PLZ HELP!!!!
If a vertical parabola opens downward, has its vertex in the fourth quadrant,
and y =ax +bx +c is the equation of this parabola, which of the following
can be true?
a 0, b >0, and c >0
a >0, b 0
a 0, and c >0
a 0, and c 0, b 0
a >0, b >0, and c <0

Answer:

False

Step-by-step explanation:

A nonlinear function that can be written on the standard form

ax2+bx+c,wherea≠0

is called a quadratic function.

All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is

y=x2

picture51

The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate

x=−b2a

The y-coordinate of the vertex is the maximum or minimum value of the function.

a > 0                   parabola opens up                    minimum value

picture52

a < 0                    parabola opens down              maximum value

picture53

A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression.

The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation

x=−b2a

The y-intercept of the equation is c.

picture54

When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.

Example

Graph

x=x2+2x+1

Make a table of value for some values of x. Use both positive and negative values!

x y = x2 + 2x + 1

-3 4

-2 1

-1 0

0 1

1 4

2 9

3 16

Graph the points and draw a smooth line through the points and extend it in both directions

picture55

Notice that we have a minimum point which was indicated by a positive a value (a = 1). The vertex has the coordinates (-1, 0)  which is what you will get if you use the formula for the x-coordinate of the vertex

x=−b2a=−22⋅1=−1

and that the line has an y-intercept of (0, 1) which could have been determined from the c-value which is 1.

If you have an absolute value of a that is greater than 1 the parabola will be narrower than the parental quadratic function. And the opposite that if you have a absolute value of a that is less than 1 then the parabola will be wider than the parental quadratic function.

The vertical parabola opens downward, has its vertex in the fourth quadrant, and y = ax + bx +c is the equation of this parabola given conditions none of them is true.

A nonlinear function that can be written on the standard form

[tex]ax^{2} + bx +c = 0 where (a\neq 0)[/tex]

This called a quadratic function.

All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is'

[tex]y = x^{2}[/tex]

The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate .

x = −b2a

The y coordinate of the vertex is the value maximum or minimum of the function.

a > 0                   parabola opens up                    minimum value

a < 0                   parabola opens down     maximum value

A rule of thumb reminds us that when we have a positive symbol before we get a happy expression on the graph and a negative symbol renders a sad expression.

The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation

x = −b2a

The y-intercept of the equation is c.

[tex]XY = x^{2} +2X +1[/tex]

When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.

[tex]x = x^{2} +2x+1[/tex]

Make a table of value for some values of x. Use both positive and negative values!

This is the points lies on parabola

Graph the points and draw a smooth line through the points and extend it in both directions.

Notice that we have a minimum point which was indicated by a positive a value (a = 1). The vertex has the coordinates (-1, 0)  which is what you will get if you use the formula for the x-coordinate of the vertex

x =−b2a  =−22⋅1  =−1

And that the line has an y-intercept of (0, 1) which could have been determined from the c-value which is 1.

If you have an absolute value of a that is greater than 1 the parabola will be narrower than the parental quadratic function. And the opposite that if you have a absolute value of a that is less than 1 then the parabola will be wider than the parental quadratic function.

For more information about basics of parabola click the link given below .

https://brainly.com/question/13053904.

Complete the table of values for each given function rule

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