation:  

2*3*3

Answer:

a. The average daily amount of time an adult spends on the internet is different than 4.5 hours.

Step-by-step explanation:

An internet provider states that, on average, the daily amount of time an adult spends on the internet is 4.5 hours.

At the null hypothesis, it is claimed that the mean is of 4.5 hours, that is:

[tex]H_0: \mu = 4.5[/tex]

A sociologist studying the behaviors of internet consumers believes the average daily amount an adult spends on the internet is different than the amount stated by the internet provider.

At the alternative hypothesis, the sociologist claim, is that the mean is different of 4.5, that is:

[tex]H_1: \mu \neq 4.5[/tex]

Thus, the correct answer is given by option a.

Answer:

https://linksharing.samsungcloud.com/ul5cX9oOmhzt

Answer:

The answer is "0.695 and 0.305".

Step-by-step explanation:

Please find the attached file of the given question:

From question a:

[tex]\text{P(Either married, or a college graduate, or a professional)} \\\\=\frac{(312+143+188+191)}{1200}\\ \\ =\frac{834}{1200}\\\\=0.695[/tex]

 From question b:

[tex]\text{P( Neither married, nor a college graduate, nor a professional )}\\\\=\frac{366}{1200} \\\\=0.305[/tex]

Answer:

x=15, y=2

Step-by-step explanation:

By AA similarity, the triangles are similar. Therefore, we can find the ratios of the side lengths.

9/3=3=ratio of the side length of a larger triangle to a smaller one.

3=6/y, y=2

3=x/5, x=15

Hope this helped,

~cloud

Answer:

[tex]V(r) =101\pi r^2 + \frac{2}{3}\pi r^3[/tex]

Step-by-step explanation:

Given

Shapes: cylinder and hemisphere

[tex]h = 101[/tex] --- height of cylinder

Required

The volume of the silo

The volume is calculated as:

Volume (V) = Volume of cylinder (V1) + Volume of hemisphere (V2)

So, we have:

[tex]V_1 = \pi r^2h[/tex]

[tex]V_1 = \pi r^2 * 101[/tex]

[tex]V_1 = 101\pi r^2[/tex] --- cylinder

[tex]V_2 = \frac{2}{3}\pi r^3[/tex] ---- hemisphere

So, the volume of the silo is:

[tex]V =V_1 + V_2[/tex]

[tex]V =101\pi r^2 + \frac{2}{3}\pi r^3[/tex]

Write as a function

[tex]V(r) =101\pi r^2 + \frac{2}{3}\pi r^3[/tex]

Where: [tex]\pi = \frac{22}{7}[/tex]

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the given angle, we know the opposite side and want to know the hypotenuse. Therefore, we should use the sine function.

sin(54) = 16/AB

AB = 16/sin(54)

AB = 19.78 units

Hope this helps!

Answer:

Step-by-step explanation:

(-∞,2)

I dont know what you mean by the question but according to me.

If y=x^5

y=x^5+3

Then y+3=x^5+3

Answered by Gauthmath must click thanks and mark brainliest

Answer: 20.5

Step-by-step explanation:

Cos 43 = X/28

O.73 = x/28

(0.73)(28)=20.5

Answer:2

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

7-5=2

2x9=18

Answer:

The width is:

[tex]-2+\sqrt{26}\text{ meters}\text{ }(\text{or approximately 3.0990 meters})[/tex]

And the length is:

[tex]2+\sqrt{26}\text{ meters}\text{ } (\text{or approximately 7.0990 meters})[/tex]

Step-by-step explanation:

Recall that the area of a rectangle is given by:

[tex]\displaystyle A = w\ell[/tex]

Where w is the width and l is the length.

We are given that the length of a rectangle is four meters longer than the width. Thus:

[tex]\ell = w + 4[/tex]

And we also know that the area of the rectangle is 22 square meteres.

Substitute:

[tex](22)=w(w+4)[/tex]

Distribute and isolate the equation:

[tex]w^2+4w-22=0[/tex]

The equation isn't factorable, so we can instead use the quadratic formula:

[tex]\displaystyle w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 1, b = 4, and c = -22. Substitute:

[tex]\displaystyle w = \frac{-(4)\pm\sqrt{(4)^2-4(1)(-22)}}{2(1)}[/tex]

Evaluate:

[tex]\displaystyle\begin{aligned} w &= \frac{-4\pm\sqrt{104}}{2}\\ \\ &=\frac{-4\pm\sqrt{4\cdot 26}}{2} \\ \\ &=\frac{-4\pm2\sqrt{26}}{2} \\ \\ & = -2\pm \sqrt{26} \end{aligned}[/tex]

Thus, our two solutions are:

[tex]w_1=-2+\sqrt{26}\approx 3.0990\text{ or } w_2=-2-\sqrt{26}\approx-7.0990[/tex]

Since the width cannot be negative, we can ignore the second solution.

Since the length is four meters longer than the width:

[tex]\ell = (-2+\sqrt{26})+4=2+\sqrt{26}\text{ meters}[/tex]

Thus, the dimensions of the rectangle are:

[tex]\displaystyle (2+\sqrt{26}) \text{ meters by } (-2+\sqrt{26})\text{ meters}[/tex]

Or, approximately 3.0990 by 7.0990.

Answer:

y = -1x + 2

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

because the equation above says p+p+p+p+p+p+5+1+1

so if we add up the p's it will give us 6p and if we add up the nos it will give us 6p+7

Answer:

$14.40

Step-by-step explanation:

my way of doing things:

15/100=0.15=1%of total amount

0.15 x 6=0.9= the 6% which is the tax

0.15 x 10 = 1.5=the coupon

Take the coupon amount $1.50 minus the tax amount $0.90 =$0.60. Because the coupon amount is greater than the tax the 60 cents gets taken away from the original 15 dollars leaving Mr. Longely only having to pay $14.40.

Answer:

2.5

Step-by-step explanation:

i had it

Answer:

The rental rate for the Fords is of $12 per day.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a Nissan.

y is the cost of a Ford.

z is the cost of a Chevrolet.

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day.

This means that:

[tex]3x + 2y + 4z = 106[/tex]

Two Nissans, four Fords, and three Chevrolets cost $107 per day

This means that:

[tex]2x + 4y + 3z = 107[/tex]

Four Nissans, three Fords, and two Chevrolets cost $102 per day.

This means that:

[tex]4x + 3y + 2z = 102[/tex]

From the first equation:

[tex]4z = 106 - 3x - 2y[/tex]

[tex]2z = 53 - 1.5x - y[/tex]

[tex]z = 26.5 - 0.75x - 0.5y[/tex]

Replacing into the third equation:

[tex]4x + 3y + 53 - 1.5x - y = 102[/tex]

[tex]2.5x + 2y = 49[/tex]

From the second equation:

[tex]2x + 4y + 3z = 107[/tex]

[tex]2x = 107 - 4y - 3z[/tex]

[tex]x = 53.5 - 2y - 1.5z[/tex]

[tex]x = 53.5 - 2y - 1.5(26.5 - 0.75x - 0.5y)[/tex]

[tex]x - 1.125x = 53.5 - 2y - 39.75 + 0.75y[/tex]

[tex]-0.125x = 13.75 - 1.25y[/tex]

[tex]0.125x = 1.25y - 13.75[/tex]

[tex]x = \frac{1.25y - 13.75}{0.125}[/tex]

[tex]x = 10y - 110[/tex]

Find the rental rate for the Fords.

We have to find y, so:

[tex]2.5x + 2y = 49[/tex]

[tex]2.5(10y - 110) + 2y = 49[/tex]

[tex]25y - 275 + 2y = 49[/tex]

[tex]27y = 324[/tex]

[tex]y = \frac{324}{27}[/tex]

[tex]y = 12[/tex]

The rental rate for the Fords is of $12 per day.

Answer:

D. Neither perpendicular nor parallel

Step-by-step explanation:

Let's find the slope (m) of both lines:

✔️Slope (m) of the line that passes through (6, -1) and (11, 2):

Slope (m) = change in y/change in x

Slope (m) = (2 -(-1))/(11 - 6) = 3/5

✔️Slope (m) of the line that passes through (5, -7) and (8, -2)

Slope (m) = change in y/change in x

Slope (m) = (-2 -(-7))/(8 - 5) = 5/3

✅The slope of both lines are not the same, therefore they are not parallel nor same line.

Also, the slope of one is not the negative reciprocal of the other, therefore they are not perpendicular.

*see attachment for clearer diagram

Answer:

16.5

Step-by-step explanation:

BC = 11

AB = 3

Area of the shaded region = area of ∆AEB + area of ∆CED

Area of a triangle is given as,

A = ½*base*height

Find the area of each triangle and add together

✔️Area of ∆AEB = ½*bh

Where,

base (b) = 3

height (h) = ½(BC) = ½(11) = 5.5

Area of ∆AEB = ½*3*5.5 = 8.25

✔️Area of ∆CED = ½*bh

Where,

b = 3

h = ½(BC) = ½(11) = 5.5

Area of ∆CED = ½*3*5.5 = 8.25

✅Area of the shaded region = area of ∆AEB + area of ∆CED

= 8.25 + 8.25

= 16.5

Using the points stated in the original problem, I have determined the lines for the graph.  

f(x)=3x-1

g(x)= 3x+17

Using the basic descriptions of transformations, we can determine the movement of the lines as being either horizontal or vertical shifts. (to put a visual to this problem, I the diagram in Desmos and then marked the stated points on the graph.)

Horizontal shifts move the line either to the left or to the right.  Vertical shifts move the line either up or down.

If you look at the graphs as being the same x-value for the functions, the change in the y- value is +18, which is a vertical shift.  

If you look at the graphs as being the same y-values, the change in x is -6 which is a horizontal shift.  

So, the value of k is the amount of change each equation has to have to match the points given. (from f(x) to g(x))

The vertical shift is g(x)=f(x) +18

The horizontal shift is g(x)=f(x-6)

Answer:

The vertical shift is g(x)=f(x) +18

The horizontal shift is g(x)=f(x-6)

Step-by-step explanation:

The area bounded by a chord and arc it intercepts is known as a segment of a circle segment of a circle

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

The reason the above value is correct is as follows:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

Required:

The area of part of the circle enclosed by chord PL and arc PL

Solution:

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

Area of segment = Area of minor sector APL - Area of triangle APL

Area of minor sector APL:

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of r and θ, we get;

Area of the minor sector APL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of Triangle APL:

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

Required shaded area enclosed by line PL and arc PL:

Therefore, the area of shaded segment enclosed by line PL and arc PL is found as follows;

Area of the required segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

The area of the circle enclosed by line PL and arc PL ≈ 37.62 square units

Learn more about the finding the area of a segment can be found here:

https://brainly.com/question/22599425

The area of the circle enclosed by line segment PL and circle arc PL is 37.80 square units.

The calculation of the area between line segment PL and circle arc PL is described below:

1) Calculation of the area of the circle arc.

2) Calculation of the area of the triangle.

3) Subtracting the area found in 2) from the area found in 1).

Step 1:

The area of a circle arc is determined by the following formula:

[tex]A_{ca} = \frac{\alpha\cdot \pi\cdot r^{2}}{360}[/tex] (1)

Where:

[tex]A_{ca}[/tex] - Area of the circle arc.

[tex]\alpha[/tex] - Arc angle, in sexagesimal degrees.

[tex]r[/tex] - Radius.

If we know that [tex]\alpha = 93^{\circ}[/tex] and [tex]r = 11[/tex], then the area of the circle arc is:

[tex]A_{ca} = \frac{93\cdot \pi\cdot 11^{2}}{360}[/tex]

[tex]A_{ca} \approx 98.201[/tex]

Step 2:

The area of the triangle is determined by Heron's formula:

[tex]A_{t} = \sqrt{s\cdot (s-l)\cdot (s-r)^{2}}[/tex] (2)

[tex]s = \frac{l + 2\cdot r}{2}[/tex]

Where:

[tex]A_{t}[/tex] - Area of the triangle.

[tex]r[/tex] - Radius.

[tex]l[/tex] - Length of the line segment PL.

If we know that [tex]l = 16[/tex] and [tex]r = 11[/tex], then the area of the triangle is:

[tex]s = \frac{16+2\cdot (11)}{2}[/tex]

[tex]s = 19[/tex]

[tex]A_{t} = \sqrt{19\cdot (19-16)\cdot (19-11)^{2}}[/tex]

[tex]A_{t} \approx 60.399[/tex]

Step 3:

And the area between the line segment PL and the circle arc PL is:

[tex]A_{s} = A_{ca}-A_{t}[/tex]

[tex]A_{s} = 98.201 - 60.399[/tex]

[tex]A_{s} = 37.802[/tex]

The area of the circle enclosed by line segment PL and circle arc PL is 37.80 square units.

Solution :

a). The test is a left tailed test.

b). The sample proportion is :

[tex]$\hat p = \frac{x}{n}$[/tex]

[tex]$\hat p = \frac{17}{258}$[/tex]

  = 0.065

Determining the Z statistics using the formula :

[tex]$Z=\frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n}}}$[/tex]

[tex]$Z=\frac{0.065 - 0.11}{\sqrt{\frac{0.11(1-0.11)}{258}}}$[/tex]

   = -2.31

∴ Z statistics value is -2.31

c). Using the excel function, the P-value is :

P-value = Normsdist(-2.31)

             = 0.0104441

d). The null hypothesis is [tex]$H_0: P = 0.11$[/tex]

    The level of significance is 0.01

    We fail to reject the null hypothesis as the P value is less than or equal to the significant level.

Answer:

x = 12

y = -29

Step-by-step explanation:

Our given equations: x + y = -17 and x - y = 41

Solve for x and substitute.

x = -17 - y

(-17 - y) - y = 41

-17 - 2y = 41

2y = -58

y = -29

Solve for x using y

x + (-29) = -17

x = 12