pls help me my mom won’t stop yelling at me Bc have missing assignments

Answer:

Some particles of gas and dust that the planets are made of were too far away from the core of the planet and could not be squashed together by gravity. They remained behind to form the ring system

Explanation:

so in simplier terms yes lol

Answer: the heavy ball of a demolition machine is storing energy when it is held at an elevated position.

Which has potential energy

Explanation:

Answer: hope u dont mind i think ash answer ur question just imagine i had the correct answer woah UwU

Explanation:

Answer:

the blank is on.

Turning on a switch completes a circuit.

Explanation:

Answer:

e. 4.847 x 10-19 J

Explanation:

From the given information:

The equation connecting the photon energy and the wavelength is:

[tex]E_{photon } = \dfrac {hc}{\lambda}[/tex]

where;

[tex]planck's \ constant \ (h)[/tex]= 6.626 * 10 ^{-34} J.s

[tex]velocity \ of \ light \ (c)[/tex] = 3.00 * 10^8 m/s

wavelength [tex]\lambda = 410.1 \ nm \times \dfrac{10^{-9} \ m}{1 \ nm}[/tex]

[tex]\lambda = 4.101 \times 10^{-7} \ m[/tex]

To determine the photon energy of violet light

[tex]E_{photon } = \dfrac {(6.626 \times 10^{-34} J/s ) \times (3.00 \times 10^8 \ m/s) }{4.101 \times 10^{-7} \ m}[/tex]

= 4.847 × 10⁻¹⁹ J

Answer:

%composition of B₂ = 4.3%

%composition of Br₆ = 95.7%

Explanation:

Given data:

Percent composition of B₂Br₆ = ?

Solution:

Total mass of B₂Br₆ = 10.8×2 + 79.9×6 = 501 g/mol

%composition of B₂ = ( 21.6 g/ 501 g ) × 100

%composition of B₂ = 0.043 × 100

%composition of B₂ = 4.3%

%composition of Br₆ = ( 479.4 g/ 501 g ) × 100

%composition of Br₆ = 0.957 × 100

%composition of Br₆ = 95.7%

0.843 mol KNO₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

85.2 g KNO₃

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

[tex]\displaystyle 85.2 \ g \ KNO_3(\frac{1 \ mol \ KNO_3}{101.11 \ g \ KNO_3} )[/tex] = 0.842647 mol KNO₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.842647 mol KNO₃ ≈ 0.843 mol KNO₃

Answer: compounds

Explanation:

Compounds are made of atoms of two or more different types of elements, and they can be chemically combined to create a compound. The compound will have molecules from each of the elements you add in the compound. The answer to the question is compounds.

Explanation:

the answer is in the attachment

Answer:

It helps you predict how much of a reactant participates in a chemical reaction

Explanation:

Answer:

101.78 g

Explanation:

We know that density is given by; mass/volume

Mass = ?

Density = 0.789 g/ml

Volume = 129 ml

Mass = volume × density

Mass= 129 ml × 0.789 g/ml

Mass= 101.78 g

Answer:

The mass of 4.5 moles of Cu(NO3)2 is 843.55g

Explanation:

Mass = moles x Molar mass

Mass = 4.50(187.55)

         = 843.97g

Explanation:

been defined in such a way. It is defined as the numbers of particles in 12 g of 12C. If it were 24 g instead of 12 g, then the weight of 1 mole of substance would equal 2 times the atomic/molecular mass in grams.

Answer:

cells?

Explanation:

Answer:  A. [tex]0.00301J/g^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,[tex]\Delta T=T_f-T_i=12.32^0C[/tex]

Putting in the values, we get:

[tex]4.56J=123g\times c\times 12.32^0C[/tex]

[tex]c=0.00301J/g^0C[/tex]

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is [tex]0.00301J/g^0C[/tex]

Answer:

The number of moles of calcium atom in each mole of calcium carbonate is 1 mole of calcium atoms

Explanation:

The chemical formula for CaCO₃ = 100.086 g

The number of molecules in one mole of a substance is given by the Avogadro's number, [tex]N_A[/tex] = 6.022 × 10²³ molecules

The number of calcium atoms in one molecule of CaCO₃ = 1 atom of calcium

Therefore, the number of calcium atoms in 1 mole of CaCO₃ = 1 × 6.022 × 10²³ atoms of calcium = 6.022 × 10²³ atoms of calcium

6.022 × 10²³ atoms of calcium = The number of toms in 1 mole of calcium atoms

Therefore, the number of moles of calcium atom in each mole of calcium carbonate = 1 mole of calcium atoms.

Answer:

1.)Elements

2.)Compound

3.)Subscript

4.)Formulas

Explanation:

Answer:

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Explanation:

Answer:

the water underwent a physical change. This is because the water simply changed states, and could become liquid again, but it will remain H20 throughout the time

Answer:

Explanation:

2Al + 3Cl2 --> 2AlCl3

Ag2O + Be -----> 2Ag + BeO

4K + O2 ---> 2K2O

CoP  + 3NaBr ---> CoBr3 + Na3P

Si +  Hg2S ---> SiS2 + Hg

6Li + Ni3N2 --- > 2Li3N + 3Ni

3Ca + 2K3N  --> Ca3N2 + 6K

SnS2 + 2F2 --> SnF4 + 2S

Answer:

See explanation

Explanation:

Among all the options listed, only compound (c) is a carbohydrate and it is a  trisaccharide.

Carbohydrates are represented by the formula (CH2O)n, the subscript n denotes the number of carbon atoms in the carbohydrate. Carbohydrates contains carbon, hydrogen and oxygen in the ratio of 1:2:1.

Carbohydrates can have linear structures and cyclic structures. The cyclic structure as in (c) is mostly obtained in solution. All carbohydrates are six carbon sugars linked together at a certain point as in structure (c).

Answer:

There are 15 grams of copper chloride in 50 cubic centimeters of solution.

Explanation:

The statement is incorrect. The complete sentence will be presented below:

What is the mass of cooper chloride in 50 cubic centimeters of a 300 grams per cubic decimeters?

In Chemistry, a common unit for concentration is grams per cubic centimeter. A cubic decimeter equals 1000 cubic centimeters. First, we convert the given concentration into the requested unit:

[tex]c = 300\,\frac{g}{dm^{3}} \times \frac{1\,dm^{3}}{1000\,cm^{3}}[/tex]

[tex]c = 0.3\,\frac{g}{cm^{3}}[/tex]

Which means there are 0.3 grams of copper chloride per each cubic centimeter of solution.

The amount of mass of copper chloride contained in 50 cubic centimeters of solution is calculated by dimensional analysis:

[tex]m = \left(0.3\,\frac{g}{cm^{3}} \right)\cdot (50\,cm^{3})[/tex]

[tex]m = 15\,g[/tex]

There are 15 grams of copper chloride in 50 cubic centimeters of solution.

Answer:

Mass = 2.77 g

Explanation:

Given data:

Mass of HCl = 2 g

Mass of CaCl₂ produced = ?

Solution:

Chemical equation:

2HCl + Ca    →     CaCl₂ + H₂

Number of moles of HCl:

Number of moles = mass / molar mass

Number of moles = 2 g/ 36.5 g/mol

Number of moles = 0.05 mol

now we will compare the moles of HCl with CaCl₂.

                   HCl       :         CaCl₂

                     2         :          1

                   0.05     :       1/2×0.05 = 0.025 mol

Mass of CaCl₂:

Mass = number of moles × molar mass

Mass = 0.025 mol × 110.98 g/mol

Mass = 2.77 g

Answer:

2. waves

3. True

4. the distance between successive crests of a wave, especially points in a sound wave or electromagnetic wave.

5. Frequency is the number of occurrences of a repeating event per unit of time.

6. slow, fast

7. left to right

8. The maximum displacement or distance moved by a point on a vibrating body

9. No

10. radio waves, and microwave.

11. tv uses electromagentic waves while light uses electromagenti radition.

Explanation:

Answer:

I hate to not answer and have you repost this if you could repost it with the choices by clicking the arrow I can figure it out a lot faster and I'll copy and paste to show you that it's right

Explanation:

I'm good with history biology sum math so if you want to do what I asked and reposted I can give you the answers and I will show that they are correct I won't just guess like some people do just to get points cuz I don't care about points I just get on here to help people

Answer: The answer for the blanks is initial appearance and than final appearance.

Explanation:

Answer:

d) Mass = 460 g      

Explanation:

Given data:

Mass of N₂O₄ produced = ?

Number of moles of NO₂ consumed = 10 mol

Solution:

2NO₂     →        N₂O₄

Now we will compare the moles of NO₂  and   N₂O₄.

                          NO₂         :             N₂O₄

                            2            :                1

                           10            :            1/2×10 = 5 mol

Mass of  N₂O₄ produced:

Mass =  number of moles × molar mass

Mass = 5 mol × 92 g/mol

Mass = 460 g